Bonus 2: Just make an unequal by striking the equal sign and the equation is correct (Doesn't make much sense, but it is correct - 101010 is not equal 9.5)
For "IX" question, I find another solution. You just fold the paper in such a way that cut IX in half horizontally, then you rotate the paper around and you'll get "VI" which is six, without even using the pen in the first place.
Not that side, the other side. when you fold it, you'll get "IV" on one side and "I^" on the other side. If you rotate the "I^" upside down, it became "VI".
to be perfectly honest, this was the solution I came up with because I misread the question thinking we were asked to do it without lifting the pen PERIOD.
two options for the second bonus riddle: put a slash through the equal sign to make it an inequality, or turn the second 1 into a T for "10 to 10," also known as 9:50 (or 9.50)
Riddle 7: The total volume of liquid is 119 L. That leaves a remainder of 2 when divided by 3. The volume of milk must be divisible by 3. So the barrel containing water is the one that leaves a remainder of 2 when divided by 3. That quickly shows you that the 20 L barrel is the one containing water.
There is an easier way to do this in your head - all numbers divisible by three have digits that add up to a multiple of three. When you add up all the digits on the barrels you get 38, which is 2 higher than 36 which is divisible by 3, so as the digits of 20 add up to 2, the 20l barrel must contain the water
6 barrels. 1 contains water, leaving 5 w/milk. The total liters of milk purchased for customer 1 must be double for customer 2. Customer 1 bought 33L (18+15), so customer 2 bought 66 (31+19+16). Leaving the water in the barrel w/ 20L...
I don't understand why the number of liters of milk needs to be divisible by 3. 1/3 l is also a valid measurement of volume. There was no restriction about whole numbers in the problem statement.
@@agfd5659 The number of litres of milk needs to be divisible by 3 because customer 1 bought twice as much milk as customer 2, so the total amount of milk must be a multiple of 3. There _was_ an implicit restriction about whole numbers because each barrel was specified as containing a whole number of litres of liquid. It's true that 1/3 is a valid measurement of volume, but 1/3 of a barrel is not a sensible container for any liquid. That's why we're working with a whole number of barrels and hence whole numbers of litres.
The 5th riddle has another way to solve it: The speeds say that for every 10 meters Alice runs, Bob runs 9. Alice has to run 110 meters, so divide that by her 10 meters, we get 11. We now have to multiply Bob’s 9 by 11, which means he runs 99 meters in the time it takes Alice to run 110. It’ll be close at that finish line.
I solved it using a roundabout way. I calculated the average number of meters based on time. Although the question did not tell me how long each runner took, I made up my own! I divided each by 100. So, that means Alice is running 1 Meter per time and Bob is running 0.9 Meters per time. With this in mind, I calculated how long each runner took to finish the race. The lower number took less time, meaning they won. I did this by dividing the total distance by their speed. Alice was given an extra 10 Meters to win. Thus, she took 110 amount of time to finish (110 / 1). Bob took 111.111111... amount of time (100 / 0.9). Alice took less time. Therefore, she wins!
@@tastywallet7992 I thought similar. If Alice runs 10m/s and Bob runs 9m/s, Alice runs 110 in 11 sec and Bob runs 100 in 11.1 sec. Therefore, Alice wins.
I simplified it. Figuring Alice would win unless she started 20 meters behind. If she was 10 meters ahead in the first race, then even if she started 10 meters behind, they would tie at 90 meters with 10 meters to go and she is still faster, so she would still win.
For the logic in the "Odd number of coins in 3 glasses" to work you would have to assume Glass A and Glass B are combined into one entity that would represent and odd amount of coins. With that in mind... it is no longer 3 glasses OR you have to admit Glass A still has an even amount while also holding Glass B, which DOES have an odd amount. Either way, you still have 2 separate glasses containing odd amounts with a 3rd glass containing an even amount. Putting Glass B into Glass A doesn't leave you with the results you asked for.
Not the way he did it, no. You put glass A into glass B, and then you put 5 coins in it. Put the other 5 coins in glass C. Now Glass A and Glass B each have (the same) 5 coins in them, and glass C has its own 5 coins.
This strays from math into philosophy of what constitutes a glass / glass containment space. You can stretch that even further and put any number of coins into any glass, as long as it is at least one. Then you can truthfully claim that each glass does contain an odd number of coins - the question did not specify that the _total_ amount of coins in the glass should be odd.
8:24 For the barrels, you can take a shortcut: 15+19+18+16+20+31=119 Which divided by 3 gives a remainder of 2 (117+2). That means that means that you only have to look at the barrel which is also yielding a remainder of 3. 15 and 18 have a remainder of 0 19 is 18+1 16 is 15+1 31 is 30+1 20 is 18+2 So, if we remove the barrel 20, the new sum will be a multiple of 3.
While this is the intended solution, The way it is set up you cannot know which barrel it is, Unless the 31 barrel is the one with water, As the first one can buy 5L and the second one 10L And then all you know is that 31L barrel is most likely 100% full.
even shorter, add all digits (1+5+1+9+1+8+.........) = 38, now greatest number disible by 3 is 36 so find a barrel whose digits add up to 2, which is 20.
#4: Take the top match. Bend it in the middle to make a right angle. Put it in the bottom-left corner to make a square when combined with the bottom and left matches.
another trick for last riddle. The total of all the barrels is 119, this is 2 mod 3. Thus to make the total milk divisible by 3 the single barrel of water must be 2 mod 3. The only barrel that is 2 mod 3 is 20. Thus the 20 barrel is the water.
We should also specify that customer must buy only full barrels. I did pretty much the same, but I considered remainders being 0,0,1,1,1,2. The only combination that yields divisibility is 0,0,1,1,1.
@@LOGICALLYYOURSbonus riddle 1 is kind of stupid because for writing six we have to lift pen, so they didn't researched properly, as there answer is wrong because we had to lift pen,
There's quite a few ways to solve this one. I "scratched out" the top half of th I and X. Then you turn the paper around and it leaves VI which is the Roman numeral for 6.
I know this isn't the way you probably WANT it, but for the final question I would put a straight diagonal line through the equal sign. You would end up with the "Not Equal Sign", signifying that these 2 sides of the equation are not equal, and then equation itself becomes true.
Pretty sure that is exactly the way to resolve it. The theme of the other riddles suggests that the final answer is not to correct the solutions to make them equal each other. It is a theme of unconventional conclusions. The glasses and coins, for example. Unconventional, but technically true. This was phrased specifically with the original statement that it is an unequal equation. The question is not to make it equal, but to make it correct, and only with a straight line. A diagonal line making the equals sign unequal would make the question correct in an unconventional way, matching the other riddles.
I figured he wanted to place one cup in another but I think that is technically wrong since there are still three cups and one of them has an even number of coins. Just because it jumped into another cup doesn’t make the cup non existent.
I thought the same. Couldn’t we just distribute a value of 0 to one of the cups? You can then put any odd combination of coins into the remaining 2 cups without “cheating”.
If one cup contains another cup, it also contains the contents of that cup. So if it has 4 originally, and the cup added has 3, then the cup holding another cup now has 7, whereas the top cup still has 3.
