Excellent job teaching this material. Im not sure what you qualifications are but you definitely taught it much better in my opinion than my college professor.
I have been flying through chemistry my whole year and this is the one thing that stumps me. I saw this video and I have been saved! Thank you so much!!
This was very helpful. I have a test tomorrow and this has made me feel much more confident. Now if only you can teach me EVERYTHING about thermodynamics, at least when it comes to chemistry **pulling my hair out** haha
sir i just want to thank you for saving my life and also for saving my career (soon) in gods plan. I am currently taking a chemical engineering degree and guess what, your videos are so much fun to learn and i learned so many things about chemistry. I hope u're in good shape and may the lord God bless you sir, thank you su much! - love from philippines!
The problem was that my instructor havent done a great job explaining that we can use M as a relationship with L as a conversion factor! so thank you for making it clear!!
i just failed a quiz on this and decided i needed some help from someone other than my teacher, found this and i think i get it! thank you! let's hope i remember how to do it on my final!
that is great video ! i gotta introduce to my friends. Yet, I have a Q. At 4:40, i thought that 0.3 M AlCl3 has a 5 L of solution so what i am thinking is 0.3 mol AICI3 / 5.0 L AICI (aq). Can you explain why it is 0.3 M AlCl3 per 1 L AlCl3 ?
ok so it's kind of late but, molarity (M) = moles / L (volume), so basically .30 moles AlCL3 / 1L (volume) = .30 M because M is moles over liter. IDK if this helps but if there is confusion feel free to ask. So to get to moles from M and L just multiply both. and get moles and do mole to mole ratio
AWESOME TEACHER 🏆🏆 You make the difficult concept so easy. Please could you make a video on finding the ph without using the calculator. The exam I am preparing for does not allow calculators. 🙏🙏
Hi, Wonderful explanation. Can you tell me how do you decide which chemical from the equation will become A and which one will become B while using the formula bridge. Is it that given is A and wanted is B?
The c1v1=c2v1 formula does not work because you are changing the compound, which means changing the amount of particles in a way that is different than a simple dilution. This is why the mole ratio is used. On the other hand it might work only if the coefficients (the mole ratio) are the same, giving a 1:1 ratio. Better to stick with the mole ratio.
chem final is in 8 hours, and my teacher has barely prepared me so here I am. Ill update with my exam score update: I failed the exam: I got a 18/50 :I
I'm not aware of removing any. The stoichiometry video is still up at th-cam.com/video/XnfATaoubzA/w-d-xo.html, limiting reactants is at th-cam.com/video/c11YBShZnmA/w-d-xo.html, and percent yield is at th-cam.com/video/L7NEeVY4-P0/w-d-xo.html. I also have mole conversions at th-cam.com/video/t1pjGbwqt9o/w-d-xo.html. Was there something else you are looking for?
You just saved me from completely failing a chemistry final. I wish you the best in life sir, and may god shine upon you.
William Milligan one year later when the online classes don’t teach it right
5 years later for the same reason 🤣
@@amayak_japrus 6 years now
7Years now
@@agentj1754 1 month as of me writing this until 8 years this video has saved chemistry students
Bless the person who made this vid 🙏
Excellent job teaching this material. Im not sure what you qualifications are but you definitely taught it much better in my opinion than my college professor.
Thanks! I'm a high school chemistry teacher in Evanston IL.
I dont think you understand how helpful this was for me
This is the best solution stoic video! Thank you
You made that so easy to understand! I think I learn more on TH-cam than I do in class. Thank you!
I have been flying through chemistry my whole year and this is the one thing that stumps me. I saw this video and I have been saved! Thank you so much!!
This was very helpful. I have a test tomorrow and this has made me feel much more confident. Now if only you can teach me EVERYTHING about thermodynamics, at least when it comes to chemistry **pulling my hair out** haha
I love the way you explaining chemistry ,you've made a clear picture to me thank you very much ,i really appreciate your help .
This is an excellent extension of stoichiometry. You saved my stoich test.
sir i just want to thank you for saving my life and also for saving my career (soon) in gods plan. I am currently taking a chemical engineering degree and guess what, your videos are so much fun to learn and i learned so many things about chemistry. I hope u're in good shape and may the lord God bless you sir, thank you su much! - love from philippines!
You explain it SO WELL - thank you! It just clicked and I was so stressed about chapter 12!
Thanks!
The problem was that my instructor havent done a great job explaining that we can use M as a relationship with L as a conversion factor! so thank you for making it clear!!
Thank you, I have been struggling to understand the concept of stoich and somehow made it this far, in this video, you made it clear so thanks : )
thank you sir!!!! this actually a very good videos
This is 100x better than Khan Academy
you made it easy to understand. Thank you so much.
