Hi Guys, please comment and let me know what you think about this Operations Research Open Course. Your feedback is really appreciated. If you enjoy the video, please subscribe and share. All my replies here are only related to the content in my own videos. I am afraid I won't be able to answer other questions. Thanks for your understanding.
شكرا جدا لحضرتك الحمد لله فهمت الجزء الخاص بالمدى Before I watched your explanation I couldn't know how we calculate the range but now I understand it from you All thanks from Egypt
Thank you so much for this. We have online classes and our professor can't discuss this topic and we have to self study to be able to understand the concepts behind this. I am very much grateful for this video, sir. It is very clear, precise and concise. It is very easy to follow and understand. More power!
Thanks for your videos, the lecture that my prof presents is too abstract and a nightmare to follow with too many proofs. This is much easier to digest with subtitle as well!
Thank you for this! But how would you know the sensitivity ranges for the profit without a given additional value for the max z? Should I just assume? Thank very much!
@@YongWang Hi, thanks so much for this video! IT helped me in most part but there are still some uncertainties that I have. At 5:40, for the optimality range, its -1/2 =< -C1/C2 =< -2. May I ask how did you get the value of -1/2 and -2?
Great question. The optimal range formula does not work in that case. But the basic concept of sensitivity analysis still applies, i.e., how the changes in the rhs or coefficients affect the optimal solution.
Ankit, good question. In that case, you can still calculate the optimal value of the objective function and see how the changes in available resources (which is time in this example) can affect the optimal solution.
Yong Wang thanks for the reply. But we r already working on maximum capacity and increasing one more unit applies that we r exceeding it. In that case only one constraint can be changed. Is it right?
Thanks prof but I have a question when u get the slope 0.5≤c1/c2 ≤2 I didn't get it How did u get it while c1/c2 in this problem 300/200 And thanks again ♥️♥️
Hi, thanks so much for this video! IT helped me in most part but there are still some uncertainties that I have. At 5:40, for the optimality range, its -1/2 =< -C1/C2 =< -2. May I ask how did you get the value of -1/2 and -2? Sorry if this is a dumb question but I just started learning this, still haven't really gotten the hang of it yet.
@@kavishdaya3594 those are the slopes of the constraint equations. You can write each in y intercept form (where x2 would be your y value) and you obtain a slope of -1/2 for m2 and -2 for m1 so the objective value line has to lie within those 2 slope boundaries. Ik its a year later but hope this helps lol
-1/2 is the slope of the first constraint and -2 is the slope of the other constraint. you want your optimum solution to be between these two slopes as they give us the feasible solution area.
I haven't done the calculations myself, but I am fairly certain that it is the value you get from plugging the optimal solution of x1 and x2 into the function max(z)=300x1+200x2
Hi Guys, please comment and let me know what you think about this Operations Research Open Course. Your feedback is really appreciated. If you enjoy the video, please subscribe and share. All my replies here are only related to the content in my own videos. I am afraid I won't be able to answer other questions. Thanks for your understanding.
Very good, thanks!
Can you share ppt?
Thank you, well done Yong !
im not enjoying this course not because of the subject but bcs of my lecturers...i really like operations thinggy but my lecturer makes it worse
This is really good !! The visualization is excellent
Very helpful ty
شكرا جدا لحضرتك الحمد لله فهمت الجزء الخاص بالمدى
Before I watched your explanation I couldn't know how we calculate the range but now I understand it from you
All thanks from Egypt
Thank you so much for this. We have online classes and our professor can't discuss this topic and we have to self study to be able to understand the concepts behind this. I am very much grateful for this video, sir. It is very clear, precise and concise. It is very easy to follow and understand. More power!
One of the best videos on this topic. To the point and very clear explanation, thank you sir.
Wow, I've watch every video by you thus far on OR and you are a scientist and an artist!
Thanks, Brent, for the comments
I never comment on study videos, but this was awesome and on point. Thanks!
yong abi saol cok güzel anlatmışsın türkiyeden selamlar öptüm canım
You are welcome, Kerem.
Love how u make it look easy to understand
I had difficulty understanding this topic, but the video helped a lot. Thank you.
Thank you clear explanation. I have a question. How we determine the profit range to change?how about slack and surplus?
That was very useful to understand shadow prices, thank you :D
Thanks for the comment, Sobiah
noods?
Thank you so much for your explanations. It's much easier to understand the process now (I was lost in class)
A very good video, thanks for your effort. I hope that it will help with my exam tomorrow
Oh my god!! You made this topic so damn easy!!!!!!!!!!!!!! Thanks, man.
amazing video finally I understood shadow and optimal range thanks
that was the best explanation, i could get on the subject sir
Very nice explanation.Thanks for your effort.
No problem, Kayambu.
i'll pass the class thanks to you
Thanks, ufuk
Thank you for this series. It is really impressive.
Thanks for the comment, jhon
Thanks for your videos, the lecture that my prof presents is too abstract and a nightmare to follow with too many proofs. This is much easier to digest with subtitle as well!
Thank you very much. All my problems regarding sensitivity analysis were solved :-)
glad to know it helped, Shavindi
I wish I could like this video twice
Hi! Great video - it would be excellent if you could also post the AMPL code to solve the problem.
wow. thanks for the lecture on this topic. am nowb bright enough
Glad you liked it, Peter.
I really appreciate your videos, sir.
crisp and crystal clear ...
Thanks, Asutosh
Thank you so much for making such a video. You have taught very good!
Amazing!!!! videos on operations research. You have a great skill of teaching complex subjects
Thank you for this! But how would you know the sensitivity ranges for the profit without a given additional value for the max z? Should I just assume? Thank very much!
Yes, Glady. You can just assume.
