The integral is broken into two parts because there is a point of discontinuity or singularity at x = 2. The expression (x-2)^{2/3} becomes undefined when x is equal to 2. Breaking the integral at the point of singularity allows us to separately analyze the behavior of the function on either side of x = 2. This is particularly important for improper integrals involving singularities or points of discontinuity. By considering the intervals [1, 2) and (2, 5] separately, we can address the singularity and evaluate the integral more effectively.
Agr question me substitution se krnay ka kha jaye to substitution se hi krna ho ga Lekin agr substitution se krnay ka ni kha gya aur bgher substitution shi answer aa rha to wesay b kr sktay
10:18 question no. 4
Sir aik integral ko integrals main divide kiu kia???
The integral is broken into two parts because there is a point of discontinuity or singularity at x = 2. The expression (x-2)^{2/3} becomes undefined when x is equal to 2.
Breaking the integral at the point of singularity allows us to separately analyze the behavior of the function on either side of x = 2. This is particularly important for improper integrals involving singularities or points of discontinuity. By considering the intervals [1, 2) and (2, 5] separately, we can address the singularity and evaluate the integral more effectively.
sir question six ka koi oor method bta dein plz , its easy but difficult to write in math type
Practice krain mathtype ki method change krna acha solution ni hy
Sir g question 3 ma ham substitution method ka baghar bhi integration kar sakhta ha or answer bhi same a raha ha kia kar sakhta ha
Agr question me substitution se krnay ka kha jaye to substitution se hi krna ho ga
Lekin agr substitution se krnay ka ni kha gya aur bgher substitution shi answer aa rha to wesay b kr sktay