You have to put the even number (4) of coins in the lower/outer cup, and the odd (3)in the inner cup. Since the coins in the inner cup are also now in the lower/outer cup, the cup now has an odd number (7) but the inner still only has 3. If you put the odd on bottom, the lower/outer would have 7, but the inner would still only have 4. Does that make more sense?
Bonus Riddle 2: drawing a line on top of the middle | makes the equation: 10 TO 10 = 9.50 So the equation is telling you the time. Also because these comments frustrated me after reading 50+ of them: Any (good or decent) riddles NEVER have the answer to "just make it not equals to".
@@davidjones-vx9ju well thats why the riddle is better with matchsticks because you rip off the tip to make 9:50 and add the dot. Either way the "is not equals to" hurr durr would render ALL equation puzzles absolutely meaningless.
For the milk and water barrels riddle, there was no need to add up each combination if you were too lazy to do so. Just look at the remainders when divided by 3. I was too lazy to add them.
I did the same too. Totally 119L from all six barrels and the remainder is 3, so I look for the barrel in which the volume has a remainder of 2 as well.
I added all six barrels to 119 in my head, then subtracted each number one by one until a remainder was divisible by 3. Tried 19 first and knew that 100/3 wasnt a whole number, thought of 99 and saw the number 20 next. 2 trial and errors and got it.
I solved this one by calling "time out", fast forwarding the video a little bit to get the answer, then rewinding it again and declaring "okay GO". It was pretty much a sure win for me after that.
5:02 mathematical proof: lets say the race took 10 seconds Alice walks 100/10=10m/s Bob walks 90/10=9m/s Alice having to walk 110m will take 11 seconds Bob having to walk 100m will take 100/9 (11.111) seconds Alice still wins.
Bob is trolling Alice. He is running slower than normal. Since Alice will be more tired to run farther and Bob is actually faster than what he was in the first race, he wins.
In Riddle 5, the assumption is that a 100m racer can also win a 2000m race! When you increase the distance, there could be other factors, maybe Alice has stamina only good for a 100m race, and when asked to run for another 10m, she lags behind to her competitor.
Yep, that was my solution, too! He didn't say it was a vertical or horizontal line, just a straight line. The slash mark across the equal sign qualifies as a straight line.
U dont have to chek every barrel on riddle 7.. just add all the numbers.. and see how much it is more or less by a nearby number which is divisible by 3.. then chek which barrel's number has the same difference with it's nearby number divisible by 3..
@@raviprema6176 Just add all the numbers and compare with the divisible formula of 3. i.e. add all the digits of the number and test what should be substracted to make it divisible by 3.
10 TO 10 = 9:50 If there are 10 minutes to (‘till’) 10 o’clock, it means its 9:50. However, 9.50 really means 9 and a half, or 9:30, so the riddle is messy.
For the coin puzzle: put 5 in 1st glass, 5 in 2nd glass, none in third. Then tell the person giving test "WOW, no coins in the last glass, that sure sounds *odd* to me, huh?"
@@MrJinglejanglejingle I agree, but it states there needs to be coins in each glass. You could just break the 3rd glass and problem solved. Or, Put two glasses to lip, tilted on their side with one coin straddling two glasses. Now you have 2 glasses with a half coin in each.
The old answer to the riddle that involved placing an odd number of coins in three glasses was to put three in one glass, seven in a second glass, and zero in the third glass. 3 and 7 are odd numbers, and the fact that zero is the only number that is neither positive nor negative also makes it quite an odd number. Outside the box thinking, right?
Riddle 5 is actually undecidable because it is not stated that Alice and Bob run at constant speeds. It might be that Alice accelerates so much faster that she gets for example a 20 m headstart by the time she reaches 70 m, but Bob has reached his top speed at that point and starts catching up and is only 10 m behind when Alice crosses 100 m line. In this scenario, they would again be at 90 m at the same time in the second race, but Bob would be 2.5 m ahead at the finish line. Moreover, it is assumed that Alice can run the extra 10 m without slowing down, but as people have limited stamina, that is not necessarily the case.
Riddle 2 is a sequence of numbers combined with their reflections. Any finite sequence of numbers can be generated by a polynomial rule, i.e. a pattern. This means that the last picture can be any number combined with its reflection. Riddle 4: partially break one of the matches so that its bottom faces up. The bottom is shaped like a perfect square. Riddle 5: we can only conclude that Alice's *average* speed is greater than Bob's, in the amount of time it takes Alice to run 100m. It is possible for either Alice *or* Bob to win the race if Alice starts 10m behind. This can be visualized graphically. Bonus riddle 2: define a notation in which three numbers, a, b, and c, are written next to each other and a giant curly brace is drawn under them. Then define that expression to equal 9.50, or anything that makes it equal 9.50 using 10, 10, and 10. Then the solution is to draw a curly brace below the three 10s.
For the matchsticks, you could also take any of them, break it exactly in half and line up the two pieces with one of the remaining 90 degree angles to make the perfect square. Rule said move one matchstick, not make one move. :)
This is not a solution. You must solve the riddle by "moving just one matchstick," not by "breaking and moving just one matchstick." Moving is the only permitted action.
In the bonus question, it is asked to subtract 3 from IX without lifting the pen. So, I can simply write 6 (substracted product) in front of it, which can be done without lifting the pen. It was never mentioned that we have to make change in the existing text.
For question 7, just add the total of all the barrels (119) and subtraction each barrel.If the remaining quantity is divisible by 3 then the subtracted barrel is the milk. If you minus 119-20=99 , 99 is divisible by 3 hence the answer is 20.
Actually in the bonus riddle how could we write S without lifting the pen? So I think, folding the paper vertically and cutting it will be the perfect answer. So that we'll get VI.
@@tanujgarg792 You're free to make that conclusion, but if you get called for it don't blame people being accurate, blame the people with the poor wording choices that should've borrowed vocabulary and use stroke instead, because you certainly do lift a pen to make that s.
"Without lifting the pen." "Without lifting the pen FROM THE PAPER." Two different statements. The illustration shows that the pen is initially next to the paper, NOT on it. You can lift the pen without violating the rules of the challenge, just not after it touches the paper. The wording in the video is fine.
@@joemanco8002 So in theory, you could write a whole sentence by writing a letter, laying the pen without lifting from the paper, roll the pen and write another letter making sure not losing contact eith the paper
I take issue with a lot of these "riddles" as well as some cognitive tests where not all of the information is given or there are red herrings, tricks, or just plain unusual wording. Then people solve the problem by "thinking outside the box" which just means changing the constraints of the problem to match your solution. For instance. The coins question is also true if you have any negative amount of coins. The coins and glasses question is true if you distribute the coins as 7-3-0. In my mind, riddles and other cognitive tests should have one definitive solution with all information present and clear in the problem statement. If anything is left up to interpretation, then the answer becomes subjective.
Haha. I agree. The first test stated you have coins. Yet the answer was zero. If you are told you have something, you cannot take it away to fit your narrative
I also came up with that same solution BUT it did say you had to have coins in ALL the glasses too, so having one glass empty would of broke that rule. :(
@@mr.knight8967 It also doesn't say they ran at constant speed. Alice might only be able to run 105m, initially fast before stopping, while Bob can run steadily, so Bob wins.
