Newton's 4th law says that every book continue to be in rest until and unless internal or external exam appears and speed of page turning is directly proportional to the syllabus to be covered and tension in the mind remains constant.
52:05 work done by applied force Work done = Fs cos ∅ = Fs cos 0⁰ = 20×10×1 Work done by applied force = 200 J Work done by gravity Work done = Fs cos ∅ (mg)× s cos 90⁰ ( 5×10) × 10 × 0 Work done by gravity = 0 J Work done by friction Work done = Fs cos∅ Fs cos 180⁰ 5× 10× -1 Hence, work done by friction = - 50 J Net workdone= 200+(-50)+0 200-50= 150 Joules Answer
@@VishnuSharma-dr2yi Listen I'm not sure about this..as far as I know, mass is not calculated.. Well if you have any doubt then I would ask this to my teacher to clear some doubts🙏🏻
Thank you so much I think that so and my answer is also coming this but sir calculated mass in every question that's why I have doubt in this and I also ask my teacher about this
Dekho! Yaha pr question mein bola gya h ki 'ek block h ya tum maanlo ek box hai usmein jetni bhi forces lag rhi hai voh sb bata na h, toh figure ke according block mein 3 Forces lg rhi h 1.Gravity(g) 2.Applied force (jo box ko move krne keliye lgaya gya h) 3. Frictional force Tmhe sbka workdone batana h, toh phele separately nikalo example- applied force- w=fs w=20x10 w=200 waise hi bakyion ka nikalo aur sabko add krdo kyuki Net workdone pucha h (net ka mtlb whole ya pura)
@@sheshkumarSingh-sf8xt Dekho! Shesh waha pr workdone pucha h aur maine workdone ka formula use kiya h which is W=fs and question mein given h ki F=20N S=10m Thus, W=fs W=20x10 W=200J
Introduction - 00:00-02:03 Workdone - 02:04-16:47 Calculation of Work: Positive Work - 16:47-23:54 Calculation of Work: Negative work - 23:55-27:04 Calculation of Work: Zero Work - 27:05 to 34:42 Why do we pay coolie/porter ? - 38:28 to 43:32 ENERGY - 53:24 to 57:02 Kinetic Energy - 57:03 to 59:55 Finding experssion of Kinetic energy - 59:56 to 01:05:40 Potential Energy - 01:19:51 to 01:26:46 Finding experssion of Potential energy (position) - 01:26:47 to 01:29:00 Potential Energy - 01:35:11 to 01:35:36 Understanding Potential Energy (Configuration) - 01:35:37 to 01:37:49 Law of conservation of energy - 01:37:50 to 01:41:10 Examples of conservation of energy - 01:41:11 to 01:47:06 Proof of conservation of mechanical energy - 01:47:07 to 01:57:03 Power - 01:57:04 to 01:59:19 Relation between Kinetic Energy and Momentum - 02:11:29 to 02:14:35 Relation Between Power, force and velocity - 02:14:36 to 02:16:03
time stamps Introduction - 00:00-02:03 Workdone - 02:04-16:47 Calculation of Work: Positive Work - 16:47-23:54 Calculation of Work: Negative work - 23:55-27:04 Calculation of Work: Zero Work - 27:05 to 34:42 Why do we pay coolie/porter ? - 38:28 to 43:32 ENERGY - 53:24 to 57:02 Kinetic Energy - 57:03 to 59:55 Finding experssion of Kinetic energy - 59:56 to 01:05:40 Potential Energy - 01:19:51 to 01:26:46 Finding experssion of Potential energy (position) - 01:26:47 to 01:29:00 Potential Energy - 01:35:11 to 01:35:36 Understanding Potential Energy (Configuration) - 01:35:37 to 01:37:49 Law of conservation of energy - 01:37:50 to 01:41:10 Examples of conservation of energy - 01:41:11 to 01:47:06 Proof of conservation of mechanical energy - 01:47:07 to 01:57:03 Power - 01:57:04 to 01:59:19 Relation between Kinetic Energy and Momentum - 02:11:29 to 02:14:35 Relation Between Power, force and velocity - 02:14:36 to 02:16:03
37:46 The minus sign indicates that the speed of the object is slowing down due to negative workdone. In other words we can say that ,the object is experiencing retardation. 51:40 Workdone by applied force = 200J Workdone by friction force = -50J Workdone by weight force = 0 J Net Work done = 150J 2:11:18 Total Cost = 48*3 = Rs.144
at 1:35:08 the ans should be 300J as the obj is lowered down to the height of 5m instead of bringing it down 5m. Now s will be equal to 10 and the ans will be 60X10 = 600J and now on subtracting W2 from W1 (900-600) the ans will be 300J
@@lizarahman__ because the force of friction is 5N and is applied in the opposite direction so the angle(cos theta) will be 180° which is equal to -1 So by multiplying 5 x 10 x -1 You get -50J
37:45 THIS MINUS SIGN IS BECAUSE OF THE VALUE OF COS 180DEGREE THAT IS -1 THE MINUS SIGN INDICATES THE NAGATIVE WD AND THE DIRECTION OF DISP IS OPPOSITE FROM THE DIRECTION OF FORCE
@@VishnuSharma-dr2yi workdone=FxSxcos theta so, workdone by friction=5x10xcos180o =50x-1 =-50J so here we can see that mass is not included in the calculation and so mass is not required in questions of mass.It may be given to trick the students.
