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Meaning of Lagrange multiplier

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  • เผยแพร่เมื่อ 5 ธ.ค. 2016
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    In the previous videos on Lagrange multipliers, the Lagrange multiplier itself has just been some proportionality constant that we didn't care about. Here, you can see what its real meaning is.

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  • @8bit_pineapple
    @8bit_pineapple 6 ปีที่แล้ว +319

    lol, I went to 3Blue1Brown to see if Grant had any videos explaining what the langrange multipliar and lagrangians are.... seeing not I head over to Khan Academy... and Grant is teaching the lesson

    • @Jurgan6
      @Jurgan6 3 ปีที่แล้ว +12

      Two years later, I did the exact same thing.

    • @brandontay2053
      @brandontay2053 3 ปีที่แล้ว +8

      @@Jurgan6 2 months later, here I am, having done the same thing :')

    • @morancium
      @morancium 3 ปีที่แล้ว +3

      @@brandontay2053 2 weeks later, mee too!!

    • @YashPatel-vt8or
      @YashPatel-vt8or 3 ปีที่แล้ว +1

      me too

    • @morancium
      @morancium 3 ปีที่แล้ว +1

      @@YashPatel-vt8or which college bro 😂

  • @sjwang3892
    @sjwang3892 3 ปีที่แล้ว +45

    Went from Constrained Optimization Introduction to this video. Absolutely love the clear explanation w/ the graphs! No idea why other materials have to make it so hard to understand.

    • @technosapien330
      @technosapien330 6 หลายเดือนก่อน +1

      My theory is they either don't actually understand the topic, or they are gate-keeping

  • @masterchief8646
    @masterchief8646 3 ปีที่แล้ว +15

    good Lord this video brought so much understanding to the LaGrange multiplier it´s insane. God bless you Sir

  • @leeris19
    @leeris19 หลายเดือนก่อน

    Last time I checked I am studying how to minimize Optimum Margin Classifier for Support Vectors, now I am here, I don't know how, but I love it.

  • @dirkjensen935
    @dirkjensen935 2 ปีที่แล้ว +6

    Needed to pick up some basic know how about lagrangian in order to work through a proof regarding partition functions. And I was worried it was going to take me forever considering other texts I have aren't particularly clear and I didn't take lagrangian in undergrad. But oh my, this series is short, snappy, to the point and intuitive. Your tutorials are timeless and a gift to humanity. Thank you.

  • @DefinitelyNotNhanTho
    @DefinitelyNotNhanTho 6 ปีที่แล้ว +43

    9:50 I believe what you meant was “let’s pause and ponder...” right ? Yeah, you can’t fool us, we know it was you lecturing, 3Blue1Brown.

  • @mehdij9494
    @mehdij9494 6 ปีที่แล้ว +8

    I knew Lagrange Optimization since long time. But NOW I can claim understand it perfectly!
    Thank you so much!

  • @tunim4354
    @tunim4354 7 ปีที่แล้ว +24

    This is important in economics. One of the major concepts in Real business cycle.‎

    • @jairjuliocc
      @jairjuliocc 3 ปีที่แล้ว +1

      I know im a little late but, Can you explain more?

    • @tunim4354
      @tunim4354 3 ปีที่แล้ว +2

      @@jairjuliocc I was talking about the famous Real Business Cycle model in macroeconomics. When you are working with factors of production like labor and capital and you need Utility maximisation in a single period RBC model. The first order condition equations for capital and labor need a lagrange multiplier. If you are not a student of finance and economics, these will go over your head. And if you have studied macroeco, then these will be the most basic thing you learn.

    • @Leo-tf3rw
      @Leo-tf3rw 3 ปีที่แล้ว +4

      @@tunim4354 wow you replied after 4 years

    • @hbbh
      @hbbh 3 ปีที่แล้ว

      @@Leo-tf3rw AHAHHAHAH he did

    • @hbbh
      @hbbh 3 ปีที่แล้ว

      That person probably already finished college

  • @SuperIdiotMan00
    @SuperIdiotMan00 7 ปีที่แล้ว +56

    "Hours of Labor and Tons of Steel". That sounds like a rejected thrash metal album.

  • @pritomroy2465
    @pritomroy2465 4 ปีที่แล้ว +5

    9:31 I thought most of the things in math comes from nowhere until I got your videos.