@@fununlimited4738 So what? In the video they assume as word IX instead of the roman numeral. Its all about how you interpret it. If that answer is correct, this is too.
@@hotshot0079 right , as this question can also be solved by folding the paper from centre of "IX " and placing it upside down,which will give us Roman number "IV" i.e, 6
3:00 couldn’t you also flip A and B on their side and put 5 in C so they have a slight slope then balance coin in the middle It would be in Both at once making it 2 in A 2 in B and 1 in both
4:22 "if you face this riddle in an interview".. .. stand up, and say goodbye, as no one should want to work any companies which gives this riddle for a potential employees. Except if you want the HR position and save the company :)
For the bonus riddle you can also write a 6 after IX which makes it look like 1x6 which is 6. Also for the matches to make a perfect square there is a third way. Some people write 4 differently so the slanted line is vertical making 3 solutions to the problem.
9.50 is acceptable as 9:50 in some countries (I guess). The proper solution will be put a slanting line on equal to sign making it != (not equal to sign).
The solution to #3 (coins in glasses) was kind of silly. If you can go that far into the ozone for an answer, then you might as well allow this solution, "Poke a hole through the bottom of one of the glasses (nobody said it wasn't plastic). Put 3 coins in each of the two undamaged glasses and 4 coins in the 3rd glass (with the hole poked in it). Shake the coins around in the 3rd glass until one of them falls through the bottom. Technically, you still "Placed 10 coins into 3 glasses" ... and now, "each glass contains an odd number of coins."
How about this - Put 11 coins into each glass. Each glass contains and odd number, plus you technically put 10 coins in each glass. The problem is poorly worded.
2:20 For any who know the basics of math, there is no summation of odd odd numbers that can make an even number. So for me I gave it a very little try then directly skipped to the answer. And by your answer if we considered the two cups as a one cup, then you just filled 2 cups not three.
Exactly. My first solution was 5 in one cup, and 5 in another. Did it really say you had to use all 3? To me their answer is no better and less elegant then 5 and 5...
Solution @ 8:30 involves heavy calculations, using divisibility rule for 3 : (sum of digits) mod 3 = 0 helps. Numbers which are divisible by 3 (i.e 15, 18) are definitely not included. From the rest, 19, 16, 31 are of form 3k+1 and 20 is 3k+2 to take out one, from these 20 is the only solution.
8:50 rotate the paper 180 degrees, fold 25% paper from the south of the paper. It will show half of the content written in the middle of the paper. Which makes it look VI
About the perfect square, the matchstick you remove to form the number 4 can be also broken forming an L shape and place its 90* angle mirroring one of the 2 existing 90* angles courtesy of the 3 remaining matchsticks T-shape intersection
The fourth riddle has a third solution. You can take the matchstick you take for forming the 4 and put it on the one on the left to form a "filled" square.
There is another way to answer the "coins" question at the beginning. The main premise is to ask how many coins you have. The part about saying "only one statement is true" is a clue. If #1 is true without the others being stated, you cannot definitively say how many you have. It would be the same with #3 if looked at by itself; you cannot definitively say how many coins exist. #2 is almost the same way until shown with the other 2 statements and given the clue; there's a definitive choice: 0. If #2 is true, then #1 is false. As such, you can give a definite answer to the basic question. In this way, the clue is merely an indicator to say how many. Standing alone, #2 doesn't have an infinite number of answers; it only has 4. As such, you can guess that it's the true statement without comparing it to the other two.
That wasn't really clear but I think it meant not to be lifted from the paper ONCE YOU STARTED WRITING. You would have to lift it from the paper to write.
My idea was to cover the half part of the x by tape and rotate the paper so it looked like VI.because I thought u can't lift the pen.I miss the part from the paper
Bonus riddle 2: Since there is no sign between the terms on the left, I assume they are one number, so 101010. Since that is not equal to 9.50 however, I place a diagonal line through the = sign, making it an unequal sign. This way the equation is correct, since 101010 is not equal to 9.50
I disagree with the "solution" to riddle 3. If you place glass b inside glass a, you still have 4 coins in glass a. glass just contains 4 coins plus another glass with 3 coins. You can't ignore glass a and combine the coins together because you put glass b in glass a. The original question says "each glass contains an odd number of coins". Glass a still contains an even number of coins.
@@ElProf except the definition of in a glass is different from in a bag or in a safe, A bag can be completely inside a bag of equal size and volume, a glass by definition cannot. Is a safe really in a bag if you can only see the zipper poke out from under it?
For the second one, another interesting solution would be to place the three glasses in an equilateral triangle type formation. Three coins in each glass, and the last coin in the center of the formation, just so that a third of the coin rests on a section of each glass's rim. But that is only viable if you don't care about whether the number is whole or not.
I have 1 question. It's been bothering me. It is about the 10 coins to be put in 3 glasses. There 3 separate glasses. There are 10 coins. You've put 3 coins each until you have add 1 coin in glass A. That does not match the requirements because glass A has even total of coins which is 4. Then, you've joined glass A and glass B so that it will have a total of 7 coins. But is that against such term? 'Coz if you put glass B into Glass A, it is still the same. Glass A has 4 coins and Glass B has 3 coins. The 4 coins are still inside the glass A and the 3 coins still in glass B. However, glass B is inside glass A. So, the statement now is wrong. There are 3 glasses which to be filled with odd counts of coins ( IT BECOMES 2 GLASSES ONLY ACCORDING TO WHAT YOU DID). I am not judging what you did. Please enlighten me. Thank you
Maybe think of it more as a subset? Set A (which contains subset B) has a total of 7 coins, subset B (which is a set on its own) has 3 coins, and set C also has three. The fact that the glass is in another glass doesn't mean it doesn't exist anymore I thought it was weird too, but a creative solution!
9:25 When you read and translate automatically in your native language and think for like 5 mins and just give up and then this solution appeared and you feel like a dumbass because in your language 6 is also spelled "six" :')
Glasses riddle: Each glass demands that each individual glass contain coins NOT two (A+B) stacked together to become A. Glasses must remain separated !
For the cups it seems better to solve it by placing 10 coins into three glasses and then taking one coin out to make that glass odd. I still fulfilled the rules because a total of 10 coins were placed and now each contain an odd number of coins. Rules didn't say anything about not being able to take coins out, and it didn't say that the total number of coins that the 3 glasses contain must equal ten. Okay so maybe I'm going too extreme with the interpretation but hey its fun.
I mean given the solution is to put a glass inside another glass I'd buy it. Honestly the given solution already feels like its against the spirit of the question.
Bonus Riddle #1: There's a big mistake there, how can I write "S" if I can't lift the pen? My solution would be covering the upper half of the IX with the pen, and then turning the paper upside down, would show VI, which is six in roman. Your solution failed.
