Can I still use this method even with different sample size, like data for Drug-A is taken as the average of 5 drugs, data for Drug-B is taken as the average of 8 drugs, and data for Drug-C is the average of 15 drugs?
You have to give them the average of the ranks for the positions they occupy. If there were 3 numbers for example 12, 12, and 15. The ranks given initially would be 1,2,3 but since the 12s should not have different ranks we average the ranks given initially to them. (1+2)/2=1.5. Now the ranks will be 1.5, 1.5, and 3
I tried to recreate your error but I can’t seem to get your answer. Perhaps you should simply the expression first. For example, 12/(6*3*4) is the same as 12/(6*12)=1/6.
Hi Diego, I’m not sure when I said this in the video, but perhaps it was when discussing ties. When ranking the data in the rows, you might have ties (values that are not different from each other). In that case, you must give the tied values the average rank the values would normally have (if they should be ranked 2 and 3, since they are the same, they get ranks of (2+3)/2=2.5.
@@dmcguckian Hi, what happens for the other rank, for example - should be ranked 1 and 2 so their ranks are 1.5 and 1.5 does the third rank become 3 or 2
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thank you for explaining friedmans test so well sir!
Thanks for watching!
Thank you so much Sir for the much needed help.
Glad it was helpful
Thank you sr for wonderful explanation ❤
Great video. Thanks.
Thanks
Having a non parametric test in a few,,, I'm sure if I'm to encounter friedman's,,I will be sure to have maximum points,,thanks💯
Good luck!
thank you
Thanks sir
You’re welcome
Can I still use this method even with different sample size, like data for Drug-A is taken as the average of 5 drugs, data for Drug-B is taken as the average of 8 drugs, and data for Drug-C is the average of 15 drugs?
How does Friedman compare to Pearson?
What if some of the blocks have the same values? How do you rank them?
You have to give them the average of the ranks for the positions they occupy. If there were 3 numbers for example 12, 12, and 15. The ranks given initially would be 1,2,3 but since the 12s should not have different ranks we average the ranks given initially to them. (1+2)/2=1.5. Now the ranks will be 1.5, 1.5, and 3
@@dmcguckian Thank you sir, this helps a lot.
how did you get 8.33 ? everytime i calculate i got 68.33. plz help
I tried to recreate your error but I can’t seem to get your answer. Perhaps you should simply the expression first. For example, 12/(6*3*4) is the same as 12/(6*12)=1/6.
@@dmcguckian don’t still understand please. If you can help me more, I’ve a presentation today
How did you do it please cos I’m getting 289… as an Answer not a..
Great example, but why use the chi square table whereas there is a friedman table which generates a different value from yours
What do you do when there's a non unique value in the same row?
Hi Diego, I’m not sure when I said this in the video, but perhaps it was when discussing ties. When ranking the data in the rows, you might have ties (values that are not different from each other). In that case, you must give the tied values the average rank the values would normally have (if they should be ranked 2 and 3, since they are the same, they get ranks of (2+3)/2=2.5.
@@dmcguckian Thank you!
@@dmcguckian Hi, what happens for the other rank, for example - should be ranked 1 and 2 so their ranks are 1.5 and 1.5 does the third rank become 3 or 2
I thought the Friedman equation uses 12N for the numerator and not just 12 as per your example? Am I missing something?
Ah i see, two different formulas. Thank you for the video as it helped me to figure out the Friedman equation.
THE Formula has 12 as the numerator
ez for you way