WORK, ENERGY AND POWER in One Shot - From Zero to Hero || Class 9th

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  • เผยแพร่เมื่อ 4 ธ.ค. 2024

ความคิดเห็น • 5K

  • @PW-Foundation
    @PW-Foundation  ปีที่แล้ว +513

    Foundation Class 9th Sprint Batch 👉 bit.ly/3VS4OrG
    📲PW App Link - bit.ly/YTAI_foundation
    🌐PW Website - www.pw.live

    • @AnkitExplores96
      @AnkitExplores96 ปีที่แล้ว +15

      ❤❤❤❤❤❤💕💕🥰🥰🥰

    • @ishasingh12323
      @ishasingh12323 ปีที่แล้ว +7

      You're great sir 👏 👍

    • @student596
      @student596 ปีที่แล้ว +12

      Sir please neev batch me revision session start kar do. Please sir🙏🙏🙏

    • @student596
      @student596 ปีที่แล้ว +9

      I complete whole trigonometry

    • @student596
      @student596 ปีที่แล้ว +10

      Sir i complete half syllabus of class 10th physics and math 🙂

  • @shivamkushwaha9067
    @shivamkushwaha9067 ปีที่แล้ว +5220

    Newton's 4th law says that every book continue to be in rest until and unless internal or external exam appears and speed of page turning is directly proportional to the syllabus to be covered and tension in the mind remains constant.

    • @Ayush_Rathore885
      @Ayush_Rathore885 ปีที่แล้ว +129

      right bro 😂

    • @smilefreely701
      @smilefreely701 ปีที่แล้ว +94

      Bro ek dum correct, waise same here also

    • @kumarpiyush7315
      @kumarpiyush7315 ปีที่แล้ว +165

      Newton Baba crying 😭😭😥😩in the corner of heaven... After seeing this.. 😆😆🤣😂

    • @kumarpiyush7315
      @kumarpiyush7315 ปีที่แล้ว +140

      You are the second born of Newton baba.. for searching his 4th law one day this law will be in physics book.. 🤣😂😂😂👍👍

    • @biharievil6581
      @biharievil6581 ปีที่แล้ว +27

      op bro

  • @satyanarayansingh5232
    @satyanarayansingh5232 ปีที่แล้ว +132

    46:57 Cos 0°=1
    Cos 30°=√3/2
    Cos 45° = 1/√2
    Cos 60° = 1/2
    Cos 90° = 0
    Cos 120° = - 1/2
    Cos 180° = -1
    Thankyou if it is helpful please like ⬇️

  • @MonikaKhurana..
    @MonikaKhurana.. 10 หลายเดือนก่อน +102

    52:05 work done by applied force
    Work done = Fs cos ∅
    = Fs cos 0⁰
    = 20×10×1
    Work done by applied force = 200 J
    Work done by gravity
    Work done = Fs cos ∅
    (mg)× s cos 90⁰
    ( 5×10) × 10 × 0
    Work done by gravity = 0 J
    Work done by friction
    Work done = Fs cos∅
    Fs cos 180⁰
    5× 10× -1
    Hence, work done by friction = - 50 J
    Net workdone= 200+(-50)+0
    200-50= 150 Joules Answer

  • @Anwesha01
    @Anwesha01 11 หลายเดือนก่อน +135

    52:04
    Applied force= 200J (+work)
    Friction force= -50J (-work)
    Gravitational force= 0J (0 work)
    Net work done=
    200+(-50) +0= 150J

    • @sheshkumarSingh-sf8xt
      @sheshkumarSingh-sf8xt 6 หลายเดือนก่อน +2

      Please Explain me the question I can't understand the question😢😢

    • @Anwesha01
      @Anwesha01 6 หลายเดือนก่อน +4

      Dekho! Yaha pr question mein bola gya h ki 'ek block h ya tum maanlo ek box hai usmein jetni bhi forces lag rhi hai voh sb bata na h, toh figure ke according block mein 3 Forces lg rhi h
      1.Gravity(g)
      2.Applied force (jo box ko move krne keliye lgaya gya h) 3. Frictional force
      Tmhe sbka workdone batana h, toh phele separately nikalo example-
      applied force-
      w=fs
      w=20x10
      w=200
      waise hi bakyion ka nikalo aur sabko add krdo kyuki Net workdone pucha h (net ka mtlb whole ya pura)

    • @sheshkumarSingh-sf8xt
      @sheshkumarSingh-sf8xt 6 หลายเดือนก่อน +3

      @@Anwesha01 Thankyou so much 🥹🫶

    • @Anwesha01
      @Anwesha01 6 หลายเดือนก่อน +2

      ​​@@sheshkumarSingh-sf8xt Dekho! Shesh waha pr workdone pucha h aur maine workdone ka formula use kiya h which is
      W=fs
      and question mein given h ki
      F=20N
      S=10m
      Thus,
      W=fs
      W=20x10
      W=200J

    • @sheshkumarSingh-sf8xt
      @sheshkumarSingh-sf8xt 6 หลายเดือนก่อน +2

      @@Anwesha01 Thankyou aab crystal clear ho gya

  • @studyboy8248
    @studyboy8248 ปีที่แล้ว +55

    Introduction - 00:00-02:03
    Workdone - 02:04-16:47
    Calculation of Work: Positive Work - 16:47-23:54
    Calculation of Work: Negative work - 23:55-27:04
    Calculation of Work: Zero Work - 27:05 to 34:42
    Why do we pay coolie/porter ? - 38:28 to 43:32
    ENERGY - 53:24 to 57:02
    Kinetic Energy - 57:03 to 59:55
    Finding experssion of Kinetic energy - 59:56 to 01:05:40
    Potential Energy - 01:19:51 to 01:26:46
    Finding experssion of Potential energy (position) - 01:26:47 to 01:29:00
    Potential Energy - 01:35:11 to 01:35:36
    Understanding Potential Energy (Configuration) - 01:35:37 to 01:37:49
    Law of conservation of energy - 01:37:50 to 01:41:10
    Examples of conservation of energy - 01:41:11 to 01:47:06
    Proof of conservation of mechanical energy - 01:47:07 to 01:57:03
    Power - 01:57:04 to 01:59:19
    Relation between Kinetic Energy and Momentum - 02:11:29 to 02:14:35
    Relation Between Power, force and velocity - 02:14:36 to 02:16:03

