Conditional Operator in C
ฝัง
- เผยแพร่เมื่อ 12 ส.ค. 2024
- C Programming & Data Structures: Conditional Operator in C
Topics discussed:
1. Introduction to Conditional Operator in C language.
2. Use of Conditional Operator.
3. Example of Conditional Operator.
4. Homework Problem.
C Programming Lectures: goo.gl/7Eh2SS
Follow Neso Academy on Instagram: @nesoacademy(bit.ly/2XP63OE)
Follow me on Instagram: @jaspreetedu(bit.ly/2YX26E5)
Contribute: www.nesoacademy.org/donate
Memberships: bit.ly/2U7YSPI
Books: www.nesoacademy.org/recommende...
Website ► www.nesoacademy.org/
Forum ► forum.nesoacademy.org/
Facebook ► goo.gl/Nt0PmB
Twitter ► / nesoacademy
Music:
Axol x Alex Skrindo - You [NCS Release]
#CProgrammingByNeso #CProgramming #ConditionalOperator
Ans will be 65.
Explanation:
lets break the problem into part
(1) At first the condition is sizeof(var)
if this condition is evaluated to be true then (var2>23 ? ((var==75) ? 'A' : 0) : 0) will be returned
if false then 0 will be returned
As we know sizeof() is an unary operator which returns how many byte a datatype can hold
as var is an variable of integer data type , sizeof(var) will either return 2 or 4 as machine to machine int vary . We know every number except 0 is evaluated to be true. So (var2>23 ? ((var==75) ? 'A' : 0) : 0) it will returned
(2)next the condition is (var2>23)
if this condition is evaluated to be true then ((var==75) ? 'A' : 0) will be returned
if false then 0 will be returned
as we know 56>23 is true then ((var==75) ? 'A' : 0) will be returned.
(3)the condition is (var==75)
if this condition is evaluated to be true then 'A' will be returned
if false then 0 will be returned
As 75==75 then 'A' will be returned and stored into num variable
As c support auto type casting so int can store char.
In the final printf function we use the placeholder %d and it print integer value .
According to Ascii integer value of 'A' is 65
So the output will be 65.
Thank you
Thanks a lot :)
Why don't you think that ((var==75)? 'A' : 0) will be evaluated first? [As we know that bracket has the highest precedence than any other operator in C.]
@@mehadihasansanto538 xactly this is my doubt and i think bracket will only be evaluated first
@@ayushvats1808 Yeah, Brother. I also think so. Moreover, the associativity of conditional operator(? :) works from right to left. That's why I think ((var == 75)? 'A' : 0) will be evaluated first.
Answer -> 65
Solution ->
num = sizeof(var) ? (var2 > 23 ? ((var == 75) ? 'A' : 0) : 0) : 0;
as we know, var==75 is True, therefore, (var == 75) ? 'A' : 0 will be equal to 'A'.
Then we will replace the equation with 'A' in the main equation.
num = sizeof(var) ? (var2 > 23 ? 'A' : 0) : 0;
as we know, var2 == 56, hence greater than 23, therefore, var2 > 23 ? 'A' : 0 will be equal to 'A'.
Then we will replace the equation with 'A' in the main equation.
num = sizeof(var) ? 'A' : 0;
as we know, as condition is True if the result of expression is any number except 0, sizeof(var) == 4, as its an integer data type.
sizeof(var) is a True statement, therefore, sizeof(var) ? 'A' : 0 will be equal to 'A'.
This implies num = 'A';
In the printf statement, the format specifier of num is %d, so the ASCII value of the character will be printed. ASCII value of 'A' = 65.
You make it understandable. You remove my confusion to explain it line by line. Thax
Interesting lectures and also they are making to think for every homework questions.
hands down this is the best channel . pls continue blessing us with valuable information.
O/p is 65 ... because all three condition are true...sizeof(var)
Shows the size of int (which is other than 0 ....and then after all condition are executed it will return A and the decimal of A is 65 ..
according to ASCII TABLE
But here parenthesis is given first evaluate parenthesis then applied conditional ..