  • @phil97n
    @phil97n 9 หลายเดือนก่อน +1

    Many thanks! I learned about lagrange multipliers as of yesterday, but it's been rather difficult to understand just exactly what it is even thought the math makes sense - your video clarified for me. Thanks again

  • @rikenm
    @rikenm 7 ปีที่แล้ว +85

    It's a good refresher. Thanks. I would like to request you for advance math courses. You are very good at teaching. I watched your linear algebra playlist and also subscribed to your youtube (3Blue1Brown). It's awesome: How about abstract algebra, or even number theory. Thanks

    • @justinward3679
      @justinward3679 7 ปีที่แล้ว +8

      Riken Maharjan I second this!

    • @zes7215
      @zes7215 6 ปีที่แล้ว

      no such thing as gx or not

  • @ThePiMan0903
    @ThePiMan0903 ปีที่แล้ว +2

    Thank you Khan Academy!

  • @alexanderherbertkurz
    @alexanderherbertkurz 6 ปีที่แล้ว +4

    thanks a lot, great video ... I watched a few videos on Lagrange multipliers and this is the best so far ... it would be great if there were links to the previous and next video in the series

  • @abdullahalmosalami2373
    @abdullahalmosalami2373 3 ปีที่แล้ว +1

    Woah what! I was not expecting that lambda had some meaning! Oh why didn't my Calc 3 classes show me this. I don't even believe this was in my Calc 3 textbook, or maybe perhaps it was burried in some of the problems at the end of the Lagrange Multiplier section.

  • @dionsilverman4195
    @dionsilverman4195 4 ปีที่แล้ว +2

    How do we know that when the gradients are parallel, it's an extremum of the constraint g(x,y), rather than an inflection point? For example, extremising the paraboloid f(x,y) = x² +y² subject to y = 2x³ + 1. The gradients are parallel at (0,1), but this does not extremise the function f subject to the constraint g(x,y).
    Also, can I request a video on Lagrange multipliers with multiple constraints? This is much harder to find. I'm particularly interested in its use in deriving the Boltzmann distribution as maximising the number of micro states subject to constant molecule number and total energy. Also, a video on how this relates to Lagrangian or Hamiltonian mechanics would be fantastic and a common application I think.

  • @umountable
    @umountable 4 ปีที่แล้ว +2

    how to find "the previous video" there is no playlist linked to the video

  • @michaeljpchen6469
    @michaeljpchen6469 6 ปีที่แล้ว

    Really helpful to help me get a thorough understanding

  • @franks.6547
    @franks.6547 6 ปีที่แล้ว +1

    Wouldn't we suspect, just from looking at the parallel gradients of R and B, that for every small increase of B you get λ times an increase of R? I mean something like λ = |grad R|/|grad B| = dR/dB on a curve perpendicular to the two tangent contour lines -same as Anton Geraschenko says below, but more visually intuitive, I think. (I admit that you still have to believe that any variation of h and s should be along that perpendicular curve, but that is how you keep R and B contours tangent to each other)

  • @Skandalos
    @Skandalos ปีที่แล้ว

    The voice sounds familiar. Is this the guy from the 3blue1brown channel? Anyway, this is very well explained.

  • @kawhiknot1016
    @kawhiknot1016 5 ปีที่แล้ว +1

    In what playlist does constraint programming topics it belongs?

  • @supreme84x
    @supreme84x 5 ปีที่แล้ว

    Wouldn't the contour of B be pointed down,, from the concavity? Or is the multiplier acting as a "negative" scalar, flipping it around?

  • @arslanhojiyev5996
    @arslanhojiyev5996 3 ปีที่แล้ว

    If does not ask for the maximum ( or minimum), how can you know it is indeed the maximum (or minimum) value???

  • @indranilroy691
    @indranilroy691 5 ปีที่แล้ว +1

    At 4:30, why we are taking gradient of L(Lagrangian function) = 0? Can anyone please put some light on this. Thanks!

    • @dsanjoy
      @dsanjoy 4 ปีที่แล้ว

      In a previous video it has been explained. You have to calculate the tangent of the two function and they have to be proportional to each other. The propionality constant is lambda.

  • @ruSEXtreme
    @ruSEXtreme 6 ปีที่แล้ว +1

    why should the 2 gradients have to be proportional, as opposed to being equal to each other? if they're not equal at the point of contact, then theyre not tangent to each other..?

    • @BillPickle
      @BillPickle 5 ปีที่แล้ว +4

      so long as the direction is the same, the gradient vectors will be parallel scalar multiples (lambda). The magnitudes of the vectors do not matter, and if reduced to unit vectors, would be identical.

  • @xiaoweidu4667
    @xiaoweidu4667 4 ปีที่แล้ว

    this is fantastic point !

