Woooooohoooooooooo luvd this watched lots and lots of videos didn't understand anything read lots of reference textbooks but understood by this luvvdddddd this!!!!
In part d): How come you don't count the different ways you can get to Q at 8:58? Surely you can approach Q in more than one way? I.e. 2 downs 1 right, or 1 right 2 downs (going through but not crossing the forbidden second line)? And wouldn't this also apply for C, R, and S? Such that there are 3 ways to get from A to C, 4 from A to R, and 5 from A to S? I arrived at 210, which is equal to 10!/(4!6!) from the first part, so maybe I've gone wrong somewhere in my working. But it seems logical to arrive at Q-S from A in more than one way...
The calculation of going from A through X to P counts 2 downs 1 right. The Q calculation is assuming that we go from point A straight to P (1 right 2 downs).
You are correct though that there are multiples ways to get there but we have a restricted condition that we have to make exactly 10 moves for every case.... Having that constrain we get only one possible way as we have to arrange the existing R's and D's.... Hope this solves your doubt I'm 7 years late though lol.....
damn i was stuck at a similar questions and as soon as he wrote them in letters I knew where it was going. I tried marking the places with coordinates, but that seemed to go nowhere, maybe it is possible but I'm not sure.
I want to understand the rational you explained from A to C is 6 possible ways without intersecting at the same point. On paper, i can draw around 10 paths. is your rational based on shortest path ?
This man has restored my faith in humanity
You are a very smart and intelligent person in explaining.
Thank you 🎉
I wish that there was a superlike button on TH-cam!!
thank you so much for walking me through your logic and the awesome commentary!!
Fantastic explanation.. I wish I had teachers like you!
Woooooohoooooooooo luvd this watched lots and lots of videos didn't understand anything read lots of reference textbooks but understood by this luvvdddddd this!!!!
Whoa...interesting sums and a splendid explanation
That’s so good … loved this method … love from india 🇮🇳 sir !!!
Why cant i had a teacher like him...
you are amazing! god bless! love from India
Love you Mr. Woo ❤️❤️❤️
great ques...great way sir
This is best! The divide one
Thank you thank you thank you
Thanks Eddie for the clear explanations, my current teacher is a Joke!
Loving the vids
I hope youre my teacher at uni
You are amazing. Thanks
really cool !!
great question
you are too amazing!!!
my savior!
Kids in Australian schools are getting a really good education
I guess you can actually use the method from C to work out D .You just picking other line but the result is still the same :)
In part d):
How come you don't count the different ways you can get to Q at 8:58? Surely you can approach Q in more than one way? I.e. 2 downs 1 right, or 1 right 2 downs (going through but not crossing the forbidden second line)?
And wouldn't this also apply for C, R, and S? Such that there are 3 ways to get from A to C, 4 from A to R, and 5 from A to S?
I arrived at 210, which is equal to 10!/(4!6!) from the first part, so maybe I've gone wrong somewhere in my working.
But it seems logical to arrive at Q-S from A in more than one way...
I agree with you.. too bad he doesn't answer the comments
The calculation of going from A through X to P counts 2 downs 1 right. The Q calculation is assuming that we go from point A straight to P (1 right 2 downs).
Yes agreed. Total = 1 * P to B + 2* Q to B + 3 * C to B + 4* R to B + 5* S to B. 126 seems unlikely.
totally agree@@cryonim
You are correct though that there are multiples ways to get there but we have a restricted condition that we have to make exactly 10 moves for every case.... Having that constrain we get only one possible way as we have to arrange the existing R's and D's.... Hope this solves your doubt I'm 7 years late though lol.....
Thanks a lot dude!
Your incredible
ty very useful!
damn i was stuck at a similar questions and as soon as he wrote them in letters I knew where it was going. I tried marking the places with coordinates, but that seemed to go nowhere, maybe it is possible but I'm not sure.
great
this is so helpfull thanks
🎉🎉
In the last section, don't you have to account for 2 ways to get from A to P? And 3 ways to get from A to C...
I want to understand the rational you explained from A to C is 6 possible ways without intersecting at the same point. On paper, i can draw around 10 paths. is your rational based on shortest path ?
Um, it is 6 possible ways, even while writing on paper. I can't see how you possibly got 10?
Coooolll
I think calculus is way easier to understand than counting and probability...