Java Tutorial: Method Overloading in Java
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- เผยแพร่เมื่อ 6 ต.ค. 2020
- Java Method Overloading: In this video, we will see how to overload methods in java using method overloading. Method overloading is an important concept in Java and we will look into it using different examples in Java.
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Now 32 out of 113.... 😊
Notes + video + explaination in easiest way = No doubt all clear
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It's been 38 days since I have started learning, some days were too difficult for me to concentrate but still I'm on the go untill I finish this whole playlist and anyone learning or has just started or whoever gonna start in future, we all gonna make it. Take rest, take your own time but don't quit.
bro how much have u covered ?
u watched just 0.77 video per day?
@@mrunknown855 its about consistency ; consistency is not everyone's cup of tea !!
@@jatindubey7892 true in starting i was watching 5-6 videos daily and now I can't sit for one video but still trying to be consistent atleast
did u start java as your 1st programming language? In which year rn?
Wow!!!!... Amazing Harry bhai.. All concepts cleared. I came here after listening so called paid course lectures.. You are doing amazing work.. i have taken printouts of all your notes & they are helping me a lot while doing this java course. God bless you Harry bhai..!
I respect your notes and also appreciate you hard work. I try my 100% to learn java and till now I understand all things. 23:33
Call by value vs call by reference is clearly explained.
Thankyou Harry bayya ❤️
Time stamp?
@@parinkoralwala3653 case1 explains the call by value concept and case 2 explains call by reference concept bro.15:00
11:45 Change function will update the value of arr at index 0 because when we pass array to function/method it will actually pass the address of the value , therefore it is call by reference and it will definitely change the value of array at index 0 and print 98
Tq bhai now I understood
thanks bhai.😇
If thats the case then for the integer , we passed x which is reference for 45 ,shouldn't a get x and x is the address of 45 so it should change based on your logic right..? I listened to it many times but couldn't understand it properly. I would appreciate you if you could elaborate it for me
@@TabraizKhan-iv1cl suppose you have an array which is array1 = {1,2,3,4} and have a variable, int x = 6
so if you print the variable x it will give you 6 : system.out.println(x) = 6
and when you print the array it will give you the address of the array like this : [I@4517d9a3
so when you're passing x (int variable) in a method the thing you're passing is 6, because x = 6 you are not passing the address or reference of int x
but when you're passing an array you are not passing the integers in array but the address of the array : [I@4517d9a3
and because you're passing the address of array the method is changing the actual array not a copy.
in int x = 6 case you are passing 6 not the address of x that's why it is changing the copy not the actual x
I hope you understood i can further help you if you didn't understand
Harry I usually refrain from putting up comment... But Your explanation is spectacularly awesome......that i couldn't stop myself to praise your way of teaching.... I LOVE YOU BROTHER
At 12:05 it will print " 52 ", because even though the method has changed the copied value but has not returned it to the main function.
Hey Harry,you’re doing an awesome job .Keep up the good work and best of luck for future !Love from Melbourne ,Australia .
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His notes are really outstanding and very much helping + perfect !
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In the example of (12:00), *value* is changed because "array" is not a primitive data type.
(Harry said it previously that, this happens with primitive data types only).
Same thing happens in integer as well as array, but in case of array only the reference is copied. Hope you are getting the point!
It's alright if you got it wrong. Even I got it wrong at first 🙃
i rewind the video thrice but still not able to understand the difference in call by value n call by reference
@@zainabkazi4102
inshort the value changed for variables because they are premetive data type
but array is not premetive data type so you were able to change !!!
premetive data types are (Boolean, char, byte, int, short, long, float, and double.)
@@atifasadkhanbut we can change the value of primitive data type through call by reference.
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11:52 the value of marks[0] will be changed because the address of the array will be passed in the function and all the changes will be reflected in the original array
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You are really a good tutor!! THANK YOU HARRY
The concepts of call by value and call by reference are perfectly clear now..❤️❤️❤️
so what happens actually if you call by value, copy of value is taken and then..?
He said that it is no different from what happened to array .
@@TabraizKhan-iv1cl yes, in call by value, copy of value is taken. Arrays in Java are always created in the heap memory. When an array is passed to a method, it is always passed as a reference, the array will not be copied, two variables will refer to the same array.
11:48
Sir I think the value will change cuz I learned in your C in one video that in case of passing an array, the address is passed which is capable of changing the value of an array
Baaki pata ni😅😅😅😅
same
lets see what happen
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12:05
Value of marks[0] is 98.
So '98' will be the output
11:50 the value at index 0 gets changed as whenever array is passed , array referrences are passed changing the value formally as well as in main method
sir ,your lecture is very benifical and important for me
thank you Harry sir
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12:07
It will print 98.
The value of array is changed because the reference of array is passed to the function. It didn't change during the integer because while passing an integer, the value was passed to the method.
How is that same case then. He said it in the video that for integer it is no different compared to arra
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Y O U A R E L E G E N D
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@harry 21:44
You said method overloading cannot be performed by chnaging the return type but in your source code site you have mentioned it can be perfomed by changing the return type. Please clear the confusion.
Sir, Method overloading cannot be performed by changing the return type of methods.
Both return type and parameters can be changed, and no error is invoked. But, still is it called the method overloading ?
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Thank U sir for providing this wonderful video with notes❤
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12:06
The value of x after running is :98
Hi dude i tried the same thing which you did with an array with a string, but it did not change, it behaved like a primitive data type,
public class Main {
static void changestring(String str){
str="Aniruddha";
}
public static void main(String[] args){
String str1="Samant";
changestring(str1);
System.out.println(str1);
dude what you did is,the 'str' was refering to 'Samanat' but when you did str="Anirudha"....str started refering to "Anirudha" .....you didn't change String
but you changed str reference
thnq so mch u r with us & you are doing a great job and i totally respect your effort for notes thnq...❤❤❤
Thanka for coding classes you are the best programming teacher
11:45 Haan bhai change hoga kyunki agar nahi hota to aap ye nahi karwate 🤣🤣🤣 it will print 98
sahi bole bhai or aapne is comment ko edit kiya hai
@ sujata Jena aap jabhi bhi meri pehlli comment read karoge to mujhe reply bhejo
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11:45 It will change the value of array at index 0 because you said it will pass the reference of array rather than passing copy of the original array.
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Now I understood method overloading clearly after watching this vedio
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Harry....
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today my concept of method is cleared thank you harry bhai
nicce broo
im understandingg
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