Sir, Your explanation & presentation for solving any question is excellent . A very neat explanation with complete cut diagram. Which I am sure all students will definitely like without any doubt left.
Sir, sincerely you are one of the best teachers ive ever had... Your way of explaining every single n minor details is extraordinary... you work so hard for your students, you deserve everything... i wish id have find you earlier...
Where was i before. The best explanation I've ever seen. Easy to understand and I've learnt a lot just by watching a few of your videos. Keep up the good work.
It was a confusing problem but honestly saying, I couldn't understood better than this. Thank u sir for this kind of awesome explanations. You make even these tricky problems simple with your brilliant explanations. ❤️🙏🙏😍
Very nice sir mera diploma complete ho ke 6 sal ho gaye lekin mai aj government exam ka preparation kara rahu isakliye aj samaj me aya Thank you so much
Hello sir your method of teaching is very good sir Even I do not know your language but you gives me that language is not important before understanding Your teaching is good for me to understand the concept sir Thankyou very much
When applying C.D.R on I one it is difficult to understand than same thing happen when applying second step finding I six current. And rest is easy explantion. Thanks for sharing.
In second Step when we disconnected 20v source and applied 30v...when we had to find total resistance of the circuit..... Sir can't we first solve 6ohm and 5ohm as they are in series and then solve sum of these two i.e., 11 in parallel with 20ohm ......???
Problem 3 me current remove karke short circuit kiya hai.. or voltage remove karke open circuit kiya... ab problem 5 me reverse kar diya... voltage haii to short or current hai to open
I already uploaded 2 videos on mesh analysis (KVL), 3 videos on nodal analysis (KCL) and 2 videos on Norton Theorem. Please study all of them.... for that please visit the playlist of these topics on my TH-cam channel. Also more videos will come soon.... please wait and keep in touch.
sir is video me ek jagah aapne thodi si mistake kar di aapne step 2 me i6 ko find karte time aapne 30v ke baad 6 ohm ka ressistant ko bypass kar diya or direct ans dediya jabki sir kuch currunt 6 ohm ressistsnce me se bhi drop hoga then devide hoga
Sir doubt hai step 2 me 20 and 100 ohm resistance series me he aur 5 and 6 ohm resistance parallel me he phir unka jo answers aaye voh parallel me honge aab ye calculation krke total resistance alg aata hai.. Pls help 🙏🙏
Nahi nahi, 20 and 100 series me nahi hai, 5 and 6 parallel me nahi hai. 20 and 100 ke bech me ek short branch hai esiliye wo series me nahi hai. 5 and 6 ke bech me voltage source hai esiliye wo parallel me nahi hai
Great job! One of the best teacher I have ever seen.
Thanks for your GOLDEN WORDS.
True
Same❤️
Yes
This video is very helpful for me keep teaching🙏🙏.
Thanks for this video
Thanks for watching
Sir, Your explanation & presentation for solving any question is excellent . A very neat explanation with complete cut diagram. Which I am sure all students will definitely like without any doubt left.
Beautifully explained. This 'circuits and network" always has been a horror movie for me.
Sir apne total current nikalte time 2.727 ki jaga 22.727 liya he to vo wrong hoga na sir
@@nehupreet7317kyu ki usme 20 ohms ka resistance bhi add hua hai
Parallel 2 resistance ( 20,2.7272) add kiya sir.....
Are understand...@@nehupreet7317
Your teaching>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>My whole electrical department
>>>>>>>>>>>>
Sir, sincerely you are one of the best teachers ive ever had... Your way of explaining every single n minor details is extraordinary... you work so hard for your students, you deserve everything... i wish id have find you earlier...
Right
EAST OR WEST TIKLES ACADEMY IS BEST👍 thank you so much sir 😊
Where was i before. The best explanation I've ever seen. Easy to understand and I've learnt a lot just by watching a few of your videos. Keep up the good work.
One of the best teacher for explaining 👍
Sir you are the best professor of Engineering subject
It was a confusing problem but honestly saying, I couldn't understood better than this. Thank u sir for this kind of awesome explanations. You make even these tricky problems simple with your brilliant explanations. ❤️🙏🙏😍
I understand everything u teaching sir best teacher of mine sir
THANKS FOR WATCHING
Dinesh sir ki Roop Mai aap hame mile sir , thank you so much sir
Very nice sir mera diploma complete ho ke 6 sal ho gaye lekin mai aj government exam ka preparation kara rahu isakliye aj samaj me aya Thank you so much
Thanks for watching
Hello sir your method of teaching is very good sir
Even I do not know your language but you gives me that language is not important before understanding
Your teaching is good for me to understand the concept sir
Thankyou very much
Long live sir, you are the best
Sir keep it up...🔥🔥❤️ Never stop teaching ❤️
sir very unique question of superposition theorem solved
Best teacher ever for electrical subject
Crystel clear,best teacher I have ever seen.
THANKS FOR WATCHING
Pride of TH-cam sir❤️
When applying C.D.R on I one it is difficult to understand than same thing happen when applying second step finding I six current. And rest is easy explantion. Thanks for sharing.
Sir forgot to give direction (⬇️) to last total current value in step 3
great job!one of the best teacher
Thanks for watching
Really sir you are great teacher.😘😘😘 It is very helpful for me.
