NLM + Friction - L3 | Friction theory and case studies | Umang-11 | Suri Sir | Vedantu Math
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- เผยแพร่เมื่อ 22 ก.ย. 2024
- Click here for NLM + Friction - L3 V Quiz - vdnt.in/zWUug
After watching this video you will learn NLM + Friction - L3. This video will help you to understand the topic of NLM + Friction - L3 Friction theory and case studies. Our Master Teacher Suri Sir will explain to you the topic "NLM + Friction - L3 - Friction theory and case studies "in a very simple way. Stay tuned with @Vedantu Math for more amazing session for CBSE/JEE/NEET Class 11/12.
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+1
sir 11th physics ke important topic wise questions lao aur ncert important questions bhi lao
H.w. ans =option(A) 2N
Awesome session sir 🙂🙂🙂🙂🙂🙂
home work answer A
Awesome session sir ☺️
f=u×N
:.N=10N the force applied on opposite side ...
There fore
f=0.2×10
f=2N
If body is at rest means mg= f limiting
And f limiting=mu×N, whereN is equal to applied force (10N) hence, 0.2×10=2N is the value of mg :)
Sir the session was really amazing
And HW :- Option (A) 2N
🙂🙂
F=Meu10×mg which is equal to 2N
Amazing session sir 🥰🥰
Homework answer
Option A
2N
Thank you sir...
Happy Raksha Bandhan to all... 🥰🥰
homework answer is option A: 2N
17:19 - aree apko mere dost ka video kaha se mila???