27: Stokes' Theorem - Valuable Vector Calculus

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  • เผยแพร่เมื่อ 21 ก.ย. 2024

ความคิดเห็น • 14

  • @MuPrimeMath
    @MuPrimeMath  4 ปีที่แล้ว +12

    Something I didn't mention in the video: Green's theorem is a special case of the curl theorem!
    To derive Green's theorem, consider a surface S which is only in the xy-plane. In other words, z=0 for the entire surface S. Then we take the normal vector to be [0, 0, 1]. Because the surface is just a region in the xy-plane, the "surface integral" is the same as an ordinary double integral!

    • @abrahamsweetvoice7687
      @abrahamsweetvoice7687 4 ปีที่แล้ว

      Have you still considered making a seperate video for the green's theorem. I understand your explanation, but I think it would fit perfectly for your channel cuz thats the only type of theorem ( special integral equation ) you haven't made a video of.

    • @MuPrimeMath
      @MuPrimeMath  4 ปีที่แล้ว +2

      I don't plan to make a video on Green's theorem any time soon. I'm going to start a new series in a week or two!

    • @MrChai74
      @MrChai74 2 ปีที่แล้ว

      I need that video explanation about Green Theorem and some application Too. Please.

  • @Hobbit183
    @Hobbit183 4 ปีที่แล้ว +6

    I'm really stoked for this video

  • @daniellabinjo6046
    @daniellabinjo6046 4 ปีที่แล้ว +7

    Brilliant explanation of one of the most abstract topics in calc..great upload!

  • @eswyatt
    @eswyatt ปีที่แล้ว +1

    Thanks for answering all my questions, some of which I realize have been ill-conceived. I made 18 pages of careful notes just from videos 24--27! Do you ever plan on doing a series on PDEs? I would love a different "take" on that stuff.

    • @MuPrimeMath
      @MuPrimeMath  ปีที่แล้ว +1

      I haven't taken a course on PDEs, so it's not on my roadmap!

  • @kingmunch7252
    @kingmunch7252 4 ปีที่แล้ว

    This is an awesome explanation man, thank you for this

  • @assammukhtar2716
    @assammukhtar2716 ปีที่แล้ว

    Amazing lecture😍 Thank you😊

  • @eswyatt
    @eswyatt 4 ปีที่แล้ว +2

    Am I correct in thinking there is no requirement that the boundary of the surface lie on a 2-dimensional plane in order for Stokes' Theorem to work? It could be an object like an N95 facemask--- set on a table concave up (?), its edge wouldn't lie entirely on the table.
    If the boundary *does lie on a plane, Stokes' theorem becomes an instance of Green's Theorem, *even if it's not the xy-plane (i.e. even if we can't use k = 1 as the normal vector). Otherwise we could just do a change of basis and make whatever plane the boundary lies on the "xy-plane"? Just wondering if I'm thinking about this right.

    • @MuPrimeMath
      @MuPrimeMath  4 ปีที่แล้ว +4

      You're correct that the boundary can be any curve in 3 dimensions!
      It is theoretically possible to perform some transformations on the coordinates such that a specific plane is mapped to the xy-plane while preserving shapes and function values.

  • @franktaktywolf970
    @franktaktywolf970 4 ปีที่แล้ว +1

    Amazing!

  • @long8398
    @long8398 หลายเดือนก่อน

    I am probably too stupid to understand this. Some people computing the curl, some people don‘t.