The question in 10:24 you said that the E field stays constant. However, as E=deltaV/delta r , given the potential difference (deltaV) is kept constant, doesn't the electric field strength have to vary with the distance between the plates? The question didn't really specify but I'm guessing nobody would assume that the battery voltage would just change
E= delta V/delta r is really a derivative. It applies to very (infinitessimally) small regions, but it is based on the idea that the Electric field between parallel plates is constant. We effectively consider two points in space that are so close together that the voltage and distance between points does not have enough space to change.
At 9:48, if those electric potential values (10V and 20V) were negative, then the electric field lines would be from left to right (because -10 > -20 and because electric field lines ALWAYS move from higher to lower potential). Is this assessment correct?
i do not really get why the magnitude of the electric field exprience by a charge between to plates (equipotential lines) is the same no matter what is the position of the charge
Very helpful lesson. Thank you Mr Doner.
You are very welcome
Watching this before me exam. Thanks so much
this video gives me french fries and ranch sauce vibes, thanks
Any time
bro what?!
thank you so so much! my teacher only went over parallel plates i didnt even know the rest of this was in the syllabus... THANK YOUUUUU 🙏
Glad I could help!
The question in 10:24 you said that the E field stays constant. However, as E=deltaV/delta r , given the potential difference (deltaV) is kept constant, doesn't the electric field strength have to vary with the distance between the plates? The question didn't really specify but I'm guessing nobody would assume that the battery voltage would just change
E= delta V/delta r is really a derivative. It applies to very (infinitessimally) small regions, but it is based on the idea that the Electric field between parallel plates is constant. We effectively consider two points in space that are so close together that the voltage and distance between points does not have enough space to change.
@@donerphysics Thanks! Love your videos
I had the same question! But after reading YOUR question I got what i did wrong!
Hi Mr. Chris, at 15:21 i dont understand how you got the g = GM/r^2 equation. In the data booklet its Fg = GMm/r^2. thank you in advance!
Just use g=F/m
@@donerphysics oh yeah! makes total sense now! Thank you for replying!
At 9:48, if those electric potential values (10V and 20V) were negative, then the electric field lines would be from left to right (because -10 > -20 and because electric field lines ALWAYS move from higher to lower potential). Is this assessment correct?
yup
i do not really get why the magnitude of the electric field exprience by a charge between to plates (equipotential lines) is the same no matter what is the position of the charge
Because the E field between plates is uniform. Though the potential energy depends on position, the force field is uniform.