A vertical pole is guyed by three cables PA, PB and PC tied at a common point P at 8 m above the ground. The base points of the cables are A(4,0,0), B(-1,4,0), and C(-2,-3,0) m. If the tenson in the cable PA is 20 kN, calculate the tensions to be provided in cables PB and PC so that the resultant force exerted on the pole is vertical. Find the force exerted on the pole due to these tensions. Please solve this problem
@@UzumakiNaruto-zh7mq I see, let me know the exact year of exam, type of exam (quiz, final or midterm), and your university with the country. I will solve it.
not a big fan of tilting the axis. It just complicates things. You already have P and A with forces in normal axis so you can just compute force at B and c and not have to worry about tilting the axis
it makes sense to tilt the axis cause three of the forces are in the new y direction, it would help with the 2D shortcut for moment too! hope this helps
YOU ARE THE GOAT
THANK YOU!
A vertical pole is guyed by three cables PA, PB and PC tied at a common point P at 8 m above the ground. The base points of the cables are A(4,0,0), B(-1,4,0), and C(-2,-3,0) m. If the tenson in the cable PA is 20 kN, calculate the tensions to be provided in cables PB and PC so that the resultant force exerted on the pole is vertical. Find the force exerted on the pole due to these tensions. Please solve this problem
Which textbook is this from? what question?
@@ENGMCHANSWERS its a previous year question from my exam I don't know which book this is from
@@UzumakiNaruto-zh7mq I see, let me know the exact year of exam, type of exam (quiz, final or midterm), and your university with the country. I will solve it.
And also problem 2.36 from beer and johnson
Keep an eye on the channel, I will solve this soon!
@@ENGMCHANSWERS thanks
dont really see how its 120 cos 60
it's basically the definition of the cosine of an angle which is the ratio of the adjacent side to the hypotenuse in a right-angled triangle.
not a big fan of tilting the axis. It just complicates things. You already have P and A with forces in normal axis so you can just compute force at B and c and not have to worry about tilting the axis
just seems like you took another step of work for no real benefit or quickness
it makes sense to tilt the axis cause three of the forces are in the new y direction, it would help with the 2D shortcut for moment too! hope this helps