Interatomic Forces & Energy Curves {Texas A&M: Intro to Materials}

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  • เผยแพร่เมื่อ 4 ก.ย. 2024

ความคิดเห็น • 50

  • @onyangoachieng9178
    @onyangoachieng9178 4 ปีที่แล้ว +4

    What an instructor! This is superb. Kenya

  • @odstknight00
    @odstknight00 7 ปีที่แล้ว +5

    This video is so help full, you are saving my intro to strengths grade, thank you and please keep the content coming.

  • @droyprimechoudhary1802
    @droyprimechoudhary1802 2 ปีที่แล้ว +1

    Thanks Very Much Helpful I Was Confused And Was Curious To Understand Deeply about Elasticity In Terms Of Interatomic force.

  • @hungdo4611
    @hungdo4611 5 ปีที่แล้ว +1

    This presentation is completely correct. Nothing is wrong here!

  • @mr.rachetphilanthrophist601
    @mr.rachetphilanthrophist601 6 ปีที่แล้ว +2

    very very very nice explanation ,very knowledgeable teacher you are , i have always been confused in these two curves now you made it clear ........thank you

  • @davysong9488
    @davysong9488 4 ปีที่แล้ว +6

    thank you so much! this is absolutely helpful even for my gen chem class!

  • @LonDanDoc
    @LonDanDoc 9 หลายเดือนก่อน

    Prof you are a life saver . Owe you a cold one 👍🏾

  • @BaldurKhr
    @BaldurKhr 4 ปีที่แล้ว +2

    Such an easy to grasp lecture. Thank you!
    I imagine atoms as small balls and the electric forces as a compressed spring that tries to split them apart and a tensioned elastic rubber passing right through the middle of the spring which opposes the spring and holds the atom not to depart. Because of the elasticity of the spring and rubber, the atoms are also vibrating.
    Though i don't quite understand, when fire its taking place, why CO2 gains so much speed after recombination?...

  • @samgu1930
    @samgu1930 5 ปีที่แล้ว +3

    THANK YOU SO MUCH !!! It is really aid for me so much

  • @the_lord7961
    @the_lord7961 3 ปีที่แล้ว +1

    Thank you so much for making these videos. Everything makes sense now oml

  • @hugom6388
    @hugom6388 6 หลายเดือนก่อน

    They could add on those energy graphs the point (or distance) at which the material changes state.

  • @monicasenese2839
    @monicasenese2839 3 ปีที่แล้ว +1

    Amazing lecture, thank you so much

  • @fozansharfulhaque1973
    @fozansharfulhaque1973 7 หลายเดือนก่อน

    Wow such an amazing lecture thank you prof

  • @iengineer.1686
    @iengineer.1686 หลายเดือนก่อน

    Crystal-clear to understand, but I have a question about the Force-radius curve. Why does the force-radius curve start from positive force to negative force. While other literatures draw starting from the negative force to positive?

  • @ahmedtareq3787
    @ahmedtareq3787 8 หลายเดือนก่อน

    Very informative, Thanks professor 💯

  • @wolf.of.scbd14
    @wolf.of.scbd14 4 ปีที่แล้ว

    thank u mister it's helpful for my study

  • @KLCII88
    @KLCII88 6 ปีที่แล้ว +1

    Very clear video, just like the others. Thank you so much for the effort you put into these.

  • @vijay6543211
    @vijay6543211 5 ปีที่แล้ว

    Helped me in knowing about fundamental topics.

  • @aakaspokhrel9254
    @aakaspokhrel9254 3 ปีที่แล้ว

    Thank you myan for this

  • @anashayajneh9510
    @anashayajneh9510 3 ปีที่แล้ว

    you are way better than my teacher👍

  • @ashuemmanuel2019
    @ashuemmanuel2019 3 ปีที่แล้ว

    Thanks sir you've been helpful

  • @Scruffyx56
    @Scruffyx56 2 ปีที่แล้ว

    thank you for the explanation.

  • @serisingh
    @serisingh 3 ปีที่แล้ว

    I was hoping he would derive the modulus from the force gradient! My homework asks for the complete derivation, and of course it wasn't covered in my lecture.