The riddle said lift the pen "from the paper", not lift the pen at all. That implies that you can lift the pen but once you start writing you can no longer lift it. that said, I do like your solution.
riddle 6 has a lot of answers... 1. The girl would technically have been 10 on her 11th birthday (only for a few hours, maybe, but still). It would then be true that she would be 12 the next year on her birthday. 2. Her birthday is February 29th, and her 11th birthday was technically missed. 3. The answer that was given
Bonus 2: Just make an unequal by striking the equal sign and the equation is correct (Doesn't make much sense, but it is correct - 101010 is not equal 9.5)
You mean ≠? That's what I came up with.
🙏🏼🙏🏼🙏🏼
I found that too
That is not an equation
@@pf.simoes what makes a mathematical expression an equation? Is it the truth of the statement or the equality sign?
Since i cannot lift the pen, i added "6" after "IX"
Assuming it would give me 1x6.
Wow this one works too
me too I did the same
In last reddil we can applie a straight line on equal to and its becam in equal anf ans became right
Me too
i just wrote the number 6 seperately
9:50 simply draw "/" over the "=" to make it not equal
darknight came here for this. Correct.
Exactly what i was gonna comment
Also my initial thought.
Thats not a straight line its a slanting line
He said equation, not an inequality.Read the question properly.
bonus riddle 1: i solved it by scribbling out the top half of the IX and turning the paper 180 degrees giving you VI, or 6.
I just wanted to fold the paper and rotate. This works even without the pen :)
Glad someone else thinks the same way !
I see I’m not the only one with a slightly off thought process
Same y'all
Same
For "IX" question, I find another solution. You just fold the paper in such a way that cut IX in half horizontally, then you rotate the paper around and you'll get "VI" which is six, without even using the pen in the first place.
if you do that, then you will get "٨I", which is not "VI"
Not that side, the other side.
when you fold it, you'll get "IV" on one side and "I^" on the other side.
If you rotate the "I^" upside down, it became "VI".
@@Kairikey I thought the same thing... Our answer is more creative :)
Yeah I was going to say just use the pen to cross out the top of the IX and then rotated to find a smaller VI.
to be perfectly honest, this was the solution I came up with because I misread the question thinking we were asked to do it without lifting the pen PERIOD.
Add a straight line on second 1st digit of second 10 i.e, on 1 now it becomes 10 T0 10 = 9:50 (Showing time)
???
@jatin balani it's time
@@manirajchakinarapu2166 oooo got it thanks
Just change the equal to sign (=) to not-equal to sign...it works..
Strike the equals sign to make it not equal to
two options for the second bonus riddle: put a slash through the equal sign to make it an inequality, or turn the second 1 into a T for "10 to 10," also known as 9:50 (or 9.50)
nice😂
We are supposed to place one straight line that's all... No turns or movements allowed
@@badrinathgaming636 thats what he meant bruh putting slash over the middle 1 will make it T
@@saddamsheikh207 Yes thanks for informing
clever!
Riddle 7: The total volume of liquid is 119 L. That leaves a remainder of 2 when divided by 3. The volume of milk must be divisible by 3. So the barrel containing water is the one that leaves a remainder of 2 when divided by 3. That quickly shows you that the 20 L barrel is the one containing water.
Brilliant
There is an easier way to do this in your head - all numbers divisible by three have digits that add up to a multiple of three. When you add up all the digits on the barrels you get 38, which is 2 higher than 36 which is divisible by 3, so as the digits of 20 add up to 2, the 20l barrel must contain the water
6 barrels. 1 contains water, leaving 5 w/milk. The total liters of milk purchased for customer 1 must be double for customer 2. Customer 1 bought 33L (18+15), so customer 2 bought 66 (31+19+16). Leaving the water in the barrel w/ 20L...
I don't understand why the number of liters of milk needs to be divisible by 3. 1/3 l is also a valid measurement of volume. There was no restriction about whole numbers in the problem statement.
@@agfd5659 The number of litres of milk needs to be divisible by 3 because customer 1 bought twice as much milk as customer 2, so the total amount of milk must be a multiple of 3.
There _was_ an implicit restriction about whole numbers because each barrel was specified as containing a whole number of litres of liquid. It's true that 1/3 is a valid measurement of volume, but 1/3 of a barrel is not a sensible container for any liquid. That's why we're working with a whole number of barrels and hence whole numbers of litres.
With the final problem, just have a really thick line covering the problem. It automatically works
The 5th riddle has another way to solve it:
The speeds say that for every 10 meters Alice runs, Bob runs 9. Alice has to run 110 meters, so divide that by her 10 meters, we get 11. We now have to multiply Bob’s 9 by 11, which means he runs 99 meters in the time it takes Alice to run 110. It’ll be close at that finish line.
That is how I got the correct answer as well!
I solved it using a roundabout way. I calculated the average number of meters based on time. Although the question did not tell me how long each runner took, I made up my own! I divided each by 100. So, that means Alice is running 1 Meter per time and Bob is running 0.9 Meters per time.
With this in mind, I calculated how long each runner took to finish the race. The lower number took less time, meaning they won. I did this by dividing the total distance by their speed. Alice was given an extra 10 Meters to win. Thus, she took 110 amount of time to finish (110 / 1). Bob took 111.111111... amount of time (100 / 0.9). Alice took less time. Therefore, she wins!
@@tastywallet7992 I thought similar. If Alice runs 10m/s and Bob runs 9m/s, Alice runs 110 in 11 sec and Bob runs 100 in 11.1 sec. Therefore, Alice wins.
exactly simple 100 = 90 is 10=9 so 110 =99 Alice wins
I simplified it. Figuring Alice would win unless she started 20 meters behind. If she was 10 meters ahead in the first race, then even if she started 10 meters behind, they would tie at 90 meters with 10 meters to go and she is still faster, so she would still win.
9:10 i can do that without using a pen
Just fold the paper so that it divides IX equally ( like this -IX- ) and flip the book upside down
Seriously good 👌👍
Or use a pen to scratch over the top half and then turn the paper round.
In some countries the decimal digit are separated by a "," not by the dot.
I did the same at first as well
Thats what I was about to comment... Except I'm gonna flip it from the side of tape...
Regarding bonus riddle: simple folding the paper in half and viewing it upside down makes it V| : which is six in roman
It is glued to the table.
Fold also the table then
@@greedisgood902 I also thought that
@@greedisgood902 “It is glued to the house”
Fold the flippin house then.
@@verlax8956 it is taped to your computer screen
For the logic in the "Odd number of coins in 3 glasses" to work you would have to assume Glass A and Glass B are combined into one entity that would represent and odd amount of coins. With that in mind... it is no longer 3 glasses OR you have to admit Glass A still has an even amount while also holding Glass B, which DOES have an odd amount. Either way, you still have 2 separate glasses containing odd amounts with a 3rd glass containing an even amount. Putting Glass B into Glass A doesn't leave you with the results you asked for.
THANK YOU! That solution was so stupid
Thought same thing !!!
I agree. Not a good solution...
Not the way he did it, no. You put glass A into glass B, and then you put 5 coins in it. Put the other 5 coins in glass C. Now Glass A and Glass B each have (the same) 5 coins in them, and glass C has its own 5 coins.
This strays from math into philosophy of what constitutes a glass / glass containment space.
