Thank you sir. Many people get the following question wrong, so please explain. [Question] Find the probabilities that the following events will occur when two dice are rolled. ①Both show odd numbers ②One shows odd number and another shows evenn number ③Both show even number P(E):the probability that event E occurs. 【Distinguishable dice A and B】 (the number that dice A shows,the number dice B shows):event If we only judge whether the numbers indicated by the dice are odd or even, the following four events will occur. (odd,odd) (odd,even) (even,odd) (even,even) If each event occurs with equal probability, the probability is 1/4. Therefore, P(①)=1/4, P(②)=1/2, P(③)=1/4 (1) If we judge the number(1,2,···,6) indicated by the dice ,the following 36 events will occur. (1,1), (1,3),(1,5) (1,2),(1,4),(1,6) (3,1), (3,3),(3,5) (3,2),(3,4),(3,6) (5,1), (5,3),(5,5) (5,2),(5,4),(5,6) (2,1), (2,3),(2,5) (2,2),(2,4),(2,6) (4,1), (4,3),(4,5) (4,2),(4,4),(4,6) (6,1), (6,3),(6,5) (6,2),(6,4),(6,6) If each event occurs with equal probability, the probability is 1/36. Therfore P(①)=9×(1/36)=1/4, P(②)=18×(1/36)=1/2, P(③)=9×(1/36)=1/4 (2) (2) matches (1). 【Indistinguishable two dice】 (odd,even)is the same event as(even,odd). Thererore, if we only judge whether the numbers indicated by the dice are odd or even, the following three events will occur. (odd,odd) (even,odd) (even,even) If each event occurs with equal probability, the probability is 1/3. Therefore P(①)=1/3, P(②)=1/3, P(③)=1/3 (3) (1,3) is the same event as (3,1). If we judge the number(1,2,···,6) indicated by the dice ,the following 21 events will occur. (1,1) (3,1), (3,3) (5,1), (5,3),(5,5) (2,1), (2,3),(2,5) (2,2) (4,1), (4,3),(4,5) (4,2),(4,4) (6,1), (6,3),(6,5) (6,2),(6,4),(6,6) If each event occurs with equal probability, the probability is 1/21. Therefore P(①)=6×(1/21)=2/7, P(②)=9×(1/21)=3/7, P(③)=6×(1/21)=2/7 (4) (4) contradicts (3).
super, i need a solution for this problem, a pair of dice rolled once. let x be the random variable whose value for any out come is the sum of the two numbers on the dice, find P(3
Thanks for the request. Here is an example with 3 dice: th-cam.com/video/gWJDSzsJhq4/w-d-xo.html You can search my videos by Anil Kumar Topic example , anil kumar three dics Thanks
Lowest probability will be Zero and the Highest will be 1 (100%). Sum less than 1 will give the lowest probability and Sum greater than 1 will be highest.
I don't know why it bothered me so badly that you didn't reduce 15/36, while the other ratios got that reduction love. I guess I am just easily bothered by unimportant things. Thanks for the video!
Thanks for pointing that out. I should have reduced it to 5/12 as has been done for the others. I highly appreciate and will incorporate the correction in the video also. Thanks
As you can see in the table created for the sum there are 6 ways the sum of two dice can be 7 There are in all 36 ways of adding numbers of two dice Probability is ratio of Favourable and Total. Probability can never be more than 1. Hope that helps. Thanks
You made a mistake? You totally left out the probability of rolling a 6???? WHY????????????? Didn't you mean Probability of rolling a dice with a value of LESS THAN 7????????????
i have a test of probability, and this 8 minutes video helped me sooo much, thank you so much mr. i really appreciate your effort :)
Thanks for appreciation and All the Best!
Tomorrow i have 😊
@@MathematicsTutor i really appreciate, well explained Mr
Yes...and i have my homework 🙂👍😂
Thank you sir.
Many people get the following question wrong, so please explain.
[Question]
Find the probabilities that the following events will occur when two dice are rolled.
①Both show odd numbers
②One shows odd number and another shows evenn number
③Both show even number
P(E):the probability that event E occurs.