H/W W1= Fs costheta =20×10×cos0°(As F and s are acting in same direction so angle b/w them is 0°) =20×10×1(Value of cos 0° is 1) =200J(Ans.) W2= fs cos theta =5×10×cos180°(As f and s are acting in opp. direction and angle b/w them is 180°) =5×10× -1 = -50J(Ans.) W3= f¹(let force be f¹)×s× costheta =mg ×10×cos 90°(As weight of body is acting perpendicular to the displacement of body) =5×9.8×10×0(Value of cos90° is 0) =0J Work done by all the forces acting on the block is W1=200J; W2= -50J; W3=0J Net workdone is {200+(-50)+0} J =150 J
Timestamps Introduction - 00:00-02:03 Workdone - 02:04-16:47 Calculation of Work: Positive Work - 16:47-23:54 Calculation of Work: Negative work - 23:55-27:04 Calculation of Work: Zero Work - 27:05 to 34:42 Why do we pay coolie/porter ? - 38:28 to 43:32 ENERGY - 53:24 to 57:02 Kinetic Energy - 57:03 to 59:55 Finding experssion of Kinetic energy - 59:56 to 01:05:40 Potential Energy - 01:19:51 to 01:26:46 Finding experssion of Potential energy (position) - 01:26:47 to 01:29:00 Potential Energy - 01:35:11 to 01:35:36 Understanding Potential Energy (Configuration) - 01:35:37 to 01:37:49 Law of conservation of energy - 01:37:50 to 01:41:10 Examples of conservation of energy - 01:41:11 to 01:47:06 Proof of conservation of mechanical energy - 01:47:07 to 01:57:03 Power - 01:57:04 to 01:59:19 Relation between Kinetic Energy and Momentum - 02:11:29 to 02:14:35 Relation Between Power, force and velocity - 02:14:36 to 02:16:03
Because of upward direction and force being downwards so 180° tells -1.🎉 It tells that the work is done in the opposute direction of force. 38:04 Speed is slowed down
00:07 Introduction to Sprint Series on Class 9th Physics 00:51 Understanding Work, Energy, and Power in Class 9th NCERT Chapter 11 02:26 Work, Energy and Power are related in various activities like revision, brain training, meditation, breathing and physical work. 03:14 Force and displacement lead to work 04:41 Understanding Work in the Same Direction 05:30 Calculating work in different directions of force and displacement 07:02 Understand Work done in the same direction of displacement 07:43 Understanding the relationship between force, displacement, and work. 09:28 Understanding force and displacement in different angles 10:12 Understanding angles and cosines in physics. 11:57 Work done is defined as the product of force and displacement in the direction of force 12:38 Understanding Work-Done Calculation in Work, Energy, and Power 13:58 Scalar and vector products of two vectors 14:50 Understanding Work, Energy, and Power in Physics 17:04 Understanding work and displacement in relation to force 17:54 Force and displacement are related in the direction and magnitude. 19:58 Positive work leads to object speeding up 20:51 Energy is converted into work done by our body. 22:26 Discussion on friction and displacement of objects 23:11 Understanding friction and displacement values 24:54 Understanding the formula of work done with Cos Theta 25:37 Understanding the role of frictional force in changing speed 27:24 Work done is the product of force and displacement. 28:36 Force and its Direction 31:04 Understanding work, energy, and power in school curriculum 32:11 Direction determines work done, not value. 34:17 Understanding Work and Zero Work 35:20 Understanding force, displacement, and conversion 37:22 Understanding 180 degrees and its implications 38:20 Understanding the concept of work, energy and power 40:00 Understanding work, energy, and power conceptually 40:43 Understanding Work in Motion 42:14 Understanding the direction of force and displacement 42:52 Chemical work done and forces involved 44:22 Preparing to carry a body for burial 45:00 Understanding work and force in terms of displacement and angles 47:32 Calculating force required to lift an object 48:51 Discussing the effects of applying force less than or greater than 150 units 50:24 Calculating work done by force 51:43 Calculating work done and displacement in a gravitational field. 53:11 Understanding the concept of energy and work in physics 54:09 Conversion of food into energy 55:37 Understanding Work, Energy, and Power conversion 56:21 Introduction to Work, Energy, and Power concepts 58:32 Understanding Kinetic Energy in Motion 59:22 Derivation of kinetic energy formula and work done formula 1:02:09 Deriving formula for work done using force and displacement 1:03:32 Understanding manipulation of equations for work, energy, and power calculations 1:06:32 Understanding Work and Energy in Simple Terms 1:07:36 Conversion of work done to kinetic energy 1:09:30 Understanding the concept of kinetic energy and its general expression 1:10:31 Work done results in change in kinetic energy 1:12:12 Understanding Work and Energy 1:13:01 Conversion of work to kinetic energy 1:14:27 Understanding work, energy, and power concepts 1:15:18 Calculation of work, energy and power equations 1:17:41 Calculation of final energy using formula 1:18:35 Calculate percentage change using the initial and final values 1:20:34 Work, force, and displacement relationship 1:21:09 Kinetic energy is converted into potential energy through work done. 1:22:36 Understanding Potential and Kinetic Energy 1:23:28 Transfer of potential energy to kinetic energy explained 1:24:59 Understanding different types of energy 1:25:44 Kinetic energy is derived from the motion of an object. 1:27:19 Understanding displacement and force equivalence 1:28:02 Work is related to energy and force in every derivation. 1:29:43 Understanding work, energy, and power in a nutshell 1:30:47 Force always acts in the upward direction. 1:32:09 Understanding displacement and work done 1:33:24 Introduction to Potential Energy 1:35:08 Understanding independent path and displacement dependent path 1:35:50 Potential energy is dependent on height 1:37:35 Conversion of energy between potential and kinetic forms 1:38:17 Energy is derived from chemicals in food through photosynthesis in plants, and can be transformed into different forms. 1:39:39 Understanding Energy Transfer in Connected Work Chains 1:40:25 Conversion of muscular energy into kinetic energy 1:42:27 Electricity is converted to thermal energy in heaters 1:43:17 Hydroelectric power generation process explained 1:45:14 Conversion of chemical energy to kinetic energy 1:46:07 Conversion of thermal energy to electrical energy 1:48:24 Understanding potential and kinetic energy 1:49:06 Understanding potential energy and its connection with mechanical energy. 1:52:26 Understanding displacement and velocity calculations 1:53:18 Calculating displacement and speed 1:55:09 Changes in potential and kinetic energy 1:56:10 Conservation of total mechanical energy 1:57:45 Understanding the concept of power in physics. 1:58:32 Understanding Power and Horsepower Units 2:00:24 Understanding the concept of force and weight 2:01:13 Understanding power and energy in physics 2:03:15 Introduction to energy unit and its importance in classes 9th to 12th 2:03:55 Commercial vehicle can use energy unit for trading and consumption of energy. 2:06:10 Understanding commercial electric units and monitoring household appliances 2:06:57 Understanding kilowatt-hour and its implications on electricity consumption and cost 2:08:44 Understanding power and energy calculations 2:09:40 Understanding energy consumption and cost calculation 2:11:38 Understanding the relationship between kinetic energy and momentum 2:12:37 Kinetic energy changes as variables change 2:14:28 Relation between Power, Force, and Velocity 2:15:12 Relationship between force, velocity, and power explained through dot product 2:16:51 Practice numericals for better understanding
37:54 Here the work done came as -1400 Joules indicate that the force and displacement are in the opposite actors. And it is termed as negative workdone. Here also the cos 180° termed or known as the value of -1 as per the shown tablular form.
