Prove that k0 = 0 using axioms only

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  • เผยแพร่เมื่อ 26 ม.ค. 2025

ความคิดเห็น • 22

  • @flamewings3224
    @flamewings3224 ปีที่แล้ว +6

    I always have a problems with that types of proofs in abstract algebra, so thank you for your content. tbh, when I saw your channel I didn’t like you, well, that’s normal for people, but you have been started to be in my recommendations, and sometimes I see EXACT topics I would like to know more… So I’ve been starting to love your content and your way to describe hard topics for student. I’m from Russia, and even in the internet I din’t meet a lot of really good teachers. I can numerate them by my 2 or even 1 hand. So thank you for making your video, which will help really a lot of people, even they aren’t commenting or liking your videos.

  • @maphypsd
    @maphypsd ปีที่แล้ว +5

    Thanks for the great videos. As a math teacher, I get great ideas from them.
    One note: you also used the commutativity of vector addition. When adding -k0, you add from the left on one side and the right on the other.

  • @punditgi
    @punditgi ปีที่แล้ว +10

    Symmetric property of equality, sir.
    In any case it is axiomatic that watching Prime Newtons follows logically from a desire to learn mathematics. 🎉😊

  • @nocoreal
    @nocoreal ปีที่แล้ว +1

    you have a nice voice, and explain stuff very well. Keep it up man!

  • @Nutshell_Mathematica
    @Nutshell_Mathematica ปีที่แล้ว +2

    Superb
    Can I know software u r using make thumbnail with math formulas and all stuff

    • @PrimeNewtons
      @PrimeNewtons  ปีที่แล้ว +2

      PowerPoint ->Draw->Ink to math

  • @salarsan12
    @salarsan12 ปีที่แล้ว +9

    bro is Dora the explorer for math 💀

    • @mikedubovs1574
      @mikedubovs1574 ปีที่แล้ว +2

      Dora is explorer in Spanish.. so Dora the explorer is .. Dora squared minus swiper no swiping

  • @LionKimbro
    @LionKimbro 2 หลายเดือนก่อน

    When you get to k0 = k0+k0, is it legal to then reason that k0 must be 0, because 0 is the only element of a group that, when combined with another element, gives back itself? There is an existing proof of the uniqueness of the 0 element of a group, and that it is the only element that ever combines with another element to render itself, and it's trivial to show that vector spaces fit the four requirements of a group over addition: closure, associativity, identity, and inverses, because those are given in the definition of a vector space.

  • @izzyqrz1
    @izzyqrz1 ปีที่แล้ว

    By any change, do you know any book that may teach you proofs for linear algebra

  • @golddddus
    @golddddus 10 หลายเดือนก่อน

    -(k0) cannot be written without an additional axiom. Likewise, (k0)+ -(k0) looks ugly and the additional axiom PN-axiom is needed there. If it were translated into one of the programming languages, it would lead to a syntax error in the message. It is more correct to write (k0) + (-k0) = (k0) + (k0) + (-k0). Even putting minus leak from the bracket is not in your set of axioms at all. The task was to use only the given set of vector space axioms.😎

  • @brianmulenga5963
    @brianmulenga5963 10 หลายเดือนก่อน +1

    You are amazing, God bless you

  • @nothingbutmathproofs7150
    @nothingbutmathproofs7150 6 หลายเดือนก่อน +1

    Students have such difficulty understanding these type of proofs. I myself never had any trouble with proofs like this (that doesn't mean I never had trouble with proofs!!)

  • @AinomugishaAllan
    @AinomugishaAllan 2 หลายเดือนก่อน

    Your my best teacher

  • @profenevarez
    @profenevarez ปีที่แล้ว

    well done, sir.

  • @elonmusk8341
    @elonmusk8341 4 หลายเดือนก่อน

    bhai sahab maza aa gaya

  • @mikedubovs1574
    @mikedubovs1574 ปีที่แล้ว

    Proof for the algorithm

  • @jakeaustria5445
    @jakeaustria5445 6 หลายเดือนก่อน

    Thanks

  • @AhmedElsaman-rk1wo
    @AhmedElsaman-rk1wo ปีที่แล้ว

    I liked it