Hello K0nze. I´´m trying to do the homework you gave us in this video and I have problem...😐 I don`t know how to continue this calculation: (X and (not Y(Z OR Y))) OR NOT Z. Could you help me??
Great that you try the homework. I would suggest you start with the inner-most term: Z or ( Y and not Z) Using the distributive law you get: (Z or Y) and (Z or not Z) Now you can use the complement law for (Z or not Z) which is reduced to 1. Then you got (Z or Y) and 1 which is equal to just (Z or Y) using the identity law. Now that you reduced the inner part you can take the next step and try reducing the rest.
I already did that. I did the same as you until the same step as you and I got the result that I already sent you in first message. The "(X and (not Y(Z or Y)))" confuses me. 🤨
@@themirroruniverse33 @k0nze builds The expression: (x and ( not y (z or (y and not z))))or not z gives me an error in Python. It would be correct to add an and after not y? (x and ( not y and(z or (y and not z))))or not z This way python accepts it and also gives me the same results as the shorter expression: (x and not y) or not zed
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Loved it, Very nicely put!!
Very detailed vid👍
Glad you liked it
Legend
Hello K0nze.
I´´m trying to do the homework you gave us in this video and I have problem...😐
I don`t know how to continue this calculation: (X and (not Y(Z OR Y))) OR NOT Z. Could you help me??
Great that you try the homework. I would suggest you start with the inner-most term: Z or ( Y and not Z)
Using the distributive law you get: (Z or Y) and (Z or not Z)
Now you can use the complement law for (Z or not Z) which is reduced to 1.
Then you got (Z or Y) and 1 which is equal to just (Z or Y) using the identity law.
Now that you reduced the inner part you can take the next step and try reducing the rest.
Thank you so much. Your answer was helpful. I keep learning. 😅
I already did that. I did the same as you until the same step as you and I got the result that I already sent you in first message. The "(X and (not Y(Z or Y)))" confuses me. 🤨
@@themirroruniverse33 @k0nze builds The expression: (x and ( not y (z or (y and not z))))or not z
gives me an error in Python. It would be correct to add an and after not y?
(x and ( not y and(z or (y and not z))))or not z
This way python accepts it and also gives me the same results as the shorter expression: (x and not y) or not zed