  • @AnushkaModi-m7r
    @AnushkaModi-m7r 9 หลายเดือนก่อน +16

    51:53
    Force applied =200J
    "(W=fscosQ
    20×10×0°
    200J)""
    Friction applied = -50J
    "(W=fscosQ
    Fscos180°
    = -1
    5×10×-1
    -50J)""
    Gravitation applied= 0J
    So, net work =200+(-50)×0
    150J
    Thus...net work = 150J

    • @VishnuSharma-dr2yi
      @VishnuSharma-dr2yi 9 หลายเดือนก่อน

      Bro I wanna ask you a question didn't we calculate the mass in it please reply

    • @AnushkaModi-m7r
      @AnushkaModi-m7r 9 หลายเดือนก่อน +1

      @@VishnuSharma-dr2yi
      Listen I'm not sure about this..as far as I know, mass is not calculated..
      Well if you have any doubt then I would ask this to my teacher to clear some doubts🙏🏻

    • @VishnuSharma-dr2yi
      @VishnuSharma-dr2yi 9 หลายเดือนก่อน +2

      Thank you so much I think that so and my answer is also coming this but sir calculated mass in every question that's why I have doubt in this and I also ask my teacher about this

    • @ubaidullaharifsiddiqui7026
      @ubaidullaharifsiddiqui7026 หลายเดือนก่อน +1

      @@VishnuSharma-dr2yi because we simply take the force and force is[ mass * g ] sir is simply doing it in this form

  • @Bachpan_se_shayar
    @Bachpan_se_shayar ปีที่แล้ว +197

    Best teacher in the world

  • @Anita-v3w6r
    @Anita-v3w6r 10 หลายเดือนก่อน +20

    31:30
    Our teacher explained that ,work can be zero when displacement=0 and force is applied.
    Eg:- Pushing a wall.
    In this way work done is zero

    • @Parrrth-0001
      @Parrrth-0001 3 หลายเดือนก่อน +2

      S2U

    • @sakshigupta-q4i
      @sakshigupta-q4i หลายเดือนก่อน +2

      yes this is also true as even if the cos theta value is 1 but displacement is 0 which will make work done 0 as well

  • @vihaandilwaria9529
    @vihaandilwaria9529 9 หลายเดือนก่อน +18

    time stamps
    Introduction - 00:00-02:03
    Workdone - 02:04-16:47
    Calculation of Work: Positive Work - 16:47-23:54
    Calculation of Work: Negative work - 23:55-27:04
    Calculation of Work: Zero Work - 27:05 to 34:42
    Why do we pay coolie/porter ? - 38:28 to 43:32
    ENERGY - 53:24 to 57:02
    Kinetic Energy - 57:03 to 59:55
    Finding experssion of Kinetic energy - 59:56 to 01:05:40
    Potential Energy - 01:19:51 to 01:26:46
    Finding experssion of Potential energy (position) - 01:26:47 to 01:29:00
    Potential Energy - 01:35:11 to 01:35:36
    Understanding Potential Energy (Configuration) - 01:35:37 to 01:37:49
    Law of conservation of energy - 01:37:50 to 01:41:10
    Examples of conservation of energy - 01:41:11 to 01:47:06
    Proof of conservation of mechanical energy - 01:47:07 to 01:57:03
    Power - 01:57:04 to 01:59:19
    Relation between Kinetic Energy and Momentum - 02:11:29 to 02:14:35
    Relation Between Power, force and velocity - 02:14:36 to 02:16:03

    • @SavitaYadav-ev7bm
      @SavitaYadav-ev7bm 9 หลายเดือนก่อน +1

      When you have a much time😅😅

    • @surajroy5091
      @surajroy5091 6 หลายเดือนก่อน

      😂

  • @saloniMishra12
    @saloniMishra12 ปีที่แล้ว +178

    No ''school wali madam'' is harmed in this video 💀

  • @PhysicswallahStudent.
    @PhysicswallahStudent. ปีที่แล้ว +423

    *ACTION* : SIR'S EFFORT FOR TEACHING ME.
    *REACTION* : I GOT FULL MARKS IN PHYSICS.
    SIR YOU ARE GREAT.
    SUCH A GREAT TEACHING SKILLS.

    • @dhwaj9889
      @dhwaj9889 ปีที่แล้ว +4

      Good , me to

    • @lavishjoshi894
      @lavishjoshi894 ปีที่แล้ว +4

      😊

    • @rounak3706
      @rounak3706 ปีที่แล้ว +5

      But why they are not opposite

    • @Heyliieli
      @Heyliieli ปีที่แล้ว +5

      U should also say.... Sir tussi great oo.. ❤😂

    • @debaleenadebnath
      @debaleenadebnath ปีที่แล้ว

      😊

  • @ashokdas8228
    @ashokdas8228 11 หลายเดือนก่อน +17

    37:46 The minus sign indicates that the speed of the object is slowing down due to negative workdone. In other words we can say that ,the object is experiencing retardation.
    51:40 Workdone by applied force = 200J
    Workdone by friction force = -50J
    Workdone by weight force = 0 J
    Net Work done = 150J
    2:11:18 Total Cost = 48*3
    = Rs.144

  • @anupamkumari8701
    @anupamkumari8701 ปีที่แล้ว +18

    51:26 (i) 200j positive work done
    (ii) -50 j negative work done
    (iii) 0j zero work done
    (iv) net work done =200j+(-50) +0 =150j net work done

  • @neetuagrawal8276
    @neetuagrawal8276 ปีที่แล้ว +34

    2:11:33= Power consumed in 1 month= 48 units
    Cost of 1 unit= 3 Rupees/Unit
    Total Cost= 3×48units= 144 rupees

  • @gauravjha90314
    @gauravjha90314 ปีที่แล้ว +64

    51:30 positive work done=200j
    51:30 negative work done=-50j
    51:30 work done by gravity=0j
    52:16 net work done=150j

    • @ArtfulAnandaPrada
      @ArtfulAnandaPrada ปีที่แล้ว +1

      Absolutely right answers... I got them all same

    • @sushmapandey2079
      @sushmapandey2079 ปีที่แล้ว +1

      Same to same

    • @lizarahman__
      @lizarahman__ ปีที่แล้ว

      How did you get the negative workdone -50j?

