Abaqus Explicit: Pendulum Impact with Material Damage
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- เผยแพร่เมื่อ 25 ส.ค. 2024
- This video is on Pendulum Impact with Material Damage example in Abaqus/CAE 6.14. This video shows you how to develop Pendulum Impact with Material Damage simulation model with example enables you to practice and reproduce the FE model on your own. If you find this video useful like us and Subscribe Abaqus Acumen Channel.
thank you so much.can you please realise a video of wire rope or cable please
and also with gravity used
Your videos are awesome and I have been following you for some time now. Finally, I believe I have something to add. The reason the elements are not deleted is because your keyword needs to be "Shear Failure, Element Deletion=YES", you also need to tick element deletion in the mesh element type and in Field Output requests activate SDEG under Failure/Fracture and STATUS under State/Field/User/Time. Your elements should delete properly.
Thanks for sharing!
another great video
Thank you so much. This video really helped me. I only ever worked with static problems and this tutorial helped me model my dynamic problem :D.
Thank you so much! all the videos are worthy!
Good work. :)
Fantastic demo.
Glad you liked it!
Useful video. Thanks a lot.
Soo nice
I came across an interesting problem if you wish to try and make video on the same.
It's a tensile test upto failure.
It is a multilayer steel material with approximately 15-16 alternative layers of austenitic (ductile and low strength, 40%, 1000MPa) and martensite (10% failure strain at 1600MPa). The resulting behaviour is interesting.
thank you so much you did helped me a lot
Thank you so much. keep it up
Firstly, thank you so much for your informative and very useful videos.
I have a question in relation to the rotary inertia, this was previously asked by Ryan McKnight
The calculated kinetic energy given the 750 r/s, a radius of 500 mm and a ball mass of 1.5 kg is 105468 J
Using the 0.77 value (for the solid sphere) produces a kinetic energy significantly less than the stated value.
Using the rotary inertia I=mr^2 as per Ryan McKnight's value (375 ton mm^2) produces the correct kinetic energy in the Abaqus analysis. In the case where the rigid body reference point is at 0,500,0, as per your example.
If the reference point is placed at the centre of the sphere, the rotary inertia is correctly defined using the 0.77 value. With the addition of an external reference point and coupling constraint in the assembly model, and the application of the velocity field at the reference point. The model also solves with the correct kinetic energy.
Again thank you for you excellent work.
If this is incorrect please comment.
Thank you so much for this video. Can you please upload a model for ball drop impact on laminated glass
Than you sir,
If there are multiple components then how to give shear failure to a particular component?
thank you very much for your interesting video. I have a question , how can you calculate the rotary inertial value for this model ?
I = (2/5)mr^2 for full solid spheres.
Thank you very much for this tutorials, currently your videos are my principal learning source, can you upload a drilling simulation
Thank you. We will try
I have one question. I did exactly as you, but my ball went through the plate, not reflect. I assumed that problem at constant rotational velocity, but I am not sure.
The maximum displacement of plate with element deletion is different from the plate without element deletion. what could be the reason. Please help
I wonder if any kind of mesh sensitivity was observed in this analysis.
can you please share any video for modeling explosion using abaqus CEL?
I want to replicate the piercing operation using abaqus.Can you please let me know the procedure for simulating the piercing operation?
Excuse me, I just have one question. Why should the Reference Point's end point be 100,500,0 ? I think both start and end point are same... I'm confused...
in simulation of low velocity impact on cfrp plate .there is one element distortion excessively bcz of that it get aborted .so plz guide me to remove that problem.
Thank, please it is possible to make an impact video with illustration how one obtain the function response frequency. It is very important for me
seems quickly is his fav word!XD
how to get the pendulum oscillations?
Thank you sir. Can you please tell me how did you decide the angular velocity of pendulum ( at time 14:43 ) ? Did you assume it ? If yes then how the time period given by you ( at 16:22) is related to it ? If not then how to calculate it ?
Could you please e-mail me
Is it lowering the global size means lowering the number of nodes? i'm using Student Edition ABAQUS 2016 which limit only for 1000 nodes.
make the grid coarser to get less than 1000 nodes
sir pls upload FSW(friction stir welding) simulation video
I have the warning ( The *shear failure option will not be supported in the future release.) So, I have no damage. How to fix it? I put the keywords as in the video.
I have same problem too, if you are able to solve it then plz let me know
This warning concerns the future release of abaqus for which the *shear failure option will not be supported however you can use instead *damage initiation and *damage evolution options for modeling progressive damage and failure of materials. I have not paid attention to this warning since the model runs perfectly.
✌🏻✌🏻✌🏻
i need someone expert in abaqus... please contact me...
rotary inertia is wrong
I=mr^2
m=1.5e-3
r=500
I=1.5e-3 * 500^2
I=375
its 375 not 0.77
Inertia calculated about the ball
thanks
you better start with appreciation.... thanks.
what a nonse
He used the formula of I = (2/5)mr^2 for solid spheres.
i need your help please,
your mail please
thank you
I have one question. I did exactly as you, but my ball went through the plate, not reflect. I assumed that problem at constant rotational velocity, but I am not sure.