There are some rules of drawing molecular orbitals. You are not following them. Can you justify your diagrams? Following are the rules: A single node must cut through the centre of the molecular orbital. Two nodes must be placed an equal distance from the centre (i.e. such that they are balanced with respect to the centre) Each successive energy level adds an extra node. Note that an orbital with an odd number of nodes will always have one node in the centre.
@@autobiography-g2zI am already an assistant professor in a college. However I need blessings from everyone. I already have thought about myself. Understood ?
Didi for 1.3- butadiene app nodes ko jara dekhiye... For ¥2 one node present and node will be middle of 4 orbital... That is in between 4 two are same side and two are opposite side... Node present between this....
Mam... your videos are very complete but try getting some technical assistance for voice echo and also a humble request... Please step aside when instructing so that we can still see what's written on the board... Or the other way around... Please get a bigger board.🙂 Anyways, keep up the work... Its really good.👍🚩🇮🇳🚩
in psi 2 node should be in the middle , not at left side which you did . if a wave is constructed on this basis , then you can clearly see that node should be in the middle not at right . if i am wrong then please comment so that i can easily rectify my mistake .
Mam ap content depply dete ho but ek problem hmse rhta hai apke content mai wo sound ke problem hmse hote hai clear nhi aa patti hai but content best milta hai hme 🙏🙏
Mam the node should be generated in the very symmetric way. But in case of 1,3-butadiene the way you generated the node in si2 and si3 is not the most symmetry way. I think in si2 the node will come in between lobe 2 and lobe 3 and in case of si3 it will come aftr lobe 1st and 3rd one. Plz clarify it.
please teach the concept of constructive and distructive interference to the viewers instead of cramming the signs of lobes to find nodes, it will definitely help to understand in a easier way.
10:55 lumo to excited state ke niche vale ne bhi possible hai na mam, because vaha bhi 1 electron aa sakta hai and lowest bhi hai and unoccupied bhi hai
Ma'am HOMO and LUMO of the wave function cannot be same that you represented in the molecules. These molecules will become highly reactive and unstable if this happens.
Mam, you are missing the Characteristic features of Pericyclic reactions I.e. Cyclic Geometry shape of the transition state of molecule and not a linear shape. You jumped directly toWoodward- Hoffmann Rule.
There are some rules of drawing molecular orbitals. You are not following them. Can you justify your diagrams?
Following are the rules:
A single node must cut through the centre of the molecular orbital.
Two nodes must be placed an equal distance from the centre (i.e. such that they are balanced with respect to the centre)
Each successive energy level adds an extra node. Note that an orbital with an odd number of nodes will always have one node in the centre.
After a long time,. finally I realized homo-lumo concept,... thanks Didi..
Don't leave the channel..plz...
Arrey yaar ye channel pehle kyu nahi mila.. Aaj hi dikha.
Thanks a lot didi. Bohot help hui
Hu
subhah subhah pehli video se hi dil jit li...
aaj continue karna hein baki sare parts ke sath
Gorgeous you are...extraordinary teaching skills
In photochemical reaction of 1,3-butadiene psi 4 will be lumo
No...she is right..psi 3 will be LUMO...lowest unoccupied ...name se hi idea lg jata h itna
@@manishathakur509 no Puja is right
No psi 3 will be lumo
Yes
Sahi bol rhi ho aap
Thank you for the video, Ma'am.
I just want to bring to your notice that psi 3 should have symmetry.
But mam, 1st example ethylene , in comparison to state function si 2.. Si1 is lowest unoccupied molecular orbital in excited state.
Now I can realize. In excited state homo & lumo will be same.
Mother promise mam your very great thanks for classes
Mam your teaching skill is so extraordinary....god bless you mam.
ma'am is already blessed...think about yourself
@@autobiography-g2zI am already an assistant professor in a college.
However I need blessings from everyone.
I already have thought about myself. Understood ?
