es Probability of solving specific problem independently by A and B are 1/2 * and * 1/3 d respectively. If both try to solve the problem independently, find the probability that (i) the problem is solved (ii) exactly one of them solves the problem.
well for part A, it doesn't matter who solves it, the problem just needs to be solved, so how about we take the case of the problem not being solved first, by anyone at all, right? If A has a probability of solving it 1/2 then the probability of A not solving the problem is 1/2 aka 50 percent as well, B has a probability of solving it by 1/3, so not solving it is 2/3, now understand what we mean here by independently, im guessing that confused you. It means that it doesn;t depend whether A solves the problem or not in corelation to B. Understand it as this, you are sitting at the last bench while giving an exam, and a person who is sitting across the room is someone you can't cheat from, so if he solves the problem or not usse tumpar koi effect nhi aayega, woh tumpar depend krta hai. Back to the question. Ab ya to problem solve hogi ya nhi hogi, nhi hogi ki probabilty : 1/2 * 2/3 (to create combinations, p and c padha hai toh you will know why i multiplied) = 1/3 1 - 1/3 = 2/3 b) Case 1 : A solves it b does not : 1/2 * 2/3 Case 2 : B solves it A does not = 1/2 *1/3 1/2 *2/3 + 1/2 *1/3 = 1/2
@@thoughtsofs7728 Try to make sense out of the english written, try to make out connections to real life scenarios, alright ill give you an example, agar B ne solve kiya toh A solve kr bhi sakta hai nhi bhi kr sakta uska solve krna ya na krna B pe depend nhi krta. second time mein bhi yahi matlab nikaalenge, i recommend you to read a little bit of theory in this scenario and then come to questions, don't watch lectures easy aur chhote topic ko kheech denge, read ncert ya cengage, uske baad solve ncert ke basic sawaal and then cengage, will hardly take an hour
What do you mean?? He used the symmetry of palindrome polynomials which is ideal to deal with even degrees polynomials. If you asked for using quartic equation formula, then I must ask you to search up how long and unproductive that is.
Sar Agar 1 / X ko X / X multiply kar denge Uske bad 1 by x square common le lenge Sab Mein Se to aapane Jo question thoda Din pahle karaya tha 4 5 Mahina pahle Usi ke jaisa ho jaega
Sir Let A= (1/x - 1/×^3)^0.5 and B = (1/x^2 - 1/×^3)^0.5 A^2 - B^2 = 1/x * (1-1/x) A - B will be equal to the above value since A + B = 1 as given in the question itself So now we have the sum and difference of A and B This will gimme 2A = 1 + 1/x - 1/x^2. Putting the value of A and sending 2 to the RHS in the denominator gives {(1/x)*(1-1/x^2)}^0.5 = 0.5*[(1/x) + (1-1/x^2)] Careful observation says, it's GM = AM, which is only possible when both the numbers are equal 1/x = 1-1/x^2 Solving which gives X = (1+5^0.5)÷2 Negative root will be ignored for the same reason as sir said
Sir If we put x=(5^1/2+1)/2 in the question then it is 0.5(approx) and if we put x=(-5^1/2-1)/2 then we get ans 1.1 which is approx =1 sir please check and reply 🙏🙏
Sir plz solve it with explanation a pack of card contain 4 ace 4 king 4 queen 4 jack two cards are drwan find probability that one ace is drwan least no of times
Sir for (t^2-t^3)^1/2 there should not be -ve inside the root but when we are keeping t=(5^1/2 -1)/2 we are getting -ve inside the root which is not possible and in the same way in 2(t-t^3)^1/2 if we put t=( 5^1/2-1) then also we are getting -ve inside the root which is not possible and I think we should check LHS if the root it self is not defined the how can we do SOBS
es Probability of solving specific problem independently by A and B are 1/2 * and * 1/3 d respectively. If both try to solve the problem independently, find the probability that (i) the problem is solved (ii) exactly one of them solves the problem.