By evaluating with the parentheses the answer will be A.
But in what manner computer will execute.?
@@saiyadav5014 Answer should A for sure as all the conditions are true, but compiler should execute A as a integer value as it is assigned to num variable that is integer variable.
tq bro
@@Gautamsingh-dy4cp but as for associvity rule it caan be done from left to right
Thanks a lot for videos sir ❣️. It's really helpful.
This question is like 10 questions in one question. Neso team is great.
it will be wayyy better if you can explain the homework problems @nesoacademy sometimes I can't fully comprehend the answers
yes
Yes
Yeah, that would be really nice :(
65
@@AK--vc9wd I to get the same answer
Result is 65, start to solve from the inner bracket to the outer bracket, fixed inputs and take care of format specifier used during output, it will convert the result A into ASCII decimal 65 (%d is used for output)
Output will be the ASCI code of 'A' =65; Thank you for your efforts, I like your explanation so much ❤
thanks bro
Sir please solve homework problems also so that we can give it a try and if we are not able to solve it then we can refer to your explanation that would really really be helpful for beginners like me and all would really appreciate that effort of yours!!!! 🙏🙏🙏🙏
First rule to be followed while solving these type of conditions is:
First of all we need to divide given expression into three parts i.e L|M|R
And then start evaluate each and expression.
Al last num variable initialised by A which is equivalent of 65.
The answer is 65
First we will solve the inner brackets. According to that our condition is true so it will store the corresponding value of A according to ASCII i.e. 65 (because we are dealing with integer datatype). Then we will work our way out solving the outer brackets one by one. Hence the final answer is 65.
Thank you so much for this information
65 since sizeof var is 4or 8 according to processor which is True in boolean form and ascii value of A is 65 as we need to print in integer the value.
can you determine the size of on your own without using the sizeof() operator? is it like a rule where int is always 4? And do we start solving the expression from the parenthese on the inside or outside first?
Great job kn explaining this! Thank you 😊 soo much
O/p - ASCII Value of A= 65
Explained it perfectly man!!!!
It will print output as a 65
which is ASCII equivalent of 'A'
okay guys , here is the point ..
if we considered it as an if statement , it'll be as following ; )
int var = 75 , var2 = 65;
int num ;
if(sizeof(var))
{
if(var2 > 23)
{
if(var == 75)
{
num = 'A';
}
}
printf("%d" , num);
}
else
return 0;
the output is gonna be 65 , and this is according to ASCII table , as 'A' is = 65 ..
thank you very much for explanation Mr Sedeek. If you do not mind
i will ask you questions in future too
by looking at this equation now i understood the last stage of the problem clearly
Please make your own videos,no gyan choding here
else statements biro ?
Var 2 is 56 .how u right 65?
Sir firstly applied parenthesis operation after that apply ternary operator..first offl all remove parenthesis then evaluate ..it true or not
Thnx . U have given me a best lecture
Pls tell the ans with ur explain @neso academy.. All doute are clear
questions are just amazing..
Your classes are amazing sir , the way you explain with examples makes us more easier to understand the topics .
Output will be ASCII value of 'A' ie. 65
Numeric value of a return 65
Output will be : 65
do we have to memorise the ascii table values?
Sir please give the solution video also so that we can compare our result
As the variable num is of data type integer how can it take of char 'A' as its value and print 65 in integer
Thank you sir very nice gide & very nice best information conditional operator teaching video.👍
Really awesome classes.
Thanks for teaching me something in 5 minutes that my teacher took two 50 minutes classes for! 😃😃
I think that's the main reason, why does our education system lag behind.
true uncle@@kunalkhallar9699
all the three boolean returns true value so the value of num is "A" then the ASCII value of A is printed.
so the final answer will be 65...........
U r awesome
Whole expression is true that's by it has to return 65(at the place of A because c supports auto casting).
