If we treat the given network as π network, converting the open terminal impedance as 0 conductance , answer we get is different from the original answer
Y parameters not exist for this two port network and Z11,Z12,Z21,Z22,these all four values are equal to Z ( simple convert into T network and definitely you will get your answer ❤
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Answer is-
Z11 = Z12 = Z21 = Z22 = z(ohm)
And
Y11 = Y22 = infinity(mho)
Y12 = Y21 = -(infinity)(mho)
highest respect to this channel from my side... it has saved a lot of time by giving a brief and required information......
Right sabiya 🔥🔥🔥
Solution of homework problem :--
Y parameters = y11=y22=(infinity) ; y12=y21=-(infinity) ;
Z parameters =
z11=z12=z21=z22=(z) ;
Am I correct ??
yes
How u getting z11, z22 is z??
@@yasvanths3507
Appy KVL in both the loop
V1=zI1+zI2
V2=zI1+zI2
Compare these equations with those of [z]
how you are getting y12 and y21 = -infinity....?
Yes
The shortcut method is very helpful...sir...😁😁😁🤗🤗🤗.
You're lectures are really helpful sir, Thank You
Sir, please provide the solution to the homework problem.
Your explanation is super and perfect understandable
Thanks a lot for this example. It helps a lot. I am completely dependent on your lectures. Please cover as more examples
Very helpful kudos to you sir thank you
Thanks a lot SIR for this solved problem..
H.W. ans will be Z11=Z12=Z21=Z22=Z & [Y]=∞
Answer of the hw:-z parameter Z11=Z12=Z21=Z22=Z & the y parameter is y11= infinity =y12=y21=y22[y11=z22/|z|=0]
Sir . Please tell me are you going to start Microprocessor series..Or any other.. Please let me know if yes and which subject?
All Z parameters are of value 'Z' ohms
Y11=Y22=infinite
Y12=Y21=0
Is it right sir?
Please reply...
Ganesha A B please , can you tell me how you get y12 and y21 equals zero? . I have got them negative infinity not zero . And thank you in progress
If we treat the given network as π network, converting the open terminal impedance as 0 conductance , answer we get is different from the original answer
Y parameters :y11=y12=y21=y22 =infinity
Z parameters : z11=z12=z21=z22=z
Y parameters not exist for this two port network and Z11,Z12,Z21,Z22,these all four values are equal to Z ( simple convert into T network and definitely you will get your answer ❤
Sir . U don't have video lacture on filter
Sir, please talk about how to find transform equation in two port network and upload video on this topic.
Y11=Y12=Y21=Y22= infinity
Z11=Z12=Z21=Z22= Z
it's my ans...😁😁🤗🤗...
Thanku sir thanku soomuch
Yes , all z pars. are equal to z
Sir ap.great hai more helpful
im done with the solution and my answer is [Y]=infinity and Z11=Z12=Z21=Z22=z
All z parameters are z , y11 =z,y12=y21= 0,z22= infinite
Z11=Z22=Z12=Z21=Z
And all Y parameter are infinity
Thanks a ton :))))
Sir please upload all the Discrete mathematics videos
Sir...can you explain about linear ICs ic741
sir why didn't you use kvl?
Z parameters=z
Y parameters=Infinity
Can we take 1 input port impedance with value 0ohm and also for op port,?? write
Please provide gate syllabus and gate coaching for ece
z11=z12=z21=z22= Z
y11=y12=y21=y22= infinite
Y11=y22=infinity , y12=y21=- infinity
Z11= z, z12=z21=z, z22= z
13/5,-7/5,23/5,18/5
Z11=Z12=Z21=Z22=Z
Y11=Y22=INFINITE Y12=Y21=-INFINTE
Z11= Z22= Z12=Z21= Z
Y - parameter does not exist
🙏❣
Z11=Z22=Z and Z12=Z21=-Z and y parameters we will get Infinite
How did u get -z??? When u convert it to T network z1=0 and z2=z and z3=0. Right?
Z11=z1+z2
Z12=z21=z2
Z22=z2+z3
Right?
Then how -z?
@@NaveenSword
The right answer will be z not -z
🏳🌈