THANKS FOR WATCHING.
really very nice explanation sir 👍🔥
thank u sir
Our sir gave assignment to watch your videos
NICE EXPLAINED SIR .
THANKYOU SIR.
East or West Our Sir is the Best❤❤
Thank you very much sir🎉🎉🎉.
Best, thanks sir 😊
Thanks a lot sir🙏
Best explained ......
Great sir
Thanks for watching.
these teacher are god for average students like us
Intro is also awesome.
many many thanks sir
Awesome explanation 🔥🔥👍😀👌
Sir you are the best teacher in the world
Gajab sir
Thanks for watching
Sir I'm BE level student, I request for you explain circuit analysis in All theorem . For preparation of GATE Exam. Your explanation in excellent.✍️
aur kya explain karenge sir?
Amazing explanation 👌.
Amazing explanation
Excellent sir
THANKS FOR WATCHING.
Very nice site
Nice teaching sir quick to understand
Good teaching style
Thanks for watching
Sir i am continuously studying from Saturday till now🙏
Thankyou sir for explaining key points .
Thank you sir this topic is useful to Diploma students
Sir, lectures are very excellent.
if we put 100 ohm as dummy branch, then also answer is same
Amazing teacher 👍
Sir isme 100ohm dummy nhi hoga kyuki voh voltage source ke parallel hai?
Thank you so much Sir
Thank you sir
You are great 🙏🙏🙏🙏
Thank you sir .. For the excellent explaination.
Very nice explanation 👍
So great sir ji
Thanks sir my blessings are with you sir because I hate this but because of you I getting love towards the subject 😉
marvelous
Great teacher 🤠😃
Tq sir ....
Superb sirrrr
Thank you very much sir 🙏😊❤
In second Step when we disconnected 20v source and applied 30v...when we had to find total resistance of the circuit..... Sir can't we first solve 6ohm and 5ohm as they are in series and then solve sum of these two i.e., 11 in parallel with 20ohm ......???
Thanku sir❤️
Calculator km use Kariye sir
Problem 3 me current remove karke short circuit kiya hai.. or voltage remove karke open circuit kiya... ab problem 5 me reverse kar diya... voltage haii to short or current hai to open
Nodal analysis and mesh analysis and Norton theroem please sir upload kigeye nhi main detain hojaunga
I already uploaded
2 videos on mesh analysis (KVL),
3 videos on nodal analysis (KCL)
and
2 videos on Norton Theorem.
Please study all of them.... for that please visit the playlist of these topics on my TH-cam channel.
Also more videos will come soon.... please wait and keep in touch.
Sir, do we need to consider 100 ohm resistor? Because it is parallel to 20V battery (dummy element?
i have the same doubt
Same problem
❤️❤️❤️❤️❤️❤️❤️🙏🙏🙏👍
THANKS FOR WATCHING
Good job
sir is video me ek jagah aapne thodi si mistake kar di aapne step 2 me i6 ko find karte time aapne 30v ke baad 6 ohm ka ressistant ko bypass kar diya or direct ans dediya jabki sir kuch currunt 6 ohm ressistsnce me se bhi drop hoga then devide hoga
U are legend
❤❤❤
Sir I2 current bi R 3 and R4 mein bi guzrta hai tu i1 ki opposite brnch i2 ki brnch mein r4 &r3 reistance add ho skty hai
Thank u sir
32:34 me sir 120 ohms hoga n pls reply sir dummy ckt hai to 100 ohms wala ckt v khatm kr denge
Sir, lectures to be given on load flow system
Sir, if current divide into three branches then how to find the resistance of opposite branch?
Sir doubt hai step 2 me 20 and 100 ohm resistance series me he aur 5 and 6 ohm resistance parallel me he phir unka jo answers aaye voh parallel me honge aab ye calculation krke total resistance alg aata hai.. Pls help 🙏🙏
Nahi nahi, 20 and 100 series me nahi hai, 5 and 6 parallel me nahi hai.
20 and 100 ke bech me ek short branch hai esiliye wo series me nahi hai. 5 and 6 ke bech me voltage source hai esiliye wo parallel me nahi hai
❤
Woow
sir 100 ohm is dummy branch then did you not neglect the dummy branch ❓❓❓
Sir......
Norton's theorem ka video kn upload hoga......
Exam aane wala h
I don’t understand dummy branch . Why some circuit have dummy branch and some circuit don’t have?
Sir node voltages nikalna or find karana
Sir I2 wala current age 5ohm wali branch me flow kyn nhi hoga??
nhi kyuki question mein direction upside down diya hai Jo ki sirf I1 WALE current se hi possible hai.
Sir, what about the I2 current? Will it not divide at the node?
I6 ke liye total I keya 3 hoga???
Joss.
How to find dummy branch
Here why U didn't take dommy branch sir
I2 v toh distribute hua hai pure branch mei usko consider total nhi kiye 20:53
thank you so much . you saved my ass
Please make one with three sources and also using kvl and kcl
Please wait.... more problems will come soon... keep in touch
Please check the no.4 video because you haven't taken the dummy branch there
Don't worry Q No 4 is correct because there will not be any dummy branch as voltage source is in series with resistor.