thank you for the kind words! extra views would be nice 👌😉 is there anything you think i should improve on and what are the good parts you saw on the video? cheers 🍻🍺
@@ASoftwareEngineer yes its usefull and your js series is osm can you make about big tech companies interview process if you are working on any Faang or any uber ,stripe,coca cola etc
I'm not sure if I understood it well, but this will check wheter the string has a pair number of parenthesis but not exactly if all parenthesis opened within it are closed afterwards. For example: ") ) ( (" will return true, right?
I made a long and understandable function for balanced parenthesis in case if it starts with ")" function isBalanced(str) { let stackL = [] let stackR = [] for(let char of str){ if(char === '(' ) { stackL.push(char) } else if(char === ')' ){ stackR.push(char) } } console.log( stackL, stackR) if(stackL.length> 0 && stackL.length === stackR.length){ return true } else return false }
Could you please also make video on object equality...? A function which accepts २ objects as input and check equality of keys and values. Recently this question is asked by interviewer to me.
creating video will take a long time here are 3 potential solutions i created for you - codepen.io/angelo_jin/pen/abLKKaX added comments on the codepen Update: Here is the video you requested th-cam.com/video/2j8L8RsHQpM/w-d-xo.html
My very first thought was - "A hungry fox!" has 4 vowels. Your match gives 3 because y is missing. Then after checking seems y is considered a vowel but only "sometimes". That is just funny.
Another simple way to remove duplicate from array function removeArray(arr){ let uniqueArray=[] for (let num of arr){ if(!uniqueArray.includes(num)){ uniqueArray.push(num) } } return uniqueArray } let resp=removeArray(['a','a','a','b',1,1,1,22,3,22]); console.log(resp,"check");
Very Helpful... Indeed if someone practices this before an interview then it's enough. Please get one more series of it.
will surely add more videos like this. thanks for the comment.
Thank you for this vid, it deserves more views, keep it up!
thank you for the kind words!
extra views would be nice 👌😉
is there anything you think i should improve on and what are the good parts you saw on the video?
cheers 🍻🍺
very helpfull content on this channel for js developer thanks a lot man
been adding css videos lately. do you think it is useful?
@@ASoftwareEngineer yes its usefull and your js series is osm can you make about big tech companies interview process if you are working on any Faang or any uber ,stripe,coca cola etc
We can refactor a little bit more the "Balacend Parenthesis exercise"
function isBalanced(arr){
return arr.split("").length % 2 == 0 ? true : false
}
yep, can do that as well. what i like about JS is that there are many solutions to a problem.
thanks for the snippet Jorge.
@@ASoftwareEngineer Exactly
I'm not sure if I understood it well, but this will check wheter the string has a pair number of parenthesis but not exactly if all parenthesis opened within it are closed afterwards. For example: ") ) ( (" will return true, right?
good point. when it doubt, ensure to test the code to verify :)
codepen.io/angelo_jin/pen/OJgwaed
I made a long and understandable function for balanced parenthesis in case if it starts with ")"
function isBalanced(str) {
let stackL = []
let stackR = []
for(let char of str){
if(char === '(' ) {
stackL.push(char)
} else if(char === ')' ){
stackR.push(char)
}
}
console.log( stackL, stackR)
if(stackL.length> 0 && stackL.length === stackR.length){
return true
} else return false
}
Could you please also make video on object equality...? A function which accepts २ objects as input and check equality of keys and values. Recently this question is asked by interviewer to me.
creating video will take a long time
here are 3 potential solutions i created for you - codepen.io/angelo_jin/pen/abLKKaX
added comments on the codepen
Update: Here is the video you requested
th-cam.com/video/2j8L8RsHQpM/w-d-xo.html
My very first thought was - "A hungry fox!" has 4 vowels. Your match gives 3 because y is missing. Then after checking seems y is considered a vowel but only "sometimes". That is just funny.
when is `y` considered a vowel. Anyway, if one consider this as a vowel, we should be able to adapt as a programmer easily
Another simple way to remove duplicate from array
function removeArray(arr){
let uniqueArray=[]
for (let num of arr){
if(!uniqueArray.includes(num)){
uniqueArray.push(num)
}
}
return uniqueArray
}
let resp=removeArray(['a','a','a','b',1,1,1,22,3,22]);
console.log(resp,"check");
yes. that looks like another winner to me! 🤙🏻