What you've drawn are the 1st, 3rd and 5th harmonics. For a tube open at only one end, the even harmonics don't form. The reason we count them this way is because the definition for higher harmonics is in terms of frequency: fn = n*f1. If you look at the waves you've drawn, the wavelength is 4L, then 4L/3, then 4L/5. So wavelength decreases by a factor of 3, then by a factor of 5 from the fundamental. This means that, if we call the frequency of the fundamental f1, the frequencies of the harmonics you drew are 3f1 and 5f1. So they correspond to the 3rd and 5th harmonic.
in a closed pipe 4L/3 is Second harmonic and 4L/5 is third harmonic. There are 2 Different equation/formula for fn. the general expression is fn=nc/2L and for closed pipe the expression for fn=(2n-1)c/4L (this is what my book says and thats what he is teaching so i think its prolly correct)
@Sazid-Shahriyar-Roop because on the closed side the air doesn't vibrate so it is where the node is but on the open side of the tube the air vibrates most freely so that point is the antinode. This results in the length of the air column being one quarter of the wavelength
I believe that the diagrams you have drawn represent the first, third and fifth harmonics. Thank you for the rest of the video though, I appreciate it.
Thank you so much for posting these videos, they have been extremely useful! Also, could I get the model of the pens you're using please? I'm albeit mad about pens.
Darren Ng Great question, and one I've just had to look up. Try this www.britannica.com/EBchecked/topic/555255/sound/63994/Overtones and also hyperphysics.phy-astr.gsu.edu/hbase/music/otone.html to find out a bit more.
How come you can't set up a standing wave at a tube length of λ/2? (I understand this is between the two harmonics, but how would you word this for an explanation?)
No its an open pipe if youve done the experiment the wave enters at the opening of the pipe hits the bottom and reflects back out therefore creating the stationary wave
From one anode to the next is half the wavelength of the wave. However here we went from one anode to its adjacent node, meaning its half of half a wavelength, in other words one quarter.
OK so I wanna ask a few questions about the stationary wave, first up, in a stationary wave formed due to reflection, is the stationary wave instantaneous?
Imagine disliking free education
What you've drawn are the 1st, 3rd and 5th harmonics. For a tube open at only one end, the even harmonics don't form. The reason we count them this way is because the definition for higher harmonics is in terms of frequency: fn = n*f1. If you look at the waves you've drawn, the wavelength is 4L, then 4L/3, then 4L/5. So wavelength decreases by a factor of 3, then by a factor of 5 from the fundamental. This means that, if we call the frequency of the fundamental f1, the frequencies of the harmonics you drew are 3f1 and 5f1. So they correspond to the 3rd and 5th harmonic.
Just watched this and got confused as I thought the same as you
makes sense. i was really confused. thank you.
in a closed pipe 4L/3 is Second harmonic and 4L/5 is third harmonic. There are 2 Different equation/formula for fn. the general expression is fn=nc/2L and for closed pipe the expression for fn=(2n-1)c/4L
(this is what my book says and thats what he is teaching so i think its prolly correct)
Can someone explain to me why the anti-node has to be on the open side and the node being on the closed side? I am not understanding.
@Sazid-Shahriyar-Roop because on the closed side the air doesn't vibrate so it is where the node is but on the open side of the tube the air vibrates most freely so that point is the antinode. This results in the length of the air column being one quarter of the wavelength
I believe that the diagrams you have drawn represent the first, third and fifth harmonics. Thank you for the rest of the video though, I appreciate it.
I agree with you
Your videos are extremely helpful, thank you for making them! :D
she's started drinking young
Did you see her drink it with your eye
@@movielife1425 r/whoooosh
You are really motivating me to learn more about this.. This is very interresting!
your videos are really useful, thanks a lot.
Thank you so much for posting these videos, they have been extremely useful!
Also, could I get the model of the pens you're using please?
I'm albeit mad about pens.
lmao Pilot V Sign pens
I must say, this video was very helpful. Subscribed!!!!
Thank you
Thank you for this, seriously!
No problem
Wait so the first one is the fundamental frequency, third frequency then fifth?
Aren't these Stationary Waves in a CLOSED tube?
Dessa filmer är riktigt bra och jag hoppas få se mer i framtiden . Fortsätt med det goda arbetet .
Tack, jag hoppas du hittar dem användbara
What you have as the 2nd Harmonic (L=3lamda/4), according to my textbook is the Third Harmonic (first overtone)...I don't understand
i think you are right. i'm pretty late, but check Doc Schuster out. more helpful explanations there.
I'm not following at 1:16. Why is this distance lambda*(3/4)?
A node to a node is lambda/2 and a node to an anti node is half that so in total to equals 3lambda/2
@@MiniNinjaUK1comment from 7years ago cleared my concept❤
Could you do a video on how this works on bass reflex ports please.
your daughter is so cute :(
Isn't it Fundamental > First Overtone > Second Overtone? So I'm assuming that 2nd Harmonic is another word for First Overtone?
Darren Ng Great question, and one I've just had to look up. Try this www.britannica.com/EBchecked/topic/555255/sound/63994/Overtones and also hyperphysics.phy-astr.gsu.edu/hbase/music/otone.html to find out a bit more.
Thank you :) Keep making videos btw I'm sure you'll have more viewers in the future
How come you can't set up a standing wave at a tube length of λ/2? (I understand this is between the two harmonics, but how would you word this for an explanation?)
i know this is extremely late but lol the reason is that this is an open tube....one end will always be a node and the other will be an antinode
is all your content from edexcel board
+juwon fari It's for every board
Works perfectly fine for CIE
This video is for closed pipe is it?
Foo Cindy No its an open tube/pipe
yes, im pretty sure its for a closed pipe, must be a mistake in the video title
Yes this is closed pipe.Go to the previous video on strings that's for strings/open pipe.
No its an open pipe if youve done the experiment the wave enters at the opening of the pipe hits the bottom and reflects back out therefore creating the stationary wave
no its open pipe with the antinode at the opening
Thank you so much your videos are so useful
Isn't it 1st, 3rd, and 5th harmonic wavelength?
Why does the top have to be an antinode?
How did you go from half the wavelength to a quarter ?
From one anode to the next is half the wavelength of the wave. However here we went from one anode to its adjacent node, meaning its half of half a wavelength, in other words one quarter.
. 1st you showed a vessel open at one end which showed one node and one antinode. and again at the same vessel you showed 2 of them each ... ?
very good video
THANKYOU SO MUCH!
I wonder how old is she now ( and was during this video )
OK so I wanna ask a few questions about the stationary wave,
first up, in a stationary wave formed due to reflection, is the stationary wave instantaneous?
yes
is it just me feel the girl is so cute... :D
It is close not open man
why she drinking beer