I have my p1 exam and I just want to tell you that I am forever in your debt. Your videos have helped me countless times during this Math AS course, you explain very clearly and take your time to deliver the ideas of the question exceptionally, I am pretty sure that even after I finish this Math AS course I will come back and revisit your channel during the Math A2 course, and you will, as always, deliver. THANK YOU SO MUCH MR HASSAAN!!!!!
Ok well before studying P2 ... the easiest way to get your head around it ... is to think that the sine of the angle alpha is equal to k.... and the graph is of y= sin(x/12) ... so at that particular point sin(x/12) =k... So sin (alpha) = k And sin(x/12) =k x/12 = alpha I hope that's clear... :/
@@MrHassaansMathsChannel i thought it is when x=a, y=k, which means sin(a/12)=k, thus, cos(6pi - a/12)=k, and the answer for ii should be 36pi - a instead, am i wrong somewhere...
@@anduong801 I'm sorry was busy the last few days... I'm looking at your answer and figuring out how to explain ... the mark scheme for the paper definitely says 6pi - alpha
many students will not have been exposed to the CAST or ASTC diagram until they have done P2 and Im trying to explain this according to P1 knowledge - which is more related to the symmetry of the sine curve
it tells us about how functions repeats the same pattern. the sine cosine and tangent functions are called periodic functions as their graphs repeat the exact same shape again and again. the sine and cosine curves repeat after 360 degrees, while the tangent curve after 180 degrees
I ddnt quite get why the part that u labelled as - alpha is equal to alpha can u like elaborate more as to why or give modifications that we can do to understand why? Thats the case
Actually ur technically correct... maybe I shouldn't have mentioned that sin (alpha) = k ... I was trying to answer this question in a manner that suits someone who has not studied P2 trigonometry and looks at it purely from the idea of transformations of the sine curve. I was looking at it as one big sine curve at first but then adjusted the x values according to sin(x/12) once I figured out the points I need. Basically my point in the answer is the symmetry of the curve and the distance of alpha along the x axis from the other part of the graph which will share the same y value (k) as when alpha is put into the equation. I'll have a look at trying to redo the answer in a way that avoids mentioning sine (alpha)= k. And ty for the feedback... much appreciated.
I have my p1 exam and I just want to tell you that I am forever in your debt. Your videos have helped me countless times during this Math AS course, you explain very clearly and take your time to deliver the ideas of the question exceptionally, I am pretty sure that even after I finish this Math AS course I will come back and revisit your channel during the Math A2 course, and you will, as always, deliver. THANK YOU SO MUCH MR HASSAAN!!!!!
Ur welcome Abdel Rahman.
same
Man I also have P1 exam today,May Allah shines His blessings upon us
Insha' Allah.
Dude you’re a live saver
Hope the exam went well
Lol anyone watching for tommorow???
Yea p1 exam
yes
@@greenie2228 yo when is your p1
10:05 for (c)(ii)
Should I write my answer as
x =12(1080° - alpha)? And also then do the same for (c)(i)? Because that would be the solution right?
thank you a literal beast
exam in 8 hours🤞🏽🙏🏽
Hope it was good..
Thank you, so much sir.
Got my As oct session exam in 15 hrs.
Absolute legend
Isn't the equation sin theta = cos theta-pi/2? Because the graph of sine theta is a translation of costheta in the positive x direction?
Could you explain why in (c), x/12 is equal to alpha?
Ok well before studying P2 ... the easiest way to get your head around it ... is to think that the sine of the angle alpha is equal to k.... and the graph is of y= sin(x/12) ... so at that particular point sin(x/12) =k...
So sin (alpha) = k
And sin(x/12) =k
x/12 = alpha
I hope that's clear... :/
@@MrHassaansMathsChannel i thought it is when x=a, y=k, which means sin(a/12)=k, thus, cos(6pi - a/12)=k, and the answer for ii should be 36pi - a instead, am i wrong somewhere...
@@anduong801 I'm sorry was busy the last few days... I'm looking at your answer and figuring out how to explain ... the mark scheme for the paper definitely says 6pi - alpha
For those struggling in last part of this question. Literally just use the cast diagram
many students will not have been exposed to the CAST or ASTC diagram until they have done P2 and Im trying to explain this according to P1 knowledge - which is more related to the symmetry of the sine curve
Alsalam Alikom,
what is a period. How do u find it?
وعليكم السلام
360/coefficient of x
In this case 2 pi / 1/12 or 2x12 as pi in radians = 180 degrees 2 pi = 360 degrees
@@yaseralshroofi jazak Allah kheir.
you saved my life
i dont understand what's meant by period like what is it
it tells us about how functions repeats the same pattern. the sine cosine and tangent functions are called periodic functions as their graphs repeat the exact same shape again and again. the sine and cosine curves repeat after 360 degrees, while the tangent curve after 180 degrees
Was a tonne of help. Thanks!
You're welcome
I ddnt quite get why the part that u labelled as - alpha is equal to alpha can u like elaborate more as to why or give modifications that we can do to understand why? Thats the case
from the symmetry of the curve the dustance between zero and alpha is the same as the distance between -12pi and the place i marked on the curve
hi, i don't understand why sin(alpha) = k, why did we assume that?
Actually ur technically correct... maybe I shouldn't have mentioned that sin (alpha) = k ... I was trying to answer this question in a manner that suits someone who has not studied P2 trigonometry and looks at it purely from the idea of transformations of the sine curve. I was looking at it as one big sine curve at first but then adjusted the x values according to sin(x/12) once I figured out the points I need. Basically my point in the answer is the symmetry of the curve and the distance of alpha along the x axis from the other part of the graph which will share the same y value (k) as when alpha is put into the equation. I'll have a look at trying to redo the answer in a way that avoids mentioning sine (alpha)= k. And ty for the feedback... much appreciated.
Thank you!
thank you sm for this :)
Your welcome.. I'm glad you found it useful
toughest exam of all time
jan p1 2020 is now the hardest :)
100 % i failed p1
hamdullah if i get c
@@عصيرقصب-د2ظ im resitting the exam without even waiting for the grade to come back. I know I failed it for sure.
عصير قصب tell me what you get I also did the exam
Oct 2020 exam tomorrow lol
Yep mine
@@sadmanthefalcon783 how was the paper bro?
I think my mock is October paper
So y’all can tell me the questions?
@@bilalsajid3441 youve probably done it alr but damn oct 2020 was the toughest p1 paper so far
@@yousof8546 fr especially question 6c