Moment equals to force * perpendicular distance to this force. So choose a force first, then find the distance. Since this is the 3D problem, so the distance or direction parallel to force won't create any moment. Then move to the other directions perpendicular to this force, now you can calculate the moment. You can use right-hand rule to find moment direction (four finger in the force direction, your palm need to face the distance you choose also make sure your palm kinda perpendicular to the distance, now curl your hand, your thumb direction will be the moment direction). Or you can use math to calculate, for example, k=ixj, so if the force in x-direction, distance in y-direction, then you will get the moment in z-direction.
Amazing video ! Very well explained
What's a lovely voice
Me, John, Derek, and Tyler watched this for Exam 3 :)
I hope it helps:)
Thanks for the video!
Hello
I think 300 N force will also create a twisting Moment of (300*2) at crossection AB, isn't it ?
Yes, that is correct.
How come the 200N force does not create any moment about y-axis
Because 200 N force parallel to y-axis.
How did you find out what forces and distance did you yse for the specific moments. I'm really having a hard time trying to put it all together
Moment equals to force * perpendicular distance to this force. So choose a force first, then find the distance. Since this is the 3D problem, so the distance or direction parallel to force won't create any moment. Then move to the other directions perpendicular to this force, now you can calculate the moment. You can use right-hand rule to find moment direction (four finger in the force direction, your palm need to face the distance you choose also make sure your palm kinda perpendicular to the distance, now curl your hand, your thumb direction will be the moment direction). Or you can use math to calculate, for example, k=ixj, so if the force in x-direction, distance in y-direction, then you will get the moment in z-direction.