1:33:01 sir the object is brought down to the height of 5m so from 15 m it will come down to 5 m so the equation formed will be w=60x10xcos 180 w=600x-1 w=-600
37:57 It is because here the force is acting in opposite direction to displacement so here we will use formula :- *W= F•sCOSTHETA* = F•sCOS 180° = F•s×-1 😊😅❤
@@Ashubhai_shorts bhai gravity me F= mg hota hai jaha m= mass ,g=10n or angle between object and gravity is 90° which is = 0 so w= mg×s×0 = 0 work done
51:53 HOMEWORK ANSWERS. 1) W1 = 200J ( by force applied) 2) W2 = -50J (by force of friction) 3) W3 = 0J( by force of gravity) Net work done = 200+(-50)+0= 150J Thank you sir ☺️☺️
51:27 the positive workdone will be 200J The negative workdone will be -50 The zero workdone will be 0 The net work done will be 200+(-50)=>200-50=150J
1:29:29 sir Aaj aapne 'g' ka value negative kyu nahi liya pichle lectures me to bola tha ki Cartesian plan ko follow karenge ?? Or kaha tha ki har baar g ka value negative lena ???
37:54 it is in negative sign because the ball is moving upward but the gravitational force is applied from the downward direction so it makes 180 degree angle. And the value of Cos180 degree is -1
49:00 sir isme wo object uper ke taraf ja rha hai to wo accelerate hi to kar rha hai kyuki uska initial position rest tha to 150N se jada force ka jarurat padega na Pls clear this doubt
🎉🎉 I was searching for all the videos uploaded by u sir and u r an excellent teacher seriously!!! I hv watched all your videos even of all classes that u teach because I like ur way of teaching physics which gives me interest in physics and I m liking this subject studying from u now sir🎉🎉
37:51 minus sign is there because force is in the opposite direction of the displacement so we've taken cos theta as 180 which is equal to -1 so the answer has a minus sign.
28:35 - can we say that 'the value we get using Workdone formula, will also state, whether its +, -, or 0?' for instance, in case of positive, even the value is positive, while in negative workdone, the value is also negative.
51:29 sir work done by the applied force is 200 J ; work done by frictional force is -50 J and work done by force of gravity is 0 J And the net work done is 150 J
H/w : Net force: big - small = 20 N - 5N = 15N W1= fs cos thita = 15N × 10m× cos0( because force and dislacement acting on same direction) = 15N× 10m×1(cos0=1) = 150j W2 = fs cos thita = mg×s× cos90( because the force is acting in downward direction and displacement is forward. so it will make 90 ° and cos90 =0) = 5kg ×10 ×10 m× 0 = 500 ×0 = 0j The total work done = 150j +0j = 150 j.
the sign "-" came because the angle creates between the force and displacement is 180 degrees. Since cos180 is equal to -1,then answer will come in negative form.
That negative sing had occurred because the value of cos180° = -1 If we multiply it Fs cos theta Then, 20×10×7× -1 = -1400 Jule The - sign denotes that both forces are working on opposite direction In simple words it defines retardation 37:45 Am I right? 👇🏻
Sir there is a sign of minus because the force is acting downwards and the displacement is being upwards so the angle between them is 180 degree and the value of Cos180 is -1.
@@WanzeenWhen we say Zillion, we are generally using it to emphasize a vast quantity without providing a numerical value or simply it means many many thanks or something........
@@VishnuSharma-dr2yi yup , we did but only in finding the downward force , which is mg(mass×gravity) . We did not use mass in finding the other forces .
51:57 THE ANSWER IS : SOL- F³ = MG F³ = 5*10 F³ = 50N Answer of F¹ is : 200J Answer of F² is : -50J Answer of F³ is : 0J Net work done is = =200J+0J+(50J) =(200J)+(-50J) =(200J)-(50J) =150J ANSWER
Sir i am waiting for chapter 𝙎𝙊𝙐𝙉𝘿 from many days sir please give a lacture on sound with numericals practice as soon as because my science exam is on 16 jan. 𝙄 𝙖𝙢 𝙣𝙤𝙩 𝙖𝙗𝙡𝙚 𝙩𝙤 𝙪𝙣𝙙𝙚𝙧𝙨𝙩𝙖𝙣𝙙 𝙩𝙝𝙖𝙩 𝙛𝙧𝙤𝙢 𝙖𝙣𝙮𝙬𝙝𝙚𝙧𝙚 𝙄 𝙖𝙡𝙨𝙤 𝙬𝙖𝙩𝙘𝙝𝙚𝙙 𝙮𝙤𝙪𝙧 𝙡𝙖𝙨𝙩 𝙮𝙚𝙖𝙧 𝙨𝙥𝙧𝙞𝙣𝙩 𝙗𝙖𝙩𝙘𝙝 𝙨𝙚𝙨𝙨𝙞𝙤𝙣 𝙗𝙪𝙩 𝙩𝙝𝙚𝙞𝙧 𝙣𝙪𝙢𝙚𝙧𝙞𝙘𝙖𝙡𝙨 𝙖𝙧𝙚 𝙣𝙤𝙩 𝙖𝙫𝙖𝙞𝙡𝙖𝙗𝙡𝙚. 𝙈𝙪𝙟𝙝𝙚 𝙨𝙖𝙢𝙖𝙟𝙝 𝙩𝙤 𝙖𝙖 𝙜𝙖𝙮𝙖 𝙗𝙪𝙩 𝙣𝙪𝙢𝙚𝙧𝙞𝙘𝙖𝙡𝙨 𝙣𝙖𝙝𝙞 𝙗𝙣 𝙧𝙖𝙝𝙚 𝙨𝙤𝙪𝙣𝙙 𝙘𝙝𝙖𝙥𝙩𝙚𝙧 𝙠𝙚. 😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭 𝙎𝙞𝙧 𝙥𝙡𝙚𝙖𝙨𝙚 𝙝𝙚𝙡𝙥 𝙢𝙚 𝙊𝙩𝙝𝙚𝙧𝙬𝙞𝙨𝙚 𝙞 𝙘𝙤𝙪𝙡𝙙 𝙣𝙤𝙩 𝙜𝙚𝙩 𝙗𝙚𝙩𝙩𝙚𝙧 𝙢𝙖𝙧𝙠𝙨 𝙞𝙣 𝙢𝙮 exams🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏😒😒😒😒😒😒😣😣
37:50 whenever there is a negative sign in case of workdone , it shows that the angle between force and displacement is 180' and the value of cos 180' si -1 The impact of it is that it would responsible for the reduction in the speed of the object as the force is exerted on the object in opposite direction.
