I agree that 217 can be the right Child of X so that x range is [94 to 136] [=43 different values] but 217 can also be the left child of X so that x permissible range becomes [218 to 235] [=18 different values] so in total x can have 61 different/unique values
@@bestquotes2765 because the next node traversed from X is 217 and while searching we follow a single path till the searched node . Just try to go for a BST and search any value in it you will get it
in ques 3 there should be specified that the tree is also binary search tree, then only we can perform your procedure other wise information is not enough...... and if this is specified that the tree is binary search tree then we can find post order just after finding inorder as inorder of a BST is just all keys with ascending order arrangement... so at the end we can find post order with the help of pre and in order
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Gud mrng mam/sir In tcs profile I have entered Rakshitha only instead of Rakshitha N will they allow me to write an exam because in Aadhar card my name as Rakshitha N.
Prepinsta tell me how to get my paid material u deducted my money but not send me any material.what the hell is going to happen from ur side.u give me ur no.i want my paid material
I agree that 217 can be the right Child of X so that x range is [94 to 136] [=43 different values] but 217 can also be the left child of X so that x permissible range becomes [218 to 235] [=18 different values] so in total x can have 61 different/unique values
In question 10, i think correct answer would be 43 instead of 42. as x can take values from 94 till 136. to understand this suppose x can be 5,6,7 if we do 7-5 this will give us 2 but here x is actually taking 3 values.
I really appreciate your hard work to give easy explanation for students who really need this . I follow Prep Insta 's all video regarding TCS NQT. All the materials are really helpful and I also go through all your website course..Good quality content. 5 stars 🌟🌟🌟🌟🌟
This video helped a lot, I thought all the important matter would only be in your paid content which I couldn't buy. I hope it all helps in clearing the test.
answer to ques 10 should be 43 as number of elements between 136 -94 is 43 not 42, Eg: elements between 94-98 is (94,95,96,97,98) =5 (98-94+1=5) therefore 136-94+1 is required
Thank You very much sir it was a great videos, every question is explained in detail so the concept also clear and if question of this type comes can also be solved ...once again thank you very much
The first explanation of the question was wrong. it's not about 6 zeros there. The actual reason is when we store 0.1 in variable "f" it stored in binary form in memory. we can not convert 0.1 into binary accurately there will be some transaction error. The same question if you do with 0.5 you will get output "yes" without typecasting. Happy coding
In Qns.10 : As per the sequence of order the X had appeared in-between the number 93 and 217. So, the ans would be 124(217 - 93). In Qns.7 : When we look at the key point "the packets arriving in right order" we can use queue data structure right? as it's increase size based on input.
Thank you Atulya Sir...your explanation is always the easiest..whether it is your online class or study material. Keep explaining like this only no complains
in ques 3 there should be specified that the tree is also binary search tree, then only we can perform your procedure other wise information is not enough...... and if this is specified that the tree is binary search tree then we can find post order just after finding inorder as inorder of a BST is just all keys with ascending order arrangement... so at the end we can find post order with the help of pre and in order
In Question 7 how can Linked List be the answer when we know in Computer Networking Flow Control Methods like Stop & Wait/Go Back N etc use Queue as the Receiver Buffer to receive data packets from Sender?
How to approach pointer based question in Tcs. And ur team is so active. And we are preparing in ur platform and we are sharing your videos to my frds.. Thanks a lot.
@@arnavsingh381 but where she wants recent changes to undo .In telephony audio message you can't undo anything. so,I think queue might be the better answer .
My answer for question 10 You chose position of x right But after that there will be 2 possibilities 217 will be the right child or the left one If right then 93
My answer for question 10 You chose position of x right But after that there will be 2 possibilities 217 will be the right child or the left one If right then 93
Sir, I have already cleared TCS digital 2020 held at our campus but didn't get selected. So can I directly appear for TNQT interview or should I take TNQT 2020 again? Our placement cell said that we can appear directly for an interview. so please sir reply asap! Thank you
@@nikitasarda7389If you appear for the interview without writing NQT you will be considered for Ninja profile only. If you are determined to get Digital profile write NQT. This is what our college said to us.
The viedo was very helpful ...can u please give a clear idea about pre and post increments and decrements by explaning more examples ..bcz its a confusing topic when to solve from right or left
Diffrent compiler read this statemenr differently.... Some reads it from left to r8 and some r8 to left!! Always go from right to left (as per c or c++)
anybody saw this????? after the question is answered and the right tick mark which comes on the solutions on the slides are different in many of the problems??? Which is the right answers solved one or ticked one??