  • @liabraga4641
    @liabraga4641 7 ปีที่แล้ว +1

    So elucidating

  • @Rockyzach88
    @Rockyzach88 ปีที่แล้ว

    So is the lagrange multiplier also considered an eigenvalue?

  • @miguelangelhernandezortiz7303
    @miguelangelhernandezortiz7303 2 ปีที่แล้ว

    Anybody knows a book of Multivariable Calculus' history? Please help me.

  • @CalleTful
    @CalleTful 2 ปีที่แล้ว

    Which playlist is this in?

  • @RajatGoel1
    @RajatGoel1 6 ปีที่แล้ว +1

    6:47 REALLY!!!

  • @abhishek_sengupta
    @abhishek_sengupta 3 ปีที่แล้ว

    wow...Thanx a lot!!

  • @johncharles3907
    @johncharles3907 4 ปีที่แล้ว

    I think I need some more animations to understand this.

  • @sam4395
    @sam4395 7 ปีที่แล้ว +4

    oh

  • @usamsersultanov689
    @usamsersultanov689 7 ปีที่แล้ว

    Finally I got it

  • @atriagotler
    @atriagotler 2 ปีที่แล้ว

    I love you grant.

  • @animeshpuzari8235
    @animeshpuzari8235 5 ปีที่แล้ว

    thanks😁🏅

  • @Majestic469
    @Majestic469 4 ปีที่แล้ว

    Why can’t you just solve for h or s in one function and substitute that expression in the other function? Then you can just set the derivative to 0 to find the optimization.

    • @MayankGoel447
      @MayankGoel447 2 ปีที่แล้ว

      That's not always possible. If say, your constraint function was not factorizable e.g. xsin(y) + yx^2=1. In this case, you can't express x in terms of y or the other way around and substitute that in f(x)

  • @uvenga
    @uvenga 2 ปีที่แล้ว

    The one who can not learn is because he doesn't want 💯

  • @Postermaestro
    @Postermaestro 6 ปีที่แล้ว

    Commenting to spread on the tubes!

  • @anas.2k866
    @anas.2k866 3 ปีที่แล้ว

    I don't see why the two fradient are propotinal

    • @hectorbetancourt2854
      @hectorbetancourt2854 3 ปีที่แล้ว

      Because you made them so through the Lagrange multiplier. There are multiple grads of the contour of the function that don't have a proportional grad with the constraint, but by assuming that they are (and that they relate to each other through the Lagrande multiplier), you can solve the system of equations and get all the points at which your previous assumption, that the two gradients are proportional, is true.

  • @dagia3209
    @dagia3209 5 ปีที่แล้ว

    I like it

  • @elgodyr2683
    @elgodyr2683 2 ปีที่แล้ว

    guys can the lamda be equal to 0 ?

    • @goclbert
      @goclbert 2 ปีที่แล้ว

      Yeah but wouldn't that just mean our constraint has no impact on our ability to optimize R?

  • @mv3845
    @mv3845 ปีที่แล้ว

  • @buh357
    @buh357 3 ปีที่แล้ว

    F**k, This is GOLD.

  • @theacademyofgermanidealism6210
    @theacademyofgermanidealism6210 4 ปีที่แล้ว

    3blue one brown guy

  • @tag_of_frank
    @tag_of_frank 3 ปีที่แล้ว

    Argh why no inequality constraints

  • @jullevv
    @jullevv 7 ปีที่แล้ว +1

    first like

  • @Jmtri7
    @Jmtri7 3 ปีที่แล้ว

    While you maximize your revenue, I'll be maximizing my profit... ;)

  • @tadasvaitkevicius5799
    @tadasvaitkevicius5799 4 ปีที่แล้ว

    i dont like that he speaks so fast

  • @alaypal7484
    @alaypal7484 6 ปีที่แล้ว

    Omg

  • @shellycollorone3703
    @shellycollorone3703 7 ปีที่แล้ว +1

    why sending math i'm not needing ?

    • @zayedalsuwaidi7697
      @zayedalsuwaidi7697 7 ปีที่แล้ว +3

      Maybe just don't click videos you do not need to see?

    • @shellycollorone3703
      @shellycollorone3703 7 ปีที่แล้ว +1

      iii 3xki they sending a different kind of math i don't need.

    • @zayedalsuwaidi7697
      @zayedalsuwaidi7697 7 ปีที่แล้ว +2

      Shaelyne Collorone
      Okay, I understand this. But why don't you just go on the website www.khanacademy.com and look for what you need instead of clicking on videos you don't want to see?

    • @edjrage7745
      @edjrage7745 3 ปีที่แล้ว

      @@shellycollorone3703 who is they