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Homework question Distance trevelled from 0 to t is , 0 to t =area of triangle ABt =1/2 × b × h. (Here b=t and h=v) = 1/2 × t × v = vt/2 Now distance from t to 2.5t is , t to 2.5t = area of trepezium tBC0 = 1/2 (sum if parallel side)× h = 1/2 (2.5t - t + 2t -t) × v (Here '-' this symbol means subtraction) = 2.5 vt/2 Now, we are comparing the distance trevelled by car during time 0 to t and t to 2.5t ...... = vt/2 : 2.5 vt/2 = 1: 2.5 (Here vt and 2 will cancel out and left with 1:2.5) I got the answer after understanding the questions. Thank you for asking these types of questions. 🤗🙏 I am first to answer correctly
Distance travelled in part BC = Area of the rectangle tBC2t = base × height. = (2t - t) × vo = vot Distance travelled in part AB = Area of the triangle ABt = (1/2) × base × height = (1/2) × t × vo = (1/2) vo t Therefore, distance travelled in part BC:distance travelled in part AB :: 2:1.
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Homework question
Distance trevelled from 0 to t is ,
0 to t =area of triangle ABt
=1/2 × b × h. (Here b=t and h=v)
= 1/2 × t × v
= vt/2
Now distance from t to 2.5t is ,
t to 2.5t = area of trepezium tBC0
= 1/2 (sum if parallel side)× h
= 1/2 (2.5t - t + 2t -t) × v
(Here '-' this symbol means subtraction)
= 2.5 vt/2
Now, we are comparing the distance trevelled by car during time 0 to t and t to 2.5t
......
= vt/2 : 2.5 vt/2
= 1: 2.5
(Here vt and 2 will cancel out and left with 1:2.5)
I got the answer after understanding the questions. Thank you for asking these types of questions. 🤗🙏
I am first to answer correctly
@@himaniarora8107 oh that’s the typing mistake.Thank you to tell me
what kind of motion. it is
thank you sir and byju's team! very helpful in understanding the concept thoroughly. :)
Equal distance in equal interval of time
D is the answer
P is the answer
Speed
0
a to b
d
b to c
hiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii
halt meaning sir
halt means that the object is going to stop-
@Iva_playz it is not going to stop it is in REST.
Distance travelled in part BC = Area of the rectangle tBC2t = base × height.
= (2t - t) × vo
= vot
Distance travelled in part AB = Area of the triangle ABt
= (1/2) × base × height
= (1/2) × t × vo
= (1/2) vo t
Therefore, distance travelled in part BC:distance travelled in part AB :: 2:1.