In last question! What if x value is lesser than 93.. Then it will go to left hand side. So the method will be same for both right and left hand side.!!
x value can't be lesser than 93 else we will never get to traverse 217 while searching 137, although x can be greater than 217 which isn't mentioned. Reply if I am wrong @Prep Insta
I think you have missed something in Q3 it should be binary search tree not just tree. If its a normal tree or even binary tree then there is no compulsion on left child should have to be lesser
Sir in first question there's no bracket for "if and else" statement soo no answer ll be printed, the complier ll indicate error...I am saying no answer ll be printed(it ll indicate error)
Question 3rd sol. is wrong The order will be 9,11,15,13,19,23,21,17. Because 11 should come before 9 while traversing the tree in post order...the post order format of traversing is left,right ,root and root of left can be 13 and 11 both
when you run code for question 2 you get answer 22 as "a" will first pre incremented and will become 11 so a+a = 22 will be assigned to x. Please correct me if i am wrong.
In ques 9 when n becomes 0 you are saying it'll terminate then how can you decrement the n th value?? ...the answer of that ques ans should be '7 5 3 1'
hello sir, my doubt isnt related to these questions. Like suppose we declare an enum function and in enum function if we initialize the value to some number, then will the initialized value be considered or the value which enum assigns?
Question no. 5 doubly linked list is not even in the option than how come we can consider linked list as doubly list list, they both are different I suppose ?
in our college , students whose cgpa is above 7.5 so they not need to give quant section in tcs nqt 2020 . is it true ? if yes then on what basic they will select the students
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I agree that 217 can be the right Child of X so that x range is [94 to 136] [=43 different values]
but 217 can also be the left child of X so that x permissible range becomes [218 to 235] [=18 different values]
so in total x can have 61 different/unique values
Yes....I too rising this doubt .....
Great Buddy
Why we shouldn't assume that x value smaller than 93 so that x become left of 93?
@@bestquotes2765 because the next node traversed from X is 217 and while searching we follow a single path till the searched node . Just try to go for a BST and search any value in it you will get it
@@anandmusicverse6235 where would you put 69 or 92 on that tree?
U know what, you're best at explaining things. U became my helping hand for all time. ❤️❤️❤️
I didn't have much idea about tcs paper pattern. Such video needed to prepare placement .Thank you so much for this video. It helped a lot.
in ques 3 there should be specified that the tree is also binary search tree, then only we can perform your procedure other wise information is not enough......
and if this is specified that the tree is binary search tree then we can find post order just after finding inorder as inorder of a BST is just all keys with ascending order arrangement...
so at the end we can find post order with the help of pre and in order
ur right
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hi
I have great experience with prepinsta from August 2018..i gi through the this videos and i easily cracked tcs ninja .. programming explanation part will very excellent..i should request to same explaination about advance apptitude.. thank you prepinsta😀
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In 2nd qn u haven't checked the priority
Right to left
Gud mrng mam/sir
In tcs profile I have entered Rakshitha only instead of Rakshitha N will they allow me to write an exam because in Aadhar card my name as Rakshitha N.
Prepinsta tell me how to get my paid material u deducted my money but not send me any material.what the hell is going to happen from ur side.u give me ur no.i want my paid material
I agree that 217 can be the right Child of X so that x range is [94 to 136] [=43 different values]
but 217 can also be the left child of X so that x permissible range becomes [218 to 235] [=18 different values]
so in total x can have 61 different/unique values
Sir in ques 10 the value of X is greater thn 93 and less than 217 how come it is less than 137 ? I didnt get it
In question 10, i think correct answer would be 43 instead of 42. as x can take values from 94 till 136. to understand this suppose x can be 5,6,7 if we do 7-5 this will give us 2 but here x is actually taking 3 values.
I really appreciate your hard work to give easy explanation for students who really need this . I follow Prep Insta 's all video regarding TCS NQT. All the materials are really helpful and I also go through all your website course..Good quality content. 5 stars 🌟🌟🌟🌟🌟
Woaaaah thanks !!
In the last question, the answer will be 61 and not 42 . As -
1) for 93
Close to answer, we could consider number between 94 to 235 including both and excluding 137 and 217 which turns out to be 235-94+1=142
Thank you so much prepinsta. So many questions were there in exam. It will really help a lot. You guys are really doing a lot for all the students :)
Thank you komal
In the last question answer will be 43 (94 to 136, that's 43 values in total).
you are Right 94 and 136 also include
who else feel that voice is mismatch with pen.
Was eagerly waiting for such a video, Really helps!!!
24:28 "Eesha is doing all kinds of things" :p Boss lady!
@6:52 right to left... Pre increment will have highest priority so 11 + 11 is 22
Who liked the comment
I suggest you, write the entire code in c compiler and execute and check the output.
This video helped a lot, I thought all the important matter would only be in your paid content which I couldn't buy. I hope it all helps in clearing the test.