Thank you so much!!! The fact that you tied this in with Biology really compelled me to actually like it!
10 years later, No Video can beat you🎉🎉🎉
Thanks! 🙂
You deserve all the goodness in the world. bless ur soul. thank you
i just failed a quiz on this and decided i needed some help from someone other than my teacher, found this and i think i get it! thank you! let's hope i remember how to do it on my final!
Thanks. Really appreciate your thoroughness.
Beautiful. Love the example problems.
I found this really helpful
I was scared when you said BYE!!! 😁😆
that is great video ! i gotta introduce to my friends. Yet, I have a Q. At 4:40, i thought that 0.3 M AlCl3 has a 5 L of solution so what i am thinking is 0.3 mol AICI3 / 5.0 L AICI (aq).
Can you explain why it is 0.3 M AlCl3 per 1 L AlCl3 ?
ok so it's kind of late but, molarity (M) = moles / L (volume), so basically .30 moles AlCL3 / 1L (volume) = .30 M because M is moles over liter. IDK if this helps but if there is confusion feel free to ask. So to get to moles from M and L just multiply both. and get moles and do mole to mole ratio
Great video with perfect examples and explanations!
AWESOME TEACHER 🏆🏆 You make the difficult concept so easy. Please could you make a video on finding the ph without using the calculator. The exam I am preparing for does not allow calculators. 🙏🙏
So helpful! I even went to tutoring @ my college and didn't help as much as this video. Thank you!
Hi, Wonderful explanation. Can you tell me how do you decide which chemical from the equation will become A and which one will become B while using the formula bridge. Is it that given is A and wanted is B?
Yes, A is given and B is wanted. Thanks for your comment!
You are such a blessing brother; thank you so very much!!!
So informative, thank you!!!!
I miss your class.
***** miss your video :D you save my exaM thanks body
For problem 1. Can we use c1v1=c2v2. If I use the dilution formulae I get a different answer since I am not using the mole ratio.
The c1v1=c2v1 formula does not work because you are changing the compound, which means changing the amount of particles in a way that is different than a simple dilution. This is why the mole ratio is used. On the other hand it might work only if the coefficients (the mole ratio) are the same, giving a 1:1 ratio. Better to stick with the mole ratio.
in this i cant understand the first problem why we should divide na2co3 M
Thanks big dog you make this stuff make sense
thank you, This is the best tutorial on stoi but i need help n
Amazing. thank you so much
Thank you. Thank you. Thank you. Thank you. Thank you. Thank you!!!!!!
It is a damn shame you not my chemistry teacher, maybe I would enjoy the topic if I could understand everything as easily as I understood this video.
ur a life saver.
for example 2, shouldn't the number of sig figs be 2?
Yes you are right, the answer should be 4.3 L due to the two sig figs of the 0.45 M FeCl2.
This has no sig figs?
chem final is in 8 hours, and my teacher has barely prepared me so here I am. Ill update with my exam score
update: I failed the exam: I got a 18/50 :I
How it went?
@@juandiegoquirosgomez9405 pretty sure I failed :( but I haven't gotten my score back yet so i'll comment when I get it
you are literally my homie 4L
😊
Why did you remove the other videos on stoichiometry?
I'm not aware of removing any. The stoichiometry video is still up at th-cam.com/video/XnfATaoubzA/w-d-xo.html, limiting reactants is at th-cam.com/video/c11YBShZnmA/w-d-xo.html, and percent yield is at th-cam.com/video/L7NEeVY4-P0/w-d-xo.html. I also have mole conversions at th-cam.com/video/t1pjGbwqt9o/w-d-xo.html. Was there something else you are looking for?
9:45. Where did "241.9 g Fe(NO3)3 over 1 mol" came from?
molar mass
life saver
bless you
I am pretty sure that your molar mass of Fe(NO3)3 is incorrect. Fe= 55.85 + N =14.01*3+ O = 16*6 = 198.88g Fe(NO3)3
There are 9 oxygens, not 6. Those details can be annoying! So my molar mass is correct. Thanks for checking.
isn't Al 26.98 g/mol, which would give us 4.34 L FeCl2 (rounded to 3 sig figs)
Yes. Since the volume of FeCl2 has only 3 sig figs, I rounded the Al mass to 3 sig figs. It does not matter, either way is correct.
@@CrashChemistryAcademy okay, thank you.
Pls make it easier
6:50
❤
like like like
ap chem really sucks
I love AP chem. Think about it. Chemistry is the basis for our entire lives.
@@aesarahypatia3482 yeah but it sucks tho