Stress & Strain - Elastic Modulus & Shear Modulus Practice Problems - Physics
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- เผยแพร่เมื่อ 28 ส.ค. 2024
- This physics video tutorial provides practice problems associated with the elastic modulus and shear modulus of materials. It explains how to calculate the stress and strain of materials when an external force is applied. Stress is the ratio of force and area. Strain is the ratio of the change in length to the object's original length. Elastic modulus and the shear modulus is the ratio of stress and strain. This tutorial contains plenty of examples and practice problems.
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Why hasn’t this guy won a street nobel prize for the help and understanding he provides in such easy and quick methods👏🏼. Helpful af.
Cant wait for the Netflix doc on this guy. The Last Tutor...and I took that personaly
JG is the best , give this guy a Nobel prize already .it's not easy for a single person to understand thousand theories created by thousand scientist over thousand years.
no wonder you have 4 million subs.....I am watching this through the physics playlist and oh my god.....you have covered every topic ....literally every topic that is taught in my college and I can never be enough grateful....thank you so much!!
You have a video on every physics chemistry and mathematics concept under the sun... And yet you sound like a 24 year old ....... Just how Genius are you?? ❤❤
not apesilon and delta pricise defination of the limit
17:10
Organic Chemistry: The shape of the cube will deform a little
Also Organic Chemistry: p a r a l l e l o g r a m
This really goes well with my book. Thank you so much Mr. Tutor!!!
May i know the title of your book, sir?
@@wanggaeparkgae The book (at that time I used it) is called College Physics (OpenStax). It’s a free digital book that is pretty good (more Algebra based). Recently I have been using Physics for Scientists and Engineers 8th Edition (more calc based) that we use at my college, in which also you can get for free on Acadameia or you can buy a physical copy.
@@ginogamboni689 Sir thank you so much! ♥️
very help full god blees you from Ethiopia.
I like how he says modulus
I was just going to comment that sand then I seen you already commented that😂
You are the best and deserves a trophy 🏆 ❤
that trouble looking 8 and the other make me laugh involuntarily .thank you so much.
thank you this was very helpful
the god of tutorials almost everyone at my university knows the letters JG KKKK
Thank you very much for sharing knowledge
Thanx , It's very helpfull
thanks man I really appreciate
This guy is amazing
is the cylinder in the first question closed on one end or both ends??
Bu dersten de kaldım. Thx from Turkey
A uniform wire is subjected to longitudinal tensile stress of 5 * 10^7 Nm^-2. If the overall volume change in the wire is 0.02% , then the fractional decrease in the radius of the wire is?
This question is a good one, this is an example of things you can calculate with these formulas
Thank you from Kazakhstan!
That is great, you helped have me 👏🤝
Thanks so much this was really helpful but in the previous video you negated delta L when writing the formula for compressive strain, does this mean it's negative whatever formula you use?
In all my subjects now in college I follow you in explaining all the subjects I have and you are really good 🫂
how do you have a video about this? I swear you went through college for every single engineering major and said, "Yeah lemme make a video for every single topic ever that I learned." Lmao such a Chad
who is this boy he is fucking genius he has video for every subject whomisn heeeee????
Why does it work when he uses centimeters as the area metric, but meters as L initial? I thought you couldn't combine cm and m?
It's really of help🙏
Thanks for sharing, this tutorial is very helpful. One question please, if the rod was hollow, the cross-sectional area would still be calculated the same way?
You would substract the area that is hollow from the area that is solid and continue this way.
Can you make a video about crystallography?
Please, I also saw questions involving angles in shear modulus
In the first problem should the area of a cylinder would be equal pi*r²*height?
I was confused by this too.. He's real great though
well, thats the volume equation of cylinder not area, plus we should calculate the face thats bearing the load or weight...so it should be the area of circle
What is elastic modules of whole earth
Wow thanks
is the young's modulus included in this video??
that is the elastic modulus
@@ibhadeerua9420 both are same
Why does the area of a cube length x width instead of 6a^2?
In point (c) i typed it and that was the answer 5.10^6/25.10^9 = 2.10^14 ? Is there something wrong with my calculator?
mind the exponent and decimals
Guys there’s no time make it 1.5🏃🏻♀️😭
THANKSS
In the first problem, why is the delta L 0.004278? But the one before that is 0.4278. I'm confused.
Jethro Tuppil converted men
@@nonorv3095 SHIT oo nga no HHAHAH thank u so much MEN
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@@markstephen9307 Mahirap na nga tong topic na to magpapakahirap pako kaka Ingles 😂
@@vineboom3857 point taken HAHAHAHA
I need an example of how to get the modulus of elasticity
Why the have to multiple mg is 9.8 in first question
How are u guys getting negative exponents as the answer is my calculator wrong
where does this formula magiclly come from?
im sorry, a bit confused. why does the 300kg needs to multiply with 9.8? where did the 9.8 came from?
Gravitation constant
In short g.f=m×g
where does the 9.8 come from when dealing with the force value?
Gravity is 9.8
9.8 it's a gravitation
W=mg
There for:
W=weight
M=mass
G=gravity
At 3:21 my letter A is equals to 7.326x10^-9. Am I wrong?
i got that aswell
isn't 25mm 0.025m?
Where does 9.8 come from?
that's the Gravitational acceleration which is 9.8ms-2 OR 10ms-2
[Weight = mg] which is Mass x Gravitaional accerlation so when a mass is given to convert it into a force(weight) we must multiply it by 9.8 according to the equation so that we can get it as Newtons or Kg ms-2
1-b i got 427.6×10³m
Is it right or not any one plz tell me
in no.2 how can the compressive strain be positive ?
Strain has to be positive, the reason we have the negative sign in the compressive strain's formula is because we get a negative value of ∆L as the final length is less than the initial length and the negative sign cancels the previous negative sign to give us a positive value.
hi guys may mga taga ue ba dito
area of a cube is 6x length^2
Area not volume
We are looking for the cross-sectional area and not the total surface area.
This is what a noob speaking for itself looks like
@@hitsubitsa5039 thanks man i was also confused
👏👏👏👏🙏🙏🙏
your drawing is funny.
My calculator is giving 1.069521218x10^13 😭
🫂💜
ez
Why did u multiply 300 by 9.98
Amount: 1 kilogram (kg) in mass
Equals: 9.81 newtons earth (N)
@Ahmed Hamdy n is the same as mg, newton equals to mass x gravitational acceleration