Both conditions are satisfied and print A value or A
The output of the programa is A, because as sizeof(var) is diferent to 0 it enters to the first true statement, then it checks if var2 > 23, that is true, so finally checks it var == 75, again this is true so num equal to A
Lakshman Patel, thanks
@@lakshmanpatelofficial but why is 65 ?
Excellent👍
Thank you so much
Super sir
thank you so much sir
I wonder if we can solve not from inner bracket but from the outer bracket, in this HW, both conditions are the same.
Ans will be 65
because the return value of 'num' is equal to 'A'
according to ASCII table the value of A is 65.
Out put will be 65
Since program execution begins from main function
Declared variable var and assigned 75 to it
Declared another variable var2 and assigned 56 to it
Declared num integer type
And given condition sizeof is unary operator since given sizeof(int) it returns 2 or 4 bytes depends on the compiler machine.How many bytes int will occupy it returns
We know that if the condition is false it returns 0 and other than 0 returns 1 so now our condition is true it checks other condition of that true it checks other condition finally it returns A and num is assigned with A and it will be printed since the value of A according to ASCII in c is 65
using return in ternary operator is allowed?
5:22 o/p is 65
thanks a bunch to the tutor n nesoAcademy ❤🙏
Thank u
Thanks
Output is 65...ascii of A
Which ternary operator gets evaluated first?
thank u
thnak you
65 stand for character A
All the conditions are true.
the answer will be 65, the ASCII value of 'A'. As each of the three statements is true so expression 2 of each statement will be the outcome.
All other inner conditional expressions will be treated first. They return true. Then, the main operand, sizeof, returns true which implies 'A' will be returned.
Since %d specifier was used, the printf will print the decimal value of character A, which is 65.
thnx man
*/Output will be*/
65
as per the expression, the result will be 'A' and it will be stored in num. But, num is int type data So, 'A' will be converted to its corresponding ASCII value which is 65.
Good
Ans is A but the return value is in the form of int datatype then it will transform into ASCII format return the value of A is 65
So the output is 65
65 because all conditions are true hence variable contain A and in decimal it will be 65
I solved in first attempt , before this playlist ,i used to write stdio.h to studio.h
65. Thank you, Sir
Will print 65 because 65 is the ASCII value of A if you use print("%c", num); instead of %d you will get A.
Could any one tell me why we can't convert char to short data type?.. in typecasting..
How it will contain 1 in conditional operators
I didn't get the bracketing arrangement of this program. Why for sizeof(var) there is no enclosing bracket, and for (var2>23 there's only one bracket on the left and missing on the right, while ((var==75) has an enclosed bracket but has also an additional bracket on the left side. And when I change the bracketing in any way, I immediately receive a compiler error. Would someone please explain the bracketing arrangement of this program? I think it is very important that I know. Thank you in advance if you do answer my doubt.
Use if else statement and see why all bracket shouldn't be closed b4 the other..
so as i think that we have break it inside the bracket
(var==75)?'A':0 then the answer is A because 75 is equal to 75.
then,
(var2>23?'A':0) then the answer will be A because 56 is greater than 23.
then,
we have sizeof(var)?'A':0; then the ascii A will be implemented that is 65
Ascii value of A 65
ASCII code of 'A' will be the answer and that is 65
65
Tip: use different bracket such as {}()
Single quotations are responsible for printing ASCII value of A
Sir I’m studying only 10th standard but learning c from u thanks a lot sir and I got the answer for ur homework problem as 0 if wrong plz explain by replying to me
ans is 65
Ans will be 65.
Explanation:
lets break the problem into part
(1) At first the condition is sizeof(var)
if this condition is evaluated to be true then (var2>23 ? ((var==75) ? 'A' : 0) : 0) will be returned
if false then 0 will be returned
As we know sizeof() is an unary operator which returns how many byte a datatype can hold
as var is an variable of integer data type , sizeof(var) will either return 2 or 4 as machine to machine int vary . We know every number except 0 is evaluated to be true. So (var2>23 ? ((var==75) ? 'A' : 0) : 0) it will returned
(2)next the condition is (var2>23)
if this condition is evaluated to be true then ((var==75) ? 'A' : 0) will be returned
if false then 0 will be returned
as we know 56>23 is true then ((var==75) ? 'A' : 0) will be returned.
