Everything you need to know about Laplace transforms

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  • เผยแพร่เมื่อ 16 ต.ค. 2024

ความคิดเห็น • 46

  • @danielflood1309
    @danielflood1309 3 ปีที่แล้ว +14

    Explained better than any college professor I've had, well done!

  • @chaotic_spirits
    @chaotic_spirits 3 ปีที่แล้ว +9

    this is the most beautiful explanation I have ever heard, thank you for the contribution to the community.

  • @alvaroaberastainmarzorati7029
    @alvaroaberastainmarzorati7029 4 ปีที่แล้ว +6

    Hey, I saw your post on reddit and i´m surprised by the quality of your videos. Keep it up!

  • @aalperenpolat
    @aalperenpolat 3 ปีที่แล้ว +11

    I wish you could be my Signals and Systems teacher

  • @jacobseal
    @jacobseal 3 ปีที่แล้ว +2

    Nice video. That backing beat made me want to grab a mic and lay down some soulful 90's raps.

  • @cyadid
    @cyadid 2 ปีที่แล้ว +1

    Best explanation I have seen ! I wish I could get this when I first learned about Laplace Transform Well done !

  • @adambrekibirgisson1670
    @adambrekibirgisson1670 2 ปีที่แล้ว +1

    Very well explained, the quality of your videos is on par with the best education channels

  • @farwamumtaz176
    @farwamumtaz176 5 หลายเดือนก่อน +1

    Why i didn't find you before.Amazing ❤

  • @amanagnihotri6871
    @amanagnihotri6871 3 ปีที่แล้ว

    This channel is life saver. Thank you sir, please keep uploading such informative content

  • @Adhithya2003
    @Adhithya2003 3 ปีที่แล้ว

    Thank you so much , That analogy of PDF -> Word -> PDF was so awesome.

  • @mrmatias2618
    @mrmatias2618 2 ปีที่แล้ว

    Thanks man, the PDF example made my day. subscribed.

  • @Kobs.A
    @Kobs.A 3 ปีที่แล้ว

    Your analogies are insane

  • @aravinthdravid9183
    @aravinthdravid9183 2 ปีที่แล้ว

    Buddy which book did you referred to give this easy understanding of Laplace Transform. Kindly share if you have any.

  • @danielsharkoff4013
    @danielsharkoff4013 ปีที่แล้ว

    Wow what an amazing video.. immediately subscribed after watching.

  • @patrice9480
    @patrice9480 4 ปีที่แล้ว +2

    incredible quality, really !

  • @snowwhat3911
    @snowwhat3911 ปีที่แล้ว

    Am happy I found ur channel

  • @bunkydunk7500
    @bunkydunk7500 ปีที่แล้ว

    Great explanation! Much appreciated!

  • @stevematson4808
    @stevematson4808 11 หลายเดือนก่อน

    What model of scope is that behind you?

  • @nielscarpentier4616
    @nielscarpentier4616 ปีที่แล้ว

    Thank you so much!

  • @The_double_side
    @The_double_side 3 ปีที่แล้ว

    such a confident man .....

  • @Kobs.A
    @Kobs.A 3 ปีที่แล้ว +1

    I didn't get the Fourier analogy

  • @irfansyahril8511
    @irfansyahril8511 2 ปีที่แล้ว

    Amazing!!

  • @danielsadeko8499
    @danielsadeko8499 3 ปีที่แล้ว

    Thank you for this explanation

  • @sharadwade987
    @sharadwade987 3 ปีที่แล้ว +1

    Loved it

  • @kennethkyalo3821
    @kennethkyalo3821 2 ปีที่แล้ว

    Excellent

  • @vaibhavpatil9956
    @vaibhavpatil9956 3 ปีที่แล้ว +1

    please explain why it works!!!!!

  • @MisterBinx
    @MisterBinx 3 ปีที่แล้ว

    I remember doing these in differential equations years ago. Now I have to figure them out again in mechanical vibrations.

