Camgridge University Entrance Exam Tricks.✍️🖋️📘💙

[@raghvendrasingh1289]

Let x = y - 2
(y -2) (3y - 2) (3y+2) (y+2) = 16
(y^2 - 4)(9y^2 - 4) -16 = 0
9y^4 - 40 y^2 = 0
y = 0 ( double root) , 2√10/3 , - 2√10/3
x = - 2 ( double root) , 2√10/3 - 2 , -2√10/3 - 2

[@SidneiMV]

x = u - 2
(u - 2)(u + 2)(3u - 2)(3u + 2) = 16
(u² - 4)(9u² - 4) = 16
9u⁴ - 40u² + 16 = 16
u²(9u² - 40) = 0
u = 0 => x = -2
u² = 40/9 => u = ± (2√10)/3
*x = -2 ± (2√10)/3*

[@irenehartlmayr8369]

Its not " into " ITS " TIMES "..... when one wants to multiply ! INTO is used for DIVIDING one expression into another one !

[@superacademy247]

Point noted ✅

[@irenehartlmayr8369]

B is NOT pronounced as P !!...

[@superacademy247]

Merry Christmas 🎉🎄🌲

[@ChavoMysterio]

x(3x+4)(3x+8)(x+4)=16
(x²+4x)(9x²+36x+32)=16
(x²+4x)[9(x²+4x)+32]=16
Let y=x²+4x
y(9y+32)=16
9y²+32y=16
9y²+32y-16=0
9y²+36y-4y-16=0
9y(y+4)-4(y+4)=0
(9y-4)(y+4)=0
9y-4=0
9(x²+4x)-4=0
9x²+36x-4=0
9x²+36x+36=40
(3x+6)²=40
|3x+6|=2√10
3x+6=±2√10
3x=-6±2√10
x=-2±⅔√10 ❤❤
y+4=0
x²+4x+4=0
(x+2)²=0
x+2=0
x=-2 ❤