You can stretch that even further and put any number of coins into any glass, as long as it is at least one. Then you can truthfully claim that each glass does contain an odd number of coins - the question did not specify that the _total_ amount of coins in the glass should be odd.
8:24
For the barrels, you can take a shortcut:
15+19+18+16+20+31=119
Which divided by 3 gives a remainder of 2 (117+2).
That means that means that you only have to look at the barrel which is also yielding a remainder of 3.
15 and 18 have a remainder of 0
19 is 18+1
16 is 15+1
31 is 30+1
20 is 18+2
So, if we remove the barrel 20, the new sum will be a multiple of 3.
easier shortcut. see only 3 residuals and you get
0 1
0 1
2 1
total is 5 equals 2 in residuals.
While this is the intended solution,
The way it is set up you cannot know which barrel it is,
Unless the 31 barrel is the one with water,
As the first one can buy 5L and the second one 10L
And then all you know is that 31L barrel is most likely 100% full.
even shorter, add all digits (1+5+1+9+1+8+.........) = 38, now greatest number disible by 3 is 36 so find a barrel whose digits add up to 2, which is 20.
it all assumes milk is only sold in integer number of litres.
#4: Take the top match. Bend it in the middle to make a right angle. Put it in the bottom-left corner to make a square when combined with the bottom and left matches.
Bend all of the matches and make a swastika
Good one. Also, take any match. Strike it. Use the flame or ash to draw a square.
That brings us to 4 possible solutions.
another trick for last riddle. The total of all the barrels is 119, this is 2 mod 3. Thus to make the total milk divisible by 3 the single barrel of water must be 2 mod 3. The only barrel that is 2 mod 3 is 20. Thus the 20 barrel is the water.
Thanks Daniel for your valuable comment. Your approach is really optimal.
We should also specify that customer must buy only full barrels. I did pretty much the same, but I considered remainders being 0,0,1,1,1,2. The only combination that yields divisibility is 0,0,1,1,1.
Yep, this is it
@@LOGICALLYYOURSbonus riddle 1 is kind of stupid because for writing six we have to lift pen, so they didn't researched properly, as there answer is wrong because we had to lift pen,
What do u mean by 2 mod 3?
For turning IX into 3 less than 9. Write 6 after the "IX" so it becomes an equation. 1X6=6, being 3 less than 9.
i can do it with out even touching the pen
There's quite a few ways to solve this one. I "scratched out" the top half of th I and X. Then you turn the paper around and it leaves VI which is the Roman numeral for 6.
You can't lift the pen, for this you need to lift the pen
I know this isn't the way you probably WANT it, but for the final question I would put a straight diagonal line through the equal sign. You would end up with the "Not Equal Sign", signifying that these 2 sides of the equation are not equal, and then equation itself becomes true.
Pretty sure that is exactly the way to resolve it. The theme of the other riddles suggests that the final answer is not to correct the solutions to make them equal each other. It is a theme of unconventional conclusions.
The glasses and coins, for example. Unconventional, but technically true.
This was phrased specifically with the original statement that it is an unequal equation. The question is not to make it equal, but to make it correct, and only with a straight line.
A diagonal line making the equals sign unequal would make the question correct in an unconventional way, matching the other riddles.
That’s how I solved it. It’s correct. I guess there could be another solution but I gave up searching for it after a few minutes.
I figured he wanted to place one cup in another but I think that is technically wrong since there are still three cups and one of them has an even number of coins. Just because it jumped into another cup doesn’t make the cup non existent.
Of course, the question isn't strict. A cup with 4 coins also contains 3 coins. Like the riddle asking how many months have 28 days.
I thought the same. Couldn’t we just distribute a value of 0 to one of the cups?
You can then put any odd combination of coins into the remaining 2 cups without “cheating”.
@@Cmeigs017 0 is considered even, not odd. (Putting 0 was my first guess too)
If one cup contains another cup, it also contains the contents of that cup. So if it has 4 originally, and the cup added has 3, then the cup holding another cup now has 7, whereas the top cup still has 3.
You have to put the even number (4) of coins in the lower/outer cup, and the odd (3)in the inner cup. Since the coins in the inner cup are also now in the lower/outer cup, the cup now has an odd number (7) but the inner still only has 3. If you put the odd on bottom, the lower/outer would have 7, but the inner would still only have 4. Does that make more sense?
Bonus Riddle 2: drawing a line on top of the middle | makes the equation:
10 TO 10 = 9.50
So the equation is telling you the time.
Also because these comments frustrated me after reading 50+ of them:
Any (good or decent) riddles NEVER have the answer to "just make it not equals to".
Yes, but this is an ambiguity of the problem and a perfectly valid solution because the problem was not clear on what it wants.
time is not expressed that way
@@davidjones-vx9ju well thats why the riddle is better with matchsticks because you rip off the tip to make 9:50 and add the dot.
Either way the "is not equals to" hurr durr would render ALL equation puzzles absolutely meaningless.
4:20 I have a 3rd solution: Take (move) 1 matchstick, break it in to 4 pieces and make a square. Question doesn't say "don't break the sticks".
Question also doesn't say that you can break it.. You can just move it.. Nothing more than tha..
For the milk and water barrels riddle, there was no need to add up each combination if you were too lazy to do so. Just look at the remainders when divided by 3. I was too lazy to add them.
I saw that 15 + 16 didn't work as the smaller purchase so I tried 15 + 18
I did the same too. Totally 119L from all six barrels and the remainder is 3, so I look for the barrel in which the volume has a remainder of 2 as well.
Lol
I just removed 15 and 18 coz they were already divisible by 3, then added rest to confirm
I added all six barrels to 119 in my head, then subtracted each number one by one until a remainder was divisible by 3. Tried 19 first and knew that 100/3 wasnt a whole number, thought of 99 and saw the number 20 next. 2 trial and errors and got it.
I solved this one by calling "time out", fast forwarding the video a little bit to get the answer, then rewinding it again and declaring "okay GO". It was pretty much a sure win for me after that.
5:02 mathematical proof:
lets say the race took 10 seconds
Alice walks 100/10=10m/s
Bob walks 90/10=9m/s
Alice having to walk 110m will take 11 seconds
Bob having to walk 100m will take 100/9 (11.111) seconds
Alice still wins.
You don't know who wins, since running is typically much more complex than constant speed.
you dont need to assume any time: bob run only 9/10 of what alice does, so when she runs 110m he does only 99m
Bob is trolling Alice. He is running slower than normal. Since Alice will be more tired to run farther and Bob is actually faster than what he was in the first race, he wins.
In Riddle 5, the assumption is that a 100m racer can also win a 2000m race! When you increase the distance, there could be other factors, maybe Alice has stamina only good for a 100m race, and when asked to run for another 10m, she lags behind to her competitor.
This would be true in a fair race but Alice was taking steroids
Alice was also a horse, and Bob gave up and just took a bus.
Bonus #2 you can also just change the "equals" to "does not equal" symbol by drawing an angled line through it.
It's not equation though...