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You're great sir 👏 👍
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I complete whole trigonometry
Sir i complete half syllabus of class 10th physics and math 🙂
Newton's 4th law says that every book continue to be in rest until and unless internal or external exam appears and speed of page turning is directly proportional to the syllabus to be covered and tension in the mind remains constant.
right bro 😂
Bro ek dum correct, waise same here also
Newton Baba crying 😭😭😥😩in the corner of heaven... After seeing this.. 😆😆🤣😂
You are the second born of Newton baba.. for searching his 4th law one day this law will be in physics book.. 🤣😂😂😂👍👍
op bro
52:05 work done by applied force
Work done = Fs cos ∅
= Fs cos 0⁰
= 20×10×1
Work done by applied force = 200 J
Work done by gravity
Work done = Fs cos ∅
(mg)× s cos 90⁰
( 5×10) × 10 × 0
Work done by gravity = 0 J
Work done by friction
Work done = Fs cos∅
Fs cos 180⁰
5× 10× -1
Hence, work done by friction = - 50 J
Net workdone= 200+(-50)+0
200-50= 150 Joules Answer
❤❤❤ THANKS FOR ANSWER
53:27
Thanks sister
This is also my answer❤
Tqqq
51:53
Force applied =200J
"(W=fscosQ
20×10×0°
200J)""
Friction applied = -50J
"(W=fscosQ
Fscos180°
= -1
5×10×-1
-50J)""
Gravitation applied= 0J
So, net work =200+(-50)×0
150J
Thus...net work = 150J
Bro I wanna ask you a question didn't we calculate the mass in it please reply
@@VishnuSharma-dr2yi
Listen I'm not sure about this..as far as I know, mass is not calculated..
Well if you have any doubt then I would ask this to my teacher to clear some doubts🙏🏻
Thank you so much I think that so and my answer is also coming this but sir calculated mass in every question that's why I have doubt in this and I also ask my teacher about this
@@VishnuSharma-dr2yi because we simply take the force and force is[ mass * g ] sir is simply doing it in this form
52:04
Applied force= 200J (+work)
Friction force= -50J (-work)
Gravitational force= 0J (0 work)
Net work done=
200+(-50) +0= 150J
Please Explain me the question I can't understand the question😢😢
Dekho! Yaha pr question mein bola gya h ki 'ek block h ya tum maanlo ek box hai usmein jetni bhi forces lag rhi hai voh sb bata na h, toh figure ke according block mein 3 Forces lg rhi h
1.Gravity(g)
2.Applied force (jo box ko move krne keliye lgaya gya h) 3. Frictional force
Tmhe sbka workdone batana h, toh phele separately nikalo example-
applied force-
w=fs
w=20x10
w=200
waise hi bakyion ka nikalo aur sabko add krdo kyuki Net workdone pucha h (net ka mtlb whole ya pura)
@@Anwesha01 Thankyou so much 🥹🫶
@@sheshkumarSingh-sf8xt Dekho! Shesh waha pr workdone pucha h aur maine workdone ka formula use kiya h which is
W=fs
and question mein given h ki
F=20N
S=10m
Thus,
W=fs
W=20x10
W=200J
@@Anwesha01 Thankyou aab crystal clear ho gya
46:57 Cos 0°=1
Cos 30°=√3/2
Cos 45° = 1/√2
Cos 60° = 1/2
Cos 90° = 0
Cos 120° = - 1/2
Cos 180° = -1
Thankyou if it is helpful please like ⬇️
Thank you ❤
Copied from book😅😅
Thanks a lot bhai😊😊
Thanks Bhai
Right👍@@SidhuSobhaSinghSidhu
Introduction - 00:00-02:03
Workdone - 02:04-16:47
Calculation of Work: Positive Work - 16:47-23:54
Calculation of Work: Negative work - 23:55-27:04
Calculation of Work: Zero Work - 27:05 to 34:42
Why do we pay coolie/porter ? - 38:28 to 43:32
ENERGY - 53:24 to 57:02
Kinetic Energy - 57:03 to 59:55
Finding experssion of Kinetic energy - 59:56 to 01:05:40
Potential Energy - 01:19:51 to 01:26:46
Finding experssion of Potential energy (position) - 01:26:47 to 01:29:00
Potential Energy - 01:35:11 to 01:35:36
Understanding Potential Energy (Configuration) - 01:35:37 to 01:37:49
Law of conservation of energy - 01:37:50 to 01:41:10
Examples of conservation of energy - 01:41:11 to 01:47:06
Proof of conservation of mechanical energy - 01:47:07 to 01:57:03
Power - 01:57:04 to 01:59:19
Relation between Kinetic Energy and Momentum - 02:11:29 to 02:14:35
Relation Between Power, force and velocity - 02:14:36 to 02:16:03
Thanks bro
Thanks bro ❤❤❤
Thanks dear ❤
Already given in the video
@@goodguy-rr2pc aacha to vaha se dekh le yaha kiya kerna aaya
No ''school wali madam'' is harmed in this video 💀
Yessss😂😂😂
Uh
30:49
hshsshhssuhsheheh
😂 fr
31:30
Our teacher explained that ,work can be zero when displacement=0 and force is applied.
Eg:- Pushing a wall.
In this way work done is zero
S2U
yes this is also true as even if the cos theta value is 1 but displacement is 0 which will make work done 0 as well
Best teacher in the world
Alakh sir also 😊
@@anshu6279 yes all teachers of pw
Agreed
Right 👍
Ofcourse yrr he is . No doubt 💐💐
time stamps
Introduction - 00:00-02:03
Workdone - 02:04-16:47
Calculation of Work: Positive Work - 16:47-23:54
Calculation of Work: Negative work - 23:55-27:04
Calculation of Work: Zero Work - 27:05 to 34:42
Why do we pay coolie/porter ? - 38:28 to 43:32
ENERGY - 53:24 to 57:02
Kinetic Energy - 57:03 to 59:55
Finding experssion of Kinetic energy - 59:56 to 01:05:40
Potential Energy - 01:19:51 to 01:26:46
Finding experssion of Potential energy (position) - 01:26:47 to 01:29:00
Potential Energy - 01:35:11 to 01:35:36
Understanding Potential Energy (Configuration) - 01:35:37 to 01:37:49
Law of conservation of energy - 01:37:50 to 01:41:10
Examples of conservation of energy - 01:41:11 to 01:47:06
Proof of conservation of mechanical energy - 01:47:07 to 01:57:03
Power - 01:57:04 to 01:59:19
Relation between Kinetic Energy and Momentum - 02:11:29 to 02:14:35
Relation Between Power, force and velocity - 02:14:36 to 02:16:03
When you have a much time😅😅
😂
2:11:33= Power consumed in 1 month= 48 units
Cost of 1 unit= 3 Rupees/Unit
Total Cost= 3×48units= 144 rupees
51:26 (i) 200j positive work done
(ii) -50 j negative work done
(iii) 0j zero work done
(iv) net work done =200j+(-50) +0 =150j net work done
Correct
Thanks
Yes bro your answer is correct... 🔥🔥❤️👍👍
I am a Class 11th Arjuna JEE Student, here to see my favourite physics teacher after 8-10 months.
