it was a great, simple and very right to the point lecture, avoiding those messy confusing description and explanations which exist in many textbooks and other lectures
Do the notions of linearity (and non-linearity) for differential equations correspond to what it means for an algebraic equation to be linear (or non-linear)? -just wondering what precisely begets the classification. thank you for the instructive video
I don't understand; So for your example, ∂u/∂t + ∂^3u/∂x^3 = 6u ∂u/∂x , the unknown function is u and it and its derivatives has to appear to the power of 1 in the PDE. In the term 6u ∂u/∂x both u and its derivative ∂u/∂x appear to the power of 1 so what's the problem here? Or are you referring to every *term* in the PDE having to appear to the power of 1 and not just u and its derivatives? (so that e.g. having a u^2 term would make the PDE non-linear) Thanks
well it seems that you have great knowledge in partial differential equation. thank you for sharing the knowledge. i am also writing notes while seeing the videos
excellent -- very clear -- excellent communication -- excellent pronounation -- excellent subject matter -- excellent knowledge -- terse and too the point -- highly difficult subject very well simplified-- thanking you sir
It's a blessing to watch this video.Every is as clear as crystal.Thank you.
it was a great, simple and very right to the point lecture, avoiding those messy confusing description and explanations which exist in many textbooks and other lectures
Thank you for your clear examples. They were quite helpful in helping me understand how to classify PDEs. Again, thanks a bunch!
Do the notions of linearity (and non-linearity) for differential equations correspond to what it means for an algebraic equation to be linear (or non-linear)? -just wondering what precisely begets the classification. thank you for the instructive video
This made it very clear to me. Thank you.
I don't understand; So for your example, ∂u/∂t + ∂^3u/∂x^3 = 6u ∂u/∂x , the unknown function is u and it and its derivatives has to appear to the power of 1 in the PDE.
In the term 6u ∂u/∂x both u and its derivative ∂u/∂x appear to the power of 1 so what's the problem here? Or are you referring to every *term* in the PDE having to appear to the power of 1 and not just u and its derivatives? (so that e.g. having a u^2 term would make the PDE non-linear)
Thanks
Would the PDEs found in electrical engineering or mechanical engineering be the more solvable equations, or more difficult?
well it seems that you have great knowledge in partial differential equation. thank you for sharing the knowledge. i am also writing notes while seeing the videos
ok, sir. Can you share your notes with me?
Thank you soo much i easily understand it ❤️
Sir in Partial differential equations used delta /delta(y) = 1 ,🙄 but delta /delta (x) is m in auxiliary equation ,
excellent -- very clear -- excellent communication -- excellent pronounation --
excellent subject matter -- excellent knowledge -- terse and too the point -- highly difficult subject very well simplified-- thanking you sir
thank you !!!
thank you
great videos but I guess u didnt classf. quasi linear eq.
quasi linear , semi linear too !
- peace (th-cam.com/video/GM53mA5Boes/w-d-xo.html)
I was also waiting for explanation, this guy is playing with us.
Thank you sir!!
Thanks sir
fabulus bro