  • @theawantikamishra
    @theawantikamishra 3 ปีที่แล้ว

    This is amazing. Subscribed

  • @elaymisgav1879
    @elaymisgav1879 2 ปีที่แล้ว

    Hi thank you very much love your videos!
    I am now taking linear systems course , it feel that I don't understand well the difference between Laplace transform and Fourier, and in addition in which sort of problems I will use which of them. If their is anyway to make it clearer that will be great! thanks again!

    • @carultch
      @carultch 7 หลายเดือนก่อน

      Good question. The Fourier transform is a special case of the Laplace transform, once the system achieves steady state and initial transient behavior settles. Corresponding to the steady state, the real part of the Laplace domain variable s, will approach zero. The s-domain variable will become a purely imaginary number for the Fourier frequency domain, which is j*omega.
      The Fourier transform is a spectrum of sine and cosine waves that model the signal. The Laplace transform is a spectrum of exponentially decaying sine and cosine waves, and some with no decay, that models the behavior of the signal, inclusive of both the initial transient, and the steady state condition.

  • @abdelrahmankhalil8878
    @abdelrahmankhalil8878 2 ปีที่แล้ว

    best video on laplace transform ground up deserves better

  • @ashwiniked
    @ashwiniked 3 ปีที่แล้ว

    You are a great teacher. Put more informative videos.

  • @kratomleaf8937
    @kratomleaf8937 7 หลายเดือนก่อน

    bro where have you gone

  • @anirbanmukherjee5073
    @anirbanmukherjee5073 2 ปีที่แล้ว

    Pls make for Fourier also

  • @Nahash5150
    @Nahash5150 8 หลายเดือนก่อน

    So I want to make a dual band filter that attenuates a signal by 1dB at 250 hz and at 2.5 khz. The Q should be about 0.5

  • @aspirohk3558
    @aspirohk3558 2 ปีที่แล้ว

    Sample of solving the 'convution' solving in the time domain
    Why do they use s for frequency domain like f could work easy like f(t) t=time but f(f) f=frequency

    • @carultch
      @carultch 7 หลายเดือนก่อน +1

      I believe s is supposed to stand for state. Either that, or it's just a completely arbitrary letter, when other letters were spoken-for when the concept was coined.
      It's more than just frequency, so they don't just use f. It is called complex frequency, because it is a complex number where its real part represents exponential decay, and its imaginary part represents angular frequency.
      It's common to use the trio p/q/r, as the equivalents of s, when using position domain instead of time domain. The Laplace domain variable for x is p, for y is q, and for z is r. The next letter in this group is s, which is the Laplace domain variable that corresponds to t for time.
      Fourier transform could use omega or f, for frequency, or omega for radian frequency, depending on which variant of the transform you use. In the f-world, Fourier transform and inverse Fourier transform, are both identical processes, so it makes it easy to match the pairs. In the omega-world, you accumulate a constant. Some tables will normalize this constant, by including a factor of 1/sqrt(2*pi), so an omega-world Fourier transform is bidirectional with the time domain.

  • @to_YouTube
    @to_YouTube 3 ปีที่แล้ว +3

    pls upload practical applications of duality , autocorrelation , sample theorem .... this will help us a lots ...

  • @amanravan9795
    @amanravan9795 3 ปีที่แล้ว +1

    👍👍

  • @chrisoca958
    @chrisoca958 3 ปีที่แล้ว +1

    Your video is great! I subscribed!! ^_^

  • @utkarshtrehan9128
    @utkarshtrehan9128 3 ปีที่แล้ว +1

    MVP

  • @DhanushKumark
    @DhanushKumark 2 ปีที่แล้ว

    i wish he would have been my teacher

  • @mahmoudshata1105
    @mahmoudshata1105 2 ปีที่แล้ว

    i just wonder why s equals this ?

    • @carultch
      @carultch 7 หลายเดือนก่อน +1

      The Laplace domain variable s, represents complex frequency. The real part is exponential decays, and the imaginary part is oscillation. The Laplace transform converts a time-domain function into an s-domain function, and that s-domain function is a spectrum of various amplitudes, frequencies, and decay rates, of sine and cosine waves enveloped by exponential decay functions.

  • @el_witcher
    @el_witcher 3 ปีที่แล้ว

    +1 Sub 😉