Divisibility Rules 1 || Number Systems || Quantitative Aptitude || CAT Preparation 2024
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- เผยแพร่เมื่อ 29 ก.ย. 2024
- Number System by Ravi Prakash | Quantitative Aptitude for CAT 2024
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For those who are having confusion....first watch lectures on Remainders which begin from lecture 14 and come back here.
Thanks..!!!
Hm thanks
Thanks
THNAKS BUDDY
Thankyou
for checking divisibilty by 11 proof we make use of minus remainder , brilliant concept!
WHo else is here because of Understand UPSC
last question is a bit confusing can anyone explain?
Take simple examples....
Take 1 to 100..(here finding the 100 is going to be ur target )
The question given was
Q: 1,2,3,4,...x 192digits are there, find the last number.
• U know 1 to 99 has 189 digits
Now subtract 192-189 = 3 digits left
U know after 99 each number has 3 digits, now divide the answer (3/3= 1 no)
99 no + 1 no = 100
I've tried wid my understanding pardon u find this difficult .😅
Watch all the remainders lectures first and then divisibility rules.
Ur wellcome.
Thanks...
Thanks bhai
Can u tell the subtopics arrangement of how to watch??
@Sim Sidhanti Then what about factorials.. I guess even that is putted way before... And it should've been posted at the end right
@Sim Sidhanti Ohk .. Atlast.. Acc. To you ,are his videos enough for cat prep?
@rodha sir I would like to draw your attention towards a small correction in playlist. Please update the remainders video series prior for this video. Thank you and God bless you sir.
U are a legend!❤️
A man with huge knowledge of core concepts.
Respect+
Hey Can you please tell me how much percentile U got in CAT. So that I can observe is this enough or I should study more...?
Why are u looking for proofs? Attend his lectures and you will see why people adore him. Best faculty when you want to go from basics to advance.
Have upsc didn't raise the csat standards in cse 2023, i wouldn't have be here😢😢.
Thanku sir for helping me master number system......if i am ever selected in iim i l give its credit to you also
Are you got selected in any iim??
@@makingmoneyathome3590 no way man. did you just ask him that after reading his comment ? he couldn't form a simple sentence. no offence dude but you got to be really good at english while it comes to clearing CAT with excellent scores.
@@sidsiva3073kya baat hai bhai, doosro ko English ka gyaan pel raha hai when you have mistakes in your comment as well. Support people rather than bringing them down.
Can you clear a doubt of mine
divisibility of 2 & 5, 3&9, 11 ...and then digits counting.!
shivam kamat (10)
5-8-2021
thank you sir 🙏
Sir, can you please number the videos in a sequence in the playlist, so that we can watch in the correct order. That will be a great help. Thankyou
Before divisibility...watch reminder concept videos....
bhai remainder ke pehle factors na ?
@@P.verma0
@@SatyamRaj-zl4sb hnji...
Or Bhai nhi bhn 😅
@@P.verma0 aage ka sequence kya he list ka ?
@@SatyamRaj-zl4sb actually abhi Mera khud ka divisibility tk complete hua hai...aage ka ab continue krungi...
26:40hhahahahahahahahaha
the last answer was not clear
(634-189)*3 digits we have .
why did you divided it by three???
Beacause after 99 ,number started with 3 digits
Sir in the last 5 digits why did you take 2 from 248 and didn't stop at 247? Please explain? Thanks you!
Is it because 248 is 82*3+2 and we just have to add 1 from (143*3+1)? So we just took the remainder of the last number (248) which is 2 from (82*3+2)?
It's because in 148×3+1 we have +1 na so we have to add one digit extra which is 2 from (248).
Yeah I got it thank you so much.
Yeh jo quant ki playlist hai kya yeh sufficient hai
Yes they did cover the whole syllabus. After watching the concept videos do refer to books too like Arun sharma or any other
Sir why is (9:38 ) video part …. Why is 100 not divisible by 2(3) cube while 1000 is divisible by 2(3) cube ?
When we divide 100/8 = 4 is remainder. But when we divide 1000/8 it will be cancelled and 125 is quotient. Hope you got it now.
Thank you sir for the wonderful lecture! i am gonna crack CAT 2024 easily!🎉
i have made a study group for cat aspirants, details are in the about section of my channel.
Sir, is this playlist arranged or can you please tell the sequence to watch it??
Because in starting, you have told us that we have covered these many topics and it is not done yet till this playlist
Before this video...watch the remainder topic videos....then divisibility video
really amazing and helpful i just started prepration and i enjoying it a lot earlier i use to hate all these thing now i am getiing interest. Thanks sir for your support!!!!!!!
Last 5 digits means = 47248( because last is 248) but why you left last two digits "48" and calculate 5digits like = 62472?