Wow, this video helped me in clearing my doubts.. thank you sir for ur easy explanation.......!!!!!!
answer to ques 10 should be 43
as number of elements between 136 -94 is 43 not 42, Eg: elements between 94-98 is (94,95,96,97,98) =5 (98-94+1=5) therefore 136-94+1 is required
Great explanation.This is the best video for understanding Programming logic
Thanks ankita
answer for Q10 is 43 i.e numbers btw 93 and 137 ( Tn=a+(n-1)*d ) so 137=93+(n-1)1 is 45 then subtract 2(for 93 and 137) from 45=43,like if am right
Thank You very much sir it was a great videos, every question is explained in detail so the concept also clear and if question of this type comes can also be solved ...once again thank you very much
If you have any question Please feel free to ask us in the comment section
Is this a re-uploaded video....
I have already watched this videos last night..
I didn't get Q4 because in tree right child value is always greater than the root value
Thankyou so much for this video today. Much needed video. Tomorrow is the exam. Don't know what type of questions will come
This video is very important a few questions may also come in the exam !!!
que 10 : we cannot travel this side😂😂 Nice explaination
Lolz😂
Thank you so much for this video sir..this will really help me in preparation for tcs nqt 👍
The first explanation of the question was wrong. it's not about 6 zeros there. The actual reason is when we store 0.1 in variable "f" it stored in binary form in memory. we can not convert 0.1 into binary accurately there will be some transaction error. The same question if you do with 0.5 you will get output "yes" without typecasting. Happy coding
nice
Yes 1st question explanation is wrong
A very good explanation sir. Good 👍😍😍
217 can also become left child of X if X is [218,235] by this X can have 61 possible values
In Qns.10 : As per the sequence of order the X had appeared in-between the number 93 and 217. So, the ans would be 124(217 - 93).
In Qns.7 : When we look at the key point "the packets arriving in right order" we can use queue data structure right? as it's increase size based on input.
esha cn packet question answer should be "queue" as we can implement queue using LL and packets are arriving in an order
exactly
A heart full thanks for this video. It was a much needed video
We are glad that we could help
Thank you Atulya Sir...your explanation is always the easiest..whether it is your online class or study material. Keep explaining like this only no complains
Thanks ashish means a lot
Thank u for this video, it really helped me in understanding coding difficulty
Thanks vaibhav
Q2. I thought this type of questions solved from right hand side.
You are too good at data structures thanks alot sir
Nice video ,day after tomorrow is my tcs xm ,tnx for uploading this video we want more videos like this 😊
Thank you sir for the explanation. It helped a lot in understanding the concept..
we are really happy that you liedk it
Q)10 ans will be 61... check it properly by considering both the cases of x>93 and ×
In Q.no 3 do mention that it's a bst not just tree
exactly
in ques 3 there should be specified that the tree is also binary search tree, then only we can perform your procedure other wise information is not enough......
and if this is specified that the tree is binary search tree then we can find post order just after finding inorder as inorder of a BST is just all keys with ascending order arrangement...
so at the end we can find post order with the help of pre and in order
Sir in Question 7 queue can be the answer because queue is open from both sides just like a pipe for transmission of packets isn't so??
in queue size is fixed
Great work guys..
Learning is never been this much easy thanks for the greater good prepinsta
Thanks rishabh
In Question 7 how can Linked List be the answer when we know in Computer Networking Flow Control Methods like Stop & Wait/Go Back N etc use Queue as the Receiver Buffer to receive data packets from Sender?
How to approach pointer based question in Tcs. And ur team is so active. And we are preparing in ur platform and we are sharing your videos to my frds.. Thanks a lot.
Thanks do not forget to subscribe and ask them subscribe as well !! :)
In question 7 answer can be queue because FIFO and queue can also be implemented using Linked list.
agree, but she wants the recent changes to undo. stack will be good. pop the top
@@arnavsingh381 but where she wants recent changes to undo .In telephony audio message you can't undo anything.
so,I think queue might be the better answer .
My answer for question 10
You chose position of x right
But after that there will be 2 possibilities
217 will be the right child or the left one
If right then 93
For the ques 5
Circular doubly linked list the accurate answer
very nice and useful video.Thank u so much
honestly Q10 is going over my head :P
He did not explain it very well
same here
my que is also the same
nothing different no difference
Same here
Same here neji, maybe ask sasuke!
My answer for question 10
You chose position of x right
But after that there will be 2 possibilities
217 will be the right child or the left one
If right then 93
👌👌👌👈👌very nice video sirji
...
Hello guys,
Hope that you like the video. If have any doubts :) You can ask me in the comment section below...
Atulya Sir !!! ^_^
Sir, I have already cleared TCS digital 2020 held at our campus but didn't get selected. So can I directly appear for TNQT interview or should I take TNQT 2020 again? Our placement cell said that we can appear directly for an interview. so please sir reply asap! Thank you
@@nikitasarda7389If you appear for the interview without writing NQT you will be considered for Ninja profile only. If you are determined to get Digital profile write NQT. This is what our college said to us.
@@nikitasarda7389 You will appear for TCS direct campus selection.
sir ques no :2 is giving the ans 22 on turbo compiler which value we take in examination
22 is correct
Those sort of questions are actually compiler dependent . You can never know what is right answer
great explanation really loved it
We are really glad that you liked it !!!!
In which compiler you gives output??
In question 9, ch is int variable but ch = getchar() is present won't that result a compilation error?
Very helpful for programming
1st question, if i put 0.1 it gives "no" but while am putting 0.5 it gives "yes" in actual comliper nut why???
There is more possible value of X in question no. 10.
i cant join on whtsapp grp for 2020 batch..it says the grp is full...how to solve it
The viedo was very helpful ...can u please give a clear idea about pre and post increments and decrements by explaning more examples ..bcz its a confusing topic when to solve from right or left
Diffrent compiler read this statemenr differently.... Some reads it from left to r8 and some r8 to left!!
Always go from right to left (as per c or c++)
anybody saw this????? after the question is answered and the right tick mark which comes on the solutions on the slides are different in many of the problems??? Which is the right answers solved one or ticked one??
in Q10 .... 236>x>217 or 137>x>93
Question 4 was there in my TCS NQT exam for 2018 batch off campus
Yes, its previous year question paper for TCS
Thank u so much prepinsta for uploading the video
You're welcome.... We hope that this video will be helpful for you. If you any questions feel free to ask us in the comment section.
bhaiya.. last wala samaj nhi aaya 35:44 u said we cant jump the place. can you help?
really iam excited with this content, it was pretty good 👍
In last question!
What if x value is lesser than 93.. Then it will go to left hand side.
So the method will be same for both right and left hand side.!!
x value can't be lesser than 93 else we will never get to traverse 217 while searching 137, although x can be greater than 217 which isn't mentioned. Reply if I am wrong @Prep Insta
last question (10 q) ans should be 61 not 42....because 93
Yes, my answer is also same .I don't understand why they are not considering 217
Good video really loved it
Thanks ^_^ Do not forget to show love and sub
In last question, if X is printed on the right of 137 then how it will be less than 137?
In 10th question answer is wrong
217>x
I think you have missed something in Q3 it should be binary search tree not just tree. If its a normal tree or even binary tree then there is no compulsion on left child should have to be lesser
Sir in first question there's no bracket for "if and else" statement soo no answer ll be printed, the complier ll indicate error...I am saying no answer ll be printed(it ll indicate error)
There is no need of brackets for if and else...it still gibes the output
@kgame , okay 😊
Thank you sir
Question 3rd sol. is wrong
The order will be 9,11,15,13,19,23,21,17.
Because 11 should come before 9 while traversing the tree in post order...the post order format of traversing is left,right ,root and root of left can be 13 and 11 both
Informative video😍
Programing me career bnane ke liya kya hume compilr design,network ,os,rdms,padhna padega reply. kar
when you run code for question 2 you get answer 22 as "a" will first pre incremented and will become 11 so a+a = 22 will be assigned to x. Please correct me if i am wrong.
yes bro u r wrong
@@AllDimension to bhai correct to bta
@@nilborban8315 the one he explained was correct
Cannot join whatsapp group for 2020 batch. Its already full. Please provide another link
Despite and in spite of same meaning right and what is the difference between two words
In ques 9 when n becomes 0 you are saying it'll terminate then how can you decrement the n th value?? ...the answer of that ques ans should be '7 5 3 1'
Sir in tcs nqt there is a how much negative marking
what about queue in Q7, first come first serve and and packets are coming in right order
hello sir, my doubt isnt related to these questions.
Like suppose we declare an enum function and in enum function if we initialize the value to some number, then will the initialized value be considered or the value which enum assigns?
why question 8 shouldnt be a dynamically allocated array?
why tho? when you can simply use normal array
Thanks man.
Thank you...
Sir can i apply for both NQT and ninja . I am 2022 M.Tech passout.
in last question you need to take 94 &136 so answer is 42+1=43.
What if the value of X is 80??
Question no. 5 doubly linked list is not even in the option than how come we can consider linked list as doubly list list, they both are different I suppose ?
😅
Can anyone explain in Q4. Whats wrong in option B?
In Q no 10. The value of x can also be less than 68...than why we r not considering that??
if we start our search from 68, how come x would be less than 68
Question 7 , can't dynamic memory allocation be used for arrays?
Answer will be of second question
x=22
This is right.
How?
please explain pointer based questions sir...thank you
We will post thiat soon as well
Can anyone explain why in Q.10, numbers from 218 to 235 are not included in the answer?
in our college , students whose cgpa is above 7.5 so they not need to give quant section in tcs nqt 2020 . is it true ? if yes then on what basic they will select the students