Add the line on the equal to sign, so the equation will be 10 10 10 is not = 9.50
Yep, that was my solution, too! He didn't say it was a vertical or horizontal line, just a straight line. The slash mark across the equal sign qualifies as a straight line.
That's what I do for every matchstick problem 😂😂😂
Lets call this room a backbenchers club.. Count me in
Then it wouldn't be an equation, it becomes an inequality
U dont have to chek every barrel on riddle 7.. just add all the numbers.. and see how much it is more or less by a nearby number which is divisible by 3.. then chek which barrel's number has the same difference with it's nearby number divisible by 3..
That's perfect Shuvam.
Can u please explain me in a easiest way..... Sorry I couldn't understand and I want to know to know which difference u r specifing@shuvam kumar
@@raviprema6176 Just add all the numbers and compare with the divisible formula of 3. i.e. add all the digits of the number and test what should be substracted to make it divisible by 3.
@@raviprema6176 all addition=119
adding digits=11
Now to make it divisible we must substract 2. Ie addition of digits 20L. Barrel😇😇
@@atb3569 thank you
10 TO 10 = 9:50
If there are 10 minutes to (‘till’) 10 o’clock, it means its 9:50.
However, 9.50 really means 9 and a half, or 9:30, so the riddle is messy.
See my solution it will Amaze you
For the coin puzzle: put 5 in 1st glass, 5 in 2nd glass, none in third. Then tell the person giving test "WOW, no coins in the last glass, that sure sounds *odd* to me, huh?"
I went with 9 in the 1st Glass, 1 in the 2nd Glass, and None in the 3rd.
@@MrJinglejanglejingle I agree, but it states there needs to be coins in each glass. You could just break the 3rd glass and problem solved. Or, Put two glasses to lip, tilted on their side with one coin straddling two glasses. Now you have 2 glasses with a half coin in each.
9:50 Coincidentally 9.50 can mean 9h50m (just like the time stamp) so I0 I0 I0 will be I0 T0 I0 (ten to ten) which is 9h50
9.50 is NOT ten minutes before ten o clock. 9:50 is, but 9.5 is not
@@marvinkitfox3386 you gotta think out of the box, if they just give you 9:50 instead of 9.50 how is that even a riddle?
@@marvinkitfox3386 It is in the U.K.
@@MrOverdrive500 Nope. In UK, you could have "9.50 am" or "9.50pm" or "9:50" or "21:50"...
but never "9.50" with no further info.
Bonus riddle : I think we can write 6 after the X so that it will be 1×6 = 6 which is the correct answer
By adding a horizontal line on top of the one on middle 10. So the answer will be 10 To 10 which is another way of saying the time 9:50
👍🏼
The old answer to the riddle that involved placing an odd number of coins in three glasses was to put three in one glass, seven in a second glass, and zero in the third glass. 3 and 7 are odd numbers, and the fact that zero is the only number that is neither positive nor negative also makes it quite an odd number. Outside the box thinking, right?
0 is considered as an even no.
@@garimagarg9909 You didn't get it. :/
For the bonus riddle 2
Draw one line across the =
Riddle 5 is actually undecidable because it is not stated that Alice and Bob run at constant speeds. It might be that Alice accelerates so much faster that she gets for example a 20 m headstart by the time she reaches 70 m, but Bob has reached his top speed at that point and starts catching up and is only 10 m behind when Alice crosses 100 m line. In this scenario, they would again be at 90 m at the same time in the second race, but Bob would be 2.5 m ahead at the finish line.
Moreover, it is assumed that Alice can run the extra 10 m without slowing down, but as people have limited stamina, that is not necessarily the case.
Riddle 2 is a sequence of numbers combined with their reflections. Any finite sequence of numbers can be generated by a polynomial rule, i.e. a pattern. This means that the last picture can be any number combined with its reflection.
Riddle 4: partially break one of the matches so that its bottom faces up. The bottom is shaped like a perfect square.
Riddle 5: we can only conclude that Alice's *average* speed is greater than Bob's, in the amount of time it takes Alice to run 100m. It is possible for either Alice *or* Bob to win the race if Alice starts 10m behind. This can be visualized graphically.
Bonus riddle 2: define a notation in which three numbers, a, b, and c, are written next to each other and a giant curly brace is drawn under them. Then define that expression to equal 9.50, or anything that makes it equal 9.50 using 10, 10, and 10. Then the solution is to draw a curly brace below the three 10s.
For bonus riddle 2, I just drew a line through the equal sign. So this is what I had envisioned in my head: 10 10 10 ≠ 9.50
@@phrog9186 Because of the way the riddle is set up,
That answer is more correct than the intended answer
For the matchsticks, you could also take any of them, break it exactly in half and line up the two pieces with one of the remaining 90 degree angles to make the perfect square. Rule said move one matchstick, not make one move. :)
Woudnt necessarily need to be exactly in half you could measure and have one half snapped perpendicular to the other
This is not a solution. You must solve the riddle by "moving just one matchstick," not by "breaking and moving just one matchstick." Moving is the only permitted action.
@@macklindsey4541 i move half of this matchstick
Alternatively, pick up any matchstick, strike it, blow/wave it out, and draw with the ash.
Bonus was goofy. I just wrote a 6. Miss the Perfect Square "4". Got the rest. Thx for the fun.
4 is a perfect square (2 x 2 = 4 ) grade 9 algebra.
In the bonus question, it is asked to subtract 3 from IX without lifting the pen. So, I can simply write 6 (substracted product) in front of it, which can be done without lifting the pen. It was never mentioned that we have to make change in the existing text.
Adding the English letter "S" to a Roman Numeral expressed number does not change the value.
For question 7, just add the total of all the barrels (119) and subtraction each barrel.If the remaining quantity is divisible by 3 then the subtracted barrel is the milk. If you minus 119-20=99 , 99 is divisible by 3 hence the answer is 20.
Actually in the bonus riddle how could we write S without lifting the pen? So I think, folding the paper vertically and cutting it will be the perfect answer. So that we'll get VI.
Wow, I liked this soln too
Without lifting the pen means in one stroke.. Dude
@@tanujgarg792
You're free to make that conclusion, but if you get called for it don't blame people being accurate, blame the people with the poor wording choices that should've borrowed vocabulary and use stroke instead, because you certainly do lift a pen to make that s.
"Without lifting the pen."
"Without lifting the pen FROM THE PAPER."
Two different statements. The illustration shows that the pen is initially next to the paper, NOT on it. You can lift the pen without violating the rules of the challenge, just not after it touches the paper. The wording in the video is fine.
@@joemanco8002 So in theory, you could write a whole sentence by writing a letter, laying the pen without lifting from the paper, roll the pen and write another letter making sure not losing contact eith the paper
Riddle 3:-
What an out of the "Glass" solution 😜
Added a line through the equals sign to make it "not equal."
I take issue with a lot of these "riddles" as well as some cognitive tests where not all of the information is given or there are red herrings, tricks, or just plain unusual wording. Then people solve the problem by "thinking outside the box" which just means changing the constraints of the problem to match your solution.
For instance. The coins question is also true if you have any negative amount of coins.
The coins and glasses question is true if you distribute the coins as 7-3-0.