Because last 2 digits 48 is out of scope of 634 digits as given in the question
Yup we don't have to add any number to get 247 as 248
We just have to concentrate on digits..... I mean we have to add a next digit like 2472
Sir isn’t the answer would be 2 for last question?
Lecture 10 missing sir..
Lecture 9 is missing actually in the playlist
Did any one got lecture 9
Sir which authors books has to be preferred for preparation.
For last question, I think the last 5 digits should be 61471 as 147 would be the 148th term from 100 and one more extra digit (1) is added at the last .Can anyone clarify
Rodha❌Yodha✅
Why are we dividing N/32 in last question
that's the question, to find remainder when N is divided by 32.
Would you plz explain last question fully??
You need to find Remainder of N/32, where
N is given as 12345...634 digits which means N contains 634 digits,
You know the divisibility rule for 2^n, so even if you find remainder for just the last 5 digits of N, that will give you the answer.
Now, 1 to 9 contains 9 digits obviously,
10 to 99 contains 180 digits (90 numbers having 2 digits each).
So, 9+180 = 189 digits.
You are left with 634-189 = 445 digits.
Since all numbers after 99 contain 3 digits, you make groups of 3, that is you divide 445 by 3, that gives you 148 + 1 extra digit.
Now, you add 148 to 99, that gives you 247.
Remember you have 1 extra digit, so you use only the 2 from next number (248)
So your number becomes 2472
That is 4 digits, you want 5 digits so you take only last digit of the previous number that is 6 from 246.
Finally, you get last 5 digits of N that you were looking for, that is 62472.
Now just divide by 32 as your question demands and there's your answer 8.
Just to help visualize, the last few digits of N are like
...2422432442452462472
We only needed last 5 digits in this question to find Remainder.
Why he added 99 and 148? Can anyone explain please?
For Upsc aspirants skip tp 11:00 onwards....
Understand Upsc
Thank you
Ok
Sir what about foor non perfect square
Sir this lecture is very intresting and the way you explained concepts was just amazing 😊
We met again😅😂
Last mein lag gye nothing understand 😂
I have a query For eg if we choose a random number like 54342276/11 r=? (r= remainder) then Solution= [(5+3+2+7)-(4+4+2+6)]/11 r=1, then if we check with equation like 11y+1= 54342276 then y should be natural number or it can be in decimal?
please correct me if i'm wrong in any step.
y will be a natural number,that is it will be a quotient by when the big number is divided by 11
if we go more specific it will be a positive integer
At 18:13 1/11 remainder is 1 , how is it ?? can anyone explain
remainder is 1 or -10.
Such a nice explanation sir. Thank you for offering these lectures
Starting yhi lecture sw h ??
sir , someone is knocking on the door
Where this type of question like a number when successively divided by 7,6,5 the respective remainder are 5, 3,1 find the least number
Brilliant way of teaching🎉❤
62472/32=8 pls anyone explain?
divide krlo bro long divison method se
Sir where you live...I want to meet you to thank you😁
Always welcome. Bangalore
@@Rodha I will come soon to thank you ....I am preparing for cat and soon will get iim Bangalore under your guidance 🙏
Where is the link to the practice quizzes that sir has mentioned? Can anyone pls share
In the last answer I think remainder should be 1 instead of 8
Divide manually and check. It's 8 only
At 0:42 sir mentions a number of concepts and theorems that I'm unfamiliar with. Please send me the link to his videos discussing those?
Watch lecture 14
I have the same doubt as you. Most probably you would have finished the whole series by now, can you help defenestrate my doubts regarding the sequence of videos. Should I watch them as it or watch the concepts he is talking about first and continue the video
@@danishsingh4308 complete all the remainders videos first and then watch divisibility rules.
After divisibility can I strt number system?
In the last question 1,2,3----9 there are 9 digits total and then 10,11,12----99 how it can be 180 digits???? Infact from 10 to 90 there are only 80 digits...
From 10 -99 each no. Has 2 digits...that's why it's 180.
last sum why 2 came after 247 and how 62472 became a last 5 digit ??????
WHERE ARE THE VIDEOS OF SQUARING AND MULTIPLICATION, WHICH YOU KEEP TELLING AS TAUGHT IN THE LAST CLASS?
yea tell me also sir ???????
Mention any description to watch earlier videos
In sir's speed maths videos
Video number 9 kaha h sir?
Bro did you found that ?
@@himanshusain4404 playlist mai ha
Thnks 😊😊❤
Thanks a lot sir
Just a little doubt how 99 +148?
1 and 2 digit numbers are till 99
The number of 3 digit numbers calculated are 148 i.e. 100, 101, 102 and so on till 247(total 148 pairs of 3 digit numbers).
Thus, the last 3 digit number is 99+148 which is 247.
this is excellent content..he teaches really well...just from scratch
God bless you sir 😊😊...
Thank you sir...