Didi for 1.3- butadiene app nodes ko jara dekhiye... For ¥2 one node present and node will be middle of 4 orbital... That is in between 4 two are same side and two are opposite side... Node present between this....
First view and first like. You are uploading videos in a supersonic speed.Thank you and keep it up.
Thank you so much ma'am ....you are best teacher of chemistry
Didi,generally node chooses symmetrically in orbital wave function, every book following this convention
Yes absolutely
Ya right
Yess hme c2 and m symmetry ko bhi consider kerte huye lobes me + and - dena h
1,3 buta diene ka psi-2 me lobes sahi nhi draw huye h
Mam LUMO in presence of light is 4th energy level in 1,3Cyclobuta Diane.
Yeah , LUMO is 4 th one
Mujhe bhi lgta h 4 hoga
Yes
@@jawad_rao Google karlo ya book me dekh lo vai excited state me lumo 4th he , ma'am ne galat bataya he ye
Yes
mam....correction plz...After assigning + and - notation ..formed orbitals must be symmetrical
Exactly..
Mam why si 2 cannot be considered LUMO in case of photochemical reaction since it also has one unpaired electron like si 3
She is doing wrong
Yes.. the total number of pi bond in ethene is 1 not 2 .....she is getting mistake 🇳🇵
@@nareshguptaorchhotanirahuw958 yes pie bond is 1 but pie electrons are 2
Mam in orbital diagram nodes should be placed on symmetrically but here in phi 2 nodes are asymmetrical filled, plz have look on it.
What to say .... watching 1st video of ur channel and m fan of ur teaching....
Lumo of 1,3 butadiene will be 4 th energy level..the 3rd energy level is filled up by 1 electron so how can it be lowest "unoccupied"??
In excited state 3rd energy level is filled up by 1 electron so we can say LUMO
Ya I'm books too si 4 is lumo,, so confusing man
Mam... your videos are very complete but try getting some technical assistance for voice echo and also a humble request... Please step aside when instructing so that we can still see what's written on the board... Or the other way around... Please get a bigger board.🙂 Anyways, keep up the work... Its really good.👍🚩🇮🇳🚩
Thank you so much my dear jyothi mam
Namste mam ,
Nyc video
Yaha tak to samajh me aa gya
Waiting for next video
Next 2 videos coming today :)
Ooooo videoes vapis aa gaye ,bhut khush hu
Love from IIT D
in psi 2 node should be in the middle , not at left side which you did . if a wave is constructed on this basis , then you can clearly see that node should be in the middle not at right . if i am wrong then please comment so that i can easily rectify my mistake .
There is a mistake in her lecture.... You are right
Thank u for this video. 😍from kerala.
Lumo means lowest unaccupaid electrons so in existed state lumo is si4
In butadiene energy level 4 is...LUMO in excited state
Yes I also noticed that .. 4th LUMO hoga
Mam ap content depply dete ho but ek problem hmse rhta hai apke content mai wo sound ke problem hmse hote hai clear nhi aa patti hai but content best milta hai hme 🙏🙏
Thank you so so so so much aap bhut achchha pdhate hai thank you so much didi
Mam Now I am Second sem of msc1 year . Your all Vedio very benifatable to study tx mam plis all sylalbus Vedio uploaded
Mam the node should be generated in the very symmetric way. But in case of 1,3-butadiene the way you generated the node in si2 and si3 is not the most symmetry way. I think in si2 the node will come in between lobe 2 and lobe 3 and in case of si3 it will come aftr lobe 1st and 3rd one. Plz clarify it.