  • @toughguy9886
    @toughguy9886 6 ปีที่แล้ว

    Big thanks Dr.

  • @lostinthoughts13
    @lostinthoughts13 6 ปีที่แล้ว

    So as we approach zero,we will need to put more and more energy in order to seperate atoms,but ther is a point where we will actually get energy when atoms are seperated (that is when repulsive forces overcome attractive forces) is this correct ?

  • @nicholasmerino9608
    @nicholasmerino9608 ปีที่แล้ว

    There’s a variable involving (x)
    Assume x is a variable rate f(y)
    X simply would assume a y constant
    How’s that… y is the dividend

  • @sivakumar-ns7pk
    @sivakumar-ns7pk 4 ปีที่แล้ว

    What about the magnitude of bonding energy with respect to the potential well?

  • @MakeMeScientific
    @MakeMeScientific 6 ปีที่แล้ว +1

    Excellent explanation sir.
    #makemescientific

  • @DoctoreDoom
    @DoctoreDoom 5 ปีที่แล้ว

    Amazing thanks for uploading X)

  • @nicholasmerino9608
    @nicholasmerino9608 ปีที่แล้ว

    And If y is the divider nf

  • @drscott1
    @drscott1 6 ปีที่แล้ว +1

    Is not the Coulomb force 1/r squared?

    • @siddharthvyas3078
      @siddharthvyas3078 6 ปีที่แล้ว +1

      He is talking about Coulombic potential energy not the force, energy is = (force x distance), so the formula is correct

    • @drscott1
      @drscott1 6 ปีที่แล้ว

      Siddharth Vyas now I see he wrote V and not E. Thanks

  • @pinkybananas1
    @pinkybananas1 7 ปีที่แล้ว

    thank you

  • @shashikantmishra4460
    @shashikantmishra4460 7 หลายเดือนก่อน

    From india❤

  • @nicholasmerino9608
    @nicholasmerino9608 ปีที่แล้ว

    Of a another X(Y) derivative

  • @nicholasmerino9608
    @nicholasmerino9608 ปีที่แล้ว

    There would be a magnitude

  • @pingwin2740
    @pingwin2740 7 ปีที่แล้ว +2

    oftentimes

  • @nicholasmerino9608
    @nicholasmerino9608 ปีที่แล้ว

    Calculus

  • @mrgreatdude2
    @mrgreatdude2 7 ปีที่แล้ว +6

    The force curve seems to be incorrect

    • @mochfakhrizal1478
      @mochfakhrizal1478 6 ปีที่แล้ว +2

      i think so. cause at r approach to zero it must be up curve. am i right?

    • @naziajasmeen4203
      @naziajasmeen4203 6 ปีที่แล้ว

      YAP!

    • @pjshamberger
      @pjshamberger  6 ปีที่แล้ว +5

      Howdy! While energy has an absolute scale (lower energy is more stable), force depends on your coordinate system and on whether you're looking at the force of 'A on B' or 'B on A'. As I did not define the picture completely, and identify **which** force we're talking about, this could either be as shown, or with the sign of force reversed. For this reason, at the level of this video, it's easiest to think about this in terms of "attractive" or "repulsive" force, as labeled (at ~7:40).

  • @nirupamanaik1207
    @nirupamanaik1207 4 ปีที่แล้ว

    Tkh

  • @user-fw3vc8xt3t
    @user-fw3vc8xt3t 4 ปีที่แล้ว

    ㅋㅋ 꼬우면 안동대오셈

  • @youngsukkim881
    @youngsukkim881 5 ปีที่แล้ว

    This explanation is just imaginary. Although interatomic forces between atoms are not zero, the explanations given in this video show that the interatomic forces between atoms are zero when the interatomic distrance is set at equilibrium. In fact, it seems to remain unclear what determines the magnitude of interatomic forces acting between atoms in solids.

  • @aricirwin7631
    @aricirwin7631 9 ปีที่แล้ว +2

    Good presentation and great information but you said "Uh" or "Um" 15 times in the first 3 minutes. Huge distraction and all i could do is count crutch words. Sorry

  • @glacieg2640
    @glacieg2640 ปีที่แล้ว

    thank you sir