    • @lizarahman__
      @lizarahman__ ปีที่แล้ว

      Can you pls explain?

    • @naitik_nova
      @naitik_nova ปีที่แล้ว +2

      @@lizarahman__ because the force of friction is 5N and is applied in the opposite direction so the angle(cos theta) will be 180° which is equal to -1
      So by multiplying 5 x 10 x -1
      You get -50J

  • @sakshisingh1960
    @sakshisingh1960 ปีที่แล้ว +77

    51:29
    Workdone by applied force = 200 J
    Workdone by friction = -50 J
    Workdone by weight force = 0 J
    Net Workdone = 150 J

  • @kabitadeka4958
    @kabitadeka4958 ปีที่แล้ว +106

    You are my favourite teacher sir....I always respect you...🙏❤️🔥

    • @Tremendous_vedio
      @Tremendous_vedio 10 หลายเดือนก่อน +3

      You are my best teacher sir . Thanks sir . I always respect you 😊

  • @binayyadav8173
    @binayyadav8173 9 หลายเดือนก่อน +17

    1:23:21 Female teachers examples:😀
    Male teachers examples:💀

  • @rubiakhatun1124
    @rubiakhatun1124 ปีที่แล้ว +42

    H/W
    W1= Fs costheta
    =20×10×cos0°(As F and s are acting in same direction so angle b/w them is 0°)
    =20×10×1(Value of cos 0° is 1)
    =200J(Ans.)
    W2= fs cos theta
    =5×10×cos180°(As f and s are acting in opp. direction and angle b/w them is 180°)
    =5×10× -1
    = -50J(Ans.)
    W3= f¹(let force be f¹)×s× costheta
    =mg ×10×cos 90°(As weight of body is acting perpendicular to the displacement of body)
    =5×9.8×10×0(Value of cos90° is 0)
    =0J
    Work done by all the forces acting on the block is W1=200J; W2= -50J; W3=0J
    Net workdone is {200+(-50)+0} J
    =150 J

    • @SadhanaKhare-so9hx
      @SadhanaKhare-so9hx ปีที่แล้ว

      Bhai 5 N opposite direction ma hai tho minus hoga 20-5=15N hoga then mg se cos 90° hoga then 90°=0 0×15×10=0 J hoga workdone

    • @Shortsworld__07
      @Shortsworld__07 5 หลายเดือนก่อน

      Thanks dude

    • @Vikram.222
      @Vikram.222 22 วันที่ผ่านมา

      51:29
      ....
      Total work done = 150j..
      Am I right??....
      ✈️

  • @GTA5-e9u
    @GTA5-e9u 9 หลายเดือนก่อน +6

    Finding experssion of Kinetic energy - 59:56 to 01:05:40

  • @learnenglishwithsiddiqueesir
    @learnenglishwithsiddiqueesir ปีที่แล้ว +134

    Force applied by sir = 200J
    Force applied by friction= -50J
    Force applied by gravity= 0J

  • @SeemaDevi-pn8qp
    @SeemaDevi-pn8qp ปีที่แล้ว +139

    Work done by sir = 200J
    Work done by friction = -50J
    Work done by gravity = 0J
    Total work done = 150J

  • @rajahuja6076
    @rajahuja6076 ปีที่แล้ว +30

    at 1:35:08 the ans should be 300J as the obj is lowered down to the height of 5m instead of bringing it down 5m. Now s will be equal to 10 and the ans will be 60X10 = 600J and now on subtracting W2 from W1 (900-600) the ans will be 300J

  • @Vini_Soni
    @Vini_Soni 10 หลายเดือนก่อน +7

    51:57 work done by friction= -50J
    work done by force= 200J
    work done by gravity= 0J
    Net work done= 150 J

    • @VishnuSharma-dr2yi
      @VishnuSharma-dr2yi 9 หลายเดือนก่อน

      Bro I wanna ask you a question didn't we calculate the mass in it please reply

    • @Vini_Soni
      @Vini_Soni 9 หลายเดือนก่อน +1

      @@VishnuSharma-dr2yi
      workdone=FxSxcos theta
      so, workdone by friction=5x10xcos180o
      =50x-1
      =-50J
      so here we can see that mass is not included in the calculation and so mass is not required in questions of mass.It may be given to trick the students.

  • @RAJEEVKUMAR-cl8mm
    @RAJEEVKUMAR-cl8mm ปีที่แล้ว +31

    51:27 net workdone is 150J and workdone towards gravity is zero , 'W' towards right is 200J
    "W"towards left is -50J

    • @secretidentity7946
      @secretidentity7946 ปีที่แล้ว +1

      It's totally correct I also got same answer thank you for being a confirmation for my answer

    • @Sachin044
      @Sachin044 ปีที่แล้ว +2

      -150 negative hoga bro

    • @Jigneeshhh
      @Jigneeshhh ปีที่แล้ว

      @@Sachin044 no bro
      Net work done =200+(-50) +0
      =200-50
      W =150 J

    • @Tamatar....895
      @Tamatar....895 ปีที่แล้ว

      @@Sachin044 ho sakta hai depends krta hai ki aapne direction konsi -ve mein li hai aur konsi +ve mein

    • @Tamatar....895
      @Tamatar....895 ปีที่แล้ว

      @@Jigneeshhh Mera bhi jahi hai

  • @you-x5q4l
    @you-x5q4l 11 หลายเดือนก่อน +9

    Timestamps
    Introduction - 00:00-02:03
    Workdone - 02:04-16:47
    Calculation of Work: Positive Work - 16:47-23:54
    Calculation of Work: Negative work - 23:55-27:04
    Calculation of Work: Zero Work - 27:05 to 34:42
    Why do we pay coolie/porter ? - 38:28 to 43:32
    ENERGY - 53:24 to 57:02
    Kinetic Energy - 57:03 to 59:55
    Finding experssion of Kinetic energy - 59:56 to 01:05:40
    Potential Energy - 01:19:51 to 01:26:46
    Finding experssion of Potential energy (position) - 01:26:47 to 01:29:00
    Potential Energy - 01:35:11 to 01:35:36
    Understanding Potential Energy (Configuration) - 01:35:37 to 01:37:49
    Law of conservation of energy - 01:37:50 to 01:41:10
    Examples of conservation of energy - 01:41:11 to 01:47:06
    Proof of conservation of mechanical energy - 01:47:07 to 01:57:03
    Power - 01:57:04 to 01:59:19
    Relation between Kinetic Energy and Momentum - 02:11:29 to 02:14:35
    Relation Between Power, force and velocity - 02:14:36 to 02:16:03

