NLM + Friction - L3 | Friction theory and case studies | Umang-11 | Suri Sir | Vedantu Math

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  • เผยแพร่เมื่อ 22 ก.ย. 2024
  • Click here for NLM + Friction - L3 V Quiz - vdnt.in/zWUug
    After watching this video you will learn NLM + Friction - L3. This video will help you to understand the topic of NLM + Friction - L3 Friction theory and case studies. Our Master Teacher Suri Sir will explain to you the topic "NLM + Friction - L3 - Friction theory and case studies "in a very simple way. Stay tuned with @Vedantu Math for more amazing session for CBSE/JEE/NEET Class 11/12.
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ความคิดเห็น • 10

  • @pradnyeshbgmsandfun3668
    @pradnyeshbgmsandfun3668 ปีที่แล้ว +1

    +1

  • @yt-gsagar
    @yt-gsagar 2 ปีที่แล้ว +3

    sir 11th physics ke important topic wise questions lao aur ncert important questions bhi lao

  • @ankurtiwary1936
    @ankurtiwary1936 2 ปีที่แล้ว +1

    H.w. ans =option(A) 2N
    Awesome session sir 🙂🙂🙂🙂🙂🙂

  • @sujayvolvoikar9992
    @sujayvolvoikar9992 2 ปีที่แล้ว +1

    home work answer A
    Awesome session sir ☺️
    f=u×N
    :.N=10N the force applied on opposite side ...
    There fore
    f=0.2×10
    f=2N

  • @praveen6600
    @praveen6600 2 ปีที่แล้ว

    If body is at rest means mg= f limiting
    And f limiting=mu×N, whereN is equal to applied force (10N) hence, 0.2×10=2N is the value of mg :)

  • @sagnikroy3633
    @sagnikroy3633 2 ปีที่แล้ว

    Sir the session was really amazing
    And HW :- Option (A) 2N
    🙂🙂

  • @NitinKumar-bm3rt
    @NitinKumar-bm3rt 2 ปีที่แล้ว

    F=Meu10×mg which is equal to 2N

  • @ankitaanswal6800
    @ankitaanswal6800 2 ปีที่แล้ว +1

    Amazing session sir 🥰🥰
    Homework answer
    Option A
    2N
    Thank you sir...
    Happy Raksha Bandhan to all... 🥰🥰

  • @fatehsingh1137
    @fatehsingh1137 2 ปีที่แล้ว

    homework answer is option A: 2N

  • @khushjaiswaljaiswal691
    @khushjaiswaljaiswal691 2 ปีที่แล้ว

    17:19 - aree apko mere dost ka video kaha se mila???