Highly appreciate your teaching method. If you don't understand this video, please go back and watch the previous video and if you don't understand that, go back to the previous :)😬
Hi Joe. Great lesson. Could you think to write your equations in a bolder larger type. You see what you've written because you are close up. Your camera doesn't see it the way you do. Some of us are visual learners (videos) which means we scan the info often for reference as you continue to discuss the subject. It would be nice to be able to scan more easily. Thanks.
Mr joe tnk u very much for presenting this series that was very usefull backup me.i would like to make a small reqest, plz more explain capacitors..how it charj,how effect the voltage and freqency,capacitance , In connection with these things.
Power factor is usually represented as a percentage, in this case it is 59.3%. This is because you can't have a power factor greater than 1.0 (unity) or 100%
Great videos. One question. Where does the true power number come from? If you are measuring volts and amps with a multimeter, doesn’t that mean that watts (true power) are going to equal apparent power?
As soon as you have a right triangle with a side (not hypotenuse) of 3 or 4, then you should know all the other sides since the 3--4-5 triangle is a special case.
Hi, can you please explain the impedance formula as a square root of the R^2 + Inductive reactance^2 and make R as a subject? Big thanks in advance! Roberto
Joe: Wonderful video. As you explained before the power factor for Restive load (lamps or heaters) would be 1. My question please. You mention that this is an INDUCTIVE load, but would the PF be the same for a capacitive load, given the same known integers? Thank you as always.
Thanks Ted. Yes if the load was capacitive instead of inductive then the power factor would be the same if we'd been given the same initial values. It's just not really normal to have a capacituve load that we correct using an inductive load.
If you don't mind my asking, how are you setting work and giving feedback to your learners? I've set a few research tasks but mainly given them worksheets on topics already dealt with before the lock down.
Funnily enough the lock down had kind of tied in with me leaving the college to concentrate on @efixx full time. I believe the other lecturers are being encouraged to use Microsoft Teams to hold lessons. If it was me I'd probably deliver a lesson on Teams then email out a worksheet and get them to email back a picture of it completed. I'd consider exploring other ways as well with online quizzes they could show me the results from. We've got hundreds of questions you can do just that with on the Apprentice hub at efixx.co.uk. You should have a look.
Hi Joe, thank you for your videos its amazing. I have a similar question on my mock paper but the Current is 4.5 A. doesn't seems to work would you be able to help.
Hi ,I have a question. Why do we consider power used by inductor ( reactive power ) not useful. For an example if we consider a motor , inductors make the motor rotate yet power consumed by inductors are considered as not useful power . Can you please explain ?
The current flowing also creates a reactive inductance back into the coil from it's own magnetic field generated by current coming into the coil from the supply. This impedes the apparent power to give true power and if the ratio is closer to '1' then the inductor is creating less impedence and more efficient with a good power factor..
The whole series makes AC Theory crystal clear, and simple to understand thank you Joe Robinson
Great topic and great explanation. Thank you sir for sharing your ideas. Upload more videos. It helps a lot. Godbless.
Thank you Joe for this video and doing my L3 adv science exam on 06/09, you've explained it cleared better than my teacher, getting my understanding.
Great stuff, love hearing that the videos help. 😊 How did the exam go?
Highly appreciate your teaching method. If you don't understand this video, please go back and watch the previous video and if you don't understand that, go back to the previous :)😬
Great video. Who ever thought maths would come in handy again, I need to go through all of your other AC Theory videos 👍
Sure do if you're re-training Richard, it's not too difficult but you need to juggle a few different things in your head to understand it.
Very helpful, thank you.
You're welcome!
Brilliant thanks
Just brilliant
Thank you sir.. It is very helpful to us... Sir, As I think, ApparantPower * Sin(53.63) is a easy method to find out Reactive Power.
Nice video from Australia.
Hi Joe. Great lesson. Could you think to write your equations in a bolder larger type. You see what you've written because you are close up. Your camera doesn't see it the way you do. Some of us are visual learners (videos) which means we scan the info often for reference as you continue to discuss the subject. It would be nice to be able to scan more easily. Thanks.
THANKS Jeo you helped us a lot by the way you do have the best videos say hi to the team.
You deserve a knighthood Sir Joe for the clear and consise explanation. Lol. Thanks for another great session.
Hi Joe , Your lecture is excellent . Thanks
You're welcome, glad it helped.
Great vid Joe, nice to consolidate and apply previous vids 👍
Thanks very much, love answering this kind of question.
Nicely explained thanks, so I press shift then cos👍
Mr joe tnk u very much for presenting this series that was very usefull backup me.i would like to make a small reqest, plz more explain capacitors..how it charj,how effect the voltage and freqency,capacitance , In connection with these things.
Power factor is usually represented as a percentage, in this case it is 59.3%. This is because you can't have a power factor greater than 1.0 (unity) or 100%
which is also a ratio..
Spot on video Joe. 👍👍
Thanks chief! 👍
Great videos. One question. Where does the true power number come from? If you are measuring volts and amps with a multimeter, doesn’t that mean that watts (true power) are going to equal apparent power?
Big respect this is talent
Thanks, that's really kind. 😊
Hi Joe how use to kvar rating in capacitor bank and it how reduce EB bill for industrial?
Pls explain hormonics?
Thank you so much sir
As soon as you have a right triangle with a side (not hypotenuse) of 3 or 4, then you should know all the other sides since the 3--4-5 triangle is a special case.
Hi, can you please explain the impedance formula as a square root of the R^2 + Inductive reactance^2 and make R as a subject? Big thanks in advance! Roberto
Joe: Wonderful video. As you explained before the power factor for Restive
load (lamps or heaters) would be 1. My question please. You mention that
this is an INDUCTIVE load, but would the PF be the same for a capacitive
load, given the same known integers? Thank you as always.
Thanks Ted. Yes if the load was capacitive instead of inductive then the power factor would be the same if we'd been given the same initial values. It's just not really normal to have a capacituve load that we correct using an inductive load.
Good morning Joe. Is your college still open to you? Mine is closed and I'm working from home.
Morning, no the college is closed to almost all staff at the moment, working from home on these videos at the moment. 👍
If you don't mind my asking, how are you setting work and giving feedback to your learners? I've set a few research tasks but mainly given them worksheets on topics already dealt with before the lock down.
Funnily enough the lock down had kind of tied in with me leaving the college to concentrate on @efixx full time. I believe the other lecturers are being encouraged to use Microsoft Teams to hold lessons. If it was me I'd probably deliver a lesson on Teams then email out a worksheet and get them to email back a picture of it completed. I'd consider exploring other ways as well with online quizzes they could show me the results from. We've got hundreds of questions you can do just that with on the Apprentice hub at efixx.co.uk. You should have a look.
Nice one Joe. Great to see you supporting learners. The worrying thing is why is their own tutor not supporting them. Quality always rises to the top
Hi Joe, thank you for your videos its amazing.
I have a similar question on my mock paper but the Current is 4.5 A. doesn't seems to work would you be able to help.
I'll certainly try, best bet is to send me a picture on social media.
Hi ,I have a question.
Why do we consider power used by inductor ( reactive power ) not useful.
For an example if we consider a motor , inductors make the motor rotate yet power consumed by inductors are considered as not useful power . Can you please explain ?
The current flowing also creates a reactive inductance back into the coil from it's own magnetic field generated by current coming into the coil from the supply. This impedes the apparent power to give true power and if the ratio is closer to '1' then the inductor is creating less impedence and more efficient with a good power factor..
Best solution
Hi. Good Vidio
Cheers!
Shower man Jo 💣💣
That's me! 😊
legend