【Distinguishable dice A and B】
(the number that dice A shows,the number dice B shows):event
If we only judge whether the numbers indicated by the dice are odd or even, the following four events will occur.
(odd,odd) (odd,even)
(even,odd) (even,even)
If each event occurs with equal probability, the probability is 1/4.
Therefore, P(①)=1/4, P(②)=1/2, P(③)=1/4 (1)
If we judge the number(1,2,···,6) indicated by the dice ,the following 36 events will occur.
(1,1), (1,3),(1,5) (1,2),(1,4),(1,6)
(3,1), (3,3),(3,5) (3,2),(3,4),(3,6)
(5,1), (5,3),(5,5) (5,2),(5,4),(5,6)
(2,1), (2,3),(2,5) (2,2),(2,4),(2,6)
(4,1), (4,3),(4,5) (4,2),(4,4),(4,6)
(6,1), (6,3),(6,5) (6,2),(6,4),(6,6)
If each event occurs with equal probability, the probability is 1/36.
Therfore
P(①)=9×(1/36)=1/4, P(②)=18×(1/36)=1/2, P(③)=9×(1/36)=1/4 (2)
(2) matches (1).
【Indistinguishable two dice】
(odd,even)is the same event as(even,odd).
Thererore, if we only judge whether the numbers indicated by the dice are odd or even, the following three events will occur.
(odd,odd)
(even,odd) (even,even)
If each event occurs with equal probability, the probability is 1/3.
Therefore
P(①)=1/3, P(②)=1/3, P(③)=1/3 (3)
(1,3) is the same event as (3,1).
If we judge the number(1,2,···,6) indicated by the dice ,the following 21 events will occur.
(1,1)
(3,1), (3,3)
(5,1), (5,3),(5,5)
(2,1), (2,3),(2,5) (2,2)
(4,1), (4,3),(4,5) (4,2),(4,4)
(6,1), (6,3),(6,5) (6,2),(6,4),(6,6)
If each event occurs with equal probability, the probability is 1/21.
Therefore
P(①)=6×(1/21)=2/7, P(②)=9×(1/21)=3/7, P(③)=6×(1/21)=2/7 (4)
(4) contradicts (3).
its a huge help for my acads sir! 😄 thanks a lot , God bless you
Probability has been disturbing me but this video has opened up my eyes
Thank you so much
th-cam.com/video/urQcPWNv8JY/w-d-xo.html
Shukriyaaaaa sir gg bhot bhot You're just an amazing teacher God bless you .Thankuee so muchhh .....
Thanks. Playlist for you: th-cam.com/video/YxkOuAm3VE4/w-d-xo.html
hy sir anil kumar kindly guide me about(probability of ace drawing when die thrown twice)
This 8minls video really helped me I've been battling with probability since I was in secondary school
i never understood probabilities until now. this really helped
Cecilia Acevedo Thanks
Cecilia Acevedo It encourages me to share more videos and make mathematics simple and interesting.
wow, this turned out to be so easy!
Thank you 😊 you're video is of a great help for a student like me.
This was really helpful! Thanks man!
Very clear explanation. !!
Now I indrestrand... Thankyou 🙋💕
I thought it so hard to understand
This was very helpful. God bless you❤️✊
Thanks. All the Best!
7
thank you so much!
Thank you! That's an amazing method!
This has helped me a lot. Thank you so much
super, i need a solution for this problem, a pair of dice rolled once. let x be the random variable whose value for any out come is the sum of the two numbers on the dice, find P(3
Thank you sir I have really understood that concept
Great explanation!! Well done!
Thanks Ser. Anil Kumar it's help me a lot 👍👍👍👍💖💖💖👏👏👨🏫👨🏫👨🏫👨🏫👏 😍😍
why 6 raws and com for the table and if its 3 or more what should we do ?
Great Job !
Thanks Appreciated 😘
Great video, simple as it could be.
Very nice explanation sir
@sunithakolla9716 thanks for appreciation
It helps me a lot to my activity thank you
What is the probability of getting two odd numbers
Thank you, very clear.
Thanks man, would you mind solving a level stats past papers?
