find pressure at A, B, C, and D | hydrostatic pressure| sample problem
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- เผยแพร่เมื่อ 1 ต.ค. 2024
- #tutorjackph #fluidmechanics #relativeequilibriumofliquids #mechanicsoffluids #fluids #tutorial #lecture
Fluid Mechanics studies the response of fluids on forces exerted on them.
Video description:
This video discusses a sample problem on hydrostatic pressure.
Sample problem:
Calculate the pressures at A, B, C, and D in kPa.
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Hello sir! Sa Pressure D (Pd) ---> Gamma x h
Imu-multiply pa po ba sa Specific Gravity (sg) of oil, sg=0.9?
Pd = 4.905 + (0.9)(9.81)(1.9)
pansin ko rin nga po
Oo need pa i-multiply yan kasi given si sg
tama mga lods, nakalimutan ilagay hehehe :)
@@TutorJackPh bakit hindi po sinama yung pressure ni air? (- 12 x 0.9)
Pansin ko po sir nakalimutan ata yung value sa specific gravity ng oil
So probably, Pc+(0.9)(9.81)(1.9)=21.68 kPa
Yes lods nakalimutan hehe ✌
Hello po.
Oil po diba yung iko-consider sa point D. Imumultiply pa po ba yung 0.9 na Specific Gravity ng oil?
yes lods, nakalimutan lng sa vid hehe sorry
Sir, ask ko lang po , bakit sa iba ang gamit nilang standard uniw weight of water is 9.790 instead of 9.81? thank you po
Hello lods. Depende po yan sa specified na temperature. 9.79kn/m3 pag nasa 20deg C, 9.81 naman pag nasa 4deg C
Nakalimutan niyo po ang Specific Gravity ng oil na 0.9
opo lods hehe salamat sa puna ;)
Nagaaccept kabpo ba ng tutor sir
bakit po di nagamit ang specific gravity ng oil po? it is because air pressure ang hinahanap hindi pressure ng fluid? pasagot po huhu salamat
HAHHAHAHHAHAHHAHAHA nalimtan lang ata vladimir, sa 2500 solved problems kay gisali nya ang 0.9 na s.g HAHAHHAHHAAHHAHA nakita ko lang comment mo HAHAHHAHAHAHAHAHAHA
8:52 here you must multiply by 0.9 and equal to 21.6801 kpa
yes thank you :)
Why?
s.g of oil 😊😊@@muhammadjouharsyah6539
@@muhammadjouharsyah6539 s.g of oil
Specific gravity@@muhammadjouharsyah6539
What if po di neglect ang air pero di parin nag bigay ng unit weight ng air ? Pwede parin poba e compute ang c pero dina equal sa pressure B ?
Pwede pa din lods, constant naman yung unit weight ng air, kabisaduhin na lng hehe
Great video thank you very much sir , can you tell me what is the name of this book?
How can PB = PC its different liquid 5:54
the air pressure between B and C is neglected
New subscriber here😊. Helpful tutorial. Hoping for more engineering problems video.
Salamat lods
Sa Pressure D bat po di na po na consider yung sg na 0.9?ty po
nakalimutan lods hihi
Thank you very much sir for this great video but I dont understood why Pb = Pc.
Isnt fluid pressure dependent only on height and since C is on higher level than Pb so shouldnt C have different/higher pressure?
I dont know what topic to revise to clarify my such pressure concepts. Thank u sir.
Hello sir. Pb=Pc in this problem because it's stated that pressure due to air is negligible, therefore no pressure between points B and C
@@TutorJackPh ok got it thank you sir
Kahit naman walang nakalagay na e neglect mo ung air pressure makikita mo talaga sa table na walang dinadaanan ung air kaya kung ano pressure ng tubig na pumapasok un din pressure ng air, maliban nalang kung may nakalagay na value ung air. I thank you!
Why are you taking 0.5m as the height for B? Wasnt it 1m though? 5:02
hello, the 1-meter height liquid will cancel out because you have 1m downward and upward to point B, that's why only the 0.5m is considered. It's like 0 + 0.5L + 1.0L - 1.0L = Pb
Ty bro, new subscriber
Thanks bro 👍
Sir baka pwede po mag request ng tutorial vid about stability. Thank you po
Ay tama! Salamat lods. Nakalimutan ko, oil pala yung sa D 🤣 yep magmultiply dapat ng 0.90 na spgr
Okay lods, try ko sa next upload