great video, but at 9:45 why not just plug in the x and y values provided into the f(x) function and get k that way? It gives the same answer just seems easier
Couldn’t you just substitute the points to get k for this particular question, the info for the tangent is unnecessary i think f(1)=k(1)^2+1+3=5 k+1+3=5 k=1
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great video, but at 9:45 why not just plug in the x and y values provided into the f(x) function and get k that way? It gives the same answer just seems easier
That is correct - you could also solve it that way. Well spotted! :) Mitch
Thank you!
You're welcome! Cheers, Mitch
Couldn’t you just substitute the points to get k for this particular question, the info for the tangent is unnecessary i think f(1)=k(1)^2+1+3=5 k+1+3=5 k=1