    • @suhani467
      @suhani467 11 หลายเดือนก่อน +2

      Thankuh so much but this is already given so chill ❤️

    • @STAN_GAMERZ
      @STAN_GAMERZ 7 หลายเดือนก่อน

      ​@@suhani467hi

  • @hemapant9794
    @hemapant9794 ปีที่แล้ว +23

    51:46
    Workdone by applied force =200J
    Workdone bu friction =-50J
    Workdone by gravity = 0J
    Total or net workdone =150

    • @RajKumar-cw4ke
      @RajKumar-cw4ke 11 หลายเดือนก่อน +2

      Correct answer 😉

    • @aaravpurohit5219
      @aaravpurohit5219 11 หลายเดือนก่อน

      😀

    • @FURKANREYA
      @FURKANREYA 9 หลายเดือนก่อน

      Don't consider int this question the frictional force because unbalance conditions has already big subtract the smaal that means
      200 - 50 = 150 j

  • @anshu5860
    @anshu5860 ปีที่แล้ว +368

    I am a Class 11th Arjuna JEE Student, here to see my favourite physics teacher after 8-10 months.
    Love you Sir❤️❤️❤️

    • @aaryanrateria5147
      @aaryanrateria5147 ปีที่แล้ว +18

      Don't waste your time here 🙂

    • @nitishsingh6887
      @nitishsingh6887 ปีที่แล้ว +3

      @@aaryanrateria5147 😎

    • @anshu5860
      @anshu5860 ปีที่แล้ว +15

      @@aaryanrateria5147 mere paas boht time hai, tum apne time ki chinta kro

    • @santosh97129
      @santosh97129 ปีที่แล้ว +4

      @@anshu5860 Yai sab batai jee mai yaad ayengi

    • @ruchikagoyal8367
      @ruchikagoyal8367 ปีที่แล้ว +4

      @@aaryanrateria5147 just be quite if u don't want to watch go but we want to study okhay

  • @manikarnika31
    @manikarnika31 ปีที่แล้ว +8

    37:45 THIS MINUS SIGN IS BECAUSE OF THE VALUE OF COS 180DEGREE THAT IS -1
    THE MINUS SIGN INDICATES THE NAGATIVE WD AND THE DIRECTION OF DISP IS OPPOSITE FROM THE DIRECTION OF FORCE

  • @navdeepkayat6637
    @navdeepkayat6637 ปีที่แล้ว +12

    51:48 work done by friction is -50 J
    Work done by Force put on it 200 J
    Work done by gravity is 0 J

    • @tannusharma9092
      @tannusharma9092 ปีที่แล้ว

      Thank you for giving the right answer 🤗

    • @Sujal_032
      @Sujal_032 ปีที่แล้ว

      Thanks bro for Giving me idea

  • @nm9-t5j
    @nm9-t5j หลายเดือนก่อน +1

    37:51 Ans- The minus sign came because negative workdone is happening.
    51:57 W (for force F) = 200J
    W (for force f) = -50J
    W (for gravitational force) = 0 J
    Overall (net) workdone = (200-50+0) J = 150 J

  • @SalmaWani-i4m
    @SalmaWani-i4m ปีที่แล้ว +76

    31:06 my school madam taught us the same concept in class, I really appreciate her after studying the same here 😃

    • @arvindkr.chaudhary8476
      @arvindkr.chaudhary8476 ปีที่แล้ว +5

      My sir has also taught so deeply

    • @ROBOMECH-e9z
      @ROBOMECH-e9z 11 หลายเดือนก่อน +2

      My ma'am has also taught us just like sir ❤🎉🎉

    • @SMgamers1243
      @SMgamers1243 10 หลายเดือนก่อน

      Maam ne yhi se bada hoga😅

  • @SaloniKumari-sm3np
    @SaloniKumari-sm3np ปีที่แล้ว +21

    51:49
    Work done by force=200J
    Work done by friction=-50J
    Work done by gravity=0J
    Net work done= 150

    • @CR7DHRUV
      @CR7DHRUV ปีที่แล้ว +1

      👍 sahi hai bro mera bhi same aaya

    • @Ashubhai_shorts
      @Ashubhai_shorts ปีที่แล้ว

      Work done due to gravity samjha do pls

    • @shoaibmalik6795
      @shoaibmalik6795 ปีที่แล้ว +2

      @@Ashubhai_shorts bhai gravity me F= mg hota hai jaha m= mass ,g=10n or angle between object and gravity is 90° which is = 0 so w= mg×s×0 = 0 work done

    • @Ashubhai_shorts
      @Ashubhai_shorts ปีที่แล้ว +1

      @@shoaibmalik6795 samajh aa gaya thankyou

    • @Grow_together2
      @Grow_together2 ปีที่แล้ว +1

      ​@@CR7DHRUVbhai net force kese nikalte hai

  • @shatrughansingh646
    @shatrughansingh646 ปีที่แล้ว +58

    Best teacher , Best platform and Best explanation - one and only PW❤️

  • @yashkashyap9095
    @yashkashyap9095 9 หลายเดือนก่อน +8

    52:14 - Positive workdone:- 200J if F=20N , s= 10m .
    Negative workdone:- -50J if
    F =5N , s=10m
    Zero workdone :- 0J if F= 15kg × 10m/s^2 , s= 10m
    Net workdone= 150J .