Love you Sir❤️❤️❤️
Don't waste your time here 🙂
@@aaryanrateria5147 😎
@@aaryanrateria5147 mere paas boht time hai, tum apne time ki chinta kro
@@anshu5860 Yai sab batai jee mai yaad ayengi
@@aaryanrateria5147 just be quite if u don't want to watch go but we want to study okhay
37:46 The minus sign indicates that the speed of the object is slowing down due to negative workdone. In other words we can say that ,the object is experiencing retardation.
51:40 Workdone by applied force = 200J
Workdone by friction force = -50J
Workdone by weight force = 0 J
Net Work done = 150J
2:11:18 Total Cost = 48*3
= Rs.144
You are my favourite teacher sir....I always respect you...🙏❤️🔥
You are my best teacher sir . Thanks sir . I always respect you 😊
Kon kon class 11th ke liye apne base ko strong kar rha hai ya one shot lectures ke through... ?!
Meh
Meh 11th ki standard aj yai pard rhe hu۔۔😢
😂
I'm here too😆
No one
Finding experssion of Kinetic energy - 59:56 to 01:05:40
51:29
Workdone by applied force = 200 J
Workdone by friction = -50 J
Workdone by weight force = 0 J
Net Workdone = 150 J
same here
Thanks sis
❤
Same
Same here
Same here
1:23:21 Female teachers examples:😀
Male teachers examples:💀
44:25
@Nshchaysingh 🤣
at 1:35:08 the ans should be 300J as the obj is lowered down to the height of 5m instead of bringing it down 5m. Now s will be equal to 10 and the ans will be 60X10 = 600J and now on subtracting W2 from W1 (900-600) the ans will be 300J
Ha Bhai mai bhi yhi sochra tha
me bhi ye hi soch rha tha
Mai v yarr 😂
51:30 positive work done=200j
51:30 negative work done=-50j
51:30 work done by gravity=0j
52:16 net work done=150j
Absolutely right answers... I got them all same
Same to same
How did you get the negative workdone -50j?
Can you pls explain?
@@lizarahman__ because the force of friction is 5N and is applied in the opposite direction so the angle(cos theta) will be 180° which is equal to -1
So by multiplying 5 x 10 x -1
You get -50J
37:45 THIS MINUS SIGN IS BECAUSE OF THE VALUE OF COS 180DEGREE THAT IS -1
THE MINUS SIGN INDICATES THE NAGATIVE WD AND THE DIRECTION OF DISP IS OPPOSITE FROM THE DIRECTION OF FORCE
51:57 work done by friction= -50J
work done by force= 200J
work done by gravity= 0J
Net work done= 150 J
Bro I wanna ask you a question didn't we calculate the mass in it please reply
@@VishnuSharma-dr2yi
workdone=FxSxcos theta
so, workdone by friction=5x10xcos180o
=50x-1
=-50J
so here we can see that mass is not included in the calculation and so mass is not required in questions of mass.It may be given to trick the students.
51:48 work done by friction is -50 J
Work done by Force put on it 200 J
Work done by gravity is 0 J
Thank you for giving the right answer 🤗
Thanks bro for Giving me idea
*ACTION* : SIR'S EFFORT FOR TEACHING ME.
*REACTION* : I GOT FULL MARKS IN PHYSICS.
SIR YOU ARE GREAT.
SUCH A GREAT TEACHING SKILLS.
Good , me to
😊
But why they are not opposite
U should also say.... Sir tussi great oo.. ❤😂
😊
51:46
Workdone by applied force =200J
Workdone bu friction =-50J
Workdone by gravity = 0J
Total or net workdone =150
Correct answer 😉
😀
Don't consider int this question the frictional force because unbalance conditions has already big subtract the smaal that means
200 - 50 = 150 j
H/W
W1= Fs costheta
=20×10×cos0°(As F and s are acting in same direction so angle b/w them is 0°)
=20×10×1(Value of cos 0° is 1)
=200J(Ans.)
W2= fs cos theta
=5×10×cos180°(As f and s are acting in opp. direction and angle b/w them is 180°)
=5×10× -1
= -50J(Ans.)
W3= f¹(let force be f¹)×s× costheta
=mg ×10×cos 90°(As weight of body is acting perpendicular to the displacement of body)
=5×9.8×10×0(Value of cos90° is 0)
=0J
Work done by all the forces acting on the block is W1=200J; W2= -50J; W3=0J
Net workdone is {200+(-50)+0} J
=150 J
Bhai 5 N opposite direction ma hai tho minus hoga 20-5=15N hoga then mg se cos 90° hoga then 90°=0 0×15×10=0 J hoga workdone
Thanks dude
51:29
....
Total work done = 150j..
Am I right??....
✈️
Bro g is always -9.8 so why u took in (+)ve ?? Plz explain 🙏
51:27 net workdone is 150J and workdone towards gravity is zero , 'W' towards right is 200J
"W"towards left is -50J
It's totally correct I also got same answer thank you for being a confirmation for my answer
-150 negative hoga bro
@@Sachin044 no bro
Net work done =200+(-50) +0
=200-50
W =150 J
@@Sachin044 ho sakta hai depends krta hai ki aapne direction konsi -ve mein li hai aur konsi +ve mein
@@Jigneeshhh Mera bhi jahi hai
Timestamps
Introduction - 00:00-02:03
Workdone - 02:04-16:47
Calculation of Work: Positive Work - 16:47-23:54
Calculation of Work: Negative work - 23:55-27:04
Calculation of Work: Zero Work - 27:05 to 34:42
Why do we pay coolie/porter ? - 38:28 to 43:32
ENERGY - 53:24 to 57:02
Kinetic Energy - 57:03 to 59:55
Finding experssion of Kinetic energy - 59:56 to 01:05:40
Potential Energy - 01:19:51 to 01:26:46
Finding experssion of Potential energy (position) - 01:26:47 to 01:29:00
Potential Energy - 01:35:11 to 01:35:36
Understanding Potential Energy (Configuration) - 01:35:37 to 01:37:49
Law of conservation of energy - 01:37:50 to 01:41:10
Examples of conservation of energy - 01:41:11 to 01:47:06
Proof of conservation of mechanical energy - 01:47:07 to 01:57:03
Power - 01:57:04 to 01:59:19
Relation between Kinetic Energy and Momentum - 02:11:29 to 02:14:35
Relation Between Power, force and velocity - 02:14:36 to 02:16:03
Thankuh so much but this is already given so chill ❤️
@@suhani467hi
31:06 my school madam taught us the same concept in class, I really appreciate her after studying the same here 😃
My sir has also taught so deeply
My ma'am has also taught us just like sir ❤🎉🎉
Maam ne yhi se bada hoga😅
You are the King of Physics 😎
I recpect you sir 😎
You have to Recpect
Se🎉🎉🎉
@@mdgufran1485 alakh pandey left the chat
I am interested
#Sumit Editz
Workdone by gravity=0J and workdone by friction = -50J and workdone by 20N=200J, net workdone =150J
But how
bro ek bar aur lecture attend kr lo mai kaise explain Karu
52:14 - Positive workdone:- 200J if F=20N , s= 10m .