Concept level, God>>>>>>>
Sir, last question i didn't understand plz discuss it again😢
Is there any one from Catking or any other coaching which is good. Actually I am about to join catking so I want some honest review or any other suggestion form seniors for online coaching cat2023. If u can plz help me out its very hectic to find good coaching online.
Why CATKING ?When you are to join a coaching study from the legend himself, Ravi Prakash Sir. He teaches at Unacademy. He takes 2 to 4 hours of daily live classes there. Full Quant, DILR, Decision Making, GK.
@@ankitsinha5382 I was not aware about sir unacade my classes tq for that. so app vi prepare kr rahe ho ya through unacademy
Where is lecture 9 ? In the series it's showing lecture 8 then lecture 10
sir how 10/11 gives remainder of -1 or any reader of this comment can explain pls
watch video on remainders first
For upsc aspirants skip to 11 min … thankful to you sir
Sir remainder is 1 for last qes but you wrote 8
please tell me.. is Arun sharma 's CAT material sufficient for practice?
Im a UPSC aspirant and learning from U
Can anyone explain the last question in after 99 whats he do??
Till the 99 , we already used digits 180+9= 189
Thus we left with only 634-189=445 digits
Now how many 3 digits number can we made since we have left 445 digits,
So it will we =445/3
Since 445 is not completely divisible by 3,
The quotient is 148 and the remainder is 1,
So we can make 148 , 3 digits number and one left single digit
Then 100,101,.....247 (total 148)
If we continue above series 101,102,103,...247248, we can't take the last 48 other wise the number of digits will be 636
Thus the last 7 digits are 2462472
The last 5 digits are 62472
@@36_parthshrimali84 thank you so much
@@36_parthshrimali84can u plz expln why dividing 445 by 3
thku sir ur lecture is very grt thku by heart
Last solution didn’t get it sir😢😢
Please explain last question again
Thank you sir ...........
Sir 789÷125 we don't get a remainder 39
125*6=750 and 789-750=39
Wa wa wa sir wa moze aa gye
sir ke ghar me drilling ho rhi hai 🙂
Thank you sir
thank you, sir!!
Link for lecture 9:-
th-cam.com/video/GrbyiWvFYwA/w-d-xo.html
thank you sir
Kitna confusing hai
Why divide 445 by 3...pls can anyone explain
to find the number of 3 digit groups
Legend^10 😅
Super video sir salute
Thank You 🙏🏻
was not able to understand the last question of 634 digits divided by 32?
Am I missing something?
As 32 = 2^5, for calculating the remainder of 634 digits divided by 32 you need to check the remainder for the last 5 digits only, as explained at the start of the video. Sir is explaining how to determine the last 5 digits out of the 634 and then find the remainder and hence the answer. Watch the video again, it might make sense now :)
62472/32 = 8 can someone explain
8 is the remainder and not the quoteint. Notice, he has added a vertical line and R showing that he is calculating the remainder and not the quotient.
Sir can we get the notes
Thank you Sir🙏
Playlist of videos are not arranged correctly,,remainders are not completed yet,but u told that u r already completed in previous videos..getting confusion sir please arrange them orderly..or make a video to watch according to topics ,or on playlist,,please sir
Bro videos regarding are remainders are from lecture 14 onwards...first watch them
dividing 1 by 11 should leave remainder -10 if we're considering negative remainders
Thanku sir
Sir it is lecture 10 and you said while starting that we have learned about reminder in our last class i am bit confused
Sir meant that while explaining the concepts of previous lectures, he talked a little about remainders also whenever it was required.
Lecture no 9 is missing
Firstly watch remainder videos. Lecture 14
@@poojapoonia9496 thank you
❤
Thank you sir :)
Where is 9th no. Video sir ???
th-cam.com/video/GrbyiWvFYwA/w-d-xo.html
woow, great concepts
789/125|Ř = 39(how?) please show exactly.....
bro simply divide it 789- (125*6=750) = 39
Simply put it in the remainder formula as:
125x6+39(this stands for dividing 789 by 125 where 6 is the quotient and 39 is the remainder)
Thank you so much sir.❤❤
U r boss 🙏🙏
Sir r u on telegram
@@yashagg9767 preparing for CAT'21?
21:00 29:00
Thank you, sir.
Sir how 10/11 remainder is -1 ???
Positive remainder 10
Bro
10 divided by 11 = -1 remainder
Remainder can't be in negative so,
11-1 = 10 ans
We always Subtract divider from negative remainder
Yeah 🔥
How is 62472/32 r=8????
Means
Sir How 62472 divided by 32 gives 8??
sir where are videos of remainder theorm,crt,etc
Madam refer to lecture 14
Sir why dividing by 25 in 1st Q
Because the 1st rule was for 2 & 5 only.
and 25 = 5^2, so it is applicable to use 25 also.