    • @BearBytesYt
      @BearBytesYt 6 หลายเดือนก่อน

      Bro that's is displacement not acceleration jo tumne m/s² use kiya hai

    • @MrSambee_08
      @MrSambee_08 4 หลายเดือนก่อน

      Gravity hai bhai​@@BearBytesYt

  • @alkmakhan5588
    @alkmakhan5588 ปีที่แล้ว +22

    Workdone by gravity=0J and workdone by friction = -50J and workdone by 20N=200J, net workdone =150J

    • @sandeepupadhyay8347
      @sandeepupadhyay8347 11 หลายเดือนก่อน

      But how

    • @alkmakhan5588
      @alkmakhan5588 10 หลายเดือนก่อน +1

      bro ek bar aur lecture attend kr lo mai kaise explain Karu

  • @princeahir8926
    @princeahir8926 ปีที่แล้ว +70

    You are the King of Physics 😎
    I recpect you sir 😎

  • @rishabhsoni4337
    @rishabhsoni4337 8 หลายเดือนก่อน +151

    Kon kon class 11th ke liye apne base ko strong kar rha hai ya one shot lectures ke through... ?!

    • @Yasirarfat710
      @Yasirarfat710 6 หลายเดือนก่อน +1

      Meh

    • @SumayaZakir-br1ep
      @SumayaZakir-br1ep 6 หลายเดือนก่อน +2

      Meh 11th ki standard aj yai pard rhe hu۔۔😢

    • @theogonepieceguy
      @theogonepieceguy 5 หลายเดือนก่อน

      😂

    • @Uncool-s2m
      @Uncool-s2m 5 หลายเดือนก่อน

      I'm here too😆

    • @MINEWORLD-w9k
      @MINEWORLD-w9k 3 หลายเดือนก่อน +2

      No one

  • @Studywithkshitij10
    @Studywithkshitij10 ปีที่แล้ว +6

    Best teacher of physics in world 🌍🌍❤️❤️👍👍☺️☺️🥰🥰

  • @jaspreetsingh9592
    @jaspreetsingh9592 ปีที่แล้ว +53

    Work Done By Force = 200J
    Work Done By Friction = -50J
    Work Done By Gravity = 0J
    Net Work Done = 200+(-50)+0 = 150J

  • @jashandeepkaur2677
    @jashandeepkaur2677 ปีที่แล้ว +7

    37:53 Work done is negative 1400 because the gravity is acting in the opposite direction of applied force

  • @memegenerator980
    @memegenerator980 10 หลายเดือนก่อน +6

    1:34:52 it states the hieght is not decreased by 5m rather its decrease by 10m and the current height is 5m

  • @abkatalent734
    @abkatalent734 ปีที่แล้ว +7

    1:33:01 sir the object is brought down to the height of 5m so from 15 m it will come down to 5 m so the equation formed will be w=60x10xcos 180
    w=600x-1
    w=-600

    • @bittuankusht6791
      @bittuankusht6791 ปีที่แล้ว +2

      Mujhe bhi yahi doubt tha isiliye comment padhne aaya . Q me likha hai 5 m ki height pe laaya gaya hai to s =10m hona chahiye

    • @BlackLightGamer0718
      @BlackLightGamer0718 หลายเดือนก่อน +1

      @@bittuankusht6791same bhai

  • @anilsharma15481
    @anilsharma15481 11 หลายเดือนก่อน +11

    51:27 work done by gravity=0J
    Work done by friction= -50 J
    Workdone by sir =200J

  • @archanatiwari1398
    @archanatiwari1398 ปีที่แล้ว +9

    51:27 the positive workdone will be 200J
    The negative workdone will be -50
    The zero workdone will be 0
    The net work done will be 200+(-50)=>200-50=150J