Ab ja ke samjha mein aaya pericyclic .😟 Thanks ma'am
very nice bhut aashani se samj me aagya thaks ssssssssssssssssss
Thanks mam u r the best aap apna akle hi chanel chla. Rhi hoo
I am studying in MSC sem 4 very help full video mem
Thank you❤❤❤❤ so much mam ..... And very useful and nice video
Mam app supub ho ksham se u r best tech whole topic apke jaisa explain kash hmko hmre techer kiye hote to hmri chemistry best hota
Thnk you mam, you made this topic seem doable
Really understandable lecture ❣️
you are best mam
Achhe se samajh liya ab.. thank you ma'am
Supab👍keep it up😊
Chapter k next video description m dala kijie... Dhundne m asaani hogi
Thank you so much mam
It is very useful for the last minute of exam 😊
You are amazing teacher😍😍😍
Very good lecture mam keep it up you are genius
Didi nodes should pass symmetrically
Which book should we read to understand pericyclic from basics ..??
Mam your method to draw MOs is the shortcut. It is actually generated by MOT and LCAO MO method
Superb mam 😊bhot achha krwate ho
please teach the concept of constructive and distructive interference to the viewers instead of cramming the signs of lobes to find nodes, it will definitely help to understand in a easier way.
Thank you so much 😊
such a lifesaver.
Awesome..😍😍😍
Thank you so mach ma'am 🙏🙏🙏🙏🙏🙏🙏🙏🙏
Everything is fine but please make it slower a bit
Thank you ma'am for this video
10:55 lumo to excited state ke niche vale ne bhi possible hai na mam, because vaha bhi 1 electron aa sakta hai and lowest bhi hai and unoccupied bhi hai
Mam 5p isolated orbitals ki symmetry k liye koi lecture hai apka
Kindly link share krden...
Thank you 🙏
I think i will be paased because of you mam
Psi 4 is LUMO in case of 1,3 butadiene in hv condition... And psi 3 is LUMO in thermal condition....I think so mam...
Ma'am HOMO and LUMO of the wave function cannot be same that you represented in the molecules. These molecules will become highly reactive and unstable if this happens.
Outstanding mam
Great explanation
Thank u so muchh api...
Mam at last concept, ₩4 is LUMO. Pls correct me if I'm wrong
Mam well done but there is no symmetry in the molecular orbital of 1 3 butadiene the nodes must be symmetrical
Symmetry representative signs of butadiene are incorrect. Good effort although!
Mam very clear explanation.
Awesome concept didi
Thanku so much mam...
Nice
in case of excited state why is psi 4 not LUMO?
Mam, you are missing the Characteristic features of Pericyclic reactions I.e. Cyclic Geometry shape of the transition state of molecule and not a linear shape. You jumped directly toWoodward- Hoffmann Rule.
Awesome... Mam plz make video on Claisen rearrangement topic of pericylic rxns
I'll cover this too in coming pericyclic videos ...don't worry :)
@@JChemistrythanks mam
Pericyclic m electrophile nucleophile substitution addition elimination rxn nhi hoti ........why?
Pls explain
Thanks for motivation me to crack net jrf
Bhai MSC chemistry ke notes provide ho skte h kiya
❤❤❤❤❤❤❤💯💯u r genius mam🥰😘😘t q so much ❤❤❤❤
Hi....mam, your classes simply awesome....if possible plz use english language...for explanation
the way u draw nodes in butadiene ie nodes are very differnt frm books...is it standard or just for easy memorization
Very nice Behan
Thanks mem 👌👌
Nice explain mem
1,3 butadiene .. Thermal condition.. HOMO Psi2 LUMO psi3
Photochemical condition HOMO psi3 LUMO Psi4
Good explanation mam
Thank you mam!
Great 😊👌
Mam u told that positive and negative sign not form bond how its so ???
Good ma'am
Nice explanation mam thanku so much...
Mam Jo aapne pericyclic krva rkhe ho vo csir net ke liye enough h na ?
Mam ji empty orbital LUMO hoga n exited state mai plz explain
Mam sound k thori problem hai. O thik hoo jaya to accha hota.
Thank you mam
Mam, the concept of LUMO is wrng
Yes
Very good
Dii pls explain pmo n fmo approach for m.sc 1st sem
Thank u so much mam🙏😊