Fluid Mechanics: Topic 2.1 - Pascal's Law

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  • เผยแพร่เมื่อ 15 ม.ค. 2025

ความคิดเห็น • 58

  • @abbiemielczarek4807
    @abbiemielczarek4807 3 ปีที่แล้ว +3

    couldn't have found a more useful video! i missed a lecture and when i looked at the powerpoint all i saw was numbers, but i actually understand it now!

  • @wolframalpha8634
    @wolframalpha8634 หลายเดือนก่อน +1

    Sir, is there a particular reason as to why we assumed a wedge shaped fluid element to prove this? , can we prove the same using cuboidal or other eucledian elements?

  • @itthus9552
    @itthus9552 4 ปีที่แล้ว +2

    great video, I watched the lecture first before I watched these videoes, and I had to keep pausing it to think about how he got the numbers. This is so much better having it in short video. Thanks again for the great explanation! I look foward to mastering this fluids mechanics class!

    • @beoptimistic5853
      @beoptimistic5853 4 ปีที่แล้ว

      th-cam.com/video/XPCgGT9BlrQ/w-d-xo.html 💐💐💐

  • @numankashif6158
    @numankashif6158 ปีที่แล้ว +1

    Sir you are awesome . One of the finest videos on TH-cam for fluid mechanics topic. And you have gain one more subscribers.

  • @김찬수-i9j
    @김찬수-i9j 8 ปีที่แล้ว +1

    awesome!
    I'm the korean middle school student who has suspected about the Pascal's law for quite a long time. But because of your proof, I think i can sleep well tonight!

    • @CPPMechEngTutorials
      @CPPMechEngTutorials  8 ปีที่แล้ว +1

      Sweet dreams!

    • @김찬수-i9j
      @김찬수-i9j 8 ปีที่แล้ว

      I think I almost understood the whole proof but let me give you some questions that i hardly understood.
      By proving P1=P2=P3, can we say that pressure is independent of direction if no shearing forces exist...? + why can we suppose that dx,dy,dz go to 0...?

    • @김찬수-i9j
      @김찬수-i9j 8 ปีที่แล้ว

      Sorry for bothering... but I was just curious about some parts of proof.

    • @CPPMechEngTutorials
      @CPPMechEngTutorials  8 ปีที่แล้ว +1

      If we shrink the cube to a point in space, we find that the value of P is the same from all directions (we initially did not assume that). This implies that pressure has no preferred direction and we can treat it as a point function -- that is, pressure only depends on position in space. We say the pressure is XX Pascals at a given location, not that the pressure is XX Pascals to the left at a given location. Rather, the pressure force has a direction.

    • @김찬수-i9j
      @김찬수-i9j 8 ปีที่แล้ว +1

      CPPMechEngTutorials Got it! Thanks a lot! :)

  • @willofdodge1
    @willofdodge1 6 ปีที่แล้ว +4

    These videos are extremely helpful, Thank-You!

  • @ralphanthonymallillin2712
    @ralphanthonymallillin2712 3 ปีที่แล้ว

    I don't understand what he mean at 3:15..I'm finding answers why the back and front pressure are always separated unlike the other 3 equal pressures..Because pascal said the pressure are all equal in all direction then why does the front and back pressure are separated from the others??

  • @dbestacademybymentorgodslo2529
    @dbestacademybymentorgodslo2529 ปีที่แล้ว

    Please wat is the name of the app you are using?

  • @arthikalexander316
    @arthikalexander316 8 ปีที่แล้ว +6

    why do you particularly take a wedge or prism shaped fluid element?

    • @maheshk3368
      @maheshk3368 8 ปีที่แล้ว +2

      I think if we use cube shape, all pressures acting on opposite sides will cancel each other except weight of fluid and no conclusion can be drawn

    • @CPPMechEngTutorials
      @CPPMechEngTutorials  8 ปีที่แล้ว +5

      We didn't have to. A cube or any other shape would have given us the same results. A prism allows us to examine an arbitrarily shaped fluid element (notice we did not specify theta) that is relatively simple in shape.

    • @victormd1100
      @victormd1100 5 ปีที่แล้ว +2

      @@CPPMechEngTutorials How would prove that the pressure are equal in a fluid element shaped like a circle or an elipse (or any weird curve)? It seems that there would be many more unknowns (pressures) than equations due to all of the different directions normal to the surface

  • @sahalnijadv9237
    @sahalnijadv9237 4 ปีที่แล้ว

    6:51 pressure is actually a tensor.

    • @beoptimistic5853
      @beoptimistic5853 4 ปีที่แล้ว

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  • @pstark4
    @pstark4 5 ปีที่แล้ว +1

    Hi, the description of the surface forces acting on only three surfaces "for clarity" looks like a Cauchy stress tensor. Why is it only 3 faces, nine components, rather than 6 faces, 18 components? What about bending?

    • @ralphanthonymallillin2712
      @ralphanthonymallillin2712 3 ปีที่แล้ว

      That's also my question because pascal said that pressures in all directions but they always omit it without further explanation!!!

  • @mujeebkhan09
    @mujeebkhan09 7 ปีที่แล้ว +2

    I have one doubt...... at the end of proof, our conclusion was dependent on limit i.e dx,dy or dz approaches zero, which is correct but brings ambiguity. It could be much simplified if static equilibrium equation was applied initially as our assumption was already for static fluids, then RHS would have been zero, and then effect of differential increment in pressure due to weight of differential element could be ignored. Then things would have been much simple and easy to understand. Inclusion of acceleration, then applying limit at end brought ambiguity to a considerable extent.