    • @UdayVats
      @UdayVats 9 หลายเดือนก่อน

      Please explain how

  • @DikshaDokania
    @DikshaDokania 2 หลายเดือนก่อน +6

    00:07 Introduction to Sprint Series on Class 9th Physics
    00:51 Understanding Work, Energy, and Power in Class 9th NCERT Chapter 11
    02:26 Work, Energy and Power are related in various activities like revision, brain training, meditation, breathing and physical work.
    03:14 Force and displacement lead to work
    04:41 Understanding Work in the Same Direction
    05:30 Calculating work in different directions of force and displacement
    07:02 Understand Work done in the same direction of displacement
    07:43 Understanding the relationship between force, displacement, and work.
    09:28 Understanding force and displacement in different angles
    10:12 Understanding angles and cosines in physics.
    11:57 Work done is defined as the product of force and displacement in the direction of force
    12:38 Understanding Work-Done Calculation in Work, Energy, and Power
    13:58 Scalar and vector products of two vectors
    14:50 Understanding Work, Energy, and Power in Physics
    17:04 Understanding work and displacement in relation to force
    17:54 Force and displacement are related in the direction and magnitude.
    19:58 Positive work leads to object speeding up
    20:51 Energy is converted into work done by our body.
    22:26 Discussion on friction and displacement of objects
    23:11 Understanding friction and displacement values
    24:54 Understanding the formula of work done with Cos Theta
    25:37 Understanding the role of frictional force in changing speed
    27:24 Work done is the product of force and displacement.
    28:36 Force and its Direction
    31:04 Understanding work, energy, and power in school curriculum
    32:11 Direction determines work done, not value.
    34:17 Understanding Work and Zero Work
    35:20 Understanding force, displacement, and conversion
    37:22 Understanding 180 degrees and its implications
    38:20 Understanding the concept of work, energy and power
    40:00 Understanding work, energy, and power conceptually
    40:43 Understanding Work in Motion
    42:14 Understanding the direction of force and displacement
    42:52 Chemical work done and forces involved
    44:22 Preparing to carry a body for burial
    45:00 Understanding work and force in terms of displacement and angles
    47:32 Calculating force required to lift an object
    48:51 Discussing the effects of applying force less than or greater than 150 units
    50:24 Calculating work done by force
    51:43 Calculating work done and displacement in a gravitational field.
    53:11 Understanding the concept of energy and work in physics
    54:09 Conversion of food into energy
    55:37 Understanding Work, Energy, and Power conversion
    56:21 Introduction to Work, Energy, and Power concepts
    58:32 Understanding Kinetic Energy in Motion
    59:22 Derivation of kinetic energy formula and work done formula
    1:02:09 Deriving formula for work done using force and displacement
    1:03:32 Understanding manipulation of equations for work, energy, and power calculations
    1:06:32 Understanding Work and Energy in Simple Terms
    1:07:36 Conversion of work done to kinetic energy
    1:09:30 Understanding the concept of kinetic energy and its general expression
    1:10:31 Work done results in change in kinetic energy
    1:12:12 Understanding Work and Energy
    1:13:01 Conversion of work to kinetic energy
    1:14:27 Understanding work, energy, and power concepts
    1:15:18 Calculation of work, energy and power equations
    1:17:41 Calculation of final energy using formula
    1:18:35 Calculate percentage change using the initial and final values
    1:20:34 Work, force, and displacement relationship
    1:21:09 Kinetic energy is converted into potential energy through work done.
    1:22:36 Understanding Potential and Kinetic Energy
    1:23:28 Transfer of potential energy to kinetic energy explained
    1:24:59 Understanding different types of energy
    1:25:44 Kinetic energy is derived from the motion of an object.
    1:27:19 Understanding displacement and force equivalence
    1:28:02 Work is related to energy and force in every derivation.
    1:29:43 Understanding work, energy, and power in a nutshell
    1:30:47 Force always acts in the upward direction.
    1:32:09 Understanding displacement and work done
    1:33:24 Introduction to Potential Energy
    1:35:08 Understanding independent path and displacement dependent path
    1:35:50 Potential energy is dependent on height
    1:37:35 Conversion of energy between potential and kinetic forms
    1:38:17 Energy is derived from chemicals in food through photosynthesis in plants, and can be transformed into different forms.
    1:39:39 Understanding Energy Transfer in Connected Work Chains
    1:40:25 Conversion of muscular energy into kinetic energy
    1:42:27 Electricity is converted to thermal energy in heaters
    1:43:17 Hydroelectric power generation process explained
    1:45:14 Conversion of chemical energy to kinetic energy
    1:46:07 Conversion of thermal energy to electrical energy
    1:48:24 Understanding potential and kinetic energy
    1:49:06 Understanding potential energy and its connection with mechanical energy.
    1:52:26 Understanding displacement and velocity calculations
    1:53:18 Calculating displacement and speed
    1:55:09 Changes in potential and kinetic energy
    1:56:10 Conservation of total mechanical energy
    1:57:45 Understanding the concept of power in physics.
    1:58:32 Understanding Power and Horsepower Units
    2:00:24 Understanding the concept of force and weight
    2:01:13 Understanding power and energy in physics
    2:03:15 Introduction to energy unit and its importance in classes 9th to 12th
    2:03:55 Commercial vehicle can use energy unit for trading and consumption of energy.
    2:06:10 Understanding commercial electric units and monitoring household appliances
    2:06:57 Understanding kilowatt-hour and its implications on electricity consumption and cost
    2:08:44 Understanding power and energy calculations
    2:09:40 Understanding energy consumption and cost calculation
    2:11:38 Understanding the relationship between kinetic energy and momentum
    2:12:37 Kinetic energy changes as variables change
    2:14:28 Relation between Power, Force, and Velocity
    2:15:12 Relationship between force, velocity, and power explained through dot product
    2:16:51 Practice numericals for better understanding

    • @DivyanshuKumar-ut8pm
      @DivyanshuKumar-ut8pm หลายเดือนก่อน

      1:26

    • @BhawanaKaprig2
      @BhawanaKaprig2 หลายเดือนก่อน +1

      Ooooo behen Tu pure lecture bhar yahi karte rahte ha kya kuch toh gadbad hai daya

  • @anuranjan9486
    @anuranjan9486 ปีที่แล้ว +32

    Thank you so much sir for your efforts and positive thoughts...

  • @ehsanahmad4683
    @ehsanahmad4683 ปีที่แล้ว +12

    37:54 minus sign indicates that the work is done in the opposite direction of displacement.

  • @56paramrakampara47
    @56paramrakampara47 ปีที่แล้ว +5

    51:56 workdone by following forces
    g=0 J
    Friction=-50J
    Main force=200J
    Net workdone=150J on same side of displacement

  • @thorxprogaming4005
    @thorxprogaming4005 9 หลายเดือนก่อน +1

    In 51:53
    Applied force=20×10=200J
    Friction force=5×-10=-50J
    Gravitational force=5×10× cos90°=0
    Net workdone=200+(-50)+0=150J

  • @quickadi
    @quickadi ปีที่แล้ว +9

    work done on right side of square block = 200J
    work done on left side of the square block = -50J
    work done by gravity on the square block = 0J
    total = 150J

    • @sheshkumarSingh-sf8xt
      @sheshkumarSingh-sf8xt 6 หลายเดือนก่อน

      Please Explain me the question l can't understand please help😢😢

  • @manishagothwal8000
    @manishagothwal8000 ปีที่แล้ว +4

    51:30 Question
    Right side workdone = 200J
    Left side workdone = -50J
    Downward workdone = 0J
    NET WORKDONE = 150J

  • @shubhankar6539
    @shubhankar6539 ปีที่แล้ว +17

    37:54 Here the work done came as -1400 Joules indicate that the force and displacement are in the opposite actors. And it is termed as negative workdone. Here also the cos 180° termed or known as the value of -1 as per the shown tablular form.

    • @adityakashyap8841
      @adityakashyap8841 11 หลายเดือนก่อน +1

      Yes you are right here value -1400 jule because the value of cos 180 is -1 so answer come in negative

  • @Playercat_pixie
    @Playercat_pixie ปีที่แล้ว +5

    Because of upward direction and force being downwards so 180° tells -1.🎉
    It tells that the work is done in the opposute direction of force. 38:04
    Speed is slowed down

  • @Star.viibe....
    @Star.viibe.... 11 หลายเดือนก่อน +6

    Literally uuh r amazing faculty sir 😊😊

  • @vanshika6683
    @vanshika6683 ปีที่แล้ว +4

    51:53 HOMEWORK ANSWERS.
    1) W1 = 200J ( by force applied)
    2) W2 = -50J (by force of friction)
    3) W3 = 0J( by force of gravity)
    Net work done = 200+(-50)+0= 150J
    Thank you sir ☺️☺️

  • @VIII-ADITYASEN
    @VIII-ADITYASEN ปีที่แล้ว +45

    Really i learnt many things and the energy of teacher gives more energy to me for studying 🙂🙂

  • @Nikki-br6kl
    @Nikki-br6kl ปีที่แล้ว +22

    Sir there is a sign of minus because the force is acting downwards and the displacement is being upwards so the angle between them is 180 degree and the value of Cos180 is -1.