In my mind, riddles and other cognitive tests should have one definitive solution with all information present and clear in the problem statement. If anything is left up to interpretation, then the answer becomes subjective.
Haha. I agree. The first test stated you have coins. Yet the answer was zero. If you are told you have something, you cannot take it away to fit your narrative
I agree. The given answer to Riddle 3 is stupid.
I agree, however, 0 is even
@@obeyourfatheryah It isn't. It's zero as in nothing. It neither even or odd. You can't divide 0 by 2 either.
I also came up with that same solution BUT it did say you had to have coins in ALL the glasses too, so having one glass empty would of broke that rule. :(
Bob has 90% of the speed of Alice. So by the time that Alice runs 110 meters, Bob will have run 99 because 99 is 90% of 110. Bob loses by one meter.
Must feel pretty messed up...
Alice is not a machine. She ran an extra 10 m so she would probably get more tired and slow her pace down
Nice
@@mr.knight8967 It also doesn't say they ran at constant speed. Alice might only be able to run 105m, initially fast before stopping, while Bob can run steadily, so Bob wins.
Most of these "Out of the box solutions" seems to be made up by middle school kids, don't think any sane interviewer would ask these lol
An even better riddle is how Alice became a "he." (Answer: His last name was Cooper.)
Bob Ezrin was Alice Cooper's producer.
Like Sheldon Cooper from TBBT. He's also a man
Because she went farm and chenged her gender.🙄
What
Hahahahah nice one
my solution was different for the "subtract 3 from 9"
if u put a 6 after the X, it will read "1x6"
U assume that is sign instead of mention roman digit in this video, so u r not right
@@fununlimited4738 So what? In the video they assume as word IX instead of the roman numeral. Its all about how you interpret it. If that answer is correct, this is too.
@@fununlimited4738 so the answer in the video is also not correct? Cause he wrote S in front of the 9, he just got S9...
@@hotshot0079 right , as this question can also be solved by folding the paper from centre of "IX " and placing it upside down,which will give us Roman number "IV" i.e, 6
@@ronakjuyal9037 IV is 4 not 6
3:00 couldn’t you also flip A and B on their side and put 5 in C so they have a slight slope then balance coin in the middle
It would be in Both at once making it 2 in A 2 in B and 1 in both
4:22 "if you face this riddle in an interview"..
.. stand up, and say goodbye, as no one should want to work any companies which gives this riddle for a potential employees. Except if you want the HR position and save the company :)
For the bonus riddle you can also write a 6 after IX which makes it look like 1x6 which is 6. Also for the matches to make a perfect square there is a third way. Some people write 4 differently so the slanted line is vertical making 3 solutions to the problem.
What if I told you there's a 4th way to make a square
You missed th out side of the box version on barrel riddle: Just open barrel and check if it's water, no need to do math there.
Even easier way. 5 barrels were sold with only the last one barrel remaining that contains water.
Cut the equals to sign....implies
10 10 10 (=/) 9.50
(Not equals to)
Great sir
7:08 Python Code to Solve
import random
barrels = [15, 16, 18, 19, 20, 31]
a, b, c, d, e = 1, 2, 3, 4, 5
x = 1
while x == 1:
a = barrels[random.randint(0, 5)]
barrels.remove(a)
b = barrels[random.randint(0, 4)]
barrels.remove(b)
c = barrels[random.randint(0, 3)]
barrels.remove(c)
d = barrels[random.randint(0, 2)]
barrels.remove(d)
e = barrels[random.randint(0, 1)]
barrels.remove(e)
if (2*(a+b)) == (c+d+e):
print(a, b, c, d, e)
x = 2
break
if (a+b) != (c+d+e):
barrels.clear()
barrels = [15, 16, 18, 19, 20, 31]
9.50 is acceptable as 9:50 in some countries (I guess).
The proper solution will be put a slanting line on equal to sign making it != (not equal to sign).
more over... the time line of the question is exactly at 9:50...9min 50 sec
Hey programmer, "!" is not a single straight line :)
Put a horizontal line on second 10 which makes it 10 T0 (to) 10 ie 10 mimutes to 10 ie 9.50.
Smart
@@prachiratnappagol4308 Thank you
Instead read my solution just cut the equals sign to not equals to
9. 50 hours is 9 30
@@AaryanShah-ef3wv That's very obvious one. That crosses everyone's mind.
For Bonus Riddle #1 9:08 :
You can fold the paper, then turn it around, and you'll get "VI".
All the riddles are awesome and intersting with clear cut explanation.,🤝 The last one if we fold into two will be getting six.
I got 6 out of 7 correct. Didn't time myself, but I think in the sort of time you mention above. I'm 63.
The solution to #3 (coins in glasses) was kind of silly. If you can go that far into the ozone for an answer, then you might as well allow this solution, "Poke a hole through the bottom of one of the glasses (nobody said it wasn't plastic). Put 3 coins in each of the two undamaged glasses and 4 coins in the 3rd glass (with the hole poked in it). Shake the coins around in the 3rd glass until one of them falls through the bottom. Technically, you still "Placed 10 coins into 3 glasses" ... and now, "each glass contains an odd number of coins."
How about this - Put 11 coins into each glass. Each glass contains and odd number, plus you technically put 10 coins in each glass. The problem is poorly worded.
@@dbugged Why not put 1 coin in first then 5 in each of the other ones. Now they all have an odd number of coins.
@@DL101ca because it's 10 coins not 11.
With 11 the problem becomes trivial because then you will never get an even remainder
10 to 10
Does it make sense bro?
2:20 For any who know the basics of math, there is no summation of odd odd numbers that can make an even number. So for me I gave it a very little try then directly skipped to the answer. And by your answer if we considered the two cups as a one cup, then you just filled 2 cups not three.
Exactly. My first solution was 5 in one cup, and 5 in another.
Did it really say you had to use all 3?
To me their answer is no better and less elegant then 5 and 5...
every cup has to have an odd number of coins, so ... 0 definitely isnt odd.
8:55
You can actually do it without even touching the pen.
Fold the paper so only the bottom part of your IX is visible, and rotate it 180 degrees.
Solution @ 8:30 involves heavy calculations, using divisibility rule for 3 : (sum of digits) mod 3 = 0 helps. Numbers which are divisible by 3 (i.e 15, 18) are definitely not included. From the rest, 19, 16, 31 are of form 3k+1 and 20 is 3k+2 to take out one, from these 20 is the only solution.
For those who don't know a mod b, it is like remainder when a is divide d by b.
