A 1000 N crate is being pushed across a level floor at a constant speed by a force F of 300 N at an

A 1000 N crate is being pushed across a level floor at a constant speed by a force F of 300 N at an angle of 20.0° below the horizontal, as shown in the Figure a. (a) What is the coefficient of kinetic friction between the crate and the floor? (b) If the 300-N force is instead pulling the block at an angle of 20.0° above the horizontal, as shown in Figure b, what will be the acceleration of the crate? Assume that the coefficient of friction is the same as that found in part (a).

[@lanyssa7324]

with taking a 5 weeks physics class that got changed last minute to an online zoom class, this channel has definitely helped me immensely.

[@laplanetesauvage5391]

The way you explain it helps me understand physics better. Thank you!

[@guggystyle]

Thank you for saying so!

[@kpopisthebestful]

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[@guggystyle]

+Natsu Dragneel You're welcome! I sincerely hope they are helping you :)

[@Shadow.wolf9592]

Thanks for making this video! You helped me figure out how to solve one of the problems on my Physics homework that I was stuck on! So thanks for that and keep up the great work! ^^

[@emilyzhang7577]

this was extremely helpful for my Physics WebAssign. Thank you!

[@andreaochoa00]

Thank you so much you solved my work!

[@prettyfancynancymsp8929]

Thank god you exist

[@T8T3RT0T]

Thank you!!!

[@guggystyle]

No problem!

[@AllThingsElectric_]

The man with the yellow screen

[@ethanl886]

this is so helpful thank you so much!!

[@bunny-sk5rc]

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[@LeakCentral]

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[@jjvillejack]

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thank you!

[@Littlefrogintheocean]

Keep go on!

[@bosslin1755]

thanks a lot!!!!!

[@danisha9293]

Hello, i really appreciate the videos you have posted, i am having a hard time comprehending the components part, how do you know which side to assign cos and which side sin, i know in basic trig x axis represents cos and y axis represents sin, but i realize in physics its a little different i am not sure, i would greatly appreciate an explanation.

[@ninjamasta990]

cause

[@Khamar99]

Thanks a lot

[@patrickattankurugu7210]

Great explanation!

[@m_9714]

He solved my Hw

[@tailong3954]

@@unknown-gy8jz UITM?

[@fitrizuhairi1898]

@@tailong3954 Foundation engine?? xD

[@tailong3954]

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[@jaredhall5385]

Thank you for the video! I'm confused about how to know when to use sin vs cos for the different angles. Could anyone give some insight? Thanks!

[@emanamjad505]

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[@Ohfelious]

at 7:00 why do you use the Y normal force of 897N with the X coeff of kin friction (0.256)? Why do you use both axees if the acceleration is in the X axis? Why split f_k into mu times normal force in the first place?

[@Ohfelious]

nvm got it. When you break up the angle into x and y, how do you know what direction y should be. In part a, you said negative, but in part b, you said positive

[@valentinamontero2599]

Can someone explain how Fcos20 is pointing to the right?? Like how do we know that?

[@Ceecee384]

Why is Fx = 0 in first part and Fx=ma in 2nd part?
push vs pull: both are an acceleration in x-direction??

[@hehersonpapagayo7212]

can someone please enlighten me? What I learned was if velocity is constant acceleration is zero however, if speed is constant it doesn't mean that acceleration is zero. Is it right or wrong?

[@dylangregory5186]

What you learned is right

[@Kalone-po4yq]

ye thats right cuz since speed means sum of all velocities, an object could have travelled one way, and then slowed down and gone back the opposite direction to where it started. Since the overall velocity averages at 0, the speed is 0, but the acceleration is not because it changed throughout the objects path.

[@aokosakano3037]

why is it F x cos20 instead of mg x cos20? how will i know the difference?

[@aokosakano3037]

basically, why is it F x cos20 in some cases and mg x cos20 in others?

[@guggystyle]

Good question. If the question gives you "Newtons", then use F for the gravitational force, but if the question gives you "kg", then use mg for the gravitational force.

[@mariecurie465]

Can l ask? the problem is stated below the horizontal so its not -20° ?

[@maybinchola8501]

Sir. When finding the normal force which is mg why were you not multiplying it by 9.8m/s2 as the gravity unlike taking 1000N direct???

[@nooreennisrina9075]

i have a questionn> how should we know where to draw the components?

[@Kalone-po4yq]

the x component is horizontal to the angle, and the y component is vertical to the angle. think of it as a box that is made by the main vector, the y component is how far the vector went up, and the x component is how far it went sideways

[@juliatrillo7588]

at 1.48 minutes- why is the x component Fcos(20) instead of Fsin(20)?

[@vivekkumarpandey9182]

th-cam.com/video/91TahRMk41Q/w-d-xo.html

[@vivekkumarpandey9182]

Watch this you will understand

[@Cocogirlzchannel]

Why f sin 20 is negative?

[@joshuawatson470]

its pointing in the negative direction

[@balaportejean7015]

is the seond part accelerating just because it's not said "constant speed"?

[@yeon1573]

may i ask why Fy=0 in b?

[@VishalSh-pb8sr]

Because force =ma , here a=0 because of *a* is in the x-axis not in the y axis that's why Fy=0

[@agent_orca7512]

where do Fcos20 and fsin20 come from? this question makes no sense to me and it's only my second day in physics

[@balaportejean7015]

know that the cosine of an angle is the ratio of the adjacent side(the one that touches the angle) to the hypotenuse. So if we write formula we have Cos x=the side that we're looking for/hypotenuse. So we find the side we're looking for by multiplying the hypotenuse to cosx. Same thing with sine but it's with the opposite side to the angle. Got it? Jesus is the Son of God by the way. Believe in Him and repent.

[@africanoblackaldo1569]

came throoooooough