  • @arpitabarik1521
    @arpitabarik1521 9 หลายเดือนก่อน +10

    1) work done when F is 20 N = 200J
    2)Work done when F is 5N = -50 J
    3) Work done when F is mg =0J

  • @-mz7io
    @-mz7io ปีที่แล้ว +13

    37:54 cos180 value is -1. the force is acting opposite to the ball which means we have to use cos180

  • @urkundi2451
    @urkundi2451 ปีที่แล้ว +7

    1:14:20 shadow se pata chalta hai ki .........

  • @Altamash_o_o
    @Altamash_o_o ปีที่แล้ว +8

    30:00 madam ne bataya 0 work tab hoga gab work nhi hoga 😅😅

  • @zhssjsjs1040
    @zhssjsjs1040 ปีที่แล้ว +19

    37:54 it is in negative sign because the ball is moving upward but the gravitational force is applied from the downward direction so it makes 180 degree angle. And the value of Cos180 degree is -1

    • @monalisapatel6395
      @monalisapatel6395 10 หลายเดือนก่อน

      I was also thinking this...but I was still doubting myself...you cleared my doubt..... thanks 🙂🙂

    • @GamingMasterX77
      @GamingMasterX77 10 หลายเดือนก่อน

      Exillent

  • @Future_in07
    @Future_in07 11 หลายเดือนก่อน +48

    Happy New Year sir, the lecture was amazing, thank you, I understood every concept now I'm practicing it & will become a grandmaster.

  • @arunimagoel1240
    @arunimagoel1240 ปีที่แล้ว +4

    37:51 minus sign is there because force is in the opposite direction of the displacement so we've taken cos theta as 180 which is equal to -1 so the answer has a minus sign.

  • @randhir_yadav_45
    @randhir_yadav_45 ปีที่แล้ว +5

    51:30
    Work Done due to gravity is 0 j.
    Work done due to friction is -50 j.
    Work done due to force is 200 j.
    Net work done is 150 j .
    👍🏻👍🏻

  • @dineshkumarsingh6143
    @dineshkumarsingh6143 ปีที่แล้ว +4

    51:29 sir work done by the applied force is 200 J ; work done by frictional force is -50 J and work done by force of gravity is 0 J
    And the net work done is 150 J

  • @pranjal...
    @pranjal... ปีที่แล้ว +36

    Exam are near😮
    But no fear🎉
    Because pw is here❤❤😂😂

  • @MYTHBuSS
    @MYTHBuSS ปีที่แล้ว +20

    37:57 It is because here the force is acting in opposite direction to displacement so here we will use formula :-
    *W= F•sCOSTHETA*
    = F•sCOS 180°
    = F•s×-1 😊😅❤

    • @Aasthaj08
      @Aasthaj08 ปีที่แล้ว

      Because it is negative work

    • @syed3344
      @syed3344 ปีที่แล้ว

      cos 270 degree ki value pata hai?😂😂

    • @uniqueness1671
      @uniqueness1671 ปีที่แล้ว

      Sir ka chaap Diya ....

    • @MYTHBuSS
      @MYTHBuSS ปีที่แล้ว

      @@uniqueness1671
      For Ur Comment :-
      So Beautiful , So Elegant , Just looking like a WOW 😂

    • @Anitadevi-ui4bw
      @Anitadevi-ui4bw ปีที่แล้ว

      @@MYTHBuSS thankyou

  • @xflashgod6515
    @xflashgod6515 3 หลายเดือนก่อน +4

    59:30 actually the formula is half mv² * half mu² but as u is 0 we write half mv²

  • @rakeshbansal3870
    @rakeshbansal3870 ปีที่แล้ว +6

    H/w :
    Net force: big - small
    = 20 N - 5N
    = 15N
    W1= fs cos thita
    = 15N × 10m× cos0( because force and dislacement acting on same direction)
    = 15N× 10m×1(cos0=1)
    = 150j
    W2 = fs cos thita
    = mg×s× cos90( because the force is acting in downward direction and displacement is forward. so it will make 90 ° and cos90 =0)
    = 5kg ×10 ×10 m× 0
    = 500 ×0 = 0j
    The total work done = 150j +0j
    = 150 j.

    • @PoseidonSocial
      @PoseidonSocial ปีที่แล้ว

      ayansh bhundsal (my real name)

  • @prantikhalder2541
    @prantikhalder2541 ปีที่แล้ว +6

    Best Physics Teacher in the Universe......❤

  • @nehajaiswal5811
    @nehajaiswal5811 ปีที่แล้ว +12

    Thank you sir for clearing my all doubts about Commercial Unit of Energy

  • @ixhated4476
    @ixhated4476 ปีที่แล้ว +9

    1:14:19 ye smartboard pe kiski parchai chup ke jaa rhi 😂😂

  • @deepshikha_bhardwaj
    @deepshikha_bhardwaj 11 หลายเดือนก่อน +6

    It’s 2024 and sir your video is still the best . Positive force is 200J, negative force is -50J ,gravity force is 0J and net force is 150 J.

    • @VishnuSharma-dr2yi
      @VishnuSharma-dr2yi 9 หลายเดือนก่อน

      Bro I wanna ask you a question didn't we calculate the mass in it please reply

    • @deepshikha_bhardwaj
      @deepshikha_bhardwaj 9 หลายเดือนก่อน

      @@VishnuSharma-dr2yi yup , we did but only in finding the downward force , which is mg(mass×gravity) . We did not use mass in finding the other forces .