2:33 this is what you came for
Thank me later 😊😊
No, it not
Bro all of these were easy as fuck, the hardest for me was the "square" and the pen one, because I misread it
@@RGC_animation okay
@@woif00 ohhh 🙄🙄🙄
Placing '/ 'on the equal sign
Answer for last bonus result according to me is just put a straight line through the equals to sign that is to cut the equals to sign in the equation
8:50 rotate the paper 180 degrees, fold 25% paper from the south of the paper. It will show half of the content written in the middle of the paper. Which makes it look VI
Last Bonus riddle: just draw a line through the "equal" symbol and the whole equation is correct because then it says 10 10 10 unequal 9.50
6:05
Plot twist: first match, Bob is only warming up, while Alice was exhausted
So the winner is Bob
3:28 think outside the box and inside the box in order to create a box
That's when it hit me
For the last riddle, I would turn the paper and cut away a part of the X, making VI
About the perfect square, the matchstick you remove to form the number 4 can be also broken forming an L shape and place its 90* angle mirroring one of the 2 existing 90* angles courtesy of the 3 remaining matchsticks T-shape intersection
About your bonus riddle, if you turn the paper 180* and erase the upper half of the X you are left with VI
The fourth riddle has a third solution. You can take the matchstick you take for forming the 4 and put it on the one on the left to form a "filled" square.
There is another way to answer the "coins" question at the beginning. The main premise is to ask how many coins you have. The part about saying "only one statement is true" is a clue. If #1 is true without the others being stated, you cannot definitively say how many you have. It would be the same with #3 if looked at by itself; you cannot definitively say how many coins exist. #2 is almost the same way until shown with the other 2 statements and given the clue; there's a definitive choice: 0. If #2 is true, then #1 is false. As such, you can give a definite answer to the basic question. In this way, the clue is merely an indicator to say how many. Standing alone, #2 doesn't have an infinite number of answers; it only has 4. As such, you can guess that it's the true statement without comparing it to the other two.
Pen was lifted from the paper...in the second last riddle, so it is cheating
No it wasnt lifted
That wasn't really clear but I think it meant not to be lifted from the paper ONCE YOU STARTED WRITING. You would have to lift it from the paper to write.
The answer of bonus question was to place a straight vertical line on the equal to sign so that ot becomes not equa to
Abhay Sharma then we can't say it as equation
My idea was to cover the half part of the x by tape and rotate the paper so it looked like VI.because I thought u can't lift the pen.I miss the part from the paper
A straight line on equal = sign
Which will make it unequal👍
Bonus riddle 2:
Since there is no sign between the terms on the left, I assume they are one number, so 101010.
Since that is not equal to 9.50 however, I place a diagonal line through the = sign, making it an unequal sign. This way the equation is correct, since 101010 is not equal to 9.50
If there is no sign/symbol it means it would be 10x10x10.
@@albertross8547 isn’t that just for parentheses and variables?
3:10 honestly - shitty solution without any connection with the task
I disagree with the "solution" to riddle 3. If you place glass b inside glass a, you still have 4 coins in glass a. glass just contains 4 coins plus another glass with 3 coins. You can't ignore glass a and combine the coins together because you put glass b in glass a. The original question says "each glass contains an odd number of coins". Glass a still contains an even number of coins.
If I put a bag of coins inside a safe, the coins are inside the safe. Just also inside a bag. Same principle.
@@ElProf except the definition of in a glass is different from in a bag or in a safe,
A bag can be completely inside a bag of equal size and volume, a glass by definition cannot.
Is a safe really in a bag if you can only see the zipper poke out from under it?
For the bonus riddle at the end, make a line through the equal sign. So it becomes =/=.
For the second one, another interesting solution would be to place the three glasses in an equilateral triangle type formation. Three coins in each glass, and the last coin in the center of the formation, just so that a third of the coin rests on a section of each glass's rim. But that is only viable if you don't care about whether the number is whole or not.
Keep up the fantastic work!
I have 1 question. It's been bothering me. It is about the 10 coins to be put in 3 glasses.
There 3 separate glasses. There are 10 coins. You've put 3 coins each until you have add 1 coin in glass A. That does not match the requirements because glass A has even total of coins which is 4. Then, you've joined glass A and glass B so that it will have a total of 7 coins. But is that against such term? 'Coz if you put glass B into Glass A, it is still the same. Glass A has 4 coins and Glass B has 3 coins. The 4 coins are still inside the glass A and the 3 coins still in glass B. However, glass B is inside glass A. So, the statement now is wrong. There are 3 glasses which to be filled with odd counts of coins ( IT BECOMES 2 GLASSES ONLY ACCORDING TO WHAT YOU DID).
I am not judging what you did. Please enlighten me. Thank you
Maybe think of it more as a subset? Set A (which contains subset B) has a total of 7 coins, subset B (which is a set on its own) has 3 coins, and set C also has three. The fact that the glass is in another glass doesn't mean it doesn't exist anymore
I thought it was weird too, but a creative solution!
I didnt even try to solve for the barrel riddle cuz i thought you didnt need to solve since its a riddle. So i just picked 20 because H2O
We share the same sense of laziness :^)
Dude
9:25 When you read and translate automatically in your native language and think for like 5 mins and just give up and then this solution appeared and you feel like a dumbass because in your language 6 is also spelled "six" :')
Glasses riddle: Each glass demands that each individual glass contain coins NOT two (A+B) stacked together to become A. Glasses must remain separated !
Agree. The glasses riddle doesn't work.
It is 10 to 10. Place a horizontal line over the top of the second '1' from left
Simply make "=" to "not equal to " by placing / over =
Your riddles were interesting, i was only able to solve 2 of them
For riddle 7, you can solve it much faster by just reducing each barrel mod 3.
For the cups it seems better to solve it by placing 10 coins into three glasses and then taking one coin out to make that glass odd. I still fulfilled the rules because a total of 10 coins were placed and now each contain an odd number of coins. Rules didn't say anything about not being able to take coins out, and it didn't say that the total number of coins that the 3 glasses contain must equal ten. Okay so maybe I'm going too extreme with the interpretation but hey its fun.
I mean given the solution is to put a glass inside another glass I'd buy it. Honestly the given solution already feels like its against the spirit of the question.
@@MissingNovice that's true, i was thinking that when i watched the video
Making the equal sign to not an equal sign
Bonus Riddle #1: There's a big mistake there, how can I write "S" if I can't lift the pen? My solution would be covering the upper half of the IX with the pen, and then turning the paper upside down, would show VI, which is six in roman. Your solution failed.
The riddle said lift the pen "from the paper", not lift the pen at all. That implies that you can lift the pen but once you start writing you can no longer lift it. that said, I do like your solution.
The coins are still in three separate glasses...
True, he should put the cup inside the cup, and then add 7 coins
The answer is 7, 3, 0 in each glass. 0 is an odd number.
Garro Wolf no. 0 is even.
Odd + Odd = Even
But Odd + 0 = Odd.
@@garrowolf7112 how could 0 is an odd number bro?
I'm kidding.
You put a line crossing the "equal" sign, and it now means "not equal":
10 10 10 =/= 9.50
"10 10 10" isn't valid though.
You mean ≠ . But it is oblique line i think only straight line is allowed. Btw i thinked the same.
@@abhishekjain3344 The ≠ symbol isn't always easily typable.
riddle 6 has a lot of answers... 1. The girl would technically have been 10 on her 11th birthday (only for a few hours, maybe, but still). It would then be true that she would be 12 the next year on her birthday. 2. Her birthday is February 29th, and her 11th birthday was technically missed. 3. The answer that was given
2. Wouldn’t make sense because leap years occur every 4 years and 1. Is literally the same as 3.
I literally solved every riddle correctly. 😁😁❤️🥰