Negative workdone:- -50J if
F =5N , s=10m
Zero workdone :- 0J if F= 15kg × 10m/s^2 , s= 10m
Net workdone= 150J .
Bro that's is displacement not acceleration jo tumne m/s² use kiya hai
Gravity hai bhai@@BearBytesYt
Because of upward direction and force being downwards so 180° tells -1.🎉
It tells that the work is done in the opposute direction of force. 38:04
Speed is slowed down
37:53 Work done is negative 1400 because the gravity is acting in the opposite direction of applied force
00:07 Introduction to Sprint Series on Class 9th Physics
00:51 Understanding Work, Energy, and Power in Class 9th NCERT Chapter 11
02:26 Work, Energy and Power are related in various activities like revision, brain training, meditation, breathing and physical work.
03:14 Force and displacement lead to work
04:41 Understanding Work in the Same Direction
05:30 Calculating work in different directions of force and displacement
07:02 Understand Work done in the same direction of displacement
07:43 Understanding the relationship between force, displacement, and work.
09:28 Understanding force and displacement in different angles
10:12 Understanding angles and cosines in physics.
11:57 Work done is defined as the product of force and displacement in the direction of force
12:38 Understanding Work-Done Calculation in Work, Energy, and Power
13:58 Scalar and vector products of two vectors
14:50 Understanding Work, Energy, and Power in Physics
17:04 Understanding work and displacement in relation to force
17:54 Force and displacement are related in the direction and magnitude.
19:58 Positive work leads to object speeding up
20:51 Energy is converted into work done by our body.
22:26 Discussion on friction and displacement of objects
23:11 Understanding friction and displacement values
24:54 Understanding the formula of work done with Cos Theta
25:37 Understanding the role of frictional force in changing speed
27:24 Work done is the product of force and displacement.
28:36 Force and its Direction
31:04 Understanding work, energy, and power in school curriculum
32:11 Direction determines work done, not value.
34:17 Understanding Work and Zero Work
35:20 Understanding force, displacement, and conversion
37:22 Understanding 180 degrees and its implications
38:20 Understanding the concept of work, energy and power
40:00 Understanding work, energy, and power conceptually
40:43 Understanding Work in Motion
42:14 Understanding the direction of force and displacement
42:52 Chemical work done and forces involved
44:22 Preparing to carry a body for burial
45:00 Understanding work and force in terms of displacement and angles
47:32 Calculating force required to lift an object
48:51 Discussing the effects of applying force less than or greater than 150 units
50:24 Calculating work done by force
51:43 Calculating work done and displacement in a gravitational field.
53:11 Understanding the concept of energy and work in physics
54:09 Conversion of food into energy
55:37 Understanding Work, Energy, and Power conversion
56:21 Introduction to Work, Energy, and Power concepts
58:32 Understanding Kinetic Energy in Motion
59:22 Derivation of kinetic energy formula and work done formula
1:02:09 Deriving formula for work done using force and displacement
1:03:32 Understanding manipulation of equations for work, energy, and power calculations
1:06:32 Understanding Work and Energy in Simple Terms
1:07:36 Conversion of work done to kinetic energy
1:09:30 Understanding the concept of kinetic energy and its general expression
1:10:31 Work done results in change in kinetic energy
1:12:12 Understanding Work and Energy
1:13:01 Conversion of work to kinetic energy
1:14:27 Understanding work, energy, and power concepts
1:15:18 Calculation of work, energy and power equations
1:17:41 Calculation of final energy using formula
1:18:35 Calculate percentage change using the initial and final values
1:20:34 Work, force, and displacement relationship
1:21:09 Kinetic energy is converted into potential energy through work done.
1:22:36 Understanding Potential and Kinetic Energy
1:23:28 Transfer of potential energy to kinetic energy explained
1:24:59 Understanding different types of energy
1:25:44 Kinetic energy is derived from the motion of an object.
1:27:19 Understanding displacement and force equivalence
1:28:02 Work is related to energy and force in every derivation.
1:29:43 Understanding work, energy, and power in a nutshell
1:30:47 Force always acts in the upward direction.
1:32:09 Understanding displacement and work done
1:33:24 Introduction to Potential Energy
1:35:08 Understanding independent path and displacement dependent path
1:35:50 Potential energy is dependent on height
1:37:35 Conversion of energy between potential and kinetic forms
1:38:17 Energy is derived from chemicals in food through photosynthesis in plants, and can be transformed into different forms.
1:39:39 Understanding Energy Transfer in Connected Work Chains
1:40:25 Conversion of muscular energy into kinetic energy
1:42:27 Electricity is converted to thermal energy in heaters
1:43:17 Hydroelectric power generation process explained
1:45:14 Conversion of chemical energy to kinetic energy
1:46:07 Conversion of thermal energy to electrical energy
1:48:24 Understanding potential and kinetic energy
1:49:06 Understanding potential energy and its connection with mechanical energy.
1:52:26 Understanding displacement and velocity calculations
1:53:18 Calculating displacement and speed
1:55:09 Changes in potential and kinetic energy
1:56:10 Conservation of total mechanical energy
1:57:45 Understanding the concept of power in physics.
1:58:32 Understanding Power and Horsepower Units
2:00:24 Understanding the concept of force and weight
2:01:13 Understanding power and energy in physics
2:03:15 Introduction to energy unit and its importance in classes 9th to 12th
2:03:55 Commercial vehicle can use energy unit for trading and consumption of energy.
2:06:10 Understanding commercial electric units and monitoring household appliances
2:06:57 Understanding kilowatt-hour and its implications on electricity consumption and cost
2:08:44 Understanding power and energy calculations
2:09:40 Understanding energy consumption and cost calculation
2:11:38 Understanding the relationship between kinetic energy and momentum
2:12:37 Kinetic energy changes as variables change
2:14:28 Relation between Power, Force, and Velocity
2:15:12 Relationship between force, velocity, and power explained through dot product
2:16:51 Practice numericals for better understanding
1:26
Ooooo behen Tu pure lecture bhar yahi karte rahte ha kya kuch toh gadbad hai daya
Work done by sir = 200J
Work done by friction = -50J
Work done by gravity = 0J
Total work done = 150J
Displayment
Kya ha sir
Same answer❤
Wrong work fone by sir is 2000 j
@@Aryan-p7k3e ur answer is actually wrong. check it again
37:54 Here the work done came as -1400 Joules indicate that the force and displacement are in the opposite actors. And it is termed as negative workdone. Here also the cos 180° termed or known as the value of -1 as per the shown tablular form.
