Designing a Lag Compensator (Problem no 1)

[@Agni_Puthra]

Mam, your channel deserves much more exposure on youtube. Thanks for the knowledge you are sharing 🙏

[@kowsiteaches]

Thank you 😊

[@amrithapv5217]

For finding zero of compensator the equation is 0.1×second pole of G(S).why is it so?is this equation constant or will it change?

[@kowsiteaches]

This is the formula.It will remain the same.

[@surendrakverma555]

Very good lecture. Thanks 🙏

[@kowsiteaches]

Most welcome!

[@NaomiSoita-u1r]

Feel appreciated from kenya

[@sharant6851]

Really?

[@nithyanithya6301]

Why the second pole in step 5? What about the if 4 poles in real axis? Can we take last pole of G(s)?

[@kowsiteaches]

In step 5, as per formula we have to take only the second pole.
If there are 4 poles,the existence of rootlocus on real axis will change.
I can't understand the Iast question question

[@r.a.s.riseassun2968]

Well done mam

[@kowsiteaches]

Thank you

[@gaurangrokade3524]

after finding transfer function, what about graph of compensated system?

[@kowsiteaches]

Please check the steady state error.If it was satisfied, then no need of the graph of the compensated system

[@omkarpatil1526]

What is value of zita ?

[@kowsiteaches]

It is 0.5

[@MaharajSwamiSamarth]

180 degree into 5 divide by 3 is 300 then why you minus 360 degree from it please explain

[@kowsiteaches]

How can u mark 300° using the protractor? thats why we need to subtract

[@adityapatil1879]

Pin point explenation ❤

[@kowsiteaches]

Thank you 👍

[@NXT_BLITZ]

Should change thumbnail, its not attractive.
Quality of content is generally judged through thumbnail.

[@kowsiteaches]

Will do it.thank you

[@sahilligam3191]

mam, how did u got the zita value as 0.5 , may u please tell the steps