If A be the A.M and H, the H.M between two quantities a and b, show that a-A/a-H * b-A/b-H =A/H

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If A be the A.M and H, the H.M between two quantities a and b, show that a-A/a-H * b-A/b-H =A/H

[@sabinbaral.]

Ans (a+b)^2/4ab ho tya (a+b/2ab)^2 bhaniyeko xa tyo jhukiyera jos ma bhaniyeko ho sorry.

[@SachinSunar]

haha yes got it bro

[@AshokSamant-rj1xy]

Keep doing

[@NareshShrestha-j9t]

Thanks bro ❤

[@PreranaDevkota-jp6ux]

There proved by both side L.H.S and R.H.S and given same ans by both side. Is it not possible to to solve the L.H.S and ans be R.H.S.(like solve L.H.S and ans A\H) please say🥺😭

[@sabinbaral.]

It is possible.

[@PreranaDevkota-jp6ux]

@@sabinbaral. So, solve from the way.

[@pratik7431]

Bro 4ab bhaneko (2ab)^2 haina yar
2ab ko whole square ta 4 a^2 b^2 hunxa !!!

[@sabinbaral.]

Sorry brother tyo jos jos ma k bhaniyo (a+b)^2/4ab nai ho.

[@pratik7431]

@@sabinbaral. No worries bro !!
Keep it up what u r doing !!

[@sabinbaral.]

​@@pratik7431wish you all the best for upcoming examinations brother❤❤

[@pratik7431]

@@sabinbaral. ❤️❤️

[@user-cg5pb7yl7y]

Right🎉