Yes you are right here value -1400 jule because the value of cos 180 is -1 so answer come in negative
1:33:01 sir the object is brought down to the height of 5m so from 15 m it will come down to 5 m so the equation formed will be w=60x10xcos 180
w=600x-1
w=-600
Mujhe bhi yahi doubt tha isiliye comment padhne aaya . Q me likha hai 5 m ki height pe laaya gaya hai to s =10m hona chahiye
@@bittuankusht6791same bhai
1:34:52 it states the hieght is not decreased by 5m rather its decrease by 10m and the current height is 5m
Force applied by sir = 200J
Force applied by friction= -50J
Force applied by gravity= 0J
Net workdone
U 59:18
Apko net workdone nahi ata kya
Net = 150J
👇
U 59.67
37:57 It is because here the force is acting in opposite direction to displacement so here we will use formula :-
*W= F•sCOSTHETA*
= F•sCOS 180°
= F•s×-1 😊😅❤
Because it is negative work
cos 270 degree ki value pata hai?😂😂
Sir ka chaap Diya ....
@@uniqueness1671
For Ur Comment :-
So Beautiful , So Elegant , Just looking like a WOW 😂
@@MYTHBuSS thankyou
51:49
Work done by force=200J
Work done by friction=-50J
Work done by gravity=0J
Net work done= 150
👍 sahi hai bro mera bhi same aaya
Work done due to gravity samjha do pls
@@Ashubhai_shorts bhai gravity me F= mg hota hai jaha m= mass ,g=10n or angle between object and gravity is 90° which is = 0 so w= mg×s×0 = 0 work done
@@shoaibmalik6795 samajh aa gaya thankyou
@@CR7DHRUVbhai net force kese nikalte hai
Best teacher , Best platform and Best explanation - one and only PW❤️
51:53 HOMEWORK ANSWERS.
1) W1 = 200J ( by force applied)
2) W2 = -50J (by force of friction)
3) W3 = 0J( by force of gravity)
Net work done = 200+(-50)+0= 150J
Thank you sir ☺️☺️
@@rbgamer5683 it's ok ❤️
❤❤❤❤❤
51:56 workdone by following forces
g=0 J
Friction=-50J
Main force=200J
Net workdone=150J on same side of displacement
Bro friction kese nikali
@@rajnisaini9863given
School main kuch bhi nahi padhate😢😢 Thnak u sir🎉🎉❤❤❤ keep it up😊😊
siddha siddha bol tu school nahi jaa ya 😂😂😂
Kon kon Manta hai ki school mein padhai nahi hoti hai 😂
Beta agr Aisa lgta hai tujhe to ek baar school me padha ke dekh le pta chal jayega 😏😏😏😏
Nahi bhai sare mai aisa nahi hota hai
Sarai mai aisa. Nahi. Hota mera. School best. Hai😊
Dekho padhai hoti but online jitna deep nhi 😇😎😇😄
Me
Best teacher of physics in world 🌍🌍❤️❤️👍👍☺️☺️🥰🥰
51:27 the positive workdone will be 200J
The negative workdone will be -50
The zero workdone will be 0
The net work done will be 200+(-50)=>200-50=150J
Please explain how
1:29:29 sir Aaj aapne 'g' ka value negative kyu nahi liya pichle lectures me to bola tha ki Cartesian plan ko follow karenge ??
Or kaha tha ki har baar g ka value negative lena ???
Ha bhai g hmesa -9.8 hi Lena hai
51:30 Question
Right side workdone = 200J
Left side workdone = -50J
Downward workdone = 0J
NET WORKDONE = 150J
❤
37:54 it is in negative sign because the ball is moving upward but the gravitational force is applied from the downward direction so it makes 180 degree angle. And the value of Cos180 degree is -1
I was also thinking this...but I was still doubting myself...you cleared my doubt..... thanks 🙂🙂
Exillent
Exam are near😮
But no fear🎉
Because pw is here❤❤😂😂
Bahi tum dss me padthe ho
Wow nice ❤
37:54 cos180 value is -1. the force is acting opposite to the ball which means we have to use cos180
Literally uuh r amazing faculty sir 😊😊
Work Done By Force = 200J
Work Done By Friction = -50J
Work Done By Gravity = 0J
Net Work Done = 200+(-50)+0 = 150J
Same answer here
thank youuu
Hi@@Thespidystudent
2:11:10 sir it was asked to find the whole month's energy consumption and power also but nice work i really appreciate. thankss for teaching us!!👍👍
51:27 work done by gravity=0J
Work done by friction= -50 J
Workdone by sir =200J
30:00 madam ne bataya 0 work tab hoga gab work nhi hoga 😅😅
37:54 minus sign indicates that the work is done in the opposite direction of displacement.
Thank you so much sir for your efforts and positive thoughts...
49:00 sir isme wo object uper ke taraf ja rha hai to wo accelerate hi to kar rha hai kyuki uska initial position rest tha to 150N se jada force ka jarurat padega na
Pls clear this doubt
Really i learnt many things and the energy of teacher gives more energy to me for studying 🙂🙂
🎉🎉 I was searching for all the videos uploaded by u sir and u r an excellent teacher seriously!!! I hv watched all your videos even of all classes that u teach because I like ur way of teaching physics which gives me interest in physics and I m liking this subject studying from u now sir🎉🎉
😇
So you are a genius 😊
37:51 minus sign is there because force is in the opposite direction of the displacement so we've taken cos theta as 180 which is equal to -1 so the answer has a minus sign.
59:30 actually the formula is half mv² * half mu² but as u is 0 we write half mv²
In 51:53
Applied force=20×10=200J
Friction force=5×-10=-50J
Gravitational force=5×10× cos90°=0
Net workdone=200+(-50)+0=150J
Legengs Are Watching on 2x one day Before Exam 😂😂
Then still fail 😂
I subscribe your channel
@@Adityaartcreation8825-_ bhai teri english to kaamal ki hai😅
You make the concepts very clear and understandable 😊.... Best ever teacher of physics ❤️
Are pehle dekh toh lo lec🤣
Agreed
Papa ki pari ha na
@@CruxTV ye yha pe padhte km comment bdi lambe-lambe karte hai...😂
1:14:19 ye smartboard pe kiski parchai chup ke jaa rhi 😂😂
28:35 - can we say that 'the value we get using Workdone formula, will also state, whether its +, -, or 0?' for instance, in case of positive, even the value is positive, while in negative workdone, the value is also negative.
