love your transparent glass board if... it is really a glass board.... and as far as i m thinking... all videos are uploaded after flipping them horizontally....or..... u are writing in opposite direction......what is this...i m not getting it....please tell me....
In my physics book it says "when you use the work--kinetic energy theorem, you must include all the forces that do work on the object." I'm getting confused on net work for some reason though. I totally agree that Fk is doing work because it's parallel to the distance, just that it's acting in the opposite direction, hence the 180 degrees. But isn't there suppose to also be another force doing work too? also know as the applied force that moved the object in the first place. It is parallel to the distance as well, but why don't you include it in the problem you were solving?
In this problem we assumed that box had already been pushed to an initial velocity and now is sliding to a stop. Thus the only force here that is doing work is friction. In general, you are correct: For net work, you need to include all the forces that are doing work. If there was another force pushing it, we would need to include it. Cheers, Dr. A
YO, you are a fantastic teacher. Thank you so much for your time.
Thanks! Doing my best and trying to improve all the time.
Cheers,
yoprofmatt
Best physics teacher ever ! Thank you so much :))
ur really helping me , i love physics and u really make it feel better
love from india
How much work does the man pushing the object do
love your transparent glass board if... it is really a glass board.... and as far as i m thinking... all videos are uploaded after flipping them horizontally....or..... u are writing in opposite direction......what is this...i m not getting it....please tell me....
i also have the same question
In my physics book it says "when you use the work--kinetic energy theorem, you must include all the forces that do work on the object." I'm getting confused on net work for some reason though. I totally agree that Fk is doing work because it's parallel to the distance, just that it's acting in the opposite direction, hence the 180 degrees. But isn't there suppose to also be another force doing work too? also know as the applied force that moved the object in the first place. It is parallel to the distance as well, but why don't you include it in the problem you were solving?
In this problem we assumed that box had already been pushed to an initial velocity and now is sliding to a stop. Thus the only force here that is doing work is friction. In general, you are correct: For net work, you need to include all the forces that are doing work. If there was another force pushing it, we would need to include it.
Cheers,
Dr. A
How to make this video. Fantastic
Roosaniza Ramli,
The board is called Learning Glass. You can check it out at www.learning.glass
Cheers,
Dr. A
Which university do you teach at?
San Diego State University in California, USA
Cheers,
Dr. A