    • @hassanaleian3111
      @hassanaleian3111 4 ปีที่แล้ว +2

      Yes this proof states that pressure in any direction at a point is equal but it doesnt explain why. However your suggestion is to my understanding incorrect. That is because their can be non-zero acceleration and this law still holds. As long as all fluid elements accelerate at same rate there will still be no shear stress as the video suggests.

  • @bluefinsxmovies
    @bluefinsxmovies ปีที่แล้ว

    Please I cannot stop wondering these two things
    Where did the sin & cos disappear to?
    Why did;
    P2dxdscosΩ become P2dxdy all of a sudden?
    Please I await your response

  • @pranavkankal5604
    @pranavkankal5604 4 ปีที่แล้ว

    Great work !!! Thank you very much 😊

    • @beoptimistic5853
      @beoptimistic5853 4 ปีที่แล้ว

      th-cam.com/video/XPCgGT9BlrQ/w-d-xo.html 💐💐💐

  • @wyattblah
    @wyattblah 8 ปีที่แล้ว

    This is a great explanation!

  • @krishnaprasadps7262
    @krishnaprasadps7262 11 หลายเดือนก่อน

    Wow awesome session sir, it will be very helpful if you could share the presesentation slides.

    • @CPPMechEngTutorials
      @CPPMechEngTutorials  11 หลายเดือนก่อน

      Sorry... we only have the video to share.

  • @siten1
    @siten1 3 ปีที่แล้ว

    Why is Pressure not dP?

  • @pankajkumar-jo5sp
    @pankajkumar-jo5sp 4 ปีที่แล้ว

    Extremely interested concept

    • @beoptimistic5853
      @beoptimistic5853 4 ปีที่แล้ว

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  • @YesHerself
    @YesHerself 8 ปีที่แล้ว

    nice!
    very well explained.thank you!

  • @gangadharvenkataramanap7651
    @gangadharvenkataramanap7651 7 ปีที่แล้ว

    I like you exaplaination, I understand the concept, but what should we do if we want to prove the pressure in x direction is also equal to remaining directions.

    • @CPPMechEngTutorials
      @CPPMechEngTutorials  7 ปีที่แล้ว

      Use the same technique, but in the x-direction. Summation of Fx = dm*ax. The forces in the x-direction are pressure forces -- call the pressures P4 and P5 on the two faces and initially do not assume they are the same. You will find that P4 = P5 if the acceleration is 0. You would then have to use the idea discussed in Topic 2.2 that pressure only varies in the direction of gravity in a static fluid, so the pressure in the x-direction and y-direction should be the same since gravity is in the z-direction.

  • @amh8303
    @amh8303 6 ปีที่แล้ว

    What is the name of the reference that ur make video with?
    Abather the way ur good👌

    • @CPPMechEngTutorials
      @CPPMechEngTutorials  6 ปีที่แล้ว +1

      We made these videos to be independent of any textbook. However, many textbooks have a similar derivation for Pascal's Law

    • @amh8303
      @amh8303 6 ปีที่แล้ว

      @@CPPMechEngTutorials I meant the text book that ur follow .
      Because i think it is the same my lecturer going with!
      I had an exam this sunday .

  • @siten1
    @siten1 3 ปีที่แล้ว

    Why is everything infinitesimally small(dx, dm, dv, etc) except density?

    • @TheFuckel
      @TheFuckel ปีที่แล้ว

      It is constant

  • @mujeebkhan09
    @mujeebkhan09 7 ปีที่แล้ว

    amazing great job... thumbs up

  • @spikeoac4248
    @spikeoac4248 4 ปีที่แล้ว

    If pressure doesn't vary with direction, then how is it that in the next video you prove that pressure varies linearly in the z direction? Doesn't that disprove what you just proved in this video?

    • @weeskaterdude
      @weeskaterdude 4 ปีที่แล้ว +2

      In considering an infinitesimal fluid element, we are approximating the pressure at a point. By Pascals law we can show that the pressure is independent of direction. This does not imply that pressure cannot vary in space and therefore it is entirely possible that we can obtain a pressure differential. Consider an open tank of water. We know that a fluid element at the bottom of the tank experiences greater pressure than an element approaching the free surface. I.e there exists a pressure gradient. We can describe this gradient via a chosen coordinate system and the result obtained would be that the pressure varies linearly in the chosen coordinate. I hope this is clear.

    • @beoptimistic5853
      @beoptimistic5853 4 ปีที่แล้ว

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  • @LailaWiduri
    @LailaWiduri 4 ปีที่แล้ว

    All I can say is THANK YOUUUUU. This video is really helpful

    • @beoptimistic5853
      @beoptimistic5853 4 ปีที่แล้ว

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  • @alnajdia6
    @alnajdia6 3 ปีที่แล้ว

    You angel, you.

  • @thangcogang2739
    @thangcogang2739 4 ปีที่แล้ว

    thankss :>

    • @beoptimistic5853
      @beoptimistic5853 4 ปีที่แล้ว

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  • @rahulravi661
    @rahulravi661 3 ปีที่แล้ว

    You just went through all that to put everything to zero? (P.S it's a troll comment , I'm an idiot 😏)