51:29 sir work done by the applied force is 200 J ; work done by frictional force is -50 J and work done by force of gravity is 0 J
And the net work done is 150 J
Sahi ja
sir at 1:32:29, the height should be 10 m as it is reduced by 5m from the height 15m.From the ground the height will be 10 m.
S bro u r 👍 same was my doubt
Finding expression of Potential energy (position) - 01:26:47 to 01:29:00
H/w :
Net force: big - small
= 20 N - 5N
= 15N
W1= fs cos thita
= 15N × 10m× cos0( because force and dislacement acting on same direction)
= 15N× 10m×1(cos0=1)
= 150j
W2 = fs cos thita
= mg×s× cos90( because the force is acting in downward direction and displacement is forward. so it will make 90 ° and cos90 =0)
= 5kg ×10 ×10 m× 0
= 500 ×0 = 0j
The total work done = 150j +0j
= 150 j.
ayansh bhundsal (my real name)
the sign "-" came because the angle creates between the force and displacement is 180 degrees. Since cos180 is equal to -1,then answer will come in negative form.
Hlo
1:14:20 shadow se pata chalta hai ki .........
Kya
That negative sing had occurred because the value of cos180° = -1
If we multiply it Fs cos theta
Then,
20×10×7× -1
= -1400 Jule
The - sign denotes that both forces are working on opposite direction
In simple words it defines retardation 37:45
Am I right?
👇🏻
Kop ❤️❤️❤️the most awaited lecture thank you KOP ❤️
No one can explain like you ❤😊
Sir there is a sign of minus because the force is acting downwards and the displacement is being upwards so the angle between them is 180 degree and the value of Cos180 is -1.
at 37:51 minus sign came because negative work took place as gravity acted towards opposite direction and angle was 180 degree
Happy New Year sir, the lecture was amazing, thank you, I understood every concept now I'm practicing it & will become a grandmaster.
Best Physics Teacher in the Universe......❤
Sir you are awesome 😭
Thanking you zillion times for making me understand the concept..Hoping to do well in my exams🛐✨
bro what do u mean by zillion time😅😅
RIGHT, IT ALSO CONFUSED ME ..............@@Wanzeen
@@WanzeenWhen we say Zillion, we are generally using it to emphasize a vast quantity without providing a numerical value or simply it means many many thanks or something........
Hfhg shathe
14000 j aaya becoz
According to formula of work done =f.s.cos180°
Then f = mg 20
S=10
180°=-1
Now 20×10×7.0×-1
=1400 joule
That solve
All the best for ur tomorrow's exam 👍🏻
Thank you sir for clearing my all doubts about Commercial Unit of Energy
It’s 2024 and sir your video is still the best . Positive force is 200J, negative force is -50J ,gravity force is 0J and net force is 150 J.
Bro I wanna ask you a question didn't we calculate the mass in it please reply
@@VishnuSharma-dr2yi yup , we did but only in finding the downward force , which is mg(mass×gravity) . We did not use mass in finding the other forces .
Weight- mass×gravity
51:57
THE ANSWER IS :
SOL- F³ = MG
F³ = 5*10
F³ = 50N
Answer of F¹ is :
200J
Answer of F² is :
-50J
Answer of F³ is :
0J
Net work done is =
=200J+0J+(50J)
=(200J)+(-50J)
=(200J)-(50J)
=150J ANSWER
2:06:47 sir but ham to government house mai rehete hai 😅😂
People feeling proud after completing the whole chapter. 😊😅😊
Sir i am waiting for chapter 𝙎𝙊𝙐𝙉𝘿 from many days sir please give a lacture on sound with numericals practice as soon as because my science exam is on 16 jan.
𝙄 𝙖𝙢 𝙣𝙤𝙩 𝙖𝙗𝙡𝙚 𝙩𝙤 𝙪𝙣𝙙𝙚𝙧𝙨𝙩𝙖𝙣𝙙 𝙩𝙝𝙖𝙩 𝙛𝙧𝙤𝙢 𝙖𝙣𝙮𝙬𝙝𝙚𝙧𝙚 𝙄 𝙖𝙡𝙨𝙤 𝙬𝙖𝙩𝙘𝙝𝙚𝙙 𝙮𝙤𝙪𝙧 𝙡𝙖𝙨𝙩 𝙮𝙚𝙖𝙧 𝙨𝙥𝙧𝙞𝙣𝙩 𝙗𝙖𝙩𝙘𝙝 𝙨𝙚𝙨𝙨𝙞𝙤𝙣 𝙗𝙪𝙩 𝙩𝙝𝙚𝙞𝙧 𝙣𝙪𝙢𝙚𝙧𝙞𝙘𝙖𝙡𝙨 𝙖𝙧𝙚 𝙣𝙤𝙩 𝙖𝙫𝙖𝙞𝙡𝙖𝙗𝙡𝙚. 𝙈𝙪𝙟𝙝𝙚 𝙨𝙖𝙢𝙖𝙟𝙝 𝙩𝙤 𝙖𝙖 𝙜𝙖𝙮𝙖 𝙗𝙪𝙩 𝙣𝙪𝙢𝙚𝙧𝙞𝙘𝙖𝙡𝙨 𝙣𝙖𝙝𝙞 𝙗𝙣 𝙧𝙖𝙝𝙚 𝙨𝙤𝙪𝙣𝙙 𝙘𝙝𝙖𝙥𝙩𝙚𝙧 𝙠𝙚. 😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭😭
𝙎𝙞𝙧 𝙥𝙡𝙚𝙖𝙨𝙚 𝙝𝙚𝙡𝙥 𝙢𝙚
𝙊𝙩𝙝𝙚𝙧𝙬𝙞𝙨𝙚 𝙞 𝙘𝙤𝙪𝙡𝙙 𝙣𝙤𝙩 𝙜𝙚𝙩 𝙗𝙚𝙩𝙩𝙚𝙧 𝙢𝙖𝙧𝙠𝙨 𝙞𝙣 𝙢𝙮 exams🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏🙏😒😒😒😒😒😒😣😣
Yeah sir. Same case with me
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37:50 whenever there is a negative sign in case of workdone , it shows that the angle between force and displacement is 180' and the value of cos 180' si -1
The impact of it is that it would responsible for the reduction in the speed of the object as the force is exerted on the object in opposite direction.
U gained a sub
Thanks for the explanation
It was amazing 🤩.
51:30
Work Done due to gravity is 0 j.
Work done due to friction is -50 j.
Work done due to force is 200 j.
Net work done is 150 j .
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The force acting on the ball is downward and the displacement is happening upwards.This forms 180°.And the value of cos180 is -1 37:54
Excellent teaching 💯💯💯💯