Hey man I need help
How to make a tree diagram of 2 dies rolled? Please help
finally a table that makes perfect sense!
thank you so much, this helps a lot!
great explanation
OMG!!! Thank you!!!! NOW I ALREADY ABOUT THE SUM OF 7
All the Best!
Thanks a lot sir 🙏
Thank you so much sir nice lecture
Thank you sir
But 3, can also go into 15and36
Or there no need to divide .
In number two question
thanks a lot for the lesson, it is easy and so rationale for slow minded like me :)))
Feel free to post questions and ask for help any time. Thanks
This really helped me a lot! Thank you for sharing :)
thank u sir :) very helpful video
Wow it's helpful
this helped me a lot thanks so much
Thanks
Thank you very much! The video was really helpful
Thanks for appreciation
Thank you so much sir
this is so informative thanks
Thanks sir
Thanks so much ❤
Legends in 2022
thank you so much, keep making helpful videos like this :)
Thanks for appreciation
Thanks sir 🙏🏾
Thankyou very much.
Chennai.
thamks soooo much, you made this soooo easy!
thank you so much, hope you keep doing videos
Thank you so much
Sir it's awesome...
But what with three dice! is there any trick for it?
Thanks for the request. Here is an example with 3 dice: th-cam.com/video/gWJDSzsJhq4/w-d-xo.html
You can search my videos by Anil Kumar Topic example , anil kumar three dics
Thanks
Thank you!!!
thank you so much!!
wow, wonderful explanations. Thank you so much
thanks baby bro
good lect
thank you very much guru
+Privilege Mahuma Thanks
Hey u yeah u l
Wow bravo ,thanks sir
thank you for your video lesson:)
Sir why dint you simplify 15/36 = 5/12
I should have. Missed it.
Thanks
u just broke a mountain into soil particles in a blink of an eye
Thanks for appreciation. All the Best!
Well said
I want to learn what will be the maximum outcomes and minimum outcomes
Thank you
Thanks
What about if P(0)?
but Which totals have the highest and lowest probability of occurring
Lowest probability will be Zero and the Highest will be 1 (100%).
Sum less than 1 will give the lowest probability and Sum greater than 1 will be highest.
thanks
Thanks a lot you really helped me study for my test
Very nice
Watching now
Sir jo hmy parhya gya tha us mai at least 7 k keay prob=21/36 the
awesome! Thanks
It is useful for as thank you so much
thank you ❤
+Hamdan Al Mulla Thanks for appreciation
Thank u sir..
Thanks for appreciation. Feel free to post questions.
ager sir table nhi banay to keya nhi hal hoga
alag alag tarika se savall ka hal ho sakta hai. Table jaroori nahi. Dhanyavaad!
I slapped my dumb self for not realizing how easy it is
Thanks a lot mr. now I can give my exam in peace
😇
All the Best!
Nice sir
Sir loveeee uuuu so much😍
THANKS
I don't know why it bothered me so badly that you didn't reduce 15/36, while the other ratios got that reduction love.
I guess I am just easily bothered by unimportant things.
Thanks for the video!
Thanks for pointing that out. I should have reduced it to 5/12 as has been done for the others. I highly appreciate and will incorporate the correction in the video also. Thanks
Thanks. .....please sum of 7 I didn't get it. ....
I thought it might be 42/36
But still please help me understand thanks again and again
As you can see in the table created for the sum there are 6 ways the sum of two dice can be 7
There are in all 36 ways of adding numbers of two dice
Probability is ratio of Favourable and Total.
Probability can never be more than 1.
Hope that helps.
Thanks
Nice
to sir ek bar Bina table ke bata digiye
You made a mistake? You totally left out the probability of rolling a 6???? WHY????????????? Didn't you mean Probability of rolling a dice with a value of LESS THAN 7????????????
Wtf is this .... U r just counting the elements in the set..... It is not gonna help if the set is not a perfect square or its very large
Use different method in that case. Thanks
Its so easy
th-cam.com/video/urQcPWNv8JY/w-d-xo.html
Thank you
Thanks for appreciation
Thanks sir
Thanks for appreciation