An important example. Interestingly (1/2)a,(2/3)b is also the coordinate of the centroid of the triangle formed by omitting the upper corners. But then the centre of pressure of THAT figure can't correspond to the geometric centroid any longer due to pressure varying with depth.
An important example. Interestingly (1/2)a,(2/3)b is also the coordinate of the centroid of the triangle formed by omitting the upper corners. But then the centre of pressure of THAT figure can't correspond to the geometric centroid any longer due to pressure varying with depth.
Is this calculation similar to the centre of pressure under the foot?And is the mean CoP a point relevant to the origin as shown in that graph?
Now I understand the math behind it :D
thanks, it was a bit hard to understand in the helm boo. good work