I think k is supposed to be defined as k=(the exponent of the X's coefficient that we are looking for, in the example is 3) / (exponent of x from the expression, which in this case is 3) The coefficient will be (4 choose 3/3) times (-x^3)^(3/3) = (4 choose 1) • (-1) (x^3) =-4 I think, It's a coincidence that the answer she gets is true, caused by (-x)^3 is equal to -x^3 ,and 4 choose 3 is equal to 4 choose 1.
This channel is gold mine!
Great series!
This is actually the old series. You should check out the new one. But thank you!
Hello, Thank you for this amazing video, its a life saver. I'm wondering why we get (-x)^3 and not (-x^3)^3 in the last example. 14:16
I consider writing it as (4 1)(-x^3)^1 is more reasonable, viewing x^3 as a whole x.
I think k is supposed to be defined as k=(the exponent of the X's coefficient that we are looking for, in the example is 3) / (exponent of x from the expression, which in this case is 3)
The coefficient will be (4 choose 3/3) times (-x^3)^(3/3) = (4 choose 1) • (-1) (x^3)
=-4
I think, It's a coincidence that the answer she gets is true, caused by (-x)^3 is equal to -x^3 ,and 4 choose 3 is equal to 4 choose 1.
In 1:55 why the x is increasing..
The power of x increases as the power of y decreases. The two exponents add to n.
How is 4 choose 5 even possible? Isn't that 4!/(5!*(-1)!)?