Lecture 5, Properties of Linear, Time-invariant Systems | MIT RES.6.007 Signals and Systems

แชร์
ฝัง
  • เผยแพร่เมื่อ 17 ม.ค. 2025

ความคิดเห็น • 55

  • @AshwinAashu
    @AshwinAashu 9 ปีที่แล้ว +65

    Alan is perhaps the best signals engineer ever. The way he teaches compels me to know more, understand and reason - with myself and others. I love the MIT courseware , thank you for this wonderful series.

    • @hoanganhnguyen795
      @hoanganhnguyen795 7 ปีที่แล้ว

      im vietnammese and i fell so hard to understand =))

  • @deepakmecheri4668
    @deepakmecheri4668 7 ปีที่แล้ว +36

    I was so used to hearing the lectures at 2x speed now, when I play it in normal, it literally feels like the professor is talking in slow-mo

  • @MrQwertymnb
    @MrQwertymnb 11 ปีที่แล้ว +6

    Prof. Oppenheim, RESPECT. Your teaching is an inspiration.

  • @lightspeed79
    @lightspeed79 12 ปีที่แล้ว +9

    I wish I had profesors like these from MIT when I was in college. Then again I wasn't at MIT.

  • @version191
    @version191 12 ปีที่แล้ว +29

    opening music is dope

    • @matthewjarvis7863
      @matthewjarvis7863 หลายเดือนก่อน

      I think there's some Tron influence (1982 film)

  • @tiborszekeres
    @tiborszekeres 12 ปีที่แล้ว +10

    Time travel still possible!!! Thanks Utube!

  • @yougoog1
    @yougoog1 3 ปีที่แล้ว +3

    It is easy to understand the property of linear system that if you put nothing in then you get nothing out. But I have trouble to understand why this property has anything to do with the causality property that the system cannot anticipate its input. Why and how are these two properties related? Another confusing part of causality of linear system is why causality means initial rest of initial conditions. Can a causal linear system have a non zero initial condition? Meaning for t < t0, its input is not zero, but can such system still be linear and causal? In another word, if you put something in, then you linearly get something out.

    • @sossupummi
      @sossupummi 3 หลายเดือนก่อน

      A linear system cannot produce an output without a corresponding input. Causality requires that the system cannot anticipate its future inputs. Zero input response (initial rest) is a consequence of causality and implies that the system's output is zero before the input is applied. A causal linear system can have non-zero initial conditions, but these conditions must not violate causality.

  • @MrQwertymnb
    @MrQwertymnb 11 ปีที่แล้ว +1

    Haha!
    In any case, I find that watching the video again helps a great deal. Good luck!

  • @arnabthakuria2243
    @arnabthakuria2243 8 ปีที่แล้ว +4

    this man is amazing

  • @gadipuditushara7737
    @gadipuditushara7737 7 ปีที่แล้ว +1

    These videos are so helpful for me.Thank you sir.

  • @aSeaofTroubles
    @aSeaofTroubles 8 ปีที่แล้ว +1

    In terms of Bounded Input, Bounded Output stability, I read the Wikipedia proof for discrete time systems and it makes perfect sense:
    |y| = |h*x|

  • @mohamedessam1397
    @mohamedessam1397 2 ปีที่แล้ว

    Old but Gold

  • @canned_heat1444
    @canned_heat1444 4 ปีที่แล้ว +3

    at 22:11 it's a * not a + !!!

    • @OmarChida
      @OmarChida 3 ปีที่แล้ว

      He said h1 convolved with h2. The * was written badly but its a *

  • @osamaelzubair1203
    @osamaelzubair1203 ปีที่แล้ว

    At 39:00, when he was speaking about the invertibility of the accumulator, he first explained that an impulse is the difference between 2 unit steps and then wrote an expression for the inverse impulse response, why did he write delta(n)-delta(n-1)=h[n]^inverse instead of writing u[n]-u[n-1]=h[n]^inverse ?

    • @ayushkumar1539
      @ayushkumar1539 ปีที่แล้ว +1

      There is a reason for that,
      for accumulator, we need all the past values to determine the sum, but when it comes to difference we need the difference of only 2 consecutive values so we can simple multiply the coming input for the h(inverse) with impulses to get the required values and simple differentiate...
      for more insight integrator has limits from minus infinity to infinity but differentiator just needs it neighboring values....
      Hope you find it helpful : )

  • @SubrahmanyamGorthi
    @SubrahmanyamGorthi 7 ปีที่แล้ว +3

    As usual. great Lecture by Prof. Oppenheim. I have a question, and I hope someone here will kindly answer that.
    Can there be a system which linear but non-causal?
    I could not think of any example where a linear system is non-causal. Please shed some light.

    • @SubrahmanyamGorthi
      @SubrahmanyamGorthi 7 ปีที่แล้ว +16

      Answering myself after some brainstorming ;-)
      "Moving Average Filter" is an example of linear non-causal system!

    • @Waleedwsd
      @Waleedwsd 6 ปีที่แล้ว +1

      A Classic example. (y)

    • @hoomansadlou5655
      @hoomansadlou5655 3 ปีที่แล้ว +1

      simply y(t)=x(t+1) is linear and non-causal.