(3)the condition is (var==75)
if this condition is evaluated to be true then 'A' will be returned
if false then 0 will be returned
As 75==75 then 'A' will be returned and stored into num variable
As c support auto type casting so int can store char.
In the final printf function we use the placeholder %d and it print integer value .
According to Ascii integer value of 'A' is 65
So the output will be 65.Ans will be 65.
the num = A ，but the output should be decimal number, then it convert to its binary representation 65
when i changed var==45 it is false so it is giving output as 32764 can anyone please explain why 32764
ASCII value of 'A' may be the answer.
65
Please upload console i/o functions
65 will be printed, since it is the decimal value of character A.
Please explain again condition operation
computer science 12tn lesson wise video in Tamil explain pls I am waiting
Answer is 65 , thank you so much for this lectures
Output: 65
💐💛
65 ans because 'A' will be stored in num and due to %d it will be printed in ascii encoding equivalent 65.
Thanks Sir
ASCII value of may be 10 also and 65 too. so why even after that 65 will be output
ASCII 1-31 are not assigned to anything. I presume you got confused by first image search result of Google. There the character assigned to 10 is empty. But what you have seen is just a representation of 10 in hex code.
65 or wot blissed lectures.....
int var = 75; declares and initializes an integer variable var with the value 75.
int var2 = 56; declares and initializes another integer variable var2 with the value 56.
int num; declares an integer variable num without initializing it.
Now, let's analyze the following line:
num = sizeof(var) ? (var2 > 23 ? ((var == 75) ? 'A' : 0) : 0) : 0;
This line uses nested conditional operators to assign a value to num based on several conditions:
sizeof(var) calculates the size of the var variable, which is 4 bytes (assuming a typical 32-bit system).
var2 > 23 checks if var2 is greater than 23, which is true because var2 is 56.
(var == 75) ? 'A' : 0 checks if var is equal to 75. If it is, it assigns the character 'A' to num; otherwise, it assigns 0.
So, the value of num will be 'A' because both sizeof(var) and var2 > 23 are true, and var is indeed equal to 75.
Finally, the code prints the value of num using printf, which will output 'A' as a character (ASCII value of 'A' is 65).
Therefore, the output of this code will be:
A
Ans of H.W:It will print 65 that means the o/p of code is 'A'
65 is a ASCII value of capital 'A'.
The ans is 65 i.e. Numerical equivalent of the letter A.
Explaination:
The first condition/expression will return the size of var which is ofcourse more than 0, and as we all know, any value other than 0 is said to be true, so hence, the next expression will get terminated, which is again true...
Bec var2 i.e. 56 > 23, thus the next expression will get terminated which i again true as we can see the value of var is 75,
So thus,
being true it will again terminate the true statement,
But this time, there is no condition and its just a letter 'A',
So as it being the last one of the conditions, the 'A' will get stored in num
And as we know,
("%d") prints numerical values, so even if we store alphabetical values, it will convert the alphabetical value to its Numerical equivalent according to the ASCII Table and thus we will be getting the output as 'A' i.e. 65.
Ans is A because all 3 statement is true and if true the ans is A.
But in printf it's %d which is integer and value of A is 65 in decimal so
Final ans = 65
ASCII value of A=65
what is the definition of tenary operator 3:28
Ofcourse
i did not understand the first fact (the only ternary operator) can you help me please
answer = 65 .... this is the decimal number parallel to "A" in ascii table.
Good morning 🙏 🌄
65 ASCII code of "A"
#solution
#include
int main()
{
int var=75,var2=56,num;
num=sizeof(var)?(var>23? ((var==75)?'A':0):0):0;
printf(" the num is :%d",num);
return 0;
}
output=65