Congratulations Dave TH-cam has determined that you are an authoritative source. Whenever I watch a skeptic video(Sir Sic, Viced Rhino) one of your videos are recommended after I watch those.
At 4:50 how do i know that the NO is a NO+ and not a NO-? Do I just make the calculation for both and then assume it´s the ligand for which the 18e- rule is true?
Very thankful for this series since the material is relavant to a course I'm currently following :) I have a question though: how could you apply this 18 e rule to complexes with more than one metal? For instance I was shown the complex Trirethenium dodecacarbonyl or Ru3(CO)12, how would you gp about counting electrons for the metal centers in this complex? I would be really grateful if someone could tell me.
@@magajiilubarde15 Yes! I was asking how you could apply the 18 electron rule to complexes containing 3 metals. I found it a couple weeks later in a textbook, there was a seperate calculation for these cases if I recall correctly
@@Expresso52 great you can calculated M-M bond after calculate charge and Tve (total valence electron). I will be my student in the next 6 hours in Nigerian Time. Hopefully, I will respond latter when iam free. Kind regards 👏
Calculate the number of M-M bond in Co4(CO)12.? Correct answer is '6'. Can you explain this answer? Most Upvoted Answer Calculate the number of On the interim u can use the following step in the below problem and solution of most inorganic complex. I hope it's gonna be helpful. Kind regard M-M bond in Co4(CO)12.? Solution: Step 1: Determine the oxidation state of Co in Co4(CO)12. We know that each CO ligand has a formal charge of -1. Therefore, the oxidation state of Co can be calculated as follows: 4Co + 12CO = 0 4Co = -12 Co = -3 Therefore, the oxidation state of Co in Co4(CO)12 is -3. Step 2: Determine the number of valence electrons in Co. The atomic number of Co is 27. Therefore, the number of valence electrons in Co is 9 (2+7). Step 3: Calculate the total number of valence electrons in the complex. The total number of valence electrons in the complex can be calculated as follows: 4Co = 4 x 9 = 36 12CO = 12 x (4 + 6) = 120 Total = 36 + 120 = 156 Step 4: Determine the number of electrons required for the complex to achieve an octet configuration. Each Co atom in Co4(CO)12 has 6 valence electrons from the CO ligands. Therefore, each Co atom needs 2 more electrons to achieve an octet configuration. 2 x 4 = 8 Therefore, the complex requires a total of 8 electrons to achieve an octet configuration. Step 5: Calculate the number of M-M bonds. The number of M-M bonds can be calculated using the following formula: Number of M-M bonds = (Total number of valence electrons - Number of electrons required for octet configuration) / 2 Number of M-M bonds = (156 - 8) / 2 = 74 However, we need to divide this number by 12 (the number of bonds per Co atom in a tetrahedral geometry) to get the number of M-M bonds per Co atom. Number of M-M bonds per Co atom = 74 / 12 = 6.17 Therefore, the number of M-M bonds in Co4(CO)12 is 6.
@@magajiilubarde15 Thank you, though I solved this problem around a year ago already. I took a quick look and I think I used the CVE(cluster valence electron) count to solve this problem, which was described to me in a Inorganic chemistry textbook written by Atkins and Shriver. Maybe it is useful to somebody who will read this in the future with the same problem
I love watching about something that I absolutely know nothing about.I hear English words, but it’s like listening to a foreign language
Superb! Thanks for catch-up on the 18 electron rule.
Hey Dave, can you make a video someday about extreme social anxiety
one of the best..................
Thanks
Congratulations Dave TH-cam has determined that you are an authoritative source. Whenever I watch a skeptic video(Sir Sic, Viced Rhino) one of your videos are recommended after I watch those.
At 4:50 how do i know that the NO is a NO+ and not a NO-? Do I just make the calculation for both and then assume it´s the ligand for which the 18e- rule is true?
In the LD diagram of NO, you see N and O have 5 valence electrons. Thus, NO+
@@ianlee5812 Umm what? Care to explain a bit more please?
@@dominiktadic6459 draw out a lewis diagram to show the pos charge :)
Forgive my enthusiasm but i get very excited whenever prof Dave uploads a chemistry video especially this new series. Keep it going :)
awesome, thanks
Very thankful for this series since the material is relavant to a course I'm currently following :)
I have a question though: how could you apply this 18 e rule to complexes with more than one metal? For instance I was shown the complex
Trirethenium dodecacarbonyl or Ru3(CO)12, how would you gp about counting electrons for the metal centers in this complex? I would be really grateful if someone could tell me.
A u asking for calculation of M-M bond.
@@magajiilubarde15 Yes! I was asking how you could apply the 18 electron rule to complexes containing 3 metals. I found it a couple weeks later in a textbook, there was a seperate calculation for these cases if I recall correctly
@@Expresso52 great you can calculated M-M bond after calculate charge and Tve (total valence electron). I will be my student in the next 6 hours in Nigerian Time. Hopefully, I will respond latter when iam free. Kind regards 👏
Calculate the number of M-M bond in Co4(CO)12.?
Correct answer is '6'. Can you explain this answer? Most Upvoted Answer Calculate the number of
On the interim u can use the following step in the below problem and solution of most inorganic complex. I hope it's gonna be helpful. Kind regard
M-M bond in Co4(CO)12.?
Solution:
Step 1: Determine the oxidation state of Co in Co4(CO)12. We know that each CO ligand has a formal charge of -1. Therefore, the oxidation state of Co can be calculated as follows: 4Co + 12CO = 0 4Co = -12 Co = -3 Therefore, the oxidation state of Co in Co4(CO)12 is -3. Step 2: Determine the number of valence electrons in Co. The atomic number of Co is 27. Therefore, the number of valence electrons in Co is 9 (2+7). Step 3: Calculate the total number of valence electrons in the complex. The total number of valence electrons in the complex can be calculated as follows: 4Co = 4 x 9 = 36 12CO = 12 x (4 + 6) = 120 Total = 36 + 120 = 156 Step 4: Determine the number of electrons required for the complex to achieve an octet configuration. Each Co atom in Co4(CO)12 has 6 valence electrons from the CO ligands. Therefore, each Co atom needs 2 more electrons to achieve an octet configuration. 2 x 4 = 8 Therefore, the complex requires a total of 8 electrons to achieve an octet configuration. Step 5: Calculate the number of M-M bonds. The number of M-M bonds can be calculated using the following formula: Number of M-M bonds = (Total number of valence electrons - Number of electrons required for octet configuration) / 2 Number of M-M bonds = (156 - 8) / 2 = 74 However, we need to divide this number by 12 (the number of bonds per Co atom in a tetrahedral geometry) to get the number of M-M bonds per Co atom. Number of M-M bonds per Co atom = 74 / 12 = 6.17 Therefore, the number of M-M bonds in Co4(CO)12 is 6.
@@magajiilubarde15 Thank you, though I solved this problem around a year ago already. I took a quick look and I think I used the CVE(cluster valence electron) count to solve this problem, which was described to me in a Inorganic chemistry textbook written by Atkins and Shriver. Maybe it is useful to somebody who will read this in the future with the same problem
Can you please tell me the charge on Ch3NO2?
at 4:51 how do we know that it will be NO+ and not NO- ?
thank you
LD diagram of NO show N and O having 5 electrons. Thus, NO+
Hey dave make video about ufo of pentagon
He'll learn that UFO's have no visible signs of propulsion as witnessed by many people
I remember you when you destroyed flat earth Dave in an argument and he simply could not accept that his arguments were all invalid lol
They never do
FUCK YEAH ELECTRONS