Lumabas sa Actual na Exam | Consecutive Numbers Fast Solving Techniques
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Pinaka madaling paraan.. any sum of consecutive number , divide by 3, the answer is the second number. The 1st number minus one lang sa answer then 3rd number plus one lang sa answer,
Sir paturooo po
Thank you sir nomo for the tips, it helps po tlga s amin and hope po makapasa n po ako this coming august 11, 2024, Godbless
Nice haist gets ko tlga pag ganito ang paliwanag❤
🎉not related on math but thanks sa Nomo, upon watching some reviewers nung gabi before the exam sa umaga, may nasagutan pa din ako na sure kasi yung question lumabas sa mismong exam 😅
Thank you po, Sir. Mabilis ko lang pong naintindihan. Sana po makapasa this August 11, 2024 CSE.
Same here insan
Nasagutan ko lahat yan nung Aug 20
i got it..thanks sir..sana pumasa na ako..
Madali lang pag may video pa guide but will see sa actual exam kung kaya ko pa din 😢
Thank you po dito Sir 🙌
Hays naway makapasa na po ako 🙏
May shortcut ako solution sa number 1 and 2. Una, idivide mo yung given numbers. Kung ano ang sagot don yun na ang gitna.
Yeheeyyyyyyy🎉
Thanks sir.. gets
Sir, fraction at percentage combination analogy po feature nyo. May ganoon po kc last August 20 exam. Thank you po
Did you remember the given problem?
Yung style ko po sa pag solve ng first 2 problems kanina is ni divide ko po sa 3 yung given #, tas Yung sagot po is nag plus 1 at minus lang po ako para macheck kung tama po yung Total nila sa given #,
Ex. Po 60/3= 20
20+1=21
20-1=19
& 21+20+19=60
Yung largest at smallest # po is 21 & 19..
Sir may may isa pa po na way. Pede rin po na yung 60 divide by 3 then yung answer 20 lalagay lang sa gitna yung 20 like ganito 19 20 21 so yung sagot 19 as smallest number. Pag kinuha yung sum nyan lalabas 60. 😊
Mas mabilis pa pala itong teknik na mo sir kaysa teknik na gamit ko haha. Maka change teknik na nga
maraming slamat po
Good morning po sir, pinahuli ko po sagutan yung math nong exam day, kse alam ko po ubos oras po yung pgsosolve ng math problems,sana po makapasa🙏
Sana pumasa ako 🙏❤️
hello sir nomo studio
Madali lang yan 60 divided by 3, is 20, so 20 ung middle , 19 smaller and 21 largest.
You just simply 231/2 the answer will be your median so 76 ,77,78....78 is the largest
Yan po mismo ang lumabas sa exam knina
Lumabas kahapon iyong number 3 question.
Pano po pag naging even number? Same procedure lang po divide 2?
sir yung part na what is the sum of all odd numbers between 4 and 20, is 96 yung sagot dun pero wala sa choices. 88 lang yung pinakamalapit na nasa choices kaya yun ang sinagot ko. wala kasing 96 sa choices
Sigurado po ba na naalala nyo ang tanong? Kasi 4+6+8+10+12+14+16+18 = 88. Baka yan hinahanap sa question?
@@nomostud odd numbers ang hinahanap sir kaya nag start ako 5 to 19 which is yang nasa video nyo pero pag tingin ko sa choices, 88 lang pinaka malaki kaya yung 88 na rin sinagot ko
Mas madali yan kung may choices na
Boss, may tanong ako. Paano kung ang question ay Find the sum of the odd consecutive numbers from 25 to 66?? Need pa ba mag add ng plus one?? Odd tsaka even number ang given
Find the sum of all the consecutive integers from60-90
paano naman sir kung find the sum of the odd consen 17 to 50?
paano po kapagka whole number lang?
sa Pro po ba to lumabas?
Yespo
hindi kupo napansin to.
hindi nmn odd yung 45 ah
odd ang 45. even ata mean mo
Don't put english title and then SPEAK THIRD WORLD!
Hello po new lang po Ako sa channel mo po and it really help me po...May question po sana Ako " The sum of three consecutive integers is 21. What are the integers?
21÷3 = 7
7 will be the 2nd interger
7-1 =6 will be the 1st interger
7+1=8 will be the 3rd interger
6,7,8 are the intergers
checking:
6 +7 + 8 = 21
21=21✓