    • @barbossablink2969
      @barbossablink2969 5 หลายเดือนก่อน

      really wondering where are you rn :)

  • @maneymac
    @maneymac 12 ปีที่แล้ว +8

    little bit confusing......... :-(

  • @byambajargallhagwaa2713
    @byambajargallhagwaa2713 9 ปีที่แล้ว +2

    Thank you

  • @ninjakid-hi9uw
    @ninjakid-hi9uw 2 หลายเดือนก่อน +3

    Anybody in 2024🤩

  • @CompilerHack
    @CompilerHack 11 ปีที่แล้ว +1

    didn't you watch the previous lectures' videos? :P

  • @jitendrasinghbhadoriya153
    @jitendrasinghbhadoriya153 7 ปีที่แล้ว +5

    I like the arrangement of white board ...sometime it never ends

  • @mnada72
    @mnada72 3 ปีที่แล้ว

    Is the system in 19:00 has memory or memoryless?

    • @yougoog1
      @yougoog1 2 ปีที่แล้ว

      No. It is not memoryless. It has memory.

  • @arv_sajeev
    @arv_sajeev 4 ปีที่แล้ว

    Just to confirm, in the memory less case are we assuming that the signal is causal? Or is is being causal a property of memory less?

    • @crashraynor
      @crashraynor 4 ปีที่แล้ว

      Memoryless means that the system does not depend on previous input to determine current output. Causal means that the system depends on only current and/or past input, specifically NOT future input. Example:
      y[n]= x[n-1] is causal and not memoryless
      y[n]= x[n+1] is not causal and is memoryless
      y[n]= 2x[n] is causal and memoryless
      x[n+1] is "in the future", n is the present, thus it can't be causal.

    • @pedromatias5927
      @pedromatias5927 4 ปีที่แล้ว

      @@crashraynor "A system is said to be memory less if its output for each value of the independent variable
      at a given time is dependent only on the input at that same time." Taken straight from the course textbook. Thus, y[n]=x[n+1] is not memory less. I believe the instructor speaks about such cases in the lecture about system properties.

    • @arv_sajeev
      @arv_sajeev 4 ปีที่แล้ว

      @@pedromatias5927 this is exactly my doubt, it seems like the examples shown by the professor hint to what you are saying. I'll check the textbook for your definition, thank you for your help.

    • @yougoog1
      @yougoog1 3 ปีที่แล้ว

      For a LTI system, it is true that a memory less system is also causal. For a general system, the answer may not be true.

  • @khaledjofanee7294
    @khaledjofanee7294 8 ปีที่แล้ว +1

    please guys, i want the reference of this course

    • @mitocw
      @mitocw  8 ปีที่แล้ว +4

      The videotaped lectures are designed to be closely integrated with the text: Oppenheim, Alan V., and A. S. Willsky. Signals and Systems. Prentice Hall, 1982. ISBN: 9780138097318. (www.amazon.com/exec/obidos/ASIN/0138097313/ref=nosim/mitopencourse-20)

  • @Chris-ob6es
    @Chris-ob6es 4 หลายเดือนก่อน

    Al is the real Howard Stark

  • @igotbev1394
    @igotbev1394 4 ปีที่แล้ว

    This is it

  • @Mojomatrix
    @Mojomatrix 12 ปีที่แล้ว +1

    Free Ivy League lectures ? Shit man, I'm all up in this !

  • @truthbheard9869
    @truthbheard9869 11 ปีที่แล้ว +1

    im reading oppenheim's book on signals and systems.

  • @TheAdlcn
    @TheAdlcn 10 ปีที่แล้ว +8

    different shirt , same dude :)

  • @pedroernias
    @pedroernias 5 ปีที่แล้ว +1

    too slow... I needed to play this at 2x speed; other than that, nice lecture.

  • @ziqianzhang6192
    @ziqianzhang6192 11 ปีที่แล้ว

    ummmn. i dont get it yet..

  • @ProxyDev
    @ProxyDev 4 ปีที่แล้ว +1

    We have some Nintendo music :)

  • @storgerbenevolent5678
    @storgerbenevolent5678 4 ปีที่แล้ว

    the later 3/4th of this lecture is very confusing

    • @yougoog1
      @yougoog1 3 ปีที่แล้ว

      Because of the difficulties the impulse function has when it is defined as a value at each time like a normal function, it is defined as an operator function along with other operational symbol functions u_1(t), u_2(t), ....These symbol functions are no longer normal functions, i.e. they do not have values defined against time, but rather operators. You no longer ask them what they are, but what they do. They are just like the addition operator ‘+’. You do not know what value ‘+’ has, but you know what exactly ‘+’ does, i.e. 1+1=2.

    • @anmolkumar-lp3ox
      @anmolkumar-lp3ox 3 ปีที่แล้ว

      LTI Systems: th-cam.com/play/PLU1h6AEhPu52EzX-KO5g5KNsbzId28Vz3.html

  • @anmolkumar-lp3ox
    @anmolkumar-lp3ox 3 ปีที่แล้ว

    LTI Systems: th-cam.com/play/PLU1h6AEhPu52EzX-KO5g5KNsbzId28Vz3.html