@@YongWang Hi, thanks so much for this video! IT helped me in most part but there are still some uncertainties that I have. At 5:40, for the optimality range, its -1/2 =< -C1/C2 =< -2. May I ask how did you get the value of -1/2 and -2?
very good explanation. it was very helpful. good job
sir, if the number of the coefficient in the objective function is more than two, does the optimal range formula still work?
Great question. The optimal range formula does not work in that case. But the basic concept of sensitivity analysis still applies, i.e., how the changes in the rhs or coefficients affect the optimal solution.
Very nice explanation
thanks, dharmender
Do you have any videos for LP problems that have 3 or more variables? How do we find the slope for 3 variables?
Interesting approach, but it'd have been useful to see the graphical interpretation of the last problem.
Damn my professor did a 2h lecture on this leaving everyone fucking confused and here I find a seven minute video where everything is crystal clear...
Can u be a bit clear on the last point that y should -c1/c2 be within both the slope to maintain optimality.
Loved this explaining
Thanks, Mohamed.
Good explanation, thanks
How will you calculate the shadow price if there are more than 2 variables and conduct sensitivity analysis on the objective function coefficients?
Thank you for sharing!!
happy to share
Very nice and helpful video. But what if we increase the RHS values of both constraints on the same time?
Ankit, good question. In that case, you can still calculate the optimal value of the objective function and see how the changes in available resources (which is time in this example) can affect the optimal solution.
Yong Wang thanks for the reply. But we r already working on maximum capacity and increasing one more unit applies that we r exceeding it. In that case only one constraint can be changed. Is it right?
Thank you so much. Very great explanation
Thank you sir. You helped me a lot.
how did you find the slope and optimality range? please explain asap
Thank you very much, you're my savior!!
useful and easy to understand. thx!
Thanks prof but I have a question when u get the slope 0.5≤c1/c2 ≤2 I didn't get it
How did u get it while c1/c2 in this problem 300/200
And thanks again ♥️♥️
Fantastic explanation with corresponding graphics. Thanks for your great work!
The best explanation! Thanks :)
You are welcome, Asit
What is the shadow price in operation research?
Great video!
How did you get the slopes?
Hi, thanks so much for this video! IT helped me in most part but there are still some uncertainties that I have. At 5:40, for the optimality range, its -1/2 =< -C1/C2 =< -2. May I ask how did you get the value of -1/2 and -2? Sorry if this is a dumb question but I just started learning this, still haven't really gotten the hang of it yet.
alright its okay can ignore this, I think I've found out why haha. But still anw, thanks for the vid!
@@JingZhi45 please tell me how was the values determined im also new to this topic
@@kavishdaya3594 those are the slopes of the constraint equations. You can write each in y intercept form (where x2 would be your y value) and you obtain a slope of -1/2 for m2 and -2 for m1 so the objective value line has to lie within those 2 slope boundaries. Ik its a year later but hope this helps lol
good explanation
can you please tell me how you got :-
-1/2>=-c1/c2>=-2
as the optimality range?
-1/2 is the slope of the first constraint and -2 is the slope of the other constraint. you want your optimum solution to be between these two slopes as they give us the feasible solution area.
Thanks, Yash. You explanation is clear and correct. Thumbs up!
it helps me a lot, thankyou!!!!
you are welcome, Dika
well done thanks for your work
Thank you for this video!
You are welcome, Vivioux
How did you get A and ZA on 2:10 ?
what would we do if we are given the value for c1 (100 for example) and not c2 for the optimal range?
Then we can put value of c2 from 50 to 200 bcz by puting these values the optimum solution remains between two slopes
@@foziakhan9791 that's right
Thank you. It was helpful
Thanks Sir. It is a very clear and helpful video :)
Thanks
Thank u sir, this really save my credits!
Glad it helped
best video ever
you are the best
I am? Thanks.
MANY THANKS, SIR!
Thanks, Mia
Very nice.
Thanks, Shakeel.
Very nice! Thank you!
Glad you liked it, Augusto
Thank you! Very much
Thank you! Very Helpful
glad it helped
thanks for your effort. This video is really clear and helpful :))
Thanks
Thank you so much!!!
super clear!!!
thank you very much
You are welcome, N K
Thank you very much Sir
Thanks
Isn’t the modelling wrong. I mean why didn’t we eliminate numbers of products like number of product 1 produced at machine 1.
You are a fucking leggend my man I jst learned everything i need for my final in a couple of hours
god bless you
thanks, Abdulla
Thank you
can you add a video about reduced price ?
basically, you just follow the same procedure for reduced price and resources
well explained
thanks for the comment, Xalamukani (trying to spell your name correctly)
very very helpful vidio
glad you liked it, Fozia
you are a legend
Thanks, Gokcen. I wish.
Does anyone know how to get the ranges for the shadow prices? Thanks
Ahmed, The shadow I mentioned in the video is a value, not a range.
Beautiful.
Thank you!!
amazing! thank you so much
Beautiful!
Heeeeeelp please T.T can you tell me where the 4000/3 from?
I haven't done the calculations myself, but I am fairly certain that it is the value you get from plugging the optimal solution of x1 and x2 into the function max(z)=300x1+200x2
@@rohatrobinsarac4803 that's right. it's the optimal z value
thank u for this!
You are welcome, YH
thanks very very very very much
you are very very very very welcome, Mojahed
the slope should be C2/C1
sir thank you much for this :)
thank u sir.
no problem, Samiha
That was dope!
my academic professor would say less than that in 1 hr that's way too unfeasible for me. thanks
thanks man! much appreciated
Thanks, Rainnie
perfeeeeeeeect
5:08
başlık neden türkçe?