    • @Erenyeager-hp9vl.
      @Erenyeager-hp9vl. 7 หลายเดือนก่อน

      Weight- mass×gravity

  • @sreekar1406
    @sreekar1406 ปีที่แล้ว +6

    the sign "-" came because the angle creates between the force and displacement is 180 degrees. Since cos180 is equal to -1,then answer will come in negative form.

  • @Raghav_Garg.68
    @Raghav_Garg.68 11 หลายเดือนก่อน +7

    2:11:10 sir it was asked to find the whole month's energy consumption and power also but nice work i really appreciate. thankss for teaching us!!👍👍

  • @yogeshkumarjoshi7398
    @yogeshkumarjoshi7398 9 หลายเดือนก่อน +18

    School main kuch bhi nahi padhate😢😢 Thnak u sir🎉🎉❤❤❤ keep it up😊😊

    • @KanchanBugalia
      @KanchanBugalia 29 วันที่ผ่านมา

      siddha siddha bol tu school nahi jaa ya 😂😂😂

  • @GTA5-e9u
    @GTA5-e9u 9 หลายเดือนก่อน +1

    Finding expression of Potential energy (position) - 01:26:47 to 01:29:00

  • @Shivanshsharma9887
    @Shivanshsharma9887 ปีที่แล้ว +6

    No one can explain like you ❤😊

  • @pasta3632
    @pasta3632 ปีที่แล้ว +32

    🎉🎉 I was searching for all the videos uploaded by u sir and u r an excellent teacher seriously!!! I hv watched all your videos even of all classes that u teach because I like ur way of teaching physics which gives me interest in physics and I m liking this subject studying from u now sir🎉🎉

  • @amitwaghmode443
    @amitwaghmode443 ปีที่แล้ว +18

    You are my fav teacher ☺️❤️

  • @madhudubey9705
    @madhudubey9705 9 หลายเดือนก่อน +1

    37:50 whenever there is a negative sign in case of workdone , it shows that the angle between force and displacement is 180' and the value of cos 180' si -1
    The impact of it is that it would responsible for the reduction in the speed of the object as the force is exerted on the object in opposite direction.

  • @tiakhan1805
    @tiakhan1805 ปีที่แล้ว +4

    28:35 - can we say that 'the value we get using Workdone formula, will also state, whether its +, -, or 0?' for instance, in case of positive, even the value is positive, while in negative workdone, the value is also negative.

  • @cristiano19786
    @cristiano19786 ปีที่แล้ว +6

    Lecture starts at 1:59

  • @graspknowledge1
    @graspknowledge1 ปีที่แล้ว +5

    Sir are the one of the best physics wallah's

  • @IM_THE_RDX
    @IM_THE_RDX 9 หลายเดือนก่อน +1

    That negative sing had occurred because the value of cos180° = -1
    If we multiply it Fs cos theta
    Then,
    20×10×7× -1
    = -1400 Jule
    The - sign denotes that both forces are working on opposite direction
    In simple words it defines retardation 37:45
    Am I right?
    👇🏻

  • @vanshika6683
    @vanshika6683 ปีที่แล้ว +15

    Kop ❤️❤️❤️the most awaited lecture thank you KOP ❤️

  • @rakshitz1867
    @rakshitz1867 8 หลายเดือนก่อน +3

    1:29:29 sir Aaj aapne 'g' ka value negative kyu nahi liya pichle lectures me to bola tha ki Cartesian plan ko follow karenge ??
    Or kaha tha ki har baar g ka value negative lena ???

  • @harshimishra3721
    @harshimishra3721 ปีที่แล้ว +59

    You make the concepts very clear and understandable 😊.... Best ever teacher of physics ❤️

    • @CruxTV
      @CruxTV ปีที่แล้ว +2

      Are pehle dekh toh lo lec🤣

    • @BestBro06
      @BestBro06 ปีที่แล้ว

      Agreed

    • @kingibck4381
      @kingibck4381 ปีที่แล้ว +1

      Papa ki pari ha na

    • @SHALUYADAV9325
      @SHALUYADAV9325 ปีที่แล้ว +1

      @@CruxTV ye yha pe padhte km comment bdi lambe-lambe karte hai...😂

  • @pallaviraja4896
    @pallaviraja4896 9 หลายเดือนก่อน +1

    The force acting on the ball is downward and the displacement is happening upwards.This forms 180°.And the value of cos180 is -1 37:54

  • @apnaclassroom2317
    @apnaclassroom2317 ปีที่แล้ว +8

    Thank you sir, This zero to hero batch is really helping me a lot but can u upload such videos a bit fast so that we can start revision because kvs PT 3 exams are starting on 23 January.

  • @dymoutgaming2781
    @dymoutgaming2781 ปีที่แล้ว +5

    minus sign occurs because cosQ is 180degree and the value of cosQ IS -1 thats because workdone is in minus

  • @PreetiSharma-rd1gk
    @PreetiSharma-rd1gk 11 หลายเดือนก่อน +7

    Rakshak sir.. U r amazing... U r just like a medicine cause whenever i m feeling sad then specially i used to see ur videos ..n i smile by ur superb explanation on any topic of physics... Really i love physics because of u only...

  • @myfreestatus8827
    @myfreestatus8827 4 หลายเดือนก่อน +1

    51:55
    Applied force= w= 200j
    Friction force=w= -50j
    Gravitational force =w=0j
    Total workdone is 150j

  • @sreekar1406
    @sreekar1406 ปีที่แล้ว +5

    sir at 1:32:29, the height should be 10 m as it is reduced by 5m from the height 15m.From the ground the height will be 10 m.

    • @THE_HACKER_TRIO
      @THE_HACKER_TRIO 11 หลายเดือนก่อน

      S bro u r 👍 same was my doubt

  • @raghavchiragdave6405
    @raghavchiragdave6405 ปีที่แล้ว +4

    very good explanation sir! really appreciate

  • @Anand1440
    @Anand1440 11 หลายเดือนก่อน +4

    Don't underestimate the power ⚡💪Of Rakshak sir 💕 Power of desi boy Raksak sir❤Rakshak sir is a fit person 😍

  • @Manjotsingh-fm4nq
    @Manjotsingh-fm4nq ปีที่แล้ว +5

    Sir forces ar -50J, 200J, 0J respectively and thanks for this video