Great video! the LCT test states that the limit should be equal to L which is finite and positive, and here we have it as -1, so wouldn't the LCT fails ?
Good catch. My apologies on that mistake. The direct comparison test would be more appropriate in that case! (Just as you described in your other comment). I appreciate you pointing that out. Thankfully the end result is still the same. Sorry for any confusion I may have caused with that. Hopefully these comments will help clear things up for other students who watch in the future. Thanks again 👍
Great video! the LCT test states that the limit should be equal to L which is finite and positive, and here we have it as -1, so wouldn't the LCT fails ?
Good catch. My apologies on that mistake. The direct comparison test would be more appropriate in that case! (Just as you described in your other comment). I appreciate you pointing that out. Thankfully the end result is still the same. Sorry for any confusion I may have caused with that. Hopefully these comments will help clear things up for other students who watch in the future. Thanks again 👍
DCT would be better suited then, n+1 > n, 1/(n+1) < 1/ n , -1(n+1) > -1/n . -1/n diverges so our original series diverges as well by the DCT.