Sir please explain this question
well for part A, it doesn't matter who solves it, the problem just needs to be solved, so how about we take the case of the problem not being solved first, by anyone at all, right? If A has a probability of solving it 1/2 then the probability of A not solving the problem is 1/2 aka 50 percent as well, B has a probability of solving it by 1/3, so not solving it is 2/3, now understand what we mean here by independently, im guessing that confused you. It means that it doesn;t depend whether A solves the problem or not in corelation to B. Understand it as this, you are sitting at the last bench while giving an exam, and a person who is sitting across the room is someone you can't cheat from, so if he solves the problem or not usse tumpar koi effect nhi aayega, woh tumpar depend krta hai. Back to the question.
Ab ya to problem solve hogi ya nhi hogi, nhi hogi ki probabilty : 1/2 * 2/3 (to create combinations, p and c padha hai toh you will know why i multiplied) = 1/3
1 - 1/3 = 2/3
b) Case 1 : A solves it b does not : 1/2 * 2/3
Case 2 : B solves it A does not = 1/2 *1/3
1/2 *2/3 + 1/2 *1/3 = 1/2
Plesae explain independently meaning used in the question two times once more with detail
And how this question is generated
@@thoughtsofs7728 Try to make sense out of the english written, try to make out connections to real life scenarios, alright ill give you an example, agar B ne solve kiya toh A solve kr bhi sakta hai nhi bhi kr sakta uska solve krna ya na krna B pe depend nhi krta. second time mein bhi yahi matlab nikaalenge, i recommend you to read a little bit of theory in this scenario and then come to questions, don't watch lectures easy aur chhote topic ko kheech denge, read ncert ya cengage, uske baad solve ncert ke basic sawaal and then cengage, will hardly take an hour
@@tooawesome-won't we consider the case when both A and B hv solved it simultaneously,so in that case shouldnt the ans be 2/3??
Imaginary values in roots also exist. You should have said that we are using Real Domain and Range. Right???? 8:54
When nothing is said, it means we are always talking about Real Domain
Sir ek question solve kar dijiye please --
Let a,b are positive integer then prove that {(a²+b²)/(ab+1)} is a perfect square.
Question is wrong, put a=6 and b=5
@@sangeetoholicwhat if
They mentioned GIF function of this equation
Or
If the equation value come in intiger then it must be square
💀
@@bluexwave5930 No, put x=4 and y=10, GIF will be 2, not a perfect square😌
@@sangeetoholic good xD
@@ANYONMOUS-si5dl But he wrote the question incorrectly 🥱
3:20 Use Quartic Equation.
Bdi lambi nhi hai equation
@@harshitawasthi8742😂
ye quadratic nahi hai bhai
What do you mean?? He used the symmetry of palindrome polynomials which is ideal to deal with even degrees polynomials. If you asked for using quartic equation formula, then I must ask you to search up how long and unproductive that is.
@@techcraft455 you mean Sridharacharya Formula?
Sar Agar 1 / X ko X / X multiply kar denge Uske bad 1 by x square common le lenge Sab Mein Se to aapane Jo question thoda Din pahle karaya tha 4 5 Mahina pahle Usi ke jaisa ho jaega
Sir
Let
A= (1/x - 1/×^3)^0.5 and
B = (1/x^2 - 1/×^3)^0.5
A^2 - B^2 = 1/x * (1-1/x)
A - B will be equal to the above value since A + B = 1 as given in the question itself
So now we have the sum and difference of A and B
This will gimme 2A = 1 + 1/x - 1/x^2. Putting the value of A and sending 2 to the RHS in the denominator gives
{(1/x)*(1-1/x^2)}^0.5 = 0.5*[(1/x) + (1-1/x^2)]
Careful observation says, it's GM = AM, which is only possible when both the numbers are equal
1/x = 1-1/x^2
Solving which gives
X = (1+5^0.5)÷2
Negative root will be ignored for the same reason as sir said
Hii Keshav can u post the solution on your channel ?
🌜 nicely done bro observation is the key
One of the best approaches
@@suryanshmarathe9012can you post a picture pls
Noting the mean inequality here was pretty elegant. Good work.
i got it correct sir in 1st atrempt but sir after putting value of x eqn not satisfying it plzz check it
Sir If we put x=(5^1/2+1)/2 in the question then it is 0.5(approx) and if we put x=(-5^1/2-1)/2 then we get ans 1.1 which is approx =1 sir please check and reply 🙏🙏
I solved this equation with x
Sir 2 root ko add karke 1 tabhi aayega jab ek 0 ho and ek 1 dono ko ek ek baar leke solve karke union leke answer aajayega real ?
Society mein sir jaise logon ki bohot need hai jo itne selfless tarike se social work kree hai
Salute
Sir it is the same problem with some modification just multiply by x
I found out the range in which x lies now will be going to see the sol😅
I was able to solve the eqn sir
Sir plz solve it with explanation a pack of card contain 4 ace 4 king 4 queen 4 jack two cards are drwan find probability that one ace is drwan least no of times
Plz solve it sir
Sir pls make video on EXPONENT OF PRIME (P) in n! 🙄🙄
Bohut maja aa gaya sir...❤
Masth ek dham bhannaatttttt
Sir please tell how to improve calculus
Find the values of x, y , z and A in given equation x²+y² +z²=2A
where x=y-1, y = z-1 and z=x-1 and
x+y+z=1.50 sir plss solve this
This has no solutions
Mast❤
Prove that
4 - 4 + 4 - 4 +...... ∞ = 3 - 2 + 1 - 0.5 +.....∞
Sir jiii maths kaha se pdte ho
Sir gajab ho aap 😅
Golden ratio
2:06 Extra solution= Extratanious roots?
Yeah
Sir class 11th students ke liye kuch Tips Maths ke liye, please🙏😢
Practice
But (t^2-1/t^2) does not equals to (t-1/t)^2....
Sir pls maine jo problem diya tha usko pls discuss kar dijiye
What que
Phicli wali video ke comment mein diya tha
Iske thik pehle wali jisme sir apne Newton ke formula ke baare mein discuss kiya
Bhannat question tha sir ❤
As a 9th grader i solved and got the right answer
Sir for (t^2-t^3)^1/2 there should not be -ve inside the root but when we are keeping t=(5^1/2 -1)/2 we are getting -ve inside the root which is not possible and in the same way in 2(t-t^3)^1/2 if we put t=( 5^1/2-1) then also we are getting -ve inside the root which is not possible and I think we should check LHS if the root it self is not defined the how can we do SOBS
Check calculation bro its +ve
Sir kitna easy question tha Mai 10th Mai hu aur maine dekhte hi solve kar dala sirf rejection nahi Kiya tha
Poocha kisine? Nahi na? Kyu bhauk rahe ho faaltu mein, sachme intelligent hai to yahan baithke apni taareef nahi krta...jaake kuch kaam karo
sir aap physics galaxy pein revision checklist upload karna thoda bul gaye ho, please karoo
Bkl tu kon hota hai be bolna wala
Maths ki kahani, sabko sunani
Baat purani, jaani pehchani
Yes sir i did it.❤
Sir pichli bar Jo question dia tha 35 yr wala wo Kara do
Ji
29th comment and 180th like
Sirji kuch hard questions laona ❤❤❤
0.61803398874989484820
Aur accuracy chahiye kya 🗿🗿
❤❤❤
Lengthy que me maja aa jata h...
Good question indeed .
SIR ne kaun-kaun si degree Kari hai, janne ke liye Like kare.❤
Koi mujhe 5:20 ke bad se kya hua samjhayega please
Sir is question ka source kya hai..kis book ya ...kahaan milega ye ❓
Mai tu lcm hi leta reh gya
Sir pls make videos on INMO
Sir k upar se gya 😢
Thankyou sir 🙏 it is very very helps ful for us❤
i can't and maybe i will not be able to😢
Correct bro 😂
#StopVivekBindra
First person to like❤
1st view like it 🎉🎉
first
Solved without seeing the solution 😎
Jaldi jaldi comment karta hu likes milenge
Golden ratio
Sir pls make videos on INMO
Sir pls make videos on INMO