Vector Space - Concept of Basis, Finite dimensional Vector Space in Hindi (Lecture 7)i

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[@rajkulkarni3718]

Sir, I think that in Q No.4 (38:42), the value of the 3rd vector (3,8,-3,5) is wrong because if it is +5 then we will not get rank as 2. If it is -5 then the rank of matrix is 2. Please check once sir. Other than this wonderful video as always. Thank you so much, sir.

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Ok

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[@sakshibhatt6766]

@@BhagwanSinghVishwakarma same prblm sir now will the rank be 3 and the dim will also be 3 i guess and we will be having 3 basis

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It means that" you are a great teacher" 🙏🏽😀

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Please upload videos on linear transformation

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Sir, your videos are very helpful......please cover solid geometry, Dynamics & Statics

[@anusingh5841]

Last sum, echelon form last row us (0, 0,0,10).dim W is 3
Thank you so much sir for this video

[@suyashsinha4001]

Second row me 0 ,7, - 9,2
TO 7 KO bhi to 1 banana hoga?

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प्लिज़ सर linear transformarion पर वीडियो upload कीजिये

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[@kashishvishwakarma860]

in question no. 2 at 30:24 value of a3 has to be 1/9 not 1/6

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Ye kaise nikali a1, a2, a3 ki value ?

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Yes 1/9

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[@ankitapatnaik5619]

Hello Sir, Thank u o much for this session, its really very helpful. but at 38:40 the answer for echelon for last row is (0,0,0,10) so rank is 3 sir. please check and let me know if it is correct.

[@anmolthewonderboy]

Yes i am getting the same one....

[@42_riya47]

right so if rank is 3?basis will have 3 elements.Thus, dim also=3? please reply

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महोदय धन्यवाद आपकी मेहरबानी के लिए।
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[@strangersings]

Sir for 3:52 3rd point if there is a set of LI vectors and 0 is added then it becomes set of LD vectors but if i take a subset which doesn't contain 0 then the subset will be LI ?

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in 30:50 the value of a3 is 1/9 please check it

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@39:11 vectors are linearly independent not linearly dependent please check the solution

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[@ParasJain-id7bz]

Chacha, At 4:01 while describing the properties of linearly dependent vectors, I think 3rd property is wrong can u please explain why is it correct?

[@BhagwanSinghVishwakarma]

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