Lec-7: 3D Arrays | Addressing in 3D Arrays | Row Major Order

[@adityasahil-zj4tr]

Column Major Order = base add. +[(8-5)*16 +(4-2)+(5-3)*4] * size of element (4) = 1000+[48+2+8]*4 = 1000+232=1232th place same as row major.🙃

[@sundaringh8435]

Because 2 d matrix square matrix hai 😂

[@ShivamVermaokdone]

@@sundaringh8435 It should be a perfect cube, not only having a square matrix in it is enough to keep the CMO and RMO addresses the same.
do you assessment again
IN case of CMO the answer will be 1252

[@sheilvlog4329]

Sir please explain column wise

[@shilpymishra8778]

Please explain column wise 😊

[@dhananjaypandey4541]

hii

[@HimaniRajput67]

Great 👍

[@rumiNITPatna]

nice explanation sir

[@yt.jeskoohlgaming]

Muje nhi samja

[@AbidShabbir-q9k]

thank sir jee

[@Codebyved]

Column wise , answer is=1252

[@Kundansingh-eh8vi]

sir please "column Major order" pe bhi btao

[@tanishagoyal3922]

Sir pls explain column wise...

[@ApurvaKalvadeSDE]

In Column Major, As the point that we want to find is lying on the diagonal line, the address will remain same as of Row Major.

[@ShivamVermaokdone]

It should be a perfect cube, not only having a square matrix in it is enough to keep the CMO and RMO addresses the same.
do you assessment again
IN case of CMO the answer will be 1252

[@aspiredifferent8085]

Thank YOu

[@ArslanAS9805]

Location of element [8] [4] [5] =
1232

[@rishabhshayriofficel8600]

Plz make a video on coloum major array plz

[@hashimali179]

CMO se bhi 1232 hi answer aaega coincidentally

[@ShivamVermaokdone]

It should be a perfect cube, not only having a square matrix in it is enough to keep the CMO and RMO addresses the same.
do you assessment again
IN case of CMO the answer will be 1252

[@JayantaBarman-uj7ip]

@Gate Smashers Varun bhaiya I have already completed mtech cse from a state government college through gate scholarship before and now this year I qualified gate again and want to do m.tech. in AI if I take admission in any NIT or IIIT will I get GATE scholarship again this time

[@Makeupwithsehar]

I don't know why but 3D wala lec dekhny k baad meko 1st or 2nd dimension bhi bhul gya

[@nithinrajchittath7820]

Makeup karne me kam dhyan aur padhai me jyada dhyan de.

[@इराज9]

Exactly 💯

[@Utkarshkushwaha-ld8xh]

Sir first of all you must explain to us the general formula then it's details

[@kshitizbhardwajsingh]

Same

[@shaik0278]

Bhai thum acha explain kathe ho meri eak request CYBERSECURITY AND ETHICAL HACKING COURSE thoda advance topic par video karo na

[@snsi6766]

Column major : [(i-lb1) np + (j-lb3) n + (k-lb2)] * size + base address
Answer column major : 1256

[@ShabbarAbbas-fu3je]

n , p KYa Hy ?

[@ShabbarAbbas-fu3je]

Value put kr k snd krdo asy smjh nhi a rahi

[@snsi6766]

@@ShabbarAbbas-fu3je
Brother there is correction in the formula
Column major = [(i-lb1) np + (j-lb2) n + (k-lb3)] * size + base address
here given array[5...10] [2...5] [3...6] , thus
n = no. of elements in [2...5] = 4
p = no. of elements in [3...6] = 4
lb1 = 5
lb2 = 2
lb3 = 3
We have to find location of a[8] [4] [5], thus let i=8, j=4, k=5,
Thus after putting it in equation
Column major = [(i-lb1) np + (j-lb2) n + (k-lb3)] * size + base address
= [(8-5)4x4 + (4-2)4 +(5-3)]*4+1000
= 58*4+1000
= 232+1000
= 1232
Answer column major : 1232

[@aneeshoak2199]

Is the topic C ?

[@RayyanKhan-g2n]

Get the concept not the syntax-y coding language 🙃

[@nightmare5490]

Column major order ni smjh ara

[@Anonymous-lb5jp]

1252

[@vidhushisharma4437]

1248

[@AsoRoastMari]

1232

[@Vedprakashkumar01]

CMO please

